3.93.14 \(\int \frac {e^{-2 x+\frac {e^{-2 x} (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} (-9+2 \log (2)+\log ^2(2)))}{x}} (-25-50 x+e^{4 x} (-1+2 x)+e^x (-10-10 x+(-10-10 x) \log (2))+e^{3 x} (2-2 x+(2-2 x) \log (2))+e^{2 x} (9-2 \log (2)-\log ^2(2)))}{x^2} \, dx\)

Optimal. Leaf size=24 \[ e^{\frac {\left (1+5 e^{-x}-e^x+\log (2)\right )^2}{x}} \]

________________________________________________________________________________________

Rubi [F]  time = 29.55, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {\exp \left (-2 x+\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right ) \left (-25-50 x+e^{4 x} (-1+2 x)+e^x (-10-10 x+(-10-10 x) \log (2))+e^{3 x} (2-2 x+(2-2 x) \log (2))+e^{2 x} \left (9-2 \log (2)-\log ^2(2)\right )\right )}{x^2} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Int[(E^(-2*x + (25 + E^(4*x) + E^(3*x)*(-2 - 2*Log[2]) + E^x*(10 + 10*Log[2]) + E^(2*x)*(-9 + 2*Log[2] + Log[2
]^2))/(E^(2*x)*x))*(-25 - 50*x + E^(4*x)*(-1 + 2*x) + E^x*(-10 - 10*x + (-10 - 10*x)*Log[2]) + E^(3*x)*(2 - 2*
x + (2 - 2*x)*Log[2]) + E^(2*x)*(9 - 2*Log[2] - Log[2]^2)))/x^2,x]

[Out]

(9 - Log[2]^2 - Log[4])*Defer[Int][E^((5 - E^(2*x) + E^x*(1 + Log[2]))^2/(E^(2*x)*x))/x^2, x] - 25*Defer[Int][
E^(-2*x + (25 + E^(4*x) + E^(3*x)*(-2 - 2*Log[2]) + E^x*(10 + 10*Log[2]) + E^(2*x)*(-9 + 2*Log[2] + Log[2]^2))
/(E^(2*x)*x))/x^2, x] - 10*(1 + Log[2])*Defer[Int][E^(-x + (25 + E^(4*x) + E^(3*x)*(-2 - 2*Log[2]) + E^x*(10 +
10*Log[2]) + E^(2*x)*(-9 + 2*Log[2] + Log[2]^2))/(E^(2*x)*x))/x^2, x] + 2*(1 + Log[2])*Defer[Int][E^(x + (25
+ E^(4*x) + E^(3*x)*(-2 - 2*Log[2]) + E^x*(10 + 10*Log[2]) + E^(2*x)*(-9 + 2*Log[2] + Log[2]^2))/(E^(2*x)*x))/
x^2, x] - Defer[Int][E^(2*x + (25 + E^(4*x) + E^(3*x)*(-2 - 2*Log[2]) + E^x*(10 + 10*Log[2]) + E^(2*x)*(-9 + 2
*Log[2] + Log[2]^2))/(E^(2*x)*x))/x^2, x] - 50*Defer[Int][E^(-2*x + (25 + E^(4*x) + E^(3*x)*(-2 - 2*Log[2]) +
E^x*(10 + 10*Log[2]) + E^(2*x)*(-9 + 2*Log[2] + Log[2]^2))/(E^(2*x)*x))/x, x] - 10*(1 + Log[2])*Defer[Int][E^(
-x + (25 + E^(4*x) + E^(3*x)*(-2 - 2*Log[2]) + E^x*(10 + 10*Log[2]) + E^(2*x)*(-9 + 2*Log[2] + Log[2]^2))/(E^(
2*x)*x))/x, x] - 2*(1 + Log[2])*Defer[Int][E^(x + (25 + E^(4*x) + E^(3*x)*(-2 - 2*Log[2]) + E^x*(10 + 10*Log[2
]) + E^(2*x)*(-9 + 2*Log[2] + Log[2]^2))/(E^(2*x)*x))/x, x] + 2*Defer[Int][E^(2*x + (25 + E^(4*x) + E^(3*x)*(-
2 - 2*Log[2]) + E^x*(10 + 10*Log[2]) + E^(2*x)*(-9 + 2*Log[2] + Log[2]^2))/(E^(2*x)*x))/x, x]

