3.105 \(\int \frac {A+B \cosh (x)}{(a-a \cosh (x))^{3/2}} \, dx\)

Optimal. Leaf size=65 \[ -\frac {(A-3 B) \tan ^{-1}\left (\frac {\sqrt {a} \sinh (x)}{\sqrt {2} \sqrt {a-a \cosh (x)}}\right )}{2 \sqrt {2} a^{3/2}}-\frac {(A+B) \sinh (x)}{2 (a-a \cosh (x))^{3/2}} \]

[Out]

-1/2*(A+B)*sinh(x)/(a-a*cosh(x))^(3/2)-1/4*(A-3*B)*arctan(1/2*sinh(x)*a^(1/2)*2^(1/2)/(a-a*cosh(x))^(1/2))/a^(
3/2)*2^(1/2)

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Rubi [A]  time = 0.07, antiderivative size = 65, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {2750, 2649, 206} \[ -\frac {(A-3 B) \tan ^{-1}\left (\frac {\sqrt {a} \sinh (x)}{\sqrt {2} \sqrt {a-a \cosh (x)}}\right )}{2 \sqrt {2} a^{3/2}}-\frac {(A+B) \sinh (x)}{2 (a-a \cosh (x))^{3/2}} \]

Antiderivative was successfully verified.

[In]

Int[(A + B*Cosh[x])/(a - a*Cosh[x])^(3/2),x]

[Out]

-((A - 3*B)*ArcTan[(Sqrt[a]*Sinh[x])/(Sqrt[2]*Sqrt[a - a*Cosh[x]])])/(2*Sqrt[2]*a^(3/2)) - ((A + B)*Sinh[x])/(
2*(a - a*Cosh[x])^(3/2))

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 2649

Int[1/Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Dist[-2/d, Subst[Int[1/(2*a - x^2), x], x, (b*C
os[c + d*x])/Sqrt[a + b*Sin[c + d*x]]], x] /; FreeQ[{a, b, c, d}, x] && EqQ[a^2 - b^2, 0]

Rule 2750

Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[((b
*c - a*d)*Cos[e + f*x]*(a + b*Sin[e + f*x])^m)/(a*f*(2*m + 1)), x] + Dist[(a*d*m + b*c*(m + 1))/(a*b*(2*m + 1)
), Int[(a + b*Sin[e + f*x])^(m + 1), x], x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 -
b^2, 0] && LtQ[m, -2^(-1)]

Rubi steps

\begin {align*} \int \frac {A+B \cosh (x)}{(a-a \cosh (x))^{3/2}} \, dx &=-\frac {(A+B) \sinh (x)}{2 (a-a \cosh (x))^{3/2}}+\frac {(A-3 B) \int \frac {1}{\sqrt {a-a \cosh (x)}} \, dx}{4 a}\\ &=-\frac {(A+B) \sinh (x)}{2 (a-a \cosh (x))^{3/2}}+\frac {(i (A-3 B)) \operatorname {Subst}\left (\int \frac {1}{2 a-x^2} \, dx,x,\frac {i a \sinh (x)}{\sqrt {a-a \cosh (x)}}\right )}{2 a}\\ &=-\frac {(A-3 B) \tan ^{-1}\left (\frac {\sqrt {a} \sinh (x)}{\sqrt {2} \sqrt {a-a \cosh (x)}}\right )}{2 \sqrt {2} a^{3/2}}-\frac {(A+B) \sinh (x)}{2 (a-a \cosh (x))^{3/2}}\\ \end {align*}

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Mathematica [A]  time = 0.16, size = 71, normalized size = 1.09 \[ \frac {\sinh ^3\left (\frac {x}{2}\right ) \left ((A+B) \text {csch}^2\left (\frac {x}{4}\right )+(A+B) \text {sech}^2\left (\frac {x}{4}\right )+4 (A-3 B) \log \left (\tanh \left (\frac {x}{4}\right )\right )\right )}{4 a (\cosh (x)-1) \sqrt {a-a \cosh (x)}} \]

Antiderivative was successfully verified.

[In]

Integrate[(A + B*Cosh[x])/(a - a*Cosh[x])^(3/2),x]

[Out]

(((A + B)*Csch[x/4]^2 + 4*(A - 3*B)*Log[Tanh[x/4]] + (A + B)*Sech[x/4]^2)*Sinh[x/2]^3)/(4*a*(-1 + Cosh[x])*Sqr
t[a - a*Cosh[x]])

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fricas [B]  time = 0.90, size = 217, normalized size = 3.34 \[ \frac {\sqrt {2} {\left ({\left (A - 3 \, B\right )} \cosh \relax (x)^{2} + {\left (A - 3 \, B\right )} \sinh \relax (x)^{2} - 2 \, {\left (A - 3 \, B\right )} \cosh \relax (x) + 2 \, {\left ({\left (A - 3 \, B\right )} \cosh \relax (x) - A + 3 \, B\right )} \sinh \relax (x) + A - 3 \, B\right )} \sqrt {-a} \log \left (\frac {2 \, \sqrt {2} \sqrt {\frac {1}{2}} \sqrt {-a} \sqrt {-\frac {a}{\cosh \relax (x) + \sinh \relax (x)}} {\left (\cosh \relax (x) + \sinh \relax (x)\right )} - a \cosh \relax (x) - a \sinh \relax (x) - a}{\cosh \relax (x) + \sinh \relax (x) - 1}\right ) - 4 \, \sqrt {\frac {1}{2}} {\left ({\left (A + B\right )} \cosh \relax (x)^{2} + {\left (A + B\right )} \sinh \relax (x)^{2} + {\left (A + B\right )} \cosh \relax (x) + {\left (2 \, {\left (A + B\right )} \cosh \relax (x) + A + B\right )} \sinh \relax (x)\right )} \sqrt {-\frac {a}{\cosh \relax (x) + \sinh \relax (x)}}}{4 \, {\left (a^{2} \cosh \relax (x)^{2} + a^{2} \sinh \relax (x)^{2} - 2 \, a^{2} \cosh \relax (x) + a^{2} + 2 \, {\left (a^{2} \cosh \relax (x) - a^{2}\right )} \sinh \relax (x)\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((A+B*cosh(x))/(a-a*cosh(x))^(3/2),x, algorithm="fricas")

