3.266 \(\int (1+a^2+2 a b x+b^2 x^2)^{3/2} \sinh ^{-1}(a+b x)^3 \, dx\)

Optimal. Leaf size=235 \[ -\frac{3 (a+b x)^4}{128 b}-\frac{51 (a+b x)^2}{128 b}-\frac{9 (a+b x)^2 \sinh ^{-1}(a+b x)^2}{16 b}+\frac{\left ((a+b x)^2+1\right )^{3/2} (a+b x) \sinh ^{-1}(a+b x)^3}{4 b}+\frac{3 \sqrt{(a+b x)^2+1} (a+b x) \sinh ^{-1}(a+b x)^3}{8 b}+\frac{3 \left ((a+b x)^2+1\right )^{3/2} (a+b x) \sinh ^{-1}(a+b x)}{32 b}+\frac{45 \sqrt{(a+b x)^2+1} (a+b x) \sinh ^{-1}(a+b x)}{64 b}+\frac{3 \sinh ^{-1}(a+b x)^4}{32 b}-\frac{3 \left ((a+b x)^2+1\right )^2 \sinh ^{-1}(a+b x)^2}{16 b}-\frac{27 \sinh ^{-1}(a+b x)^2}{128 b} \]

[Out]

(-51*(a + b*x)^2)/(128*b) - (3*(a + b*x)^4)/(128*b) + (45*(a + b*x)*Sqrt[1 + (a + b*x)^2]*ArcSinh[a + b*x])/(6
4*b) + (3*(a + b*x)*(1 + (a + b*x)^2)^(3/2)*ArcSinh[a + b*x])/(32*b) - (27*ArcSinh[a + b*x]^2)/(128*b) - (9*(a
+ b*x)^2*ArcSinh[a + b*x]^2)/(16*b) - (3*(1 + (a + b*x)^2)^2*ArcSinh[a + b*x]^2)/(16*b) + (3*(a + b*x)*Sqrt[1
+ (a + b*x)^2]*ArcSinh[a + b*x]^3)/(8*b) + ((a + b*x)*(1 + (a + b*x)^2)^(3/2)*ArcSinh[a + b*x]^3)/(4*b) + (3*
ArcSinh[a + b*x]^4)/(32*b)

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Rubi [A]  time = 0.309131, antiderivative size = 235, normalized size of antiderivative = 1., number of steps used = 15, number of rules used = 9, integrand size = 30, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.3, Rules used = {5867, 5684, 5682, 5675, 5661, 5758, 30, 5717, 14} \[ -\frac{3 (a+b x)^4}{128 b}-\frac{51 (a+b x)^2}{128 b}-\frac{9 (a+b x)^2 \sinh ^{-1}(a+b x)^2}{16 b}+\frac{\left ((a+b x)^2+1\right )^{3/2} (a+b x) \sinh ^{-1}(a+b x)^3}{4 b}+\frac{3 \sqrt{(a+b x)^2+1} (a+b x) \sinh ^{-1}(a+b x)^3}{8 b}+\frac{3 \left ((a+b x)^2+1\right )^{3/2} (a+b x) \sinh ^{-1}(a+b x)}{32 b}+\frac{45 \sqrt{(a+b x)^2+1} (a+b x) \sinh ^{-1}(a+b x)}{64 b}+\frac{3 \sinh ^{-1}(a+b x)^4}{32 b}-\frac{3 \left ((a+b x)^2+1\right )^2 \sinh ^{-1}(a+b x)^2}{16 b}-\frac{27 \sinh ^{-1}(a+b x)^2}{128 b} \]

Antiderivative was successfully verified.