Rubi steps

\begin {gather*} \begin {aligned} \text {integral} &=\int \frac {\exp \left (-2 x+\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right ) \left (-5+e^{2 x}-10 x-2 e^{2 x} x-e^x (1+\log (2))\right ) \left (5-e^{2 x}+e^x (1+\log (2))\right )}{x^2} \, dx\\ &=\int \left (\frac {\exp \left (2 x+\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right ) (-1+2 x)}{x^2}-\frac {25 \exp \left (-2 x+\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right ) (1+2 x)}{x^2}-\frac {2 \exp \left (x+\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right ) (-1+x) (1+\log (2))}{x^2}-\frac {10 \exp \left (-x+\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right ) (1+x) (1+\log (2))}{x^2}-\frac {\exp \left (\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right ) \left (-9+\log ^2(2)+\log (4)\right )}{x^2}\right ) \, dx\\ &=-\left (25 \int \frac {\exp \left (-2 x+\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right ) (1+2 x)}{x^2} \, dx\right )-(2 (1+\log (2))) \int \frac {\exp \left (x+\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right ) (-1+x)}{x^2} \, dx-(10 (1+\log (2))) \int \frac {\exp \left (-x+\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right ) (1+x)}{x^2} \, dx+\left (9-\log ^2(2)-\log (4)\right ) \int \frac {\exp \left (\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right )}{x^2} \, dx+\int \frac {\exp \left (2 x+\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right ) (-1+2 x)}{x^2} \, dx\\ &=-\left (25 \int \left (\frac {\exp \left (-2 x+\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right )}{x^2}+\frac {2 \exp \left (-2 x+\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right )}{x}\right ) \, dx\right )-(2 (1+\log (2))) \int \left (-\frac {\exp \left (x+\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right )}{x^2}+\frac {\exp \left (x+\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right )}{x}\right ) \, dx-(10 (1+\log (2))) \int \left (\frac {\exp \left (-x+\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right )}{x^2}+\frac {\exp \left (-x+\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right )}{x}\right ) \, dx+\left (9-\log ^2(2)-\log (4)\right ) \int \frac {\exp \left (\frac {e^{-2 x} \left (5-e^{2 x}+e^x (1+\log (2))\right )^2}{x}\right )}{x^2} \, dx+\int \left (-\frac {\exp \left (2 x+\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right )}{x^2}+\frac {2 \exp \left (2 x+\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right )}{x}\right ) \, dx\\ &=2 \int \frac {\exp \left (2 x+\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right )}{x} \, dx-25 \int \frac {\exp \left (-2 x+\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right )}{x^2} \, dx-50 \int \frac {\exp \left (-2 x+\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right )}{x} \, dx+(2 (1+\log (2))) \int \frac {\exp \left (x+\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right )}{x^2} \, dx-(2 (1+\log (2))) \int \frac {\exp \left (x+\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right )}{x} \, dx-(10 (1+\log (2))) \int \frac {\exp \left (-x+\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right )}{x^2} \, dx-(10 (1+\log (2))) \int \frac {\exp \left (-x+\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right )}{x} \, dx+\left (9-\log ^2(2)-\log (4)\right ) \int \frac {\exp \left (\frac {e^{-2 x} \left (5-e^{2 x}+e^x (1+\log (2))\right )^2}{x}\right )}{x^2} \, dx-\int \frac {\exp \left (2 x+\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}\right )}{x^2} \, dx\\ \end {aligned} \end {gather*}

________________________________________________________________________________________

Mathematica [F]  time = 4.85, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {e^{-2 x+\frac {e^{-2 x} \left (25+e^{4 x}+e^{3 x} (-2-2 \log (2))+e^x (10+10 \log (2))+e^{2 x} \left (-9+2 \log (2)+\log ^2(2)\right )\right )}{x}} \left (-25-50 x+e^{4 x} (-1+2 x)+e^x (-10-10 x+(-10-10 x) \log (2))+e^{3 x} (2-2 x+(2-2 x) \log (2))+e^{2 x} \left (9-2 \log (2)-\log ^2(2)\right )\right )}{x^2} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Integrate[(E^(-2*x + (25 + E^(4*x) + E^(3*x)*(-2 - 2*Log[2]) + E^x*(10 + 10*Log[2]) + E^(2*x)*(-9 + 2*Log[2] +
Log[2]^2))/(E^(2*x)*x))*(-25 - 50*x + E^(4*x)*(-1 + 2*x) + E^x*(-10 - 10*x + (-10 - 10*x)*Log[2]) + E^(3*x)*(
2 - 2*x + (2 - 2*x)*Log[2]) + E^(2*x)*(9 - 2*Log[2] - Log[2]^2)))/x^2,x]

[Out]

