3.47 \(\int \frac {(f+g x)^3 (a+b \sinh ^{-1}(c x))}{\sqrt {d+c^2 d x^2}} \, dx\)

Optimal. Leaf size=430 \[ \frac {f^3 \sqrt {c^2 x^2+1} \left (a+b \sinh ^{-1}(c x)\right )^2}{2 b c \sqrt {c^2 d x^2+d}}+\frac {3 f^2 g \left (c^2 x^2+1\right ) \left (a+b \sinh ^{-1}(c x)\right )}{c^2 \sqrt {c^2 d x^2+d}}+\frac {3 f g^2 x \left (c^2 x^2+1\right ) \left (a+b \sinh ^{-1}(c x)\right )}{2 c^2 \sqrt {c^2 d x^2+d}}+\frac {g^3 x^2 \left (c^2 x^2+1\right ) \left (a+b \sinh ^{-1}(c x)\right )}{3 c^2 \sqrt {c^2 d x^2+d}}-\frac {2 g^3 \left (c^2 x^2+1\right ) \left (a+b \sinh ^{-1}(c x)\right )}{3 c^4 \sqrt {c^2 d x^2+d}}-\frac {3 f g^2 \sqrt {c^2 x^2+1} \left (a+b \sinh ^{-1}(c x)\right )^2}{4 b c^3 \sqrt {c^2 d x^2+d}}-\frac {3 b f^2 g x \sqrt {c^2 x^2+1}}{c \sqrt {c^2 d x^2+d}}-\frac {3 b f g^2 x^2 \sqrt {c^2 x^2+1}}{4 c \sqrt {c^2 d x^2+d}}-\frac {b g^3 x^3 \sqrt {c^2 x^2+1}}{9 c \sqrt {c^2 d x^2+d}}+\frac {2 b g^3 x \sqrt {c^2 x^2+1}}{3 c^3 \sqrt {c^2 d x^2+d}} \]

[Out]

3*f^2*g*(c^2*x^2+1)*(a+b*arcsinh(c*x))/c^2/(c^2*d*x^2+d)^(1/2)-2/3*g^3*(c^2*x^2+1)*(a+b*arcsinh(c*x))/c^4/(c^2
*d*x^2+d)^(1/2)+3/2*f*g^2*x*(c^2*x^2+1)*(a+b*arcsinh(c*x))/c^2/(c^2*d*x^2+d)^(1/2)+1/3*g^3*x^2*(c^2*x^2+1)*(a+
b*arcsinh(c*x))/c^2/(c^2*d*x^2+d)^(1/2)-3*b*f^2*g*x*(c^2*x^2+1)^(1/2)/c/(c^2*d*x^2+d)^(1/2)+2/3*b*g^3*x*(c^2*x
^2+1)^(1/2)/c^3/(c^2*d*x^2+d)^(1/2)-3/4*b*f*g^2*x^2*(c^2*x^2+1)^(1/2)/c/(c^2*d*x^2+d)^(1/2)-1/9*b*g^3*x^3*(c^2
*x^2+1)^(1/2)/c/(c^2*d*x^2+d)^(1/2)+1/2*f^3*(a+b*arcsinh(c*x))^2*(c^2*x^2+1)^(1/2)/b/c/(c^2*d*x^2+d)^(1/2)-3/4
*f*g^2*(a+b*arcsinh(c*x))^2*(c^2*x^2+1)^(1/2)/b/c^3/(c^2*d*x^2+d)^(1/2)