[Out]

1/4*(sqrt(2)*((A - 3*B)*cosh(x)^2 + (A - 3*B)*sinh(x)^2 - 2*(A - 3*B)*cosh(x) + 2*((A - 3*B)*cosh(x) - A + 3*B
)*sinh(x) + A - 3*B)*sqrt(-a)*log((2*sqrt(2)*sqrt(1/2)*sqrt(-a)*sqrt(-a/(cosh(x) + sinh(x)))*(cosh(x) + sinh(x
)) - a*cosh(x) - a*sinh(x) - a)/(cosh(x) + sinh(x) - 1)) - 4*sqrt(1/2)*((A + B)*cosh(x)^2 + (A + B)*sinh(x)^2
+ (A + B)*cosh(x) + (2*(A + B)*cosh(x) + A + B)*sinh(x))*sqrt(-a/(cosh(x) + sinh(x))))/(a^2*cosh(x)^2 + a^2*si
nh(x)^2 - 2*a^2*cosh(x) + a^2 + 2*(a^2*cosh(x) - a^2)*sinh(x))

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giac [B]  time = 0.19, size = 111, normalized size = 1.71 \[ -\frac {{\left (\sqrt {2} A - 3 \, \sqrt {2} B\right )} \arctan \left (\frac {\sqrt {-a e^{x}}}{\sqrt {a}}\right )}{2 \, a^{\frac {3}{2}} \mathrm {sgn}\left (-e^{x} + 1\right )} + \frac {\sqrt {2} {\left (\sqrt {-a e^{x}} A a e^{x} + \sqrt {-a e^{x}} B a e^{x} + \sqrt {-a e^{x}} A a + \sqrt {-a e^{x}} B a\right )}}{2 \, {\left (a e^{x} - a\right )}^{2} a \mathrm {sgn}\left (-e^{x} + 1\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((A+B*cosh(x))/(a-a*cosh(x))^(3/2),x, algorithm="giac")

[Out]

-1/2*(sqrt(2)*A - 3*sqrt(2)*B)*arctan(sqrt(-a*e^x)/sqrt(a))/(a^(3/2)*sgn(-e^x + 1)) + 1/2*sqrt(2)*(sqrt(-a*e^x
)*A*a*e^x + sqrt(-a*e^x)*B*a*e^x + sqrt(-a*e^x)*A*a + sqrt(-a*e^x)*B*a)/((a*e^x - a)^2*a*sgn(-e^x + 1))

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maple [A]  time = 0.34, size = 83, normalized size = 1.28 \[ \frac {\cosh \left (\frac {x}{2}\right ) \left (2 A +2 B \right )+\left (\ln \left (-1+\cosh \left (\frac {x}{2}\right )\right ) A -\ln \left (\cosh \left (\frac {x}{2}\right )+1\right ) A -3 B \ln \left (-1+\cosh \left (\frac {x}{2}\right )\right )+3 B \ln \left (\cosh \left (\frac {x}{2}\right )+1\right )\right ) \left (\sinh ^{2}\left (\frac {x}{2}\right )\right )}{4 a \sinh \left (\frac {x}{2}\right ) \sqrt {-2 a \left (\sinh ^{2}\left (\frac {x}{2}\right )\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((A+B*cosh(x))/(a-a*cosh(x))^(3/2),x)

[Out]

1/4/a*(cosh(1/2*x)*(2*A+2*B)+(ln(-1+cosh(1/2*x))*A-ln(cosh(1/2*x)+1)*A-3*B*ln(-1+cosh(1/2*x))+3*B*ln(cosh(1/2*
x)+1))*sinh(1/2*x)^2)/sinh(1/2*x)/(-2*a*sinh(1/2*x)^2)^(1/2)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {B \cosh \relax (x) + A}{{\left (-a \cosh \relax (x) + a\right )}^{\frac {3}{2}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((A+B*cosh(x))/(a-a*cosh(x))^(3/2),x, algorithm="maxima")

[Out]

integrate((B*cosh(x) + A)/(-a*cosh(x) + a)^(3/2), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.02 \[ \int \frac {A+B\,\mathrm {cosh}\relax (x)}{{\left (a-a\,\mathrm {cosh}\relax (x)\right )}^{3/2}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((A + B*cosh(x))/(a - a*cosh(x))^(3/2),x)

[Out]

int((A + B*cosh(x))/(a - a*cosh(x))^(3/2), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {A + B \cosh {\relax (x )}}{\left (- a \left (\cosh {\relax (x )} - 1\right )\right )^{\frac {3}{2}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((A+B*cosh(x))/(a-a*cosh(x))**(3/2),x)

[Out]

Integral((A + B*cosh(x))/(-a*(cosh(x) - 1))**(3/2), x)

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