Optimal. Leaf size=61 \[ \frac {2}{3} \left (a^2-b^2\right ) (a \sinh (x)+b \cosh (x))^3+\left (a^2-b^2\right )^2 (a \sinh (x)+b \cosh (x))+\frac {1}{5} (a \sinh (x)+b \cosh (x))^5 \]
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Rubi [A] time = 0.05, antiderivative size = 61, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.182, Rules used = {3072, 194} \[ \frac {2}{3} \left (a^2-b^2\right ) (a \sinh (x)+b \cosh (x))^3+\left (a^2-b^2\right )^2 (a \sinh (x)+b \cosh (x))+\frac {1}{5} (a \sinh (x)+b \cosh (x))^5 \]
Antiderivative was successfully verified.
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Rule 194
Rule 3072
Rubi steps
\begin {align*} \int (a \cosh (x)+b \sinh (x))^5 \, dx &=i \operatorname {Subst}\left (\int \left (a^2-b^2-x^2\right )^2 \, dx,x,-i b \cosh (x)-i a \sinh (x)\right )\\ &=i \operatorname {Subst}\left (\int \left (a^4 \left (1+\frac {-2 a^2 b^2+b^4}{a^4}\right )-2 a^2 \left (1-\frac {b^2}{a^2}\right ) x^2+x^4\right ) \, dx,x,-i b \cosh (x)-i a \sinh (x)\right )\\ &=\left (a^2-b^2\right )^2 (b \cosh (x)+a \sinh (x))+\frac {2}{3} \left (a^2-b^2\right ) (b \cosh (x)+a \sinh (x))^3+\frac {1}{5} (b \cosh (x)+a \sinh (x))^5\\ \end {align*}
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Mathematica [B] time = 0.23, size = 133, normalized size = 2.18 \[ \frac {1}{240} \left (150 a \left (a^2-b^2\right )^2 \sinh (x)+150 b \left (a^2-b^2\right )^2 \cosh (x)+25 a \left (a^4+2 a^2 b^2-3 b^4\right ) \sinh (3 x)+3 a \left (a^4+10 a^2 b^2+5 b^4\right ) \sinh (5 x)-25 b \left (-3 a^4+2 a^2 b^2+b^4\right ) \cosh (3 x)+3 b \left (5 a^4+10 a^2 b^2+b^4\right ) \cosh (5 x)\right ) \]
Antiderivative was successfully verified.
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fricas [B] time = 0.41, size = 298, normalized size = 4.89 \[ \frac {1}{80} \, {\left (5 \, a^{4} b + 10 \, a^{2} b^{3} + b^{5}\right )} \cosh \relax (x)^{5} + \frac {1}{16} \, {\left (5 \, a^{4} b + 10 \, a^{2} b^{3} + b^{5}\right )} \cosh \relax (x) \sinh \relax (x)^{4} + \frac {1}{80} \, {\left (a^{5} + 10 \, a^{3} b^{2} + 5 \, a b^{4}\right )} \sinh \relax (x)^{5} + \frac {5}{48} \, {\left (3 \, a^{4} b - 2 \, a^{2} b^{3} - b^{5}\right )} \cosh \relax (x)^{3} + \frac {1}{48} \, {\left (5 \, a^{5} + 10 \, a^{3} b^{2} - 15 \, a b^{4} + 6 \, {\left (a^{5} + 10 \, a^{3} b^{2} + 5 \, a b^{4}\right )} \cosh \relax (x)^{2}\right )} \sinh \relax (x)^{3} + \frac {1}{16} \, {\left (2 \, {\left (5 \, a^{4} b + 10 \, a^{2} b^{3} + b^{5}\right )} \cosh \relax (x)^{3} + 5 \, {\left (3 \, a^{4} b - 2 \, a^{2} b^{3} - b^{5}\right )} \cosh \relax (x)\right )} \sinh \relax (x)^{2} + \frac {5}{8} \, {\left (a^{4} b - 2 \, a^{2} b^{3} + b^{5}\right )} \cosh \relax (x) + \frac {1}{16} \, {\left (10 \, a^{5} - 20 \, a^{3} b^{2} + 10 \, a b^{4} + {\left (a^{5} + 10 \, a^{3} b^{2} + 5 \, a b^{4}\right )} \cosh \relax (x)^{4} + 5 \, {\left (a^{5} + 2 \, a^{3} b^{2} - 3 \, a b^{4}\right )} \cosh \relax (x)^{2}\right )} \sinh \relax (x) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 0.14, size = 344, normalized size = 5.64 \[ \frac {1}{160} \, a^{5} e^{\left (5 \, x\right )} + \frac {1}{32} \, a^{4} b e^{\left (5 \, x\right )} + \frac {1}{16} \, a^{3} b^{2} e^{\left (5 \, x\right )} + \frac {1}{16} \, a^{2} b^{3} e^{\left (5 \, x\right )} + \frac {1}{32} \, a b^{4} e^{\left (5 \, x\right )} + \frac {1}{160} \, b^{5} e^{\left (5 \, x\right )} + \frac {5}{96} \, a^{5} e^{\left (3 \, x\right )} + \frac {5}{32} \, a^{4} b e^{\left (3 \, x\right )} + \frac {5}{48} \, a^{3} b^{2} e^{\left (3 \, x\right )} - \frac {5}{48} \, a^{2} b^{3} e^{\left (3 \, x\right )} - \frac {5}{32} \, a b^{4} e^{\left (3 \, x\right )} - \frac {5}{96} \, b^{5} e^{\left (3 \, x\right )} + \frac {5}{16} \, a^{5} e^{x} + \frac {5}{16} \, a^{4} b e^{x} - \frac {5}{8} \, a^{3} b^{2} e^{x} - \frac {5}{8} \, a^{2} b^{3} e^{x} + \frac {5}{16} \, a b^{4} e^{x} + \frac {5}{16} \, b^{5} e^{x} - \frac {1}{480} \, {\left (150 \, a^{5} e^{\left (4 \, x\right )} - 150 \, a^{4} b e^{\left (4 \, x\right )} - 300 \, a^{3} b^{2} e^{\left (4 \, x\right )} + 300 \, a^{2} b^{3} e^{\left (4 \, x\right )} + 150 \, a b^{4} e^{\left (4 \, x\right )} - 150 \, b^{5} e^{\left (4 \, x\right )} + 25 \, a^{5} e^{\left (2 \, x\right )} - 75 \, a^{4} b e^{\left (2 \, x\right )} + 50 \, a^{3} b^{2} e^{\left (2 \, x\right )} + 50 \, a^{2} b^{3} e^{\left (2 \, x\right )} - 75 \, a b^{4} e^{\left (2 \, x\right )} + 25 \, b^{5} e^{\left (2 \, x\right )} + 3 \, a^{5} - 15 \, a^{4} b + 30 \, a^{3} b^{2} - 30 \, a^{2} b^{3} + 15 \, a b^{4} - 3 \, b^{5}\right )} e^{\left (-5 \, x\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.42, size = 114, normalized size = 1.87 \[ b^{5} \left (\frac {8}{15}+\frac {\left (\sinh ^{4}\relax (x )\right )}{5}-\frac {4 \left (\sinh ^{2}\relax (x )\right )}{15}\right ) \cosh \relax (x )+a \,b^{4} \left (\sinh ^{5}\relax (x )\right )+10 a^{2} b^{3} \left (\frac {\left (\sinh ^{2}\relax (x )\right ) \left (\cosh ^{3}\relax (x )\right )}{5}-\frac {2 \left (\cosh ^{3}\relax (x )\right )}{15}\right )+10 a^{3} b^{2} \left (\frac {\sinh \relax (x ) \left (\cosh ^{4}\relax (x )\right )}{5}-\frac {\left (\frac {2}{3}+\frac {\left (\cosh ^{2}\relax (x )\right )}{3}\right ) \sinh \relax (x )}{5}\right )+a^{4} b \left (\cosh ^{5}\relax (x )\right )+a^{5} \left (\frac {8}{15}+\frac {\left (\cosh ^{4}\relax (x )\right )}{5}+\frac {4 \left (\cosh ^{2}\relax (x )\right )}{15}\right ) \sinh \relax (x ) \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.38, size = 191, normalized size = 3.13 \[ a^{4} b \cosh \relax (x)^{5} + a b^{4} \sinh \relax (x)^{5} + \frac {1}{48} \, {\left ({\left (5 \, e^{\left (-2 \, x\right )} - 30 \, e^{\left (-4 \, x\right )} + 3\right )} e^{\left (5 \, x\right )} + 30 \, e^{\left (-x\right )} - 5 \, e^{\left (-3 \, x\right )} - 3 \, e^{\left (-5 \, x\right )}\right )} a^{3} b^{2} - \frac {1}{48} \, {\left ({\left (5 \, e^{\left (-2 \, x\right )} + 30 \, e^{\left (-4 \, x\right )} - 3\right )} e^{\left (5 \, x\right )} + 30 \, e^{\left (-x\right )} + 5 \, e^{\left (-3 \, x\right )} - 3 \, e^{\left (-5 \, x\right )}\right )} a^{2} b^{3} + \frac {1}{480} \, a^{5} {\left (3 \, e^{\left (5 \, x\right )} + 25 \, e^{\left (3 \, x\right )} - 150 \, e^{\left (-x\right )} - 25 \, e^{\left (-3 \, x\right )} - 3 \, e^{\left (-5 \, x\right )} + 150 \, e^{x}\right )} + \frac {1}{480} \, b^{5} {\left (3 \, e^{\left (5 \, x\right )} - 25 \, e^{\left (3 \, x\right )} + 150 \, e^{\left (-x\right )} - 25 \, e^{\left (-3 \, x\right )} + 3 \, e^{\left (-5 \, x\right )} + 150 \, e^{x}\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.12, size = 117, normalized size = 1.92 \[ {\mathrm {cosh}\relax (x)}^5\,\left (a^4\,b-\frac {4\,a^2\,b^3}{3}+\frac {8\,b^5}{15}\right )+{\mathrm {sinh}\relax (x)}^5\,\left (\frac {8\,a^5}{15}-\frac {4\,a^3\,b^2}{3}+a\,b^4\right )-{\mathrm {cosh}\relax (x)}^2\,{\mathrm {sinh}\relax (x)}^3\,\left (\frac {4\,a^5}{3}-\frac {10\,a^3\,b^2}{3}\right )+a^5\,{\mathrm {cosh}\relax (x)}^4\,\mathrm {sinh}\relax (x)-{\mathrm {cosh}\relax (x)}^3\,{\mathrm {sinh}\relax (x)}^2\,\left (\frac {4\,b^5}{3}-\frac {10\,a^2\,b^3}{3}\right )+b^5\,\mathrm {cosh}\relax (x)\,{\mathrm {sinh}\relax (x)}^4 \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [B] time = 1.18, size = 172, normalized size = 2.82 \[ \frac {8 a^{5} \sinh ^{5}{\relax (x )}}{15} - \frac {4 a^{5} \sinh ^{3}{\relax (x )} \cosh ^{2}{\relax (x )}}{3} + a^{5} \sinh {\relax (x )} \cosh ^{4}{\relax (x )} + a^{4} b \cosh ^{5}{\relax (x )} - \frac {4 a^{3} b^{2} \sinh ^{5}{\relax (x )}}{3} + \frac {10 a^{3} b^{2} \sinh ^{3}{\relax (x )} \cosh ^{2}{\relax (x )}}{3} + \frac {10 a^{2} b^{3} \sinh ^{2}{\relax (x )} \cosh ^{3}{\relax (x )}}{3} - \frac {4 a^{2} b^{3} \cosh ^{5}{\relax (x )}}{3} + a b^{4} \sinh ^{5}{\relax (x )} + b^{5} \sinh ^{4}{\relax (x )} \cosh {\relax (x )} - \frac {4 b^{5} \sinh ^{2}{\relax (x )} \cosh ^{3}{\relax (x )}}{3} + \frac {8 b^{5} \cosh ^{5}{\relax (x )}}{15} \]
Verification of antiderivative is not currently implemented for this CAS.
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