Optimal. Leaf size=94 \[ -\frac {(3 A-5 B) \tan ^{-1}\left (\frac {\sqrt {a} \sinh (x)}{\sqrt {2} \sqrt {a-a \cosh (x)}}\right )}{16 \sqrt {2} a^{5/2}}-\frac {(3 A-5 B) \sinh (x)}{16 a (a-a \cosh (x))^{3/2}}-\frac {(A+B) \sinh (x)}{4 (a-a \cosh (x))^{5/2}} \]
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Rubi [A] time = 0.10, antiderivative size = 94, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.222, Rules used = {2750, 2650, 2649, 206} \[ -\frac {(3 A-5 B) \tan ^{-1}\left (\frac {\sqrt {a} \sinh (x)}{\sqrt {2} \sqrt {a-a \cosh (x)}}\right )}{16 \sqrt {2} a^{5/2}}-\frac {(3 A-5 B) \sinh (x)}{16 a (a-a \cosh (x))^{3/2}}-\frac {(A+B) \sinh (x)}{4 (a-a \cosh (x))^{5/2}} \]
Antiderivative was successfully verified.
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Rule 206
Rule 2649
Rule 2650
Rule 2750
Rubi steps
\begin {align*} \int \frac {A+B \cosh (x)}{(a-a \cosh (x))^{5/2}} \, dx &=-\frac {(A+B) \sinh (x)}{4 (a-a \cosh (x))^{5/2}}+\frac {(3 A-5 B) \int \frac {1}{(a-a \cosh (x))^{3/2}} \, dx}{8 a}\\ &=-\frac {(A+B) \sinh (x)}{4 (a-a \cosh (x))^{5/2}}-\frac {(3 A-5 B) \sinh (x)}{16 a (a-a \cosh (x))^{3/2}}+\frac {(3 A-5 B) \int \frac {1}{\sqrt {a-a \cosh (x)}} \, dx}{32 a^2}\\ &=-\frac {(A+B) \sinh (x)}{4 (a-a \cosh (x))^{5/2}}-\frac {(3 A-5 B) \sinh (x)}{16 a (a-a \cosh (x))^{3/2}}+\frac {(i (3 A-5 B)) \operatorname {Subst}\left (\int \frac {1}{2 a-x^2} \, dx,x,\frac {i a \sinh (x)}{\sqrt {a-a \cosh (x)}}\right )}{16 a^2}\\ &=-\frac {(3 A-5 B) \tan ^{-1}\left (\frac {\sqrt {a} \sinh (x)}{\sqrt {2} \sqrt {a-a \cosh (x)}}\right )}{16 \sqrt {2} a^{5/2}}-\frac {(A+B) \sinh (x)}{4 (a-a \cosh (x))^{5/2}}-\frac {(3 A-5 B) \sinh (x)}{16 a (a-a \cosh (x))^{3/2}}\\ \end {align*}
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Mathematica [A] time = 0.39, size = 108, normalized size = 1.15 \[ \frac {\sinh ^5\left (\frac {x}{2}\right ) \left (-\left ((A+B) \text {csch}^4\left (\frac {x}{4}\right )\right )+2 (3 A-5 B) \text {csch}^2\left (\frac {x}{4}\right )+(A+B) \text {sech}^4\left (\frac {x}{4}\right )+2 (3 A-5 B) \text {sech}^2\left (\frac {x}{4}\right )+8 (3 A-5 B) \log \left (\tanh \left (\frac {x}{4}\right )\right )\right )}{32 a^2 (\cosh (x)-1)^2 \sqrt {a-a \cosh (x)}} \]
Antiderivative was successfully verified.
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fricas [B] time = 1.12, size = 548, normalized size = 5.83 \[ \frac {\sqrt {2} {\left ({\left (3 \, A - 5 \, B\right )} \cosh \relax (x)^{4} + {\left (3 \, A - 5 \, B\right )} \sinh \relax (x)^{4} - 4 \, {\left (3 \, A - 5 \, B\right )} \cosh \relax (x)^{3} + 4 \, {\left ({\left (3 \, A - 5 \, B\right )} \cosh \relax (x) - 3 \, A + 5 \, B\right )} \sinh \relax (x)^{3} + 6 \, {\left (3 \, A - 5 \, B\right )} \cosh \relax (x)^{2} + 6 \, {\left ({\left (3 \, A - 5 \, B\right )} \cosh \relax (x)^{2} - 2 \, {\left (3 \, A - 5 \, B\right )} \cosh \relax (x) + 3 \, A - 5 \, B\right )} \sinh \relax (x)^{2} - 4 \, {\left (3 \, A - 5 \, B\right )} \cosh \relax (x) + 4 \, {\left ({\left (3 \, A - 5 \, B\right )} \cosh \relax (x)^{3} - 3 \, {\left (3 \, A - 5 \, B\right )} \cosh \relax (x)^{2} + 3 \, {\left (3 \, A - 5 \, B\right )} \cosh \relax (x) - 3 \, A + 5 \, B\right )} \sinh \relax (x) + 3 \, A - 5 \, B\right )} \sqrt {-a} \log \left (\frac {2 \, \sqrt {2} \sqrt {\frac {1}{2}} \sqrt {-a} \sqrt {-\frac {a}{\cosh \relax (x) + \sinh \relax (x)}} {\left (\cosh \relax (x) + \sinh \relax (x)\right )} - a \cosh \relax (x) - a \sinh \relax (x) - a}{\cosh \relax (x) + \sinh \relax (x) - 1}\right ) - 4 \, \sqrt {\frac {1}{2}} {\left ({\left (3 \, A - 5 \, B\right )} \cosh \relax (x)^{4} + {\left (3 \, A - 5 \, B\right )} \sinh \relax (x)^{4} - {\left (11 \, A + 3 \, B\right )} \cosh \relax (x)^{3} + {\left (4 \, {\left (3 \, A - 5 \, B\right )} \cosh \relax (x) - 11 \, A - 3 \, B\right )} \sinh \relax (x)^{3} - {\left (11 \, A + 3 \, B\right )} \cosh \relax (x)^{2} + {\left (6 \, {\left (3 \, A - 5 \, B\right )} \cosh \relax (x)^{2} - 3 \, {\left (11 \, A + 3 \, B\right )} \cosh \relax (x) - 11 \, A - 3 \, B\right )} \sinh \relax (x)^{2} + {\left (3 \, A - 5 \, B\right )} \cosh \relax (x) + {\left (4 \, {\left (3 \, A - 5 \, B\right )} \cosh \relax (x)^{3} - 3 \, {\left (11 \, A + 3 \, B\right )} \cosh \relax (x)^{2} - 2 \, {\left (11 \, A + 3 \, B\right )} \cosh \relax (x) + 3 \, A - 5 \, B\right )} \sinh \relax (x)\right )} \sqrt {-\frac {a}{\cosh \relax (x) + \sinh \relax (x)}}}{32 \, {\left (a^{3} \cosh \relax (x)^{4} + a^{3} \sinh \relax (x)^{4} - 4 \, a^{3} \cosh \relax (x)^{3} + 6 \, a^{3} \cosh \relax (x)^{2} - 4 \, a^{3} \cosh \relax (x) + 4 \, {\left (a^{3} \cosh \relax (x) - a^{3}\right )} \sinh \relax (x)^{3} + a^{3} + 6 \, {\left (a^{3} \cosh \relax (x)^{2} - 2 \, a^{3} \cosh \relax (x) + a^{3}\right )} \sinh \relax (x)^{2} + 4 \, {\left (a^{3} \cosh \relax (x)^{3} - 3 \, a^{3} \cosh \relax (x)^{2} + 3 \, a^{3} \cosh \relax (x) - a^{3}\right )} \sinh \relax (x)\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 0.24, size = 189, normalized size = 2.01 \[ -\frac {\sqrt {2} {\left (3 \, A - 5 \, B\right )} \arctan \left (\frac {\sqrt {-a e^{x}}}{\sqrt {a}}\right )}{16 \, a^{\frac {5}{2}} \mathrm {sgn}\left (-e^{x} + 1\right )} + \frac {\sqrt {2} {\left (3 \, \sqrt {-a e^{x}} A a^{3} e^{\left (3 \, x\right )} - 5 \, \sqrt {-a e^{x}} B a^{3} e^{\left (3 \, x\right )} - 11 \, \sqrt {-a e^{x}} A a^{3} e^{\left (2 \, x\right )} - 3 \, \sqrt {-a e^{x}} B a^{3} e^{\left (2 \, x\right )} - 11 \, \sqrt {-a e^{x}} A a^{3} e^{x} - 3 \, \sqrt {-a e^{x}} B a^{3} e^{x} + 3 \, \sqrt {-a e^{x}} A a^{3} - 5 \, \sqrt {-a e^{x}} B a^{3}\right )}}{16 \, {\left (a e^{x} - a\right )}^{4} a^{2} \mathrm {sgn}\left (-e^{x} + 1\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.35, size = 118, normalized size = 1.26 \[ \frac {\left (6 A -10 B \right ) \cosh \left (\frac {x}{2}\right ) \left (\sinh ^{2}\left (\frac {x}{2}\right )\right )+\left (-4 A -4 B \right ) \cosh \left (\frac {x}{2}\right )+\left (3 \ln \left (-1+\cosh \left (\frac {x}{2}\right )\right ) A -3 \ln \left (\cosh \left (\frac {x}{2}\right )+1\right ) A -5 B \ln \left (-1+\cosh \left (\frac {x}{2}\right )\right )+5 B \ln \left (\cosh \left (\frac {x}{2}\right )+1\right )\right ) \left (\sinh ^{4}\left (\frac {x}{2}\right )\right )}{32 a^{2} \left (\cosh \left (\frac {x}{2}\right )+1\right ) \left (-1+\cosh \left (\frac {x}{2}\right )\right ) \sinh \left (\frac {x}{2}\right ) \sqrt {-2 a \left (\sinh ^{2}\left (\frac {x}{2}\right )\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {B \cosh \relax (x) + A}{{\left (-a \cosh \relax (x) + a\right )}^{\frac {5}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {A+B\,\mathrm {cosh}\relax (x)}{{\left (a-a\,\mathrm {cosh}\relax (x)\right )}^{5/2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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