Integrate[(E^(-2*x + (25 + E^(4*x) + E^(3*x)*(-2 - 2*Log[2]) + E^x*(10 + 10*Log[2]) + E^(2*x)*(-9 + 2*Log[2] +
Log[2]^2))/(E^(2*x)*x))*(-25 - 50*x + E^(4*x)*(-1 + 2*x) + E^x*(-10 - 10*x + (-10 - 10*x)*Log[2]) + E^(3*x)*(
2 - 2*x + (2 - 2*x)*Log[2]) + E^(2*x)*(9 - 2*Log[2] - Log[2]^2)))/x^2, x]

________________________________________________________________________________________

fricas [B]  time = 0.67, size = 62, normalized size = 2.58 \begin {gather*} e^{\left (2 \, x - \frac {{\left (2 \, {\left (\log \relax (2) + 1\right )} e^{\left (3 \, x\right )} + {\left (2 \, x^{2} - \log \relax (2)^{2} - 2 \, \log \relax (2) + 9\right )} e^{\left (2 \, x\right )} - 10 \, {\left (\log \relax (2) + 1\right )} e^{x} - e^{\left (4 \, x\right )} - 25\right )} e^{\left (-2 \, x\right )}}{x}\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((2*x-1)*exp(x)^4+((-2*x+2)*log(2)-2*x+2)*exp(x)^3+(-log(2)^2-2*log(2)+9)*exp(x)^2+((-10*x-10)*log(2
)-10*x-10)*exp(x)-50*x-25)*exp((exp(x)^4+(-2*log(2)-2)*exp(x)^3+(log(2)^2+2*log(2)-9)*exp(x)^2+(10*log(2)+10)*
exp(x)+25)/x/exp(x)^2)/exp(x)^2/x^2,x, algorithm="fricas")

[Out]

e^(2*x - (2*(log(2) + 1)*e^(3*x) + (2*x^2 - log(2)^2 - 2*log(2) + 9)*e^(2*x) - 10*(log(2) + 1)*e^x - e^(4*x) -
25)*e^(-2*x)/x)

________________________________________________________________________________________

giac [B]  time = 0.17, size = 62, normalized size = 2.58 \begin {gather*} e^{\left (\frac {{\left (e^{\left (2 \, x\right )} \log \relax (2)^{2} - 2 \, e^{\left (3 \, x\right )} \log \relax (2) + 2 \, e^{\left (2 \, x\right )} \log \relax (2) + 10 \, e^{x} \log \relax (2) + e^{\left (4 \, x\right )} - 2 \, e^{\left (3 \, x\right )} - 9 \, e^{\left (2 \, x\right )} + 10 \, e^{x} + 25\right )} e^{\left (-2 \, x\right )}}{x}\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((2*x-1)*exp(x)^4+((-2*x+2)*log(2)-2*x+2)*exp(x)^3+(-log(2)^2-2*log(2)+9)*exp(x)^2+((-10*x-10)*log(2
)-10*x-10)*exp(x)-50*x-25)*exp((exp(x)^4+(-2*log(2)-2)*exp(x)^3+(log(2)^2+2*log(2)-9)*exp(x)^2+(10*log(2)+10)*
exp(x)+25)/x/exp(x)^2)/exp(x)^2/x^2,x, algorithm="giac")

[Out]

e^((e^(2*x)*log(2)^2 - 2*e^(3*x)*log(2) + 2*e^(2*x)*log(2) + 10*e^x*log(2) + e^(4*x) - 2*e^(3*x) - 9*e^(2*x) +
10*e^x + 25)*e^(-2*x)/x)

________________________________________________________________________________________

maple [B]  time = 1.23, size = 56, normalized size = 2.33

method	result	size
risch	\(\left (\frac {1}{4}\right )^{\frac {{\mathrm e}^{x}}{x}} 4^{\frac {1}{x}} 1024^{\frac {{\mathrm e}^{-x}}{x}} {\mathrm e}^{\frac {10 \,{\mathrm e}^{-x}+\ln \relax (2)^{2}-9+{\mathrm e}^{2 x}-2 \,{\mathrm e}^{x}+25 \,{\mathrm e}^{-2 x}}{x}}\)	\(56\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((2*x-1)*exp(x)^4+((-2*x+2)*ln(2)-2*x+2)*exp(x)^3+(-ln(2)^2-2*ln(2)+9)*exp(x)^2+((-10*x-10)*ln(2)-10*x-10)
*exp(x)-50*x-25)*exp((exp(x)^4+(-2*ln(2)-2)*exp(x)^3+(ln(2)^2+2*ln(2)-9)*exp(x)^2+(10*ln(2)+10)*exp(x)+25)/x/e
xp(x)^2)/exp(x)^2/x^2,x,method=_RETURNVERBOSE)

[Out]

(1/4)^(exp(x)/x)*4^(1/x)*1024^(1/x*exp(-x))*exp((10*exp(-x)+ln(2)^2-9+exp(2*x)-2*exp(x)+25*exp(-2*x))/x)

