Optimal. Leaf size=203 \[ -\frac{a^2 \sinh ^{-1}(a+b x)^3}{2 b^2}-\frac{3 (a+b x) \sqrt{(a+b x)^2+1}}{8 b^2}+\frac{6 a \sqrt{(a+b x)^2+1}}{b^2}+\frac{\sinh ^{-1}(a+b x)^3}{4 b^2}-\frac{3 (a+b x) \sqrt{(a+b x)^2+1} \sinh ^{-1}(a+b x)^2}{4 b^2}+\frac{3 a \sqrt{(a+b x)^2+1} \sinh ^{-1}(a+b x)^2}{b^2}+\frac{3 (a+b x)^2 \sinh ^{-1}(a+b x)}{4 b^2}-\frac{6 a (a+b x) \sinh ^{-1}(a+b x)}{b^2}+\frac{3 \sinh ^{-1}(a+b x)}{8 b^2}+\frac{1}{2} x^2 \sinh ^{-1}(a+b x)^3 \]
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Rubi [A] time = 0.30306, antiderivative size = 203, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 10, integrand size = 10, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 1., Rules used = {5865, 5801, 5831, 3317, 3296, 2638, 3311, 30, 2635, 8} \[ -\frac{a^2 \sinh ^{-1}(a+b x)^3}{2 b^2}-\frac{3 (a+b x) \sqrt{(a+b x)^2+1}}{8 b^2}+\frac{6 a \sqrt{(a+b x)^2+1}}{b^2}+\frac{\sinh ^{-1}(a+b x)^3}{4 b^2}-\frac{3 (a+b x) \sqrt{(a+b x)^2+1} \sinh ^{-1}(a+b x)^2}{4 b^2}+\frac{3 a \sqrt{(a+b x)^2+1} \sinh ^{-1}(a+b x)^2}{b^2}+\frac{3 (a+b x)^2 \sinh ^{-1}(a+b x)}{4 b^2}-\frac{6 a (a+b x) \sinh ^{-1}(a+b x)}{b^2}+\frac{3 \sinh ^{-1}(a+b x)}{8 b^2}+\frac{1}{2} x^2 \sinh ^{-1}(a+b x)^3 \]
Antiderivative was successfully verified.
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Rule 5865
Rule 5801
Rule 5831
Rule 3317
Rule 3296
Rule 2638
Rule 3311
Rule 30
Rule 2635
Rule 8
Rubi steps
\begin{align*} \int x \sinh ^{-1}(a+b x)^3 \, dx &=\frac{\operatorname{Subst}\left (\int \left (-\frac{a}{b}+\frac{x}{b}\right ) \sinh ^{-1}(x)^3 \, dx,x,a+b x\right )}{b}\\ &=\frac{1}{2} x^2 \sinh ^{-1}(a+b x)^3-\frac{3}{2} \operatorname{Subst}\left (\int \frac{\left (-\frac{a}{b}+\frac{x}{b}\right )^2 \sinh ^{-1}(x)^2}{\sqrt{1+x^2}} \, dx,x,a+b x\right )\\ &=\frac{1}{2} x^2 \sinh ^{-1}(a+b x)^3-\frac{3}{2} \operatorname{Subst}\left (\int x^2 \left (-\frac{a}{b}+\frac{\sinh (x)}{b}\right )^2 \, dx,x,\sinh ^{-1}(a+b x)\right )\\ &=\frac{1}{2} x^2 \sinh ^{-1}(a+b x)^3-\frac{3}{2} \operatorname{Subst}\left (\int \left (\frac{a^2 x^2}{b^2}-\frac{2 a x^2 \sinh (x)}{b^2}+\frac{x^2 \sinh ^2(x)}{b^2}\right ) \, dx,x,\sinh ^{-1}(a+b x)\right )\\ &=-\frac{a^2 \sinh ^{-1}(a+b x)^3}{2 b^2}+\frac{1}{2} x^2 \sinh ^{-1}(a+b x)^3-\frac{3 \operatorname{Subst}\left (\int x^2 \sinh ^2(x) \, dx,x,\sinh ^{-1}(a+b x)\right )}{2 b^2}+\frac{(3 a) \operatorname{Subst}\left (\int x^2 \sinh (x) \, dx,x,\sinh ^{-1}(a+b x)\right )}{b^2}\\ &=\frac{3 (a+b x)^2 \sinh ^{-1}(a+b x)}{4 b^2}+\frac{3 a \sqrt{1+(a+b x)^2} \sinh ^{-1}(a+b x)^2}{b^2}-\frac{3 (a+b x) \sqrt{1+(a+b x)^2} \sinh ^{-1}(a+b x)^2}{4 b^2}-\frac{a^2 \sinh ^{-1}(a+b x)^3}{2 b^2}+\frac{1}{2} x^2 \sinh ^{-1}(a+b x)^3+\frac{3 \operatorname{Subst}\left (\int x^2 \, dx,x,\sinh ^{-1}(a+b x)\right )}{4 b^2}-\frac{3 \operatorname{Subst}\left (\int \sinh ^2(x) \, dx,x,\sinh ^{-1}(a+b x)\right )}{4 b^2}-\frac{(6 a) \operatorname{Subst}\left (\int x \cosh (x) \, dx,x,\sinh ^{-1}(a+b x)\right )}{b^2}\\ &=-\frac{3 (a+b x) \sqrt{1+(a+b x)^2}}{8 b^2}-\frac{6 a (a+b x) \sinh ^{-1}(a+b x)}{b^2}+\frac{3 (a+b x)^2 \sinh ^{-1}(a+b x)}{4 b^2}+\frac{3 a \sqrt{1+(a+b x)^2} \sinh ^{-1}(a+b x)^2}{b^2}-\frac{3 (a+b x) \sqrt{1+(a+b x)^2} \sinh ^{-1}(a+b x)^2}{4 b^2}+\frac{\sinh ^{-1}(a+b x)^3}{4 b^2}-\frac{a^2 \sinh ^{-1}(a+b x)^3}{2 b^2}+\frac{1}{2} x^2 \sinh ^{-1}(a+b x)^3+\frac{3 \operatorname{Subst}\left (\int 1 \, dx,x,\sinh ^{-1}(a+b x)\right )}{8 b^2}+\frac{(6 a) \operatorname{Subst}\left (\int \sinh (x) \, dx,x,\sinh ^{-1}(a+b x)\right )}{b^2}\\ &=\frac{6 a \sqrt{1+(a+b x)^2}}{b^2}-\frac{3 (a+b x) \sqrt{1+(a+b x)^2}}{8 b^2}+\frac{3 \sinh ^{-1}(a+b x)}{8 b^2}-\frac{6 a (a+b x) \sinh ^{-1}(a+b x)}{b^2}+\frac{3 (a+b x)^2 \sinh ^{-1}(a+b x)}{4 b^2}+\frac{3 a \sqrt{1+(a+b x)^2} \sinh ^{-1}(a+b x)^2}{b^2}-\frac{3 (a+b x) \sqrt{1+(a+b x)^2} \sinh ^{-1}(a+b x)^2}{4 b^2}+\frac{\sinh ^{-1}(a+b x)^3}{4 b^2}-\frac{a^2 \sinh ^{-1}(a+b x)^3}{2 b^2}+\frac{1}{2} x^2 \sinh ^{-1}(a+b x)^3\\ \end{align*}
Mathematica [A] time = 0.126947, size = 129, normalized size = 0.64 \[ \frac{3 (15 a-b x) \sqrt{a^2+2 a b x+b^2 x^2+1}+\left (-4 a^2+4 b^2 x^2+2\right ) \sinh ^{-1}(a+b x)^3+6 (3 a-b x) \sqrt{a^2+2 a b x+b^2 x^2+1} \sinh ^{-1}(a+b x)^2+\left (-42 a^2-36 a b x+6 b^2 x^2+3\right ) \sinh ^{-1}(a+b x)}{8 b^2} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.042, size = 169, normalized size = 0.8 \begin{align*}{\frac{1}{{b}^{2}} \left ({\frac{ \left ({\it Arcsinh} \left ( bx+a \right ) \right ) ^{3} \left ( 1+ \left ( bx+a \right ) ^{2} \right ) }{2}}-{\frac{3\, \left ({\it Arcsinh} \left ( bx+a \right ) \right ) ^{2} \left ( bx+a \right ) }{4}\sqrt{1+ \left ( bx+a \right ) ^{2}}}-{\frac{ \left ({\it Arcsinh} \left ( bx+a \right ) \right ) ^{3}}{4}}+{\frac{3\,{\it