Optimal. Leaf size=72 \[ a x \, _2F_1\left (\frac {1}{2},\frac {1}{2}-p;\frac {3}{2};a^2 x^2\right )-\frac {\left (1-a^2 x^2\right )^{p+\frac {1}{2}} \, _2F_1\left (1,p+\frac {1}{2};p+\frac {3}{2};1-a^2 x^2\right )}{2 p+1} \]
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Rubi [A] time = 0.09, antiderivative size = 72, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.227, Rules used = {6148, 764, 266, 65, 245} \[ a x \, _2F_1\left (\frac {1}{2},\frac {1}{2}-p;\frac {3}{2};a^2 x^2\right )-\frac {\left (1-a^2 x^2\right )^{p+\frac {1}{2}} \, _2F_1\left (1,p+\frac {1}{2};p+\frac {3}{2};1-a^2 x^2\right )}{2 p+1} \]
Antiderivative was successfully verified.
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Rule 65
Rule 245
Rule 266
Rule 764
Rule 6148
Rubi steps
\begin {align*} \int \frac {e^{\tanh ^{-1}(a x)} \left (1-a^2 x^2\right )^p}{x} \, dx &=\int \frac {(1+a x) \left (1-a^2 x^2\right )^{-\frac {1}{2}+p}}{x} \, dx\\ &=a \int \left (1-a^2 x^2\right )^{-\frac {1}{2}+p} \, dx+\int \frac {\left (1-a^2 x^2\right )^{-\frac {1}{2}+p}}{x} \, dx\\ &=a x \, _2F_1\left (\frac {1}{2},\frac {1}{2}-p;\frac {3}{2};a^2 x^2\right )+\frac {1}{2} \operatorname {Subst}\left (\int \frac {\left (1-a^2 x\right )^{-\frac {1}{2}+p}}{x} \, dx,x,x^2\right )\\ &=a x \, _2F_1\left (\frac {1}{2},\frac {1}{2}-p;\frac {3}{2};a^2 x^2\right )-\frac {\left (1-a^2 x^2\right )^{\frac {1}{2}+p} \, _2F_1\left (1,\frac {1}{2}+p;\frac {3}{2}+p;1-a^2 x^2\right )}{1+2 p}\\ \end {align*}
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Mathematica [A] time = 0.03, size = 74, normalized size = 1.03 \[ a x \, _2F_1\left (\frac {1}{2},\frac {1}{2}-p;\frac {3}{2};a^2 x^2\right )-\frac {\left (1-a^2 x^2\right )^{p+\frac {1}{2}} \, _2F_1\left (1,p+\frac {1}{2};p+\frac {3}{2};1-a^2 x^2\right )}{2 \left (p+\frac {1}{2}\right )} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.59, size = 0, normalized size = 0.00 \[ {\rm integral}\left (-\frac {\sqrt {-a^{2} x^{2} + 1} {\left (-a^{2} x^{2} + 1\right )}^{p}}{a x^{2} - x}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (a x + 1\right )} {\left (-a^{2} x^{2} + 1\right )}^{p}}{\sqrt {-a^{2} x^{2} + 1} x}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.38, size = 90, normalized size = 1.25 \[ a x \hypergeom \left (\left [\frac {1}{2}, \frac {1}{2}-p \right ], \left [\frac {3}{2}\right ], a^{2} x^{2}\right )+\frac {\Gamma \left (\frac {3}{2}-p \right ) a^{2} x^{2} \hypergeom \left (\left [1, 1, \frac {3}{2}-p \right ], \left [2, 2\right ], a^{2} x^{2}\right )+\left (\Psi \left (\frac {1}{2}-p \right )+\gamma +2 \ln \relax (x )+\ln \left (-a^{2}\right )\right ) \Gamma \left (\frac {1}{2}-p \right )}{2 \Gamma \left (\frac {1}{2}-p \right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (a x + 1\right )} {\left (-a^{2} x^{2} + 1\right )}^{p - \frac {1}{2}}}{x}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\left (1-a^2\,x^2\right )}^p\,\left (a\,x+1\right )}{x\,\sqrt {1-a^2\,x^2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [C] time = 30.72, size = 286, normalized size = 3.97 \[ - \frac {a a^{2 p} x x^{2 p} e^{i \pi p} \Gamma \left (- p - \frac {1}{2}\right ) \Gamma \left (p + \frac {1}{2}\right ) {{}_{3}F_{2}\left (\begin {matrix} \frac {1}{2}, 1, p + \frac {1}{2} \\ p + 1, p + \frac {3}{2} \end {matrix}\middle | {a^{2} x^{2} e^{2 i \pi }} \right )}}{2 \sqrt {\pi } \Gamma \left (\frac {1}{2} - p\right ) \Gamma \left (p + 1\right )} - \frac {a a^{2 p} x x^{2 p} e^{i \pi p} \Gamma \left (- p - \frac {1}{2}\right ) \Gamma \left (p + \frac {1}{2}\right ) {{}_{3}F_{2}\left (\begin {matrix} 1, - p, - p - \frac {1}{2} \\ \frac {1}{2}, \frac {1}{2} - p \end {matrix}\middle | {\frac {1}{a^{2} x^{2}}} \right )}}{2 \sqrt {\pi } \Gamma \left (\frac {1}{2} - p\right ) \Gamma \left (p + 1\right )} - \frac {a^{2 p} x^{2 p} e^{i \pi p} \Gamma \left (- p\right ) \Gamma \left (p + \frac {1}{2}\right ) {{}_{3}F_{2}\left (\begin {matrix} \frac {1}{2}, 1, p \\ p + 1, p + 1 \end {matrix}\middle | {a^{2} x^{2} e^{2 i \pi }} \right )}}{2 \sqrt {\pi } \Gamma \left (1 - p\right ) \Gamma \left (p + 1\right )} - \frac {a^{2 p} x^{2 p} e^{i \pi p} \Gamma \left (- p\right ) \Gamma \left (p + \frac {1}{2}\right ) {{}_{3}F_{2}\left (\begin {matrix} 1, - p, - p \\ \frac {1}{2}, 1 - p \end {matrix}\middle | {\frac {1}{a^{2} x^{2}}} \right )}}{2 \sqrt {\pi } \Gamma \left (1 - p\right ) \Gamma \left (p + 1\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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