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Rubi [A]  time = 0.58, antiderivative size = 430, normalized size of antiderivative = 1.00, number of steps used = 13, number of rules used = 7, integrand size = 30, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.233, Rules used = {5835, 5821, 5675, 5717, 8, 5758, 30} \[ \frac {3 f^2 g \left (c^2 x^2+1\right ) \left (a+b \sinh ^{-1}(c x)\right )}{c^2 \sqrt {c^2 d x^2+d}}+\frac {f^3 \sqrt {c^2 x^2+1} \left (a+b \sinh ^{-1}(c x)\right )^2}{2 b c \sqrt {c^2 d x^2+d}}-\frac {3 f g^2 \sqrt {c^2 x^2+1} \left (a+b \sinh ^{-1}(c x)\right )^2}{4 b c^3 \sqrt {c^2 d x^2+d}}+\frac {3 f g^2 x \left (c^2 x^2+1\right ) \left (a+b \sinh ^{-1}(c x)\right )}{2 c^2 \sqrt {c^2 d x^2+d}}-\frac {2 g^3 \left (c^2 x^2+1\right ) \left (a+b \sinh ^{-1}(c x)\right )}{3 c^4 \sqrt {c^2 d x^2+d}}+\frac {g^3 x^2 \left (c^2 x^2+1\right ) \left (a+b \sinh ^{-1}(c x)\right )}{3 c^2 \sqrt {c^2 d x^2+d}}-\frac {3 b f^2 g x \sqrt {c^2 x^2+1}}{c \sqrt {c^2 d x^2+d}}-\frac {3 b f g^2 x^2 \sqrt {c^2 x^2+1}}{4 c \sqrt {c^2 d x^2+d}}-\frac {b g^3 x^3 \sqrt {c^2 x^2+1}}{9 c \sqrt {c^2 d x^2+d}}+\frac {2 b g^3 x \sqrt {c^2 x^2+1}}{3 c^3 \sqrt {c^2 d x^2+d}} \]

Antiderivative was successfully verified.

[In]

Int[((f + g*x)^3*(a + b*ArcSinh[c*x]))/Sqrt[d + c^2*d*x^2],x]

[Out]

(-3*b*f^2*g*x*Sqrt[1 + c^2*x^2])/(c*Sqrt[d + c^2*d*x^2]) + (2*b*g^3*x*Sqrt[1 + c^2*x^2])/(3*c^3*Sqrt[d + c^2*d
*x^2]) - (3*b*f*g^2*x^2*Sqrt[1 + c^2*x^2])/(4*c*Sqrt[d + c^2*d*x^2]) - (b*g^3*x^3*Sqrt[1 + c^2*x^2])/(9*c*Sqrt
[d + c^2*d*x^2]) + (3*f^2*g*(1 + c^2*x^2)*(a + b*ArcSinh[c*x]))/(c^2*Sqrt[d + c^2*d*x^2]) - (2*g^3*(1 + c^2*x^
2)*(a + b*ArcSinh[c*x]))/(3*c^4*Sqrt[d + c^2*d*x^2]) + (3*f*g^2*x*(1 + c^2*x^2)*(a + b*ArcSinh[c*x]))/(2*c^2*S
qrt[d + c^2*d*x^2]) + (g^3*x^2*(1 + c^2*x^2)*(a + b*ArcSinh[c*x]))/(3*c^2*Sqrt[d + c^2*d*x^2]) + (f^3*Sqrt[1 +
c^2*x^2]*(a + b*ArcSinh[c*x])^2)/(2*b*c*Sqrt[d + c^2*d*x^2]) - (3*f*g^2*Sqrt[1 + c^2*x^2]*(a + b*ArcSinh[c*x]
)^2)/(4*b*c^3*Sqrt[d + c^2*d*x^2])

Rule 8

Int[a_, x_Symbol] :> Simp[a*x, x] /; FreeQ[a, x]

Rule 30

Int[(x_)^(m_.), x_Symbol] :> Simp[x^(m + 1)/(m + 1), x] /; FreeQ[m, x] && NeQ[m, -1]

Rule 5675

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)/Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> Simp[(a + b*ArcSinh[c*x]
)^(n + 1)/(b*c*Sqrt[d]*(n + 1)), x] /; FreeQ[{a, b, c, d, e, n}, x] && EqQ[e, c^2*d] && GtQ[d, 0] && NeQ[n, -1
]

Rule 5717

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)*(x_)*((d_) + (e_.)*(x_)^2)^(p_.), x_Symbol] :> Simp[((d + e*x^2)
^(p + 1)*(a + b*ArcSinh[c*x])^n)/(2*e*(p + 1)), x] - Dist[(b*n*d^IntPart[p]*(d + e*x^2)^FracPart[p])/(2*c*(p +
1)*(1 + c^2*x^2)^FracPart[p]), Int[(1 + c^2*x^2)^(p + 1/2)*(a + b*ArcSinh[c*x])^(n - 1), x], x] /; FreeQ[{a,
b, c, d, e, p}, x] && EqQ[e, c^2*d] && GtQ[n, 0] && NeQ[p, -1]

