3.134 \(\int \frac {x^3}{\sqrt {\text {csch}(2 \log (c x))}} \, dx\)

Optimal. Leaf size=119 \[ -\frac {2}{5 c^4 \sqrt {\text {csch}(2 \log (c x))}}+\frac {2 F\left (\left .\csc ^{-1}(c x)\right |-1\right )}{5 c^5 x \sqrt {1-\frac {1}{c^4 x^4}} \sqrt {\text {csch}(2 \log (c x))}}-\frac {2 E\left (\left .\csc ^{-1}(c x)\right |-1\right )}{5 c^5 x \sqrt {1-\frac {1}{c^4 x^4}} \sqrt {\text {csch}(2 \log (c x))}}+\frac {x^4}{5 \sqrt {\text {csch}(2 \log (c x))}} \]

[Out]

-2/5/c^4/csch(2*ln(c*x))^(1/2)+1/5*x^4/csch(2*ln(c*x))^(1/2)-2/5*EllipticE(1/c/x,I)/c^5/x/(1-1/c^4/x^4)^(1/2)/
csch(2*ln(c*x))^(1/2)+2/5*EllipticF(1/c/x,I)/c^5/x/(1-1/c^4/x^4)^(1/2)/csch(2*ln(c*x))^(1/2)

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Rubi [A]  time = 0.09, antiderivative size = 119, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 9, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.600, Rules used = {5552, 5550, 335, 277, 325, 307, 221, 1181, 424} \[ \frac {2 F\left (\left .\csc ^{-1}(c x)\right |-1\right )}{5 c^5 x \sqrt {1-\frac {1}{c^4 x^4}} \sqrt {\text {csch}(2 \log (c x))}}-\frac {2 E\left (\left .\csc ^{-1}(c x)\right |-1\right )}{5 c^5 x \sqrt {1-\frac {1}{c^4 x^4}} \sqrt {\text {csch}(2 \log (c x))}}-\frac {2}{5 c^4 \sqrt {\text {csch}(2 \log (c x))}}+\frac {x^4}{5 \sqrt {\text {csch}(2 \log (c x))}} \]

Antiderivative was successfully verified.

[In]

Int[x^3/Sqrt[Csch[2*Log[c*x]]],x]

[Out]

-2/(5*c^4*Sqrt[Csch[2*Log[c*x]]]) + x^4/(5*Sqrt[Csch[2*Log[c*x]]]) - (2*EllipticE[ArcCsc[c*x], -1])/(5*c^5*Sqr
t[1 - 1/(c^4*x^4)]*x*Sqrt[Csch[2*Log[c*x]]]) + (2*EllipticF[ArcCsc[c*x], -1])/(5*c^5*Sqrt[1 - 1/(c^4*x^4)]*x*S
qrt[Csch[2*Log[c*x]]])

Rule 221

Int[1/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> Simp[EllipticF[ArcSin[(Rt[-b, 4]*x)/Rt[a, 4]], -1]/(Rt[a, 4]*Rt[
-b, 4]), x] /; FreeQ[{a, b}, x] && NegQ[b/a] && GtQ[a, 0]

Rule 277

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[((c*x)^(m + 1)*(a + b*x^n)^p)/(c*(m +
1)), x] - Dist[(b*n*p)/(c^n*(m + 1)), Int[(c*x)^(m + n)*(a + b*x^n)^(p - 1), x], x] /; FreeQ[{a, b, c}, x] &&
IGtQ[n, 0] && GtQ[p, 0] && LtQ[m, -1] &&  !ILtQ[(m + n*p + n + 1)/n, 0] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 307

Int[(x_)^2/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> With[{q = Rt[-(b/a), 2]}, -Dist[q^(-1), Int[1/Sqrt[a + b*x^
4], x], x] + Dist[1/q, Int[(1 + q*x^2)/Sqrt[a + b*x^4], x], x]] /; FreeQ[{a, b}, x] && NegQ[b/a]

Rule 325

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[((c*x)^(m + 1)*(a + b*x^n)^(p + 1))/(a*
c*(m + 1)), x] - Dist[(b*(m + n*(p + 1) + 1))/(a*c^n*(m + 1)), Int[(c*x)^(m + n)*(a + b*x^n)^p, x], x] /; Free
Q[{a, b, c, p}, x] && IGtQ[n, 0] && LtQ[m, -1] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 335

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> -Subst[Int[(a + b/x^n)^p/x^(m + 2), x], x, 1/x] /;
FreeQ[{a, b, p}, x] && ILtQ[n, 0] && IntegerQ[m]

