3.249 \(\int \frac {e^{\tan ^{-1}(a x)}}{(c+a^2 c x^2)^2} \, dx\)

Optimal. Leaf size=50 \[ \frac {(2 a x+1) e^{\tan ^{-1}(a x)}}{5 a c^2 \left (a^2 x^2+1\right )}+\frac {2 e^{\tan ^{-1}(a x)}}{5 a c^2} \]

[Out]

2/5*exp(arctan(a*x))/a/c^2+1/5*exp(arctan(a*x))*(2*a*x+1)/a/c^2/(a^2*x^2+1)

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Rubi [A]  time = 0.05, antiderivative size = 50, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.105, Rules used = {5070, 5071} \[ \frac {(2 a x+1) e^{\tan ^{-1}(a x)}}{5 a c^2 \left (a^2 x^2+1\right )}+\frac {2 e^{\tan ^{-1}(a x)}}{5 a c^2} \]

Antiderivative was successfully verified.

[In]

Int[E^ArcTan[a*x]/(c + a^2*c*x^2)^2,x]

[Out]

(2*E^ArcTan[a*x])/(5*a*c^2) + (E^ArcTan[a*x]*(1 + 2*a*x))/(5*a*c^2*(1 + a^2*x^2))

Rule 5070

Int[E^(ArcTan[(a_.)*(x_)]*(n_.))*((c_) + (d_.)*(x_)^2)^(p_), x_Symbol] :> Simp[((n - 2*a*(p + 1)*x)*(c + d*x^2
)^(p + 1)*E^(n*ArcTan[a*x]))/(a*c*(n^2 + 4*(p + 1)^2)), x] + Dist[(2*(p + 1)*(2*p + 3))/(c*(n^2 + 4*(p + 1)^2)
), Int[(c + d*x^2)^(p + 1)*E^(n*ArcTan[a*x]), x], x] /; FreeQ[{a, c, d, n}, x] && EqQ[d, a^2*c] && LtQ[p, -1]
&&  !IntegerQ[I*n] && NeQ[n^2 + 4*(p + 1)^2, 0] && IntegerQ[2*p]

Rule 5071

Int[E^(ArcTan[(a_.)*(x_)]*(n_.))/((c_) + (d_.)*(x_)^2), x_Symbol] :> Simp[E^(n*ArcTan[a*x])/(a*c*n), x] /; Fre
eQ[{a, c, d, n}, x] && EqQ[d, a^2*c]

Rubi steps

\begin {align*} \int \frac {e^{\tan ^{-1}(a x)}}{\left (c+a^2 c x^2\right )^2} \, dx &=\frac {e^{\tan ^{-1}(a x)} (1+2 a x)}{5 a c^2 \left (1+a^2 x^2\right )}+\frac {2 \int \frac {e^{\tan ^{-1}(a x)}}{c+a^2 c x^2} \, dx}{5 c}\\ &=\frac {2 e^{\tan ^{-1}(a x)}}{5 a c^2}+\frac {e^{\tan ^{-1}(a x)} (1+2 a x)}{5 a c^2 \left (1+a^2 x^2\right )}\\ \end {align*}

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Mathematica [C]  time = 0.02, size = 60, normalized size = 1.20 \[ \frac {(1-i a x)^{\frac {i}{2}} (1+i a x)^{-\frac {i}{2}} \left (2 a^2 x^2+2 a x+3\right )}{5 c^2 \left (a^3 x^2+a\right )} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[E^ArcTan[a*x]/(c + a^2*c*x^2)^2,x]

[Out]

((1 - I*a*x)^(I/2)*(3 + 2*a*x + 2*a^2*x^2))/(5*c^2*(1 + I*a*x)^(I/2)*(a + a^3*x^2))

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fricas [A]  time = 0.53, size = 39, normalized size = 0.78 \[ \frac {{\left (2 \, a^{2} x^{2} + 2 \, a x + 3\right )} e^{\left (\arctan \left (a x\right )\right )}}{5 \, {\left (a^{3} c^{2} x^{2} + a c^{2}\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(arctan(a*x))/(a^2*c*x^2+c)^2,x, algorithm="fricas")

[Out]

1/5*(2*a^2*x^2 + 2*a*x + 3)*e^(arctan(a*x))/(a^3*c^2*x^2 + a*c^2)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \mathit {sage}_{0} x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(arctan(a*x))/(a^2*c*x^2+c)^2,x, algorithm="giac")

[Out]

sage0*x

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maple [A]  time = 0.04, size = 39, normalized size = 0.78 \[ \frac {{\mathrm e}^{\arctan \left (a x \right )} \left (2 a^{2} x^{2}+2 a x +3\right )}{5 \left (a^{2} x^{2}+1\right ) a \,c^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(exp(arctan(a*x))/(a^2*c*x^2+c)^2,x)

[Out]

1/5*exp(arctan(a*x))*(2*a^2*x^2+2*a*x+3)/(a^2*x^2+1)/a/c^2

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {e^{\left (\arctan \left (a x\right )\right )}}{{\left (a^{2} c x^{2} + c\right )}^{2}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(arctan(a*x))/(a^2*c*x^2+c)^2,x, algorithm="maxima")

[Out]

integrate(e^(arctan(a*x))/(a^2*c*x^2 + c)^2, x)

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mupad [B]  time = 0.56, size = 44, normalized size = 0.88 \[ \frac {{\mathrm {e}}^{\mathrm {atan}\left (a\,x\right )}\,\left (\frac {3}{5\,a^3\,c^2}+\frac {2\,x}{5\,a^2\,c^2}+\frac {2\,x^2}{5\,a\,c^2}\right )}{\frac {1}{a^2}+x^2} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(exp(atan(a*x))/(c + a^2*c*x^2)^2,x)

[Out]

(exp(atan(a*x))*(3/(5*a^3*c^2) + (2*x)/(5*a^2*c^2) + (2*x^2)/(5*a*c^2)))/(1/a^2 + x^2)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \begin {cases} \frac {2 a^{2} x^{2} e^{\operatorname {atan}{\left (a x \right )}}}{5 a^{3} c^{2} x^{2} + 5 a c^{2}} + \frac {2 a x e^{\operatorname {atan}{\left (a x \right )}}}{5 a^{3} c^{2} x^{2} + 5 a c^{2}} + \frac {3 e^{\operatorname {atan}{\left (a x \right )}}}{5 a^{3} c^{2} x^{2} + 5 a c^{2}} & \text {for}\: c \neq 0 \\\tilde {\infty } \int e^{\operatorname {atan}{\left (a x \right )}}\, dx & \text {otherwise} \end {cases} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(atan(a*x))/(a**2*c*x**2+c)**2,x)

[Out]

Piecewise((2*a**2*x**2*exp(atan(a*x))/(5*a**3*c**2*x**2 + 5*a*c**2) + 2*a*x*exp(atan(a*x))/(5*a**3*c**2*x**2 +
5*a*c**2) + 3*exp(atan(a*x))/(5*a**3*c**2*x**2 + 5*a*c**2), Ne(c, 0)), (zoo*Integral(exp(atan(a*x)), x), True
))

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