Rule 5758

Int[(((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)*((f_.)*(x_))^(m_))/Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> Simp
[(f*(f*x)^(m - 1)*Sqrt[d + e*x^2]*(a + b*ArcSinh[c*x])^n)/(e*m), x] + (-Dist[(f^2*(m - 1))/(c^2*m), Int[((f*x)
^(m - 2)*(a + b*ArcSinh[c*x])^n)/Sqrt[d + e*x^2], x], x] - Dist[(b*f*n*Sqrt[1 + c^2*x^2])/(c*m*Sqrt[d + e*x^2]
), Int[(f*x)^(m - 1)*(a + b*ArcSinh[c*x])^(n - 1), x], x]) /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[e, c^2*d] &&
GtQ[n, 0] && GtQ[m, 1] && IntegerQ[m]

Rule 5821

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)*((f_) + (g_.)*(x_))^(m_.)*((d_) + (e_.)*(x_)^2)^(p_), x_Symbol]
:> Int[ExpandIntegrand[(d + e*x^2)^p*(a + b*ArcSinh[c*x])^n, (f + g*x)^m, x], x] /; FreeQ[{a, b, c, d, e, f, g
}, x] && EqQ[e, c^2*d] && IGtQ[m, 0] && IntegerQ[p + 1/2] && GtQ[d, 0] && IGtQ[n, 0] && ((EqQ[n, 1] && GtQ[p,
-1]) || GtQ[p, 0] || EqQ[m, 1] || (EqQ[m, 2] && LtQ[p, -2]))

Rule 5835

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)*((f_) + (g_.)*(x_))^(m_.)*((d_) + (e_.)*(x_)^2)^(p_), x_Symbol]
:> Dist[(d^IntPart[p]*(d + e*x^2)^FracPart[p])/(1 + c^2*x^2)^FracPart[p], Int[(f + g*x)^m*(1 + c^2*x^2)^p*(a +
b*ArcSinh[c*x])^n, x], x] /; FreeQ[{a, b, c, d, e, f, g, n}, x] && EqQ[e, c^2*d] && IntegerQ[m] && IntegerQ[p
- 1/2] &&  !GtQ[d, 0]