Rule 424

Int[Sqrt[(a_) + (b_.)*(x_)^2]/Sqrt[(c_) + (d_.)*(x_)^2], x_Symbol] :> Simp[(Sqrt[a]*EllipticE[ArcSin[Rt[-(d/c)
, 2]*x], (b*c)/(a*d)])/(Sqrt[c]*Rt[-(d/c), 2]), x] /; FreeQ[{a, b, c, d}, x] && NegQ[d/c] && GtQ[c, 0] && GtQ[
a, 0]

Rule 1181

Int[((d_) + (e_.)*(x_)^2)/Sqrt[(a_) + (c_.)*(x_)^4], x_Symbol] :> With[{q = Rt[-(a*c), 2]}, Dist[Sqrt[-c], Int
[(d + e*x^2)/(Sqrt[q + c*x^2]*Sqrt[q - c*x^2]), x], x]] /; FreeQ[{a, c, d, e}, x] && GtQ[a, 0] && LtQ[c, 0]

Rule 5550

Int[Csch[((a_.) + Log[x_]*(b_.))*(d_.)]^(p_.)*((e_.)*(x_))^(m_.), x_Symbol] :> Dist[(Csch[d*(a + b*Log[x])]^p*
(1 - 1/(E^(2*a*d)*x^(2*b*d)))^p)/x^(-(b*d*p)), Int[(e*x)^m/(x^(b*d*p)*(1 - 1/(E^(2*a*d)*x^(2*b*d)))^p), x], x]
/; FreeQ[{a, b, d, e, m, p}, x] &&  !IntegerQ[p]

Rule 5552

Int[Csch[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))*(d_.)]^(p_.)*((e_.)*(x_))^(m_.), x_Symbol] :> Dist[(e*x)^(m + 1
)/(e*n*(c*x^n)^((m + 1)/n)), Subst[Int[x^((m + 1)/n - 1)*Csch[d*(a + b*Log[x])]^p, x], x, c*x^n], x] /; FreeQ[
{a, b, c, d, e, m, n, p}, x] && (NeQ[c, 1] || NeQ[n, 1])

Rubi steps

\begin {align*} \int \frac {x^3}{\sqrt {\text {csch}(2 \log (c x))}} \, dx &=\frac {\operatorname {Subst}\left (\int \frac {x^3}{\sqrt {\text {csch}(2 \log (x))}} \, dx,x,c x\right )}{c^4}\\ &=\frac {\operatorname {Subst}\left (\int \sqrt {1-\frac {1}{x^4}} x^4 \, dx,x,c x\right )}{c^5 \sqrt {1-\frac {1}{c^4 x^4}} x \sqrt {\text {csch}(2 \log (c x))}}\\ &=-\frac {\operatorname {Subst}\left (\int \frac {\sqrt {1-x^4}}{x^6} \, dx,x,\frac {1}{c x}\right )}{c^5 \sqrt {1-\frac {1}{c^4 x^4}} x \sqrt {\text {csch}(2 \log (c x))}}\\ &=\frac {x^4}{5 \sqrt {\text {csch}(2 \log (c x))}}+\frac {2 \operatorname {Subst}\left (\int \frac {1}{x^2 \sqrt {1-x^4}} \, dx,x,\frac {1}{c x}\right )}{5 c^5 \sqrt {1-\frac {1}{c^4 x^4}} x \sqrt {\text {csch}(2 \log (c x))}}\\ &=-\frac {2}{5 c^4 \sqrt {\text {csch}(2 \log (c x))}}+\frac {x^4}{5 \sqrt {\text {csch}(2 \log (c x))}}-\frac {2 \operatorname {Subst}\left (\int \frac {x^2}{\sqrt {1-x^4}} \, dx,x,\frac {1}{c x}\right )}{5 c^5 \sqrt {1-\frac {1}{c^4 x^4}} x \sqrt {\text {csch}(2 \log (c x))}}\\ &=-\frac {2}{5 c^4 \sqrt {\text {csch}(2 \log (c x))}}+\frac {x^4}{5 \sqrt {\text {csch}(2 \log (c x))}}+\frac {2 \operatorname {Subst}\left (\int \frac {1}{\sqrt {1-x^4}} \, dx,x,\frac {1}{c x}\right )}{5 c^5 \sqrt {1-\frac {1}{c^4 x^4}} x \sqrt {\text {csch}(2 \log (c x))}}-\frac {2 \operatorname {Subst}\left (\int \frac {1+x^2}{\sqrt {1-x^4}} \, dx,x,\frac {1}{c x}\right )}{5 c^5 \sqrt {1-\frac {1}{c^4 x^4}} x \sqrt {\text {csch}(2 \log (c x))}}\\ &=-\frac {2}{5 c^4 \sqrt {\text {csch}(2 \log (c x))}}+\frac {x^4}{5 \sqrt {\text {csch}(2 \log (c x))}}+\frac {2 F\left (\left .\csc ^{-1}(c x)\right |-1\right )}{5 c^5 \sqrt {1-\frac {1}{c^4 x^4}} x \sqrt {\text {csch}(2 \log (c x))}}-\frac {2 \operatorname {Subst}\left (\int \frac {\sqrt {1+x^2}}{\sqrt {1-x^2}} \, dx,x,\frac {1}{c x}\right )}{5 c^5 \sqrt {1-\frac {1}{c^4 x^4}} x \sqrt {\text {csch}(2 \log (c x))}}\\ &=-\frac {2}{5 c^4 \sqrt {\text {csch}(2 \log (c x))}}+\frac {x^4}{5 \sqrt {\text {csch}(2 \log (c x))}}-\frac {2 E\left (\left .\csc ^{-1}(c x)\right |-1\right )}{5 c^5 \sqrt {1-\frac {1}{c^4 x^4}} x \sqrt {\text {csch}(2 \log (c x))}}+\frac {2 F\left (\left .\csc ^{-1}(c x)\right |-1\right )}{5 c^5 \sqrt {1-\frac {1}{c^4 x^4}} x \sqrt {\text {csch}(2 \log (c x))}}\\ \end {align*}

