3.125 \(\int \text{CosIntegral}(a+b x) \sin (a+b x) \, dx\)

Optimal. Leaf size=47 \[ \frac{\text{CosIntegral}(2 a+2 b x)}{2 b}-\frac{\text{CosIntegral}(a+b x) \cos (a+b x)}{b}+\frac{\log (a+b x)}{2 b} \]

[Out]

-((Cos[a + b*x]*CosIntegral[a + b*x])/b) + CosIntegral[2*a + 2*b*x]/(2*b) + Log[a + b*x]/(2*b)

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Rubi [A]  time = 0.076047, antiderivative size = 47, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 13, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.231, Rules used = {6518, 3312, 3302} \[ \frac{\text{CosIntegral}(2 a+2 b x)}{2 b}-\frac{\text{CosIntegral}(a+b x) \cos (a+b x)}{b}+\frac{\log (a+b x)}{2 b} \]

Antiderivative was successfully verified.

[In]

Int[CosIntegral[a + b*x]*Sin[a + b*x],x]

[Out]

-((Cos[a + b*x]*CosIntegral[a + b*x])/b) + CosIntegral[2*a + 2*b*x]/(2*b) + Log[a + b*x]/(2*b)

Rule 6518

Int[CosIntegral[(c_.) + (d_.)*(x_)]*Sin[(a_.) + (b_.)*(x_)], x_Symbol] :> -Simp[(Cos[a + b*x]*CosIntegral[c +
d*x])/b, x] + Dist[d/b, Int[(Cos[a + b*x]*Cos[c + d*x])/(c + d*x), x], x] /; FreeQ[{a, b, c, d}, x]

Rule 3312

Int[((c_.) + (d_.)*(x_))^(m_)*sin[(e_.) + (f_.)*(x_)]^(n_), x_Symbol] :> Int[ExpandTrigReduce[(c + d*x)^m, Sin
[e + f*x]^n, x], x] /; FreeQ[{c, d, e, f, m}, x] && IGtQ[n, 1] && ( !RationalQ[m] || (GeQ[m, -1] && LtQ[m, 1])
)

Rule 3302

Int[sin[(e_.) + (f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[CosIntegral[e - Pi/2 + f*x]/d, x] /; FreeQ
[{c, d, e, f}, x] && EqQ[d*(e - Pi/2) - c*f, 0]

Rubi steps

\begin{align*} \int \text{Ci}(a+b x) \sin (a+b x) \, dx &=-\frac{\cos (a+b x) \text{Ci}(a+b x)}{b}+\int \frac{\cos ^2(a+b x)}{a+b x} \, dx\\ &=-\frac{\cos (a+b x) \text{Ci}(a+b x)}{b}+\int \left (\frac{1}{2 (a+b x)}+\frac{\cos (2 a+2 b x)}{2 (a+b x)}\right ) \, dx\\ &=-\frac{\cos (a+b x) \text{Ci}(a+b x)}{b}+\frac{\log (a+b x)}{2 b}+\frac{1}{2} \int \frac{\cos (2 a+2 b x)}{a+b x} \, dx\\ &=-\frac{\cos (a+b x) \text{Ci}(a+b x)}{b}+\frac{\text{Ci}(2 a+2 b x)}{2 b}+\frac{\log (a+b x)}{2 b}\\ \end{align*}

Mathematica [A]  time = 0.0241664, size = 46, normalized size = 0.98 \[ \frac{\text{CosIntegral}(2 (a+b x))}{2 b}-\frac{\text{CosIntegral}(a+b x) \cos (a+b x)}{b}+\frac{\log (a+b x)}{2 b} \]

Antiderivative was successfully verified.

[In]

Integrate[CosIntegral[a + b*x]*Sin[a + b*x],x]

[Out]

-((Cos[a + b*x]*CosIntegral[a + b*x])/b) + CosIntegral[2*(a + b*x)]/(2*b) + Log[a + b*x]/(2*b)

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Maple [A]  time = 0.052, size = 44, normalized size = 0.9 \begin{align*}{\frac{{\it Ci} \left ( 2\,bx+2\,a \right ) }{2\,b}}-{\frac{{\it Ci} \left ( bx+a \right ) \cos \left ( bx+a \right ) }{b}}+{\frac{\ln \left ( bx+a \right ) }{2\,b}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(Ci(b*x+a)*sin(b*x+a),x)

[Out]

1/2*Ci(2*b*x+2*a)/b-Ci(b*x+a)*cos(b*x+a)/b+1/2*ln(b*x+a)/b

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int{\rm Ci}\left (b x + a\right ) \sin \left (b x + a\right )\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(Ci(b*x+a)*sin(b*x+a),x, algorithm="maxima")

[Out]

integrate(Ci(b*x + a)*sin(b*x + a), x)

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Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\operatorname{Ci}\left (b x + a\right ) \sin \left (b x + a\right ), x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(Ci(b*x+a)*sin(b*x+a),x, algorithm="fricas")

[Out]

integral(cos_integral(b*x + a)*sin(b*x + a), x)

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \sin{\left (a + b x \right )} \operatorname{Ci}{\left (a + b x \right )}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(Ci(b*x+a)*sin(b*x+a),x)

[Out]

Integral(sin(a + b*x)*Ci(a + b*x), x)

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Giac [B]  time = 1.19141, size = 130, normalized size = 2.77 \begin{align*} -\frac{\cos \left (b x + a\right ) \operatorname{Ci}\left (b x + a\right )}{b} + \frac{\cos \left (2 \, a\right )^{2} \operatorname{Ci}\left (2 \, b x + 2 \, a\right ) + \cos \left (2 \, a\right )^{2} \operatorname{Ci}\left (-2 \, b x - 2 \, a\right ) + \operatorname{Ci}\left (2 \, b x + 2 \, a\right ) \sin \left (2 \, a\right )^{2} + \operatorname{Ci}\left (-2 \, b x - 2 \, a\right ) \sin \left (2 \, a\right )^{2} + 2 \, \log \left (b x + a\right )}{4 \, b} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(Ci(b*x+a)*sin(b*x+a),x, algorithm="giac")

[Out]

-cos(b*x + a)*cos_integral(b*x + a)/b + 1/4*(cos(2*a)^2*cos_integral(2*b*x + 2*a) + cos(2*a)^2*cos_integral(-2
*b*x - 2*a) + cos_integral(2*b*x + 2*a)*sin(2*a)^2 + cos_integral(-2*b*x - 2*a)*sin(2*a)^2 + 2*log(b*x + a))/b