Optimal. Leaf size=27 \[ x^2+\frac {3}{8} \left (x+\frac {4}{3 \left (4+2 x+\frac {\log (5)}{4}\right )^2}\right ) \]
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Rubi [A] time = 0.19, antiderivative size = 20, normalized size of antiderivative = 0.74, number of steps used = 2, number of rules used = 1, integrand size = 110, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.009, Rules used = {2074} \begin {gather*} x^2+\frac {3 x}{8}+\frac {8}{(8 x+16+\log (5))^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 2074
Rubi steps
\begin {gather*} \begin {aligned} \text {integral} &=\int \left (\frac {3}{8}+2 x-\frac {128}{(16+8 x+\log (5))^3}\right ) \, dx\\ &=\frac {3 x}{8}+x^2+\frac {8}{(16+8 x+\log (5))^2}\\ \end {aligned} \end {gather*}
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Mathematica [B] time = 0.06, size = 95, normalized size = 3.52 \begin {gather*} \frac {4096 x^4+9 \log ^4(5)+576 x^2 (16+\log (5))+\log ^3(5) (419-5 \log (25))-3840 \log (5) (-7+\log (25))-8 x (16+\log (5))^2 (23+\log (25))+512 x^3 (35+\log (25))-48 \log ^2(5) (-131+5 \log (25))-512 (103+40 \log (25))}{64 (16+8 x+\log (5))^2} \end {gather*}
Antiderivative was successfully verified.
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fricas [B] time = 0.57, size = 77, normalized size = 2.85 \begin {gather*} \frac {512 \, x^{4} + 2240 \, x^{3} + {\left (8 \, x^{2} + 3 \, x\right )} \log \relax (5)^{2} + 2816 \, x^{2} + 16 \, {\left (8 \, x^{3} + 19 \, x^{2} + 6 \, x\right )} \log \relax (5) + 768 \, x + 64}{8 \, {\left (64 \, x^{2} + 16 \, {\left (x + 2\right )} \log \relax (5) + \log \relax (5)^{2} + 256 \, x + 256\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.13, size = 18, normalized size = 0.67 \begin {gather*} x^{2} + \frac {3}{8} \, x + \frac {8}{{\left (8 \, x + \log \relax (5) + 16\right )}^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.07, size = 19, normalized size = 0.70
method | result | size |
default | \(x^{2}+\frac {3 x}{8}+\frac {8}{\left (\ln \relax (5)+8 x +16\right )^{2}}\) | \(19\) |
risch | \(x^{2}+\frac {3 x}{8}+\frac {8}{\ln \relax (5)^{2}+16 x \ln \relax (5)+64 x^{2}+32 \ln \relax (5)+256 x +256}\) | \(35\) |
norman | \(\frac {\left (16 \ln \relax (5)+280\right ) x^{3}+\left (-\frac {\ln \relax (5)^{3}}{4}-\frac {105 \ln \relax (5)^{2}}{8}-1312-228 \ln \relax (5)\right ) x +64 x^{4}-\frac {\ln \relax (5)^{4}}{64}-\frac {35 \ln \relax (5)^{3}}{32}-\frac {57 \ln \relax (5)^{2}}{2}-328 \ln \relax (5)-1400}{\left (\ln \relax (5)+8 x +16\right )^{2}}\) | \(70\) |
gosper | \(-\frac {\ln \relax (5)^{4}+16 \ln \relax (5)^{3} x -1024 x^{3} \ln \relax (5)-4096 x^{4}+70 \ln \relax (5)^{3}+840 x \ln \relax (5)^{2}-17920 x^{3}+1824 \ln \relax (5)^{2}+14592 x \ln \relax (5)+20992 \ln \relax (5)+83968 x +89600}{64 \left (\ln \relax (5)^{2}+16 x \ln \relax (5)+64 x^{2}+32 \ln \relax (5)+256 x +256\right )}\) | \(89\) |
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.42, size = 33, normalized size = 1.22 \begin {gather*} x^{2} + \frac {3}{8} \, x + \frac {8}{64 \, x^{2} + 16 \, x {\left (\log \relax (5) + 16\right )} + \log \relax (5)^{2} + 32 \, \log \relax (5) + 256} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 4.15, size = 34, normalized size = 1.26 \begin {gather*} \frac {3\,x}{8}+\frac {8}{64\,x^2+\left (16\,\ln \relax (5)+256\right )\,x+32\,\ln \relax (5)+{\ln \relax (5)}^2+256}+x^2 \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 0.39, size = 34, normalized size = 1.26 \begin {gather*} x^{2} + \frac {3 x}{8} + \frac {8}{64 x^{2} + x \left (16 \log {\relax (5 )} + 256\right ) + \log {\relax (5 )}^{2} + 32 \log {\relax (5 )} + 256} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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