3.67 \(\int \frac {\cot ^{-1}(x)}{(a+a x^2)^{3/2}} \, dx\)

Optimal. Leaf size=35 \[ \frac {x \cot ^{-1}(x)}{a \sqrt {a x^2+a}}-\frac {1}{a \sqrt {a x^2+a}} \]

[Out]

-1/a/(a*x^2+a)^(1/2)+x*arccot(x)/a/(a*x^2+a)^(1/2)

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Rubi [A]  time = 0.02, antiderivative size = 35, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.071, Rules used = {4895} \[ \frac {x \cot ^{-1}(x)}{a \sqrt {a x^2+a}}-\frac {1}{a \sqrt {a x^2+a}} \]

Antiderivative was successfully verified.

[In]

Int[ArcCot[x]/(a + a*x^2)^(3/2),x]

[Out]

-(1/(a*Sqrt[a + a*x^2])) + (x*ArcCot[x])/(a*Sqrt[a + a*x^2])

Rule 4895

Int[((a_.) + ArcCot[(c_.)*(x_)]*(b_.))/((d_) + (e_.)*(x_)^2)^(3/2), x_Symbol] :> -Simp[b/(c*d*Sqrt[d + e*x^2])
, x] + Simp[(x*(a + b*ArcCot[c*x]))/(d*Sqrt[d + e*x^2]), x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[e, c^2*d]

Rubi steps

\begin {align*} \int \frac {\cot ^{-1}(x)}{\left (a+a x^2\right )^{3/2}} \, dx &=-\frac {1}{a \sqrt {a+a x^2}}+\frac {x \cot ^{-1}(x)}{a \sqrt {a+a x^2}}\\ \end {align*}

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Mathematica [A]  time = 0.03, size = 21, normalized size = 0.60 \[ \frac {x \cot ^{-1}(x)-1}{a \sqrt {a \left (x^2+1\right )}} \]

Antiderivative was successfully verified.

[In]

Integrate[ArcCot[x]/(a + a*x^2)^(3/2),x]

[Out]

(-1 + x*ArcCot[x])/(a*Sqrt[a*(1 + x^2)])

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fricas [A]  time = 3.04, size = 29, normalized size = 0.83 \[ \frac {\sqrt {a x^{2} + a} {\left (x \operatorname {arccot}\relax (x) - 1\right )}}{a^{2} x^{2} + a^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(arccot(x)/(a*x^2+a)^(3/2),x, algorithm="fricas")

[Out]

sqrt(a*x^2 + a)*(x*arccot(x) - 1)/(a^2*x^2 + a^2)

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giac [A]  time = 0.15, size = 33, normalized size = 0.94 \[ \frac {x \arctan \left (\frac {1}{x}\right )}{\sqrt {a x^{2} + a} a} - \frac {1}{\sqrt {a x^{2} + a} a} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(arccot(x)/(a*x^2+a)^(3/2),x, algorithm="giac")

[Out]

x*arctan(1/x)/(sqrt(a*x^2 + a)*a) - 1/(sqrt(a*x^2 + a)*a)

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maple [C]  time = 0.70, size = 68, normalized size = 1.94 \[ \frac {\left (i+\mathrm {arccot}\relax (x )\right ) \left (x +i\right ) \sqrt {a \left (x +i\right ) \left (x -i\right )}}{2 \left (x^{2}+1\right ) a^{2}}+\frac {\sqrt {a \left (x +i\right ) \left (x -i\right )}\, \left (x -i\right ) \left (\mathrm {arccot}\relax (x )-i\right )}{2 \left (x^{2}+1\right ) a^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(arccot(x)/(a*x^2+a)^(3/2),x)

[Out]

1/2*(I+arccot(x))*(x+I)*(a*(x+I)*(x-I))^(1/2)/(x^2+1)/a^2+1/2*(a*(x+I)*(x-I))^(1/2)*(x-I)*(arccot(x)-I)/(x^2+1
)/a^2

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maxima [A]  time = 0.48, size = 31, normalized size = 0.89 \[ \frac {x \operatorname {arccot}\relax (x)}{\sqrt {a x^{2} + a} a} - \frac {1}{\sqrt {a x^{2} + a} a} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(arccot(x)/(a*x^2+a)^(3/2),x, algorithm="maxima")

[Out]

x*arccot(x)/(sqrt(a*x^2 + a)*a) - 1/(sqrt(a*x^2 + a)*a)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.03 \[ \int \frac {\mathrm {acot}\relax (x)}{{\left (a\,x^2+a\right )}^{3/2}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(acot(x)/(a + a*x^2)^(3/2),x)

[Out]

int(acot(x)/(a + a*x^2)^(3/2), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\operatorname {acot}{\relax (x )}}{\left (a \left (x^{2} + 1\right )\right )^{\frac {3}{2}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(acot(x)/(a*x**2+a)**(3/2),x)

[Out]

Integral(acot(x)/(a*(x**2 + 1))**(3/2), x)

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