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Mathematica [C]  time = 0.12, size = 60, normalized size = 0.50 \[ \frac {x^4 \, _2F_1\left (-\frac {1}{2},\frac {3}{4};\frac {7}{4};c^4 x^4\right )}{3 \sqrt {2-2 c^4 x^4} \sqrt {\frac {c^2 x^2}{c^4 x^4-1}}} \]

Antiderivative was successfully verified.

[In]

Integrate[x^3/Sqrt[Csch[2*Log[c*x]]],x]

[Out]

(x^4*Hypergeometric2F1[-1/2, 3/4, 7/4, c^4*x^4])/(3*Sqrt[2 - 2*c^4*x^4]*Sqrt[(c^2*x^2)/(-1 + c^4*x^4)])

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fricas [F]  time = 1.99, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {x^{3}}{\sqrt {\operatorname {csch}\left (2 \, \log \left (c x\right )\right )}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3/csch(2*log(c*x))^(1/2),x, algorithm="fricas")

[Out]

integral(x^3/sqrt(csch(2*log(c*x))), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x^{3}}{\sqrt {\operatorname {csch}\left (2 \, \log \left (c x\right )\right )}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3/csch(2*log(c*x))^(1/2),x, algorithm="giac")

[Out]

integrate(x^3/sqrt(csch(2*log(c*x))), x)

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maple [A]  time = 0.16, size = 127, normalized size = 1.07 \[ \frac {x^{4} \sqrt {2}}{10 \sqrt {\frac {c^{2} x^{2}}{c^{4} x^{4}-1}}}-\frac {\sqrt {c^{2} x^{2}+1}\, \sqrt {-c^{2} x^{2}+1}\, \left (\EllipticF \left (x \sqrt {-c^{2}}, i\right )-\EllipticE \left (x \sqrt {-c^{2}}, i\right )\right ) \sqrt {2}\, x}{5 \sqrt {-c^{2}}\, \left (c^{4} x^{4}-1\right ) c^{2} \sqrt {\frac {c^{2} x^{2}}{c^{4} x^{4}-1}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3/csch(2*ln(c*x))^(1/2),x)

[Out]

1/10*x^4*2^(1/2)/(c^2*x^2/(c^4*x^4-1))^(1/2)-1/5/(-c^2)^(1/2)*(c^2*x^2+1)^(1/2)*(-c^2*x^2+1)^(1/2)/(c^4*x^4-1)
/c^2*(EllipticF(x*(-c^2)^(1/2),I)-EllipticE(x*(-c^2)^(1/2),I))*2^(1/2)*x/(c^2*x^2/(c^4*x^4-1))^(1/2)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x^{3}}{\sqrt {\operatorname {csch}\left (2 \, \log \left (c x\right )\right )}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3/csch(2*log(c*x))^(1/2),x, algorithm="maxima")

[Out]

integrate(x^3/sqrt(csch(2*log(c*x))), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {x^3}{\sqrt {\frac {1}{\mathrm {sinh}\left (2\,\ln \left (c\,x\right )\right )}}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3/(1/sinh(2*log(c*x)))^(1/2),x)

[Out]

int(x^3/(1/sinh(2*log(c*x)))^(1/2), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x^{3}}{\sqrt {\operatorname {csch}{\left (2 \log {\left (c x \right )} \right )}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**3/csch(2*ln(c*x))**(1/2),x)

[Out]

Integral(x**3/sqrt(csch(2*log(c*x))), x)

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