Rubi steps

\begin {align*} \int \frac {(f+g x)^3 \left (a+b \sinh ^{-1}(c x)\right )}{\sqrt {d+c^2 d x^2}} \, dx &=\frac {\sqrt {1+c^2 x^2} \int \frac {(f+g x)^3 \left (a+b \sinh ^{-1}(c x)\right )}{\sqrt {1+c^2 x^2}} \, dx}{\sqrt {d+c^2 d x^2}}\\ &=\frac {\sqrt {1+c^2 x^2} \int \left (\frac {f^3 \left (a+b \sinh ^{-1}(c x)\right )}{\sqrt {1+c^2 x^2}}+\frac {3 f^2 g x \left (a+b \sinh ^{-1}(c x)\right )}{\sqrt {1+c^2 x^2}}+\frac {3 f g^2 x^2 \left (a+b \sinh ^{-1}(c x)\right )}{\sqrt {1+c^2 x^2}}+\frac {g^3 x^3 \left (a+b \sinh ^{-1}(c x)\right )}{\sqrt {1+c^2 x^2}}\right ) \, dx}{\sqrt {d+c^2 d x^2}}\\ &=\frac {\left (f^3 \sqrt {1+c^2 x^2}\right ) \int \frac {a+b \sinh ^{-1}(c x)}{\sqrt {1+c^2 x^2}} \, dx}{\sqrt {d+c^2 d x^2}}+\frac {\left (3 f^2 g \sqrt {1+c^2 x^2}\right ) \int \frac {x \left (a+b \sinh ^{-1}(c x)\right )}{\sqrt {1+c^2 x^2}} \, dx}{\sqrt {d+c^2 d x^2}}+\frac {\left (3 f g^2 \sqrt {1+c^2 x^2}\right ) \int \frac {x^2 \left (a+b \sinh ^{-1}(c x)\right )}{\sqrt {1+c^2 x^2}} \, dx}{\sqrt {d+c^2 d x^2}}+\frac {\left (g^3 \sqrt {1+c^2 x^2}\right ) \int \frac {x^3 \left (a+b \sinh ^{-1}(c x)\right )}{\sqrt {1+c^2 x^2}} \, dx}{\sqrt {d+c^2 d x^2}}\\ &=\frac {3 f^2 g \left (1+c^2 x^2\right ) \left (a+b \sinh ^{-1}(c x)\right )}{c^2 \sqrt {d+c^2 d x^2}}+\frac {3 f g^2 x \left (1+c^2 x^2\right ) \left (a+b \sinh ^{-1}(c x)\right )}{2 c^2 \sqrt {d+c^2 d x^2}}+\frac {g^3 x^2 \left (1+c^2 x^2\right ) \left (a+b \sinh ^{-1}(c x)\right )}{3 c^2 \sqrt {d+c^2 d x^2}}+\frac {f^3 \sqrt {1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{2 b c \sqrt {d+c^2 d x^2}}-\frac {\left (3 b f^2 g \sqrt {1+c^2 x^2}\right ) \int 1 \, dx}{c \sqrt {d+c^2 d x^2}}-\frac {\left (3 f g^2 \sqrt {1+c^2 x^2}\right ) \int \frac {a+b \sinh ^{-1}(c x)}{\sqrt {1+c^2 x^2}} \, dx}{2 c^2 \sqrt {d+c^2 d x^2}}-\frac {\left (3 b f g^2 \sqrt {1+c^2 x^2}\right ) \int x \, dx}{2 c \sqrt {d+c^2 d x^2}}-\frac {\left (2 g^3 \sqrt {1+c^2 x^2}\right ) \int \frac {x \left (a+b \sinh ^{-1}(c x)\right )}{\sqrt {1+c^2 x^2}} \, dx}{3 c^2 \sqrt {d+c^2 d x^2}}-\frac {\left (b g^3 \sqrt {1+c^2 x^2}\right ) \int x^2 \, dx}{3 c \sqrt {d+c^2 d x^2}}\\ &=-\frac {3 b f^2 g x \sqrt {1+c^2 x^2}}{c \sqrt {d+c^2 d x^2}}-\frac {3 b f g^2 x^2 \sqrt {1+c^2 x^2}}{4 c \sqrt {d+c^2 d x^2}}-\frac {b g^3 x^3 \sqrt {1+c^2 x^2}}{9 c \sqrt {d+c^2 d x^2}}+\frac {3 f^2 g \left (1+c^2 x^2\right ) \left (a+b \sinh ^{-1}(c x)\right )}{c^2 \sqrt {d+c^2 d x^2}}-\frac {2 g^3 \left (1+c^2 x^2\right ) \left (a+b \sinh ^{-1}(c x)\right )}{3 c^4 \sqrt {d+c^2 d x^2}}+\frac {3 f g^2 x \left (1+c^2 x^2\right ) \left (a+b \sinh ^{-1}(c x)\right )}{2 c^2 \sqrt {d+c^2 d x^2}}+\frac {g^3 x^2 \left (1+c^2 x^2\right ) \left (a+b \sinh ^{-1}(c x)\right )}{3 c^2 \sqrt {d+c^2 d x^2}}+\frac {f^3 \sqrt {1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{2 b c \sqrt {d+c^2 d x^2}}-\frac {3 f g^2 \sqrt {1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{4 b c^3 \sqrt {d+c^2 d x^2}}+\frac {\left (2 b g^3 \sqrt {1+c^2 x^2}\right ) \int 1 \, dx}{3 c^3 \sqrt {d+c^2 d x^2}}\\ &=-\frac {3 b f^2 g x \sqrt {1+c^2 x^2}}{c \sqrt {d+c^2 d x^2}}+\frac {2 b g^3 x \sqrt {1+c^2 x^2}}{3 c^3 \sqrt {d+c^2 d x^2}}-\frac {3 b f g^2 x^2 \sqrt {1+c^2 x^2}}{4 c \sqrt {d+c^2 d x^2}}-\frac {b g^3 x^3 \sqrt {1+c^2 x^2}}{9 c \sqrt {d+c^2 d x^2}}+\frac {3 f^2 g \left (1+c^2 x^2\right ) \left (a+b \sinh ^{-1}(c x)\right )}{c^2 \sqrt {d+c^2 d x^2}}-\frac {2 g^3 \left (1+c^2 x^2\right ) \left (a+b \sinh ^{-1}(c x)\right )}{3 c^4 \sqrt {d+c^2 d x^2}}+\frac {3 f g^2 x \left (1+c^2 x^2\right ) \left (a+b \sinh ^{-1}(c x)\right )}{2 c^2 \sqrt {d+c^2 d x^2}}+\frac {g^3 x^2 \left (1+c^2 x^2\right ) \left (a+b \sinh ^{-1}(c x)\right )}{3 c^2 \sqrt {d+c^2 d x^2}}+\frac {f^3 \sqrt {1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{2 b c \sqrt {d+c^2 d x^2}}-\frac {3 f g^2 \sqrt {1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{4 b c^3 \sqrt {d+c^2 d x^2}}\\ \end {align*}

