Optimal. Leaf size=109 \[ -\frac{a \text{CosIntegral}(2 a+2 b x)}{2 b^2}+\frac{\text{CosIntegral}(a+b x) \sin (a+b x)}{b^2}-\frac{\text{Si}(2 a+2 b x)}{2 b^2}-\frac{a \log (a+b x)}{2 b^2}+\frac{\sin (a+b x) \cos (a+b x)}{2 b^2}-\frac{x \text{CosIntegral}(a+b x) \cos (a+b x)}{b}+\frac{x}{2 b} \]
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Rubi [A] time = 0.229298, antiderivative size = 109, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 10, integrand size = 14, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.714, Rules used = {6520, 6742, 2635, 8, 3312, 3302, 6512, 4406, 12, 3299} \[ -\frac{a \text{CosIntegral}(2 a+2 b x)}{2 b^2}+\frac{\text{CosIntegral}(a+b x) \sin (a+b x)}{b^2}-\frac{\text{Si}(2 a+2 b x)}{2 b^2}-\frac{a \log (a+b x)}{2 b^2}+\frac{\sin (a+b x) \cos (a+b x)}{2 b^2}-\frac{x \text{CosIntegral}(a+b x) \cos (a+b x)}{b}+\frac{x}{2 b} \]
Antiderivative was successfully verified.
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Rule 6520
Rule 6742
Rule 2635
Rule 8
Rule 3312
Rule 3302
Rule 6512
Rule 4406
Rule 12
Rule 3299
Rubi steps
\begin{align*} \int x \text{Ci}(a+b x) \sin (a+b x) \, dx &=-\frac{x \cos (a+b x) \text{Ci}(a+b x)}{b}+\frac{\int \cos (a+b x) \text{Ci}(a+b x) \, dx}{b}+\int \frac{x \cos ^2(a+b x)}{a+b x} \, dx\\ &=-\frac{x \cos (a+b x) \text{Ci}(a+b x)}{b}+\frac{\text{Ci}(a+b x) \sin (a+b x)}{b^2}-\frac{\int \frac{\cos (a+b x) \sin (a+b x)}{a+b x} \, dx}{b}+\int \left (\frac{\cos ^2(a+b x)}{b}-\frac{a \cos ^2(a+b x)}{b (a+b x)}\right ) \, dx\\ &=-\frac{x \cos (a+b x) \text{Ci}(a+b x)}{b}+\frac{\text{Ci}(a+b x) \sin (a+b x)}{b^2}+\frac{\int \cos ^2(a+b x) \, dx}{b}-\frac{\int \frac{\sin (2 a+2 b x)}{2 (a+b x)} \, dx}{b}-\frac{a \int \frac{\cos ^2(a+b x)}{a+b x} \, dx}{b}\\ &=-\frac{x \cos (a+b x) \text{Ci}(a+b x)}{b}+\frac{\cos (a+b x) \sin (a+b x)}{2 b^2}+\frac{\text{Ci}(a+b x) \sin (a+b x)}{b^2}+\frac{\int 1 \, dx}{2 b}-\frac{\int \frac{\sin (2 a+2 b x)}{a+b x} \, dx}{2 b}-\frac{a \int \left (\frac{1}{2 (a+b x)}+\frac{\cos (2 a+2 b x)}{2 (a+b x)}\right ) \, dx}{b}\\ &=\frac{x}{2 b}-\frac{x \cos (a+b x) \text{Ci}(a+b x)}{b}-\frac{a \log (a+b x)}{2 b^2}+\frac{\cos (a+b x) \sin (a+b x)}{2 b^2}+\frac{\text{Ci}(a+b x) \sin (a+b x)}{b^2}-\frac{\text{Si}(2 a+2 b x)}{2 b^2}-\frac{a \int \frac{\cos (2 a+2 b x)}{a+b x} \, dx}{2 b}\\ &=\frac{x}{2 b}-\frac{x \cos (a+b x) \text{Ci}(a+b x)}{b}-\frac{a \text{Ci}(2 a+2 b x)}{2 b^2}-\frac{a \log (a+b x)}{2 b^2}+\frac{\cos (a+b x) \sin (a+b x)}{2 b^2}+\frac{\text{Ci}(a+b x) \sin (a+b x)}{b^2}-\frac{\text{Si}(2 a+2 b x)}{2 b^2}\\ \end{align*}
Mathematica [A] time = 0.181983, size = 76, normalized size = 0.7 \[ \frac{-2 a \text{CosIntegral}(2 (a+b x))+\text{CosIntegral}(a+b x) (4 \sin (a+b x)-4 b x \cos (a+b x))-2 \text{Si}(2 (a+b x))-2 a \log (a+b x)+\sin (2 (a+b x))+2 b x}{4 b^2} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.062, size = 106, normalized size = 1. \begin{align*} -{\frac{x{\it Ci} \left ( bx+a \right ) \cos \left ( bx+a \right ) }{b}}+{\frac{{\it Ci} \left ( bx+a \right ) \sin \left ( bx+a \right ) }{{b}^{2}}}+{\frac{\cos \left ( bx+a \right ) \sin \left ( bx+a \right ) }{2\,{b}^{2}}}+{\frac{x}{2\,b}}+{\frac{a}{2\,{b}^{2}}}-{\frac{a\ln \left ( bx+a \right ) }{2\,{b}^{2}}}-{\frac{a{\it Ci} \left ( 2\,bx+2\,a \right ) }{2\,{b}^{2}}}-{\frac{{\it Si} \left ( 2\,bx+2\,a \right ) }{2\,{b}^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x{\rm Ci}\left (b x + a\right ) \sin \left (b x + a\right )\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (x \operatorname{Ci}\left (b x + a\right ) \sin \left (b x + a\right ), x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x \sin{\left (a + b x \right )} \operatorname{Ci}{\left (a + b x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [C] time = 1.21399, size = 150, normalized size = 1.38 \begin{align*} -{\left (\frac{x \cos \left (b x + a\right )}{b} - \frac{\sin \left (b x + a\right )}{b^{2}}\right )} \operatorname{Ci}\left (b x + a\right ) + \frac{2 \, b x - 2 \, a \log \left ({\left | b x + a \right |}\right ) - a \Re \left ( \operatorname{Ci}\left (2 \, b x + 2 \, a\right ) \right ) - a \Re \left ( \operatorname{Ci}\left (-2 \, b x - 2 \, a\right ) \right ) - \Im \left ( \operatorname{Ci}\left (2 \, b x + 2 \, a\right ) \right ) + \Im \left ( \operatorname{Ci}\left (-2 \, b x - 2 \, a\right ) \right ) - 2 \, \operatorname{Si}\left (2 \, b x + 2 \, a\right )}{4 \, b^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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