3.248 \(\int \frac {e^{\tan ^{-1}(a x)}}{c+a^2 c x^2} \, dx\)

Optimal. Leaf size=13 \[ \frac {e^{\tan ^{-1}(a x)}}{a c} \]

[Out]

exp(arctan(a*x))/a/c

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Rubi [A]  time = 0.03, antiderivative size = 13, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.053, Rules used = {5071} \[ \frac {e^{\tan ^{-1}(a x)}}{a c} \]

Antiderivative was successfully verified.

[In]

Int[E^ArcTan[a*x]/(c + a^2*c*x^2),x]

[Out]

E^ArcTan[a*x]/(a*c)

Rule 5071

Int[E^(ArcTan[(a_.)*(x_)]*(n_.))/((c_) + (d_.)*(x_)^2), x_Symbol] :> Simp[E^(n*ArcTan[a*x])/(a*c*n), x] /; Fre
eQ[{a, c, d, n}, x] && EqQ[d, a^2*c]

Rubi steps

\begin {align*} \int \frac {e^{\tan ^{-1}(a x)}}{c+a^2 c x^2} \, dx &=\frac {e^{\tan ^{-1}(a x)}}{a c}\\ \end {align*}

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Mathematica [C]  time = 0.01, size = 35, normalized size = 2.69 \[ \frac {(1-i a x)^{\frac {i}{2}} (1+i a x)^{-\frac {i}{2}}}{a c} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[E^ArcTan[a*x]/(c + a^2*c*x^2),x]

[Out]

(1 - I*a*x)^(I/2)/(a*c*(1 + I*a*x)^(I/2))

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fricas [A]  time = 0.43, size = 12, normalized size = 0.92 \[ \frac {e^{\left (\arctan \left (a x\right )\right )}}{a c} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(arctan(a*x))/(a^2*c*x^2+c),x, algorithm="fricas")

[Out]

e^(arctan(a*x))/(a*c)

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giac [A]  time = 0.13, size = 12, normalized size = 0.92 \[ \frac {e^{\left (\arctan \left (a x\right )\right )}}{a c} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(arctan(a*x))/(a^2*c*x^2+c),x, algorithm="giac")

[Out]

e^(arctan(a*x))/(a*c)

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maple [A]  time = 0.04, size = 13, normalized size = 1.00 \[ \frac {{\mathrm e}^{\arctan \left (a x \right )}}{a c} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(exp(arctan(a*x))/(a^2*c*x^2+c),x)

[Out]

exp(arctan(a*x))/a/c

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maxima [A]  time = 0.44, size = 12, normalized size = 0.92 \[ \frac {e^{\left (\arctan \left (a x\right )\right )}}{a c} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(arctan(a*x))/(a^2*c*x^2+c),x, algorithm="maxima")

[Out]

e^(arctan(a*x))/(a*c)

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mupad [B]  time = 0.53, size = 12, normalized size = 0.92 \[ \frac {{\mathrm {e}}^{\mathrm {atan}\left (a\,x\right )}}{a\,c} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(exp(atan(a*x))/(c + a^2*c*x^2),x)

[Out]

exp(atan(a*x))/(a*c)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \begin {cases} \frac {e^{\operatorname {atan}{\left (a x \right )}}}{a c} & \text {for}\: c \neq 0 \\\tilde {\infty } \int e^{\operatorname {atan}{\left (a x \right )}}\, dx & \text {otherwise} \end {cases} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(atan(a*x))/(a**2*c*x**2+c),x)

[Out]

Piecewise((exp(atan(a*x))/(a*c), Ne(c, 0)), (zoo*Integral(exp(atan(a*x)), x), True))

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