________________________________________________________________________________________

maxima [B]  time = 0.62, size = 75, normalized size = 3.12 \begin {gather*} e^{\left (\frac {10 \, e^{\left (-x\right )} \log \relax (2)}{x} - \frac {2 \, e^{x} \log \relax (2)}{x} + \frac {\log \relax (2)^{2}}{x} + \frac {e^{\left (2 \, x\right )}}{x} + \frac {10 \, e^{\left (-x\right )}}{x} + \frac {25 \, e^{\left (-2 \, x\right )}}{x} - \frac {2 \, e^{x}}{x} + \frac {2 \, \log \relax (2)}{x} - \frac {9}{x}\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((2*x-1)*exp(x)^4+((-2*x+2)*log(2)-2*x+2)*exp(x)^3+(-log(2)^2-2*log(2)+9)*exp(x)^2+((-10*x-10)*log(2
)-10*x-10)*exp(x)-50*x-25)*exp((exp(x)^4+(-2*log(2)-2)*exp(x)^3+(log(2)^2+2*log(2)-9)*exp(x)^2+(10*log(2)+10)*
exp(x)+25)/x/exp(x)^2)/exp(x)^2/x^2,x, algorithm="maxima")

[Out]

e^(10*e^(-x)*log(2)/x - 2*e^x*log(2)/x + log(2)^2/x + e^(2*x)/x + 10*e^(-x)/x + 25*e^(-2*x)/x - 2*e^x/x + 2*lo
g(2)/x - 9/x)

________________________________________________________________________________________

mupad [B]  time = 5.93, size = 73, normalized size = 3.04 \begin {gather*} 4^{\frac {{\mathrm {e}}^{-x}\,\left ({\mathrm {e}}^x-{\mathrm {e}}^{2\,x}+5\right )}{x}}\,{\mathrm {e}}^{\frac {{\ln \relax (2)}^2}{x}}\,{\mathrm {e}}^{-\frac {2\,{\mathrm {e}}^x}{x}}\,{\mathrm {e}}^{-\frac {9}{x}}\,{\mathrm {e}}^{\frac {{\mathrm {e}}^{2\,x}}{x}}\,{\mathrm {e}}^{\frac {10\,{\mathrm {e}}^{-x}}{x}}\,{\mathrm {e}}^{\frac {25\,{\mathrm {e}}^{-2\,x}}{x}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(-(exp((exp(-2*x)*(exp(4*x) + exp(x)*(10*log(2) + 10) + exp(2*x)*(2*log(2) + log(2)^2 - 9) - exp(3*x)*(2*lo
g(2) + 2) + 25))/x)*exp(-2*x)*(50*x + exp(x)*(10*x + log(2)*(10*x + 10) + 10) + exp(2*x)*(2*log(2) + log(2)^2
- 9) - exp(4*x)*(2*x - 1) + exp(3*x)*(2*x + log(2)*(2*x - 2) - 2) + 25))/x^2,x)

[Out]

4^((exp(-x)*(exp(x) - exp(2*x) + 5))/x)*exp(log(2)^2/x)*exp(-(2*exp(x))/x)*exp(-9/x)*exp(exp(2*x)/x)*exp((10*e
xp(-x))/x)*exp((25*exp(-2*x))/x)

________________________________________________________________________________________

sympy [B]  time = 0.64, size = 54, normalized size = 2.25 \begin {gather*} e^{\frac {\left (e^{4 x} + \left (-2 - 2 \log {\relax (2 )}\right ) e^{3 x} + \left (-9 + \log {\relax (2 )}^{2} + 2 \log {\relax (2 )}\right ) e^{2 x} + \left (10 \log {\relax (2 )} + 10\right ) e^{x} + 25\right ) e^{- 2 x}}{x}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((2*x-1)*exp(x)**4+((-2*x+2)*ln(2)-2*x+2)*exp(x)**3+(-ln(2)**2-2*ln(2)+9)*exp(x)**2+((-10*x-10)*ln(2
)-10*x-10)*exp(x)-50*x-25)*exp((exp(x)**4+(-2*ln(2)-2)*exp(x)**3+(ln(2)**2+2*ln(2)-9)*exp(x)**2+(10*ln(2)+10)*
exp(x)+25)/x/exp(x)**2)/exp(x)**2/x**2,x)

[Out]

exp((exp(4*x) + (-2 - 2*log(2))*exp(3*x) + (-9 + log(2)**2 + 2*log(2))*exp(2*x) + (10*log(2) + 10)*exp(x) + 25
)*exp(-2*x)/x)

________________________________________________________________________________________