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Mathematica [A]  time = 0.95, size = 304, normalized size = 0.71 \[ \frac {4 \sqrt {d} g \left (3 a \left (c^2 x^2+1\right ) \left (c^2 \left (18 f^2+9 f g x+2 g^2 x^2\right )-4 g^2\right )-2 b c x \sqrt {c^2 x^2+1} \left (c^2 \left (27 f^2+g^2 x^2\right )-6 g^2\right )\right )+36 a c f \sqrt {c^2 d x^2+d} \left (2 c^2 f^2-3 g^2\right ) \log \left (\sqrt {d} \sqrt {c^2 d x^2+d}+c d x\right )+12 b \sqrt {d} g \left (c^2 x^2+1\right ) \sinh ^{-1}(c x) \left (c^2 \left (18 f^2+9 f g x+2 g^2 x^2\right )-4 g^2\right )+18 b c \sqrt {d} f \sqrt {c^2 x^2+1} \left (2 c^2 f^2-3 g^2\right ) \sinh ^{-1}(c x)^2-27 b c \sqrt {d} f g^2 \sqrt {c^2 x^2+1} \cosh \left (2 \sinh ^{-1}(c x)\right )}{72 c^4 \sqrt {d} \sqrt {c^2 d x^2+d}} \]

Antiderivative was successfully verified.

[In]

Integrate[((f + g*x)^3*(a + b*ArcSinh[c*x]))/Sqrt[d + c^2*d*x^2],x]

[Out]

(4*Sqrt[d]*g*(-2*b*c*x*Sqrt[1 + c^2*x^2]*(-6*g^2 + c^2*(27*f^2 + g^2*x^2)) + 3*a*(1 + c^2*x^2)*(-4*g^2 + c^2*(
18*f^2 + 9*f*g*x + 2*g^2*x^2))) + 12*b*Sqrt[d]*g*(1 + c^2*x^2)*(-4*g^2 + c^2*(18*f^2 + 9*f*g*x + 2*g^2*x^2))*A
rcSinh[c*x] + 18*b*c*Sqrt[d]*f*(2*c^2*f^2 - 3*g^2)*Sqrt[1 + c^2*x^2]*ArcSinh[c*x]^2 - 27*b*c*Sqrt[d]*f*g^2*Sqr
t[1 + c^2*x^2]*Cosh[2*ArcSinh[c*x]] + 36*a*c*f*(2*c^2*f^2 - 3*g^2)*Sqrt[d + c^2*d*x^2]*Log[c*d*x + Sqrt[d]*Sqr
t[d + c^2*d*x^2]])/(72*c^4*Sqrt[d]*Sqrt[d + c^2*d*x^2])

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fricas [F]  time = 0.59, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {a g^{3} x^{3} + 3 \, a f g^{2} x^{2} + 3 \, a f^{2} g x + a f^{3} + {\left (b g^{3} x^{3} + 3 \, b f g^{2} x^{2} + 3 \, b f^{2} g x + b f^{3}\right )} \operatorname {arsinh}\left (c x\right )}{\sqrt {c^{2} d x^{2} + d}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((g*x+f)^3*(a+b*arcsinh(c*x))/(c^2*d*x^2+d)^(1/2),x, algorithm="fricas")

[Out]

integral((a*g^3*x^3 + 3*a*f*g^2*x^2 + 3*a*f^2*g*x + a*f^3 + (b*g^3*x^3 + 3*b*f*g^2*x^2 + 3*b*f^2*g*x + b*f^3)*
arcsinh(c*x))/sqrt(c^2*d*x^2 + d), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (g x + f\right )}^{3} {\left (b \operatorname {arsinh}\left (c x\right ) + a\right )}}{\sqrt {c^{2} d x^{2} + d}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((g*x+f)^3*(a+b*arcsinh(c*x))/(c^2*d*x^2+d)^(1/2),x, algorithm="giac")