[In]

Int[(1 + a^2 + 2*a*b*x + b^2*x^2)^(3/2)*ArcSinh[a + b*x]^3,x]

[Out]

(-51*(a + b*x)^2)/(128*b) - (3*(a + b*x)^4)/(128*b) + (45*(a + b*x)*Sqrt[1 + (a + b*x)^2]*ArcSinh[a + b*x])/(6
4*b) + (3*(a + b*x)*(1 + (a + b*x)^2)^(3/2)*ArcSinh[a + b*x])/(32*b) - (27*ArcSinh[a + b*x]^2)/(128*b) - (9*(a
+ b*x)^2*ArcSinh[a + b*x]^2)/(16*b) - (3*(1 + (a + b*x)^2)^2*ArcSinh[a + b*x]^2)/(16*b) + (3*(a + b*x)*Sqrt[1
+ (a + b*x)^2]*ArcSinh[a + b*x]^3)/(8*b) + ((a + b*x)*(1 + (a + b*x)^2)^(3/2)*ArcSinh[a + b*x]^3)/(4*b) + (3*
ArcSinh[a + b*x]^4)/(32*b)

Rule 5867

Int[((a_.) + ArcSinh[(c_) + (d_.)*(x_)]*(b_.))^(n_.)*((A_.) + (B_.)*(x_) + (C_.)*(x_)^2)^(p_.), x_Symbol] :> D
ist[1/d, Subst[Int[(C/d^2 + (C*x^2)/d^2)^p*(a + b*ArcSinh[x])^n, x], x, c + d*x], x] /; FreeQ[{a, b, c, d, A,
B, C, n, p}, x] && EqQ[B*(1 + c^2) - 2*A*c*d, 0] && EqQ[2*c*C - B*d, 0]

Rule 5684

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)*((d_) + (e_.)*(x_)^2)^(p_.), x_Symbol] :> Simp[(x*(d + e*x^2)^p*
(a + b*ArcSinh[c*x])^n)/(2*p + 1), x] + (Dist[(2*d*p)/(2*p + 1), Int[(d + e*x^2)^(p - 1)*(a + b*ArcSinh[c*x])^
n, x], x] - Dist[(b*c*n*d^IntPart[p]*(d + e*x^2)^FracPart[p])/((2*p + 1)*(1 + c^2*x^2)^FracPart[p]), Int[x*(1
+ c^2*x^2)^(p - 1/2)*(a + b*ArcSinh[c*x])^(n - 1), x], x]) /; FreeQ[{a, b, c, d, e}, x] && EqQ[e, c^2*d] && Gt
Q[n, 0] && GtQ[p, 0]

Rule 5682

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)*Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> Simp[(x*Sqrt[d + e*x^2]*
(a + b*ArcSinh[c*x])^n)/2, x] + (Dist[Sqrt[d + e*x^2]/(2*Sqrt[1 + c^2*x^2]), Int[(a + b*ArcSinh[c*x])^n/Sqrt[1
+ c^2*x^2], x], x] - Dist[(b*c*n*Sqrt[d + e*x^2])/(2*Sqrt[1 + c^2*x^2]), Int[x*(a + b*ArcSinh[c*x])^(n - 1),
x], x]) /; FreeQ[{a, b, c, d, e}, x] && EqQ[e, c^2*d] && GtQ[n, 0]

Rule 5675

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)/Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> Simp[(a + b*ArcSinh[c*x]
)^(n + 1)/(b*c*Sqrt[d]*(n + 1)), x] /; FreeQ[{a, b, c, d, e, n}, x] && EqQ[e, c^2*d] && GtQ[d, 0] && NeQ[n, -1
]

Rule 5661

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)*((d_.)*(x_))^(m_.), x_Symbol] :> Simp[((d*x)^(m + 1)*(a + b*ArcS
inh[c*x])^n)/(d*(m + 1)), x] - Dist[(b*c*n)/(d*(m + 1)), Int[((d*x)^(m + 1)*(a + b*ArcSinh[c*x])^(n - 1))/Sqrt
[1 + c^2*x^2], x], x] /; FreeQ[{a, b, c, d, m}, x] && IGtQ[n, 0] && NeQ[m, -1]

