Optimal. Leaf size=130 \[ \frac{\left (2 a^2+2 a+1\right ) \sqrt{a+b x+1} \sqrt{-a-b x+1}}{2 b^3}+\frac{\left (2 a^2+2 a+1\right ) \sin ^{-1}(a+b x)}{2 b^3}-\frac{x \sqrt{a+b x+1} (-a-b x+1)^{3/2}}{3 b^2}+\frac{(4 a+1) \sqrt{a+b x+1} (-a-b x+1)^{3/2}}{6 b^3} \]
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Rubi [A] time = 0.145756, antiderivative size = 130, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 7, integrand size = 14, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.5, Rules used = {6163, 90, 80, 50, 53, 619, 216} \[ \frac{\left (2 a^2+2 a+1\right ) \sqrt{a+b x+1} \sqrt{-a-b x+1}}{2 b^3}+\frac{\left (2 a^2+2 a+1\right ) \sin ^{-1}(a+b x)}{2 b^3}-\frac{x \sqrt{a+b x+1} (-a-b x+1)^{3/2}}{3 b^2}+\frac{(4 a+1) \sqrt{a+b x+1} (-a-b x+1)^{3/2}}{6 b^3} \]
Antiderivative was successfully verified.
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Rule 6163
Rule 90
Rule 80
Rule 50
Rule 53
Rule 619
Rule 216
Rubi steps
\begin{align*} \int e^{-\tanh ^{-1}(a+b x)} x^2 \, dx &=\int \frac{x^2 \sqrt{1-a-b x}}{\sqrt{1+a+b x}} \, dx\\ &=-\frac{x (1-a-b x)^{3/2} \sqrt{1+a+b x}}{3 b^2}-\frac{\int \frac{\sqrt{1-a-b x} \left (-1+a^2+(1+4 a) b x\right )}{\sqrt{1+a+b x}} \, dx}{3 b^2}\\ &=\frac{(1+4 a) (1-a-b x)^{3/2} \sqrt{1+a+b x}}{6 b^3}-\frac{x (1-a-b x)^{3/2} \sqrt{1+a+b x}}{3 b^2}+\frac{\left (1+2 a+2 a^2\right ) \int \frac{\sqrt{1-a-b x}}{\sqrt{1+a+b x}} \, dx}{2 b^2}\\ &=\frac{\left (1+2 a+2 a^2\right ) \sqrt{1-a-b x} \sqrt{1+a+b x}}{2 b^3}+\frac{(1+4 a) (1-a-b x)^{3/2} \sqrt{1+a+b x}}{6 b^3}-\frac{x (1-a-b x)^{3/2} \sqrt{1+a+b x}}{3 b^2}+\frac{\left (1+2 a+2 a^2\right ) \int \frac{1}{\sqrt{1-a-b x} \sqrt{1+a+b x}} \, dx}{2 b^2}\\ &=\frac{\left (1+2 a+2 a^2\right ) \sqrt{1-a-b x} \sqrt{1+a+b x}}{2 b^3}+\frac{(1+4 a) (1-a-b x)^{3/2} \sqrt{1+a+b x}}{6 b^3}-\frac{x (1-a-b x)^{3/2} \sqrt{1+a+b x}}{3 b^2}+\frac{\left (1+2 a+2 a^2\right ) \int \frac{1}{\sqrt{(1-a) (1+a)-2 a b x-b^2 x^2}} \, dx}{2 b^2}\\ &=\frac{\left (1+2 a+2 a^2\right ) \sqrt{1-a-b x} \sqrt{1+a+b x}}{2 b^3}+\frac{(1+4 a) (1-a-b x)^{3/2} \sqrt{1+a+b x}}{6 b^3}-\frac{x (1-a-b x)^{3/2} \sqrt{1+a+b x}}{3 b^2}-\frac{\left (1+2 a+2 a^2\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{1-\frac{x^2}{4 b^2}}} \, dx,x,-2 a b-2 b^2 x\right )}{4 b^4}\\ &=\frac{\left (1+2 a+2 a^2\right ) \sqrt{1-a-b x} \sqrt{1+a+b x}}{2 b^3}+\frac{(1+4 a) (1-a-b x)^{3/2} \sqrt{1+a+b x}}{6 b^3}-\frac{x (1-a-b x)^{3/2} \sqrt{1+a+b x}}{3 b^2}+\frac{\left (1+2 a+2 a^2\right ) \sin ^{-1}(a+b x)}{2 b^3}\\ \end{align*}
Mathematica [A] time = 0.156885, size = 126, normalized size = 0.97 \[ \frac{\left (2 a^2+2 a+1\right ) \sqrt{-b} \sinh ^{-1}\left (\frac{\sqrt{-b} \sqrt{-a-b x+1}}{\sqrt{2} \sqrt{b}}\right )}{b^{7/2}}-\frac{\sqrt{a+b x+1} \left (2 a^3+7 a^2+a (8 b x-5)+2 b^3 x^3-5 b^2 x^2+7 b x-4\right )}{6 b^3 \sqrt{-a-b x+1}} \]
Warning: Unable to verify antiderivative.