[Out]

integrate((g*x + f)^3*(b*arcsinh(c*x) + a)/sqrt(c^2*d*x^2 + d), x)

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maple [A]  time = 0.81, size = 751, normalized size = 1.75 \[ \frac {a \,g^{3} x^{2} \sqrt {c^{2} d \,x^{2}+d}}{3 c^{2} d}-\frac {2 a \,g^{3} \sqrt {c^{2} d \,x^{2}+d}}{3 d \,c^{4}}+\frac {3 a f \,g^{2} x \sqrt {c^{2} d \,x^{2}+d}}{2 c^{2} d}-\frac {3 a f \,g^{2} \ln \left (\frac {x \,c^{2} d}{\sqrt {c^{2} d}}+\sqrt {c^{2} d \,x^{2}+d}\right )}{2 c^{2} \sqrt {c^{2} d}}+\frac {3 a \,f^{2} g \sqrt {c^{2} d \,x^{2}+d}}{c^{2} d}+\frac {a \,f^{3} \ln \left (\frac {x \,c^{2} d}{\sqrt {c^{2} d}}+\sqrt {c^{2} d \,x^{2}+d}\right )}{\sqrt {c^{2} d}}-\frac {3 b \sqrt {d \left (c^{2} x^{2}+1\right )}\, f \arcsinh \left (c x \right )^{2} g^{2}}{4 \sqrt {c^{2} x^{2}+1}\, c^{3} d}+\frac {b \sqrt {d \left (c^{2} x^{2}+1\right )}\, g^{3} \arcsinh \left (c x \right ) x^{4}}{3 d \left (c^{2} x^{2}+1\right )}-\frac {b \sqrt {d \left (c^{2} x^{2}+1\right )}\, g^{3} x^{3}}{9 c d \sqrt {c^{2} x^{2}+1}}-\frac {b \sqrt {d \left (c^{2} x^{2}+1\right )}\, g^{3} \arcsinh \left (c x \right ) x^{2}}{3 c^{2} d \left (c^{2} x^{2}+1\right )}+\frac {2 b \sqrt {d \left (c^{2} x^{2}+1\right )}\, g^{3} x}{3 c^{3} d \sqrt {c^{2} x^{2}+1}}-\frac {3 b \sqrt {d \left (c^{2} x^{2}+1\right )}\, f \,g^{2}}{8 c^{3} d \sqrt {c^{2} x^{2}+1}}+\frac {3 b \sqrt {d \left (c^{2} x^{2}+1\right )}\, g \arcsinh \left (c x \right ) f^{2}}{c^{2} d \left (c^{2} x^{2}+1\right )}+\frac {3 b \sqrt {d \left (c^{2} x^{2}+1\right )}\, f \,g^{2} \arcsinh \left (c x \right ) x}{2 c^{2} d \left (c^{2} x^{2}+1\right )}+\frac {3 b \sqrt {d \left (c^{2} x^{2}+1\right )}\, g \arcsinh \left (c x \right ) x^{2} f^{2}}{d \left (c^{2} x^{2}+1\right )}-\frac {3 b \sqrt {d \left (c^{2} x^{2}+1\right )}\, g x \,f^{2}}{c d \sqrt {c^{2} x^{2}+1}}+\frac {3 b \sqrt {d \left (c^{2} x^{2}+1\right )}\, f \,g^{2} \arcsinh \left (c x \right ) x^{3}}{2 d \left (c^{2} x^{2}+1\right )}-\frac {3 b \sqrt {d \left (c^{2} x^{2}+1\right )}\, f \,g^{2} x^{2}}{4 c d \sqrt {c^{2} x^{2}+1}}+\frac {b \sqrt {d \left (c^{2} x^{2}+1\right )}\, f^{3} \arcsinh \left (c x \right )^{2}}{2 \sqrt {c^{2} x^{2}+1}\, c d}-\frac {2 b \sqrt {d \left (c^{2} x^{2}+1\right )}\, g^{3} \arcsinh \left (c x \right )}{3 c^{4} d \left (c^{2} x^{2}+1\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((g*x+f)^3*(a+b*arcsinh(c*x))/(c^2*d*x^2+d)^(1/2),x)

