3.26 \(\int \frac {1}{(d+e x)^2 (a+b \sin ^{-1}(c x))^2} \, dx\)

Optimal. Leaf size=21 \[ \text {Int}\left (\frac {1}{(d+e x)^2 \left (a+b \sin ^{-1}(c x)\right )^2},x\right ) \]

[Out]

Unintegrable(1/(e*x+d)^2/(a+b*arcsin(c*x))^2,x)

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Rubi [A]  time = 0.03, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {1}{(d+e x)^2 \left (a+b \sin ^{-1}(c x)\right )^2} \, dx \]

Verification is Not applicable to the result.

[In]

Int[1/((d + e*x)^2*(a + b*ArcSin[c*x])^2),x]

[Out]

Defer[Int][1/((d + e*x)^2*(a + b*ArcSin[c*x])^2), x]

Rubi steps

\begin {align*} \int \frac {1}{(d+e x)^2 \left (a+b \sin ^{-1}(c x)\right )^2} \, dx &=\int \frac {1}{(d+e x)^2 \left (a+b \sin ^{-1}(c x)\right )^2} \, dx\\ \end {align*}

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Mathematica [A]  time = 12.66, size = 0, normalized size = 0.00 \[ \int \frac {1}{(d+e x)^2 \left (a+b \sin ^{-1}(c x)\right )^2} \, dx \]

Verification is Not applicable to the result.

[In]

Integrate[1/((d + e*x)^2*(a + b*ArcSin[c*x])^2),x]

[Out]

Integrate[1/((d + e*x)^2*(a + b*ArcSin[c*x])^2), x]

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fricas [A]  time = 0.53, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {1}{a^{2} e^{2} x^{2} + 2 \, a^{2} d e x + a^{2} d^{2} + {\left (b^{2} e^{2} x^{2} + 2 \, b^{2} d e x + b^{2} d^{2}\right )} \arcsin \left (c x\right )^{2} + 2 \, {\left (a b e^{2} x^{2} + 2 \, a b d e x + a b d^{2}\right )} \arcsin \left (c x\right )}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x+d)^2/(a+b*arcsin(c*x))^2,x, algorithm="fricas")

[Out]

integral(1/(a^2*e^2*x^2 + 2*a^2*d*e*x + a^2*d^2 + (b^2*e^2*x^2 + 2*b^2*d*e*x + b^2*d^2)*arcsin(c*x)^2 + 2*(a*b
*e^2*x^2 + 2*a*b*d*e*x + a*b*d^2)*arcsin(c*x)), x)

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giac [A]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{{\left (e x + d\right )}^{2} {\left (b \arcsin \left (c x\right ) + a\right )}^{2}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x+d)^2/(a+b*arcsin(c*x))^2,x, algorithm="giac")

[Out]

integrate(1/((e*x + d)^2*(b*arcsin(c*x) + a)^2), x)

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maple [A]  time = 2.06, size = 0, normalized size = 0.00 \[ \int \frac {1}{\left (e x +d \right )^{2} \left (a +b \arcsin \left (c x \right )\right )^{2}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(e*x+d)^2/(a+b*arcsin(c*x))^2,x)

[Out]

int(1/(e*x+d)^2/(a+b*arcsin(c*x))^2,x)

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maxima [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x+d)^2/(a+b*arcsin(c*x))^2,x, algorithm="maxima")

[Out]

Timed out

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mupad [A]  time = 0.00, size = -1, normalized size = -0.05 \[ \int \frac {1}{{\left (a+b\,\mathrm {asin}\left (c\,x\right )\right )}^2\,{\left (d+e\,x\right )}^2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/((a + b*asin(c*x))^2*(d + e*x)^2),x)

[Out]

int(1/((a + b*asin(c*x))^2*(d + e*x)^2), x)

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sympy [A]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\left (a + b \operatorname {asin}{\left (c x \right )}\right )^{2} \left (d + e x\right )^{2}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x+d)**2/(a+b*asin(c*x))**2,x)

[Out]

Integral(1/((a + b*asin(c*x))**2*(d + e*x)**2), x)

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