Arcsinh} \left ( bx+a \right ) \left ( 1+ \left ( bx+a \right ) ^{2} \right ) }{4}}-{\frac{3\,bx+3\,a}{8}\sqrt{1+ \left ( bx+a \right ) ^{2}}}-{\frac{3\,{\it Arcsinh} \left ( bx+a \right ) }{8}}-a \left ( \left ({\it Arcsinh} \left ( bx+a \right ) \right ) ^{3} \left ( bx+a \right ) -3\, \left ({\it Arcsinh} \left ( bx+a \right ) \right ) ^{2}\sqrt{1+ \left ( bx+a \right ) ^{2}}+6\, \left ( bx+a \right ){\it Arcsinh} \left ( bx+a \right ) -6\,\sqrt{1+ \left ( bx+a \right ) ^{2}} \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.46764, size = 444, normalized size = 2.19 \begin{align*} \frac{2 \,{\left (2 \, b^{2} x^{2} - 2 \, a^{2} + 1\right )} \log \left (b x + a + \sqrt{b^{2} x^{2} + 2 \, a b x + a^{2} + 1}\right )^{3} - 6 \, \sqrt{b^{2} x^{2} + 2 \, a b x + a^{2} + 1}{\left (b x - 3 \, a\right )} \log \left (b x + a + \sqrt{b^{2} x^{2} + 2 \, a b x + a^{2} + 1}\right )^{2} + 3 \,{\left (2 \, b^{2} x^{2} - 12 \, a b x - 14 \, a^{2} + 1\right )} \log \left (b x + a + \sqrt{b^{2} x^{2} + 2 \, a b x + a^{2} + 1}\right ) - 3 \, \sqrt{b^{2} x^{2} + 2 \, a b x + a^{2} + 1}{\left (b x - 15 \, a\right )}}{8 \, b^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 1.65634, size = 248, normalized size = 1.22 \begin{align*} \begin{cases} - \frac{a^{2} \operatorname{asinh}^{3}{\left (a + b x \right )}}{2 b^{2}} - \frac{21 a^{2} \operatorname{asinh}{\left (a + b x \right )}}{4 b^{2}} - \frac{9 a x \operatorname{asinh}{\left (a + b x \right )}}{2 b} + \frac{9 a \sqrt{a^{2} + 2 a b x + b^{2} x^{2} + 1} \operatorname{asinh}^{2}{\left (a + b x \right )}}{4 b^{2}} + \frac{45 a \sqrt{a^{2} + 2 a b x + b^{2} x^{2} + 1}}{8 b^{2}} + \frac{x^{2} \operatorname{asinh}^{3}{\left (a + b x \right )}}{2} + \frac{3 x^{2} \operatorname{asinh}{\left (a + b x \right )}}{4} - \frac{3 x \sqrt{a^{2} + 2 a b x + b^{2} x^{2} + 1} \operatorname{asinh}^{2}{\left (a + b x \right )}}{4 b} - \frac{3 x \sqrt{a^{2} + 2 a b x + b^{2} x^{2} + 1}}{8 b} + \frac{\operatorname{asinh}^{3}{\left (a + b x \right )}}{4 b^{2}} + \frac{3 \operatorname{asinh}{\left (a + b x \right )}}{8 b^{2}} & \text{for}\: b \neq 0 \\\frac{x^{2} \operatorname{asinh}^{3}{\left (a \right )}}{2} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x \operatorname{arsinh}\left (b x + a\right )^{3}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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