[Out]

1/3*a*g^3*x^2/c^2/d*(c^2*d*x^2+d)^(1/2)-2/3*a*g^3/d/c^4*(c^2*d*x^2+d)^(1/2)+3/2*a*f*g^2*x/c^2/d*(c^2*d*x^2+d)^
(1/2)-3/2*a*f*g^2/c^2*ln(x*c^2*d/(c^2*d)^(1/2)+(c^2*d*x^2+d)^(1/2))/(c^2*d)^(1/2)+3*a*f^2*g/c^2/d*(c^2*d*x^2+d
)^(1/2)+a*f^3*ln(x*c^2*d/(c^2*d)^(1/2)+(c^2*d*x^2+d)^(1/2))/(c^2*d)^(1/2)-3/4*b*(d*(c^2*x^2+1))^(1/2)*f*arcsin
h(c*x)^2/(c^2*x^2+1)^(1/2)/c^3/d*g^2+1/3*b*(d*(c^2*x^2+1))^(1/2)*g^3/d/(c^2*x^2+1)*arcsinh(c*x)*x^4-1/9*b*(d*(
c^2*x^2+1))^(1/2)*g^3/c/d/(c^2*x^2+1)^(1/2)*x^3-1/3*b*(d*(c^2*x^2+1))^(1/2)*g^3/c^2/d/(c^2*x^2+1)*arcsinh(c*x)
*x^2+2/3*b*(d*(c^2*x^2+1))^(1/2)*g^3/c^3/d/(c^2*x^2+1)^(1/2)*x-3/8*b*(d*(c^2*x^2+1))^(1/2)*f*g^2/c^3/d/(c^2*x^
2+1)^(1/2)+3*b*(d*(c^2*x^2+1))^(1/2)*g/c^2/d/(c^2*x^2+1)*arcsinh(c*x)*f^2+3/2*b*(d*(c^2*x^2+1))^(1/2)*f*g^2/c^
2/d/(c^2*x^2+1)*arcsinh(c*x)*x+3*b*(d*(c^2*x^2+1))^(1/2)*g/d/(c^2*x^2+1)*arcsinh(c*x)*x^2*f^2-3*b*(d*(c^2*x^2+
1))^(1/2)*g/c/d/(c^2*x^2+1)^(1/2)*x*f^2+3/2*b*(d*(c^2*x^2+1))^(1/2)*f*g^2/d/(c^2*x^2+1)*arcsinh(c*x)*x^3-3/4*b
*(d*(c^2*x^2+1))^(1/2)*f*g^2/c/d/(c^2*x^2+1)^(1/2)*x^2+1/2*b*(d*(c^2*x^2+1))^(1/2)*f^3*arcsinh(c*x)^2/(c^2*x^2
+1)^(1/2)/c/d-2/3*b*(d*(c^2*x^2+1))^(1/2)*g^3/c^4/d/(c^2*x^2+1)*arcsinh(c*x)

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maxima [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: RuntimeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((g*x+f)^3*(a+b*arcsinh(c*x))/(c^2*d*x^2+d)^(1/2),x, algorithm="maxima")

[Out]

Exception raised: RuntimeError >> ECL says: Error executing code in Maxima: expt: undefined: 0 to a negative e
xponent.

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (f+g\,x\right )}^3\,\left (a+b\,\mathrm {asinh}\left (c\,x\right )\right )}{\sqrt {d\,c^2\,x^2+d}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((f + g*x)^3*(a + b*asinh(c*x)))/(d + c^2*d*x^2)^(1/2),x)

[Out]

int(((f + g*x)^3*(a + b*asinh(c*x)))/(d + c^2*d*x^2)^(1/2), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (a + b \operatorname {asinh}{\left (c x \right )}\right ) \left (f + g x\right )^{3}}{\sqrt {d \left (c^{2} x^{2} + 1\right )}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((g*x+f)**3*(a+b*asinh(c*x))/(c**2*d*x**2+d)**(1/2),x)

[Out]

Integral((a + b*asinh(c*x))*(f + g*x)**3/sqrt(d*(c**2*x**2 + 1)), x)

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