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Maple [B] time = 0.04, size = 535, normalized size = 4.1 \begin{align*} -{\frac{1}{3\,{b}^{3}} \left ( -{b}^{2}{x}^{2}-2\,xab-{a}^{2}+1 \right ) ^{{\frac{3}{2}}}}-{\frac{ax}{{b}^{2}}\sqrt{-{b}^{2}{x}^{2}-2\,xab-{a}^{2}+1}}-{\frac{{a}^{2}}{{b}^{3}}\sqrt{-{b}^{2}{x}^{2}-2\,xab-{a}^{2}+1}}-{\frac{a}{{b}^{2}}\arctan \left ({\sqrt{{b}^{2}} \left ( x+{\frac{a}{b}} \right ){\frac{1}{\sqrt{-{b}^{2}{x}^{2}-2\,xab-{a}^{2}+1}}}} \right ){\frac{1}{\sqrt{{b}^{2}}}}}-{\frac{x}{2\,{b}^{2}}\sqrt{-{b}^{2}{x}^{2}-2\,xab-{a}^{2}+1}}-{\frac{a}{2\,{b}^{3}}\sqrt{-{b}^{2}{x}^{2}-2\,xab-{a}^{2}+1}}-{\frac{1}{2\,{b}^{2}}\arctan \left ({\sqrt{{b}^{2}} \left ( x+{\frac{a}{b}} \right ){\frac{1}{\sqrt{-{b}^{2}{x}^{2}-2\,xab-{a}^{2}+1}}}} \right ){\frac{1}{\sqrt{{b}^{2}}}}}+{\frac{{a}^{2}}{{b}^{3}}\sqrt{- \left ( x+{\frac{1+a}{b}} \right ) ^{2}{b}^{2}+2\,b \left ( x+{\frac{1+a}{b}} \right ) }}+2\,{\frac{a}{{b}^{3}}\sqrt{- \left ( x+{\frac{1+a}{b}} \right ) ^{2}{b}^{2}+2\,b \left ( x+{\frac{1+a}{b}} \right ) }}+{\frac{1}{{b}^{3}}\sqrt{- \left ( x+{\frac{1+a}{b}} \right ) ^{2}{b}^{2}+2\,b \left ( x+{\frac{1+a}{b}} \right ) }}+{\frac{{a}^{2}}{{b}^{2}}\arctan \left ({\sqrt{{b}^{2}} \left ( x+{\frac{1+a}{b}}-{b}^{-1} \right ){\frac{1}{\sqrt{- \left ( x+{\frac{1+a}{b}} \right ) ^{2}{b}^{2}+2\,b \left ( x+{\frac{1+a}{b}} \right ) }}}} \right ){\frac{1}{\sqrt{{b}^{2}}}}}+2\,{\frac{a}{{b}^{2}\sqrt{{b}^{2}}}\arctan \left ({\sqrt{{b}^{2}} \left ( x+{\frac{1+a}{b}}-{b}^{-1} \right ){\frac{1}{\sqrt{- \left ( x+{\frac{1+a}{b}} \right ) ^{2}{b}^{2}+2\,b \left ( x+{\frac{1+a}{b}} \right ) }}}} \right ) }+{\frac{1}{{b}^{2}}\arctan \left ({\sqrt{{b}^{2}} \left ( x+{\frac{1+a}{b}}-{b}^{-1} \right ){\frac{1}{\sqrt{- \left ( x+{\frac{1+a}{b}} \right ) ^{2}{b}^{2}+2\,b \left ( x+{\frac{1+a}{b}} \right ) }}}} \right ){\frac{1}{\sqrt{{b}^{2}}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.46141, size = 235, normalized size = 1.81 \begin{align*} -\frac{\sqrt{-b^{2} x^{2} - 2 \, a b x - a^{2} + 1} a x}{b^{2}} + \frac{a^{2} \arcsin \left (b x + a\right )}{b^{3}} - \frac{\sqrt{-b^{2} x^{2} - 2 \, a b x - a^{2} + 1} x}{2 \, b^{2}} + \frac{a \arcsin \left (b x + a\right )}{b^{3}} - \frac{{\left (-b^{2} x^{2} - 2 \, a b x - a^{2} + 1\right )}^{\frac{3}{2}}}{3 \, b^{3}} + \frac{3 \, \sqrt{-b^{2} x^{2} - 2 \, a b x - a^{2} + 1} a}{2 \, b^{3}} + \frac{\arcsin \left (b x + a\right )}{2 \, b^{3}} + \frac{\sqrt{-b^{2} x^{2} - 2 \, a b x - a^{2} + 1}}{b^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.89475, size = 267, normalized size = 2.05 \begin{align*} -\frac{3 \,{\left (2 \, a^{2} + 2 \, a + 1\right )} \arctan \left (\frac{\sqrt{-b^{2} x^{2} - 2 \, a b x - a^{2} + 1}{\left (b x + a\right )}}{b^{2} x^{2} + 2 \, a b x + a^{2} - 1}\right ) -{\left (2 \, b^{2} x^{2} -{\left (2 \, a + 3\right )} b x + 2 \, a^{2} + 9 \, a + 4\right )} \sqrt{-b^{2} x^{2} - 2 \, a b x - a^{2} + 1}}{6 \, b^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{2} \sqrt{- \left (a + b x - 1\right ) \left (a + b x + 1\right )}}{a + b x + 1}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.19987, size = 143, normalized size = 1.1 \begin{align*} \frac{1}{6} \, \sqrt{-b^{2} x^{2} - 2 \, a b x - a^{2} + 1}{\left (x{\left (\frac{2 \, x}{b} - \frac{2 \, a b^{3} + 3 \, b^{3}}{b^{5}}\right )} + \frac{2 \, a^{2} b^{2} + 9 \, a b^{2} + 4 \, b^{2}}{b^{5}}\right )} - \frac{{\left (2 \, a^{2} + 2 \, a + 1\right )} \arcsin \left (-b x - a\right ) \mathrm{sgn}\left (b\right )}{2 \, b^{2}{\left | b \right |}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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