Optimal. Leaf size=59 \[ -\frac {2^{p+\frac {3}{2}} (1-a x)^{p+\frac {1}{2}} \, _2F_1\left (-p-\frac {1}{2},p+\frac {1}{2};p+\frac {3}{2};\frac {1}{2} (1-a x)\right )}{a (2 p+1)} \]
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Rubi [A] time = 0.04, antiderivative size = 59, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.105, Rules used = {6140, 69} \[ -\frac {2^{p+\frac {3}{2}} (1-a x)^{p+\frac {1}{2}} \, _2F_1\left (-p-\frac {1}{2},p+\frac {1}{2};p+\frac {3}{2};\frac {1}{2} (1-a x)\right )}{a (2 p+1)} \]
Antiderivative was successfully verified.
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Rule 69
Rule 6140
Rubi steps
\begin {align*} \int e^{\tanh ^{-1}(a x)} \left (1-a^2 x^2\right )^p \, dx &=\int (1-a x)^{-\frac {1}{2}+p} (1+a x)^{\frac {1}{2}+p} \, dx\\ &=-\frac {2^{\frac {3}{2}+p} (1-a x)^{\frac {1}{2}+p} \, _2F_1\left (-\frac {1}{2}-p,\frac {1}{2}+p;\frac {3}{2}+p;\frac {1}{2} (1-a x)\right )}{a (1+2 p)}\\ \end {align*}
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Mathematica [A] time = 0.01, size = 59, normalized size = 1.00 \[ -\frac {2^{p+\frac {1}{2}} (1-a x)^{p+\frac {1}{2}} \, _2F_1\left (-p-\frac {1}{2},p+\frac {1}{2};p+\frac {3}{2};\frac {1}{2} (1-a x)\right )}{a \left (p+\frac {1}{2}\right )} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.63, size = 0, normalized size = 0.00 \[ {\rm integral}\left (-\frac {\sqrt {-a^{2} x^{2} + 1} {\left (-a^{2} x^{2} + 1\right )}^{p}}{a x - 1}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (a x + 1\right )} {\left (-a^{2} x^{2} + 1\right )}^{p}}{\sqrt {-a^{2} x^{2} + 1}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.34, size = 44, normalized size = 0.75 \[ \frac {a \,x^{2} \hypergeom \left (\left [1, \frac {1}{2}-p \right ], \relax [2], a^{2} x^{2}\right )}{2}+x \hypergeom \left (\left [\frac {1}{2}, \frac {1}{2}-p \right ], \left [\frac {3}{2}\right ], a^{2} x^{2}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (a x + 1\right )} {\left (-a^{2} x^{2} + 1\right )}^{p - \frac {1}{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.02 \[ \int \frac {{\left (1-a^2\,x^2\right )}^p\,\left (a\,x+1\right )}{\sqrt {1-a^2\,x^2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [C] time = 11.47, size = 292, normalized size = 4.95 \[ - \frac {a a^{2 p} x^{2} x^{2 p} e^{i \pi p} \Gamma \left (- p - 1\right ) \Gamma \left (p + \frac {1}{2}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {1}{2}, 1 \\ p + 2 \end {matrix}\middle | {a^{2} x^{2} e^{2 i \pi }} \right )}}{2 \sqrt {\pi } \Gamma \left (- p\right ) \Gamma \left (p + 1\right )} - \frac {a a^{2 p} x^{2} x^{2 p} e^{i \pi p} \Gamma \left (- p - 1\right ) \Gamma \left (p + \frac {1}{2}\right ) {{}_{2}F_{1}\left (\begin {matrix} 1, - p - 1 \\ \frac {1}{2} \end {matrix}\middle | {\frac {1}{a^{2} x^{2}}} \right )}}{2 \sqrt {\pi } \Gamma \left (- p\right ) \Gamma \left (p + 1\right )} - \frac {a^{2 p} x x^{2 p} e^{i \pi p} \Gamma \left (- p - \frac {1}{2}\right ) \Gamma \left (p + \frac {1}{2}\right ) {{}_{3}F_{2}\left (\begin {matrix} \frac {1}{2}, 1, p + \frac {1}{2} \\ p + 1, p + \frac {3}{2} \end {matrix}\middle | {a^{2} x^{2} e^{2 i \pi }} \right )}}{2 \sqrt {\pi } \Gamma \left (\frac {1}{2} - p\right ) \Gamma \left (p + 1\right )} - \frac {a^{2 p} x x^{2 p} e^{i \pi p} \Gamma \left (- p - \frac {1}{2}\right ) \Gamma \left (p + \frac {1}{2}\right ) {{}_{3}F_{2}\left (\begin {matrix} 1, - p, - p - \frac {1}{2} \\ \frac {1}{2}, \frac {1}{2} - p \end {matrix}\middle | {\frac {1}{a^{2} x^{2}}} \right )}}{2 \sqrt {\pi } \Gamma \left (\frac {1}{2} - p\right ) \Gamma \left (p + 1\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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