Rule 5758

Int[(((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)*((f_.)*(x_))^(m_))/Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> Simp
[(f*(f*x)^(m - 1)*Sqrt[d + e*x^2]*(a + b*ArcSinh[c*x])^n)/(e*m), x] + (-Dist[(f^2*(m - 1))/(c^2*m), Int[((f*x)
^(m - 2)*(a + b*ArcSinh[c*x])^n)/Sqrt[d + e*x^2], x], x] - Dist[(b*f*n*Sqrt[1 + c^2*x^2])/(c*m*Sqrt[d + e*x^2]
), Int[(f*x)^(m - 1)*(a + b*ArcSinh[c*x])^(n - 1), x], x]) /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[e, c^2*d] &&
GtQ[n, 0] && GtQ[m, 1] && IntegerQ[m]

Rule 30

Int[(x_)^(m_.), x_Symbol] :> Simp[x^(m + 1)/(m + 1), x] /; FreeQ[m, x] && NeQ[m, -1]

Rule 5717

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)*(x_)*((d_) + (e_.)*(x_)^2)^(p_.), x_Symbol] :> Simp[((d + e*x^2)
^(p + 1)*(a + b*ArcSinh[c*x])^n)/(2*e*(p + 1)), x] - Dist[(b*n*d^IntPart[p]*(d + e*x^2)^FracPart[p])/(2*c*(p +
1)*(1 + c^2*x^2)^FracPart[p]), Int[(1 + c^2*x^2)^(p + 1/2)*(a + b*ArcSinh[c*x])^(n - 1), x], x] /; FreeQ[{a,
b, c, d, e, p}, x] && EqQ[e, c^2*d] && GtQ[n, 0] && NeQ[p, -1]

Rule 14

Int[(u_)*((c_.)*(x_))^(m_.), x_Symbol] :> Int[ExpandIntegrand[(c*x)^m*u, x], x] /; FreeQ[{c, m}, x] && SumQ[u]
&&  !LinearQ[u, x] &&  !MatchQ[u, (a_) + (b_.)*(v_) /; FreeQ[{a, b}, x] && InverseFunctionQ[v]]

Rubi steps

\begin{align*} \int \left (1+a^2+2 a b x+b^2 x^2\right )^{3/2} \sinh ^{-1}(a+b x)^3 \, dx &=\frac{\operatorname{Subst}\left (\int \left (1+x^2\right )^{3/2} \sinh ^{-1}(x)^3 \, dx,x,a+b x\right )}{b}\\ &=\frac{(a+b x) \left (1+(a+b x)^2\right )^{3/2} \sinh ^{-1}(a+b x)^3}{4 b}-\frac{3 \operatorname{Subst}\left (\int x \left (1+x^2\right ) \sinh ^{-1}(x)^2 \, dx,x,a+b x\right )}{4 b}+\frac{3 \operatorname{Subst}\left (\int \sqrt{1+x^2} \sinh ^{-1}(x)^3 \, dx,x,a+b x\right )}{4 b}\\ &=-\frac{3 \left (1+(a+b x)^2\right )^2 \sinh ^{-1}(a+b x)^2}{16 b}+\frac{3 (a+b x) \sqrt{1+(a+b x)^2} \sinh ^{-1}(a+b x)^3}{8 b}+\frac{(a+b x) \left (1+(a+b x)^2\right )^{3/2} \sinh ^{-1}(a+b x)^3}{4 b}+\frac{3 \operatorname{Subst}\left (\int \left (1+x^2\right )^{3/2} \sinh ^{-1}(x) \, dx,x,a+b x\right )}{8 b}+\frac{3 \operatorname{Subst}\left (\int \frac{\sinh ^{-1}(x)^3}{\sqrt{1+x^2}} \, dx,x,a+b x\right )}{8 b}-\frac{9 \operatorname{Subst}\left (\int x \sinh ^{-1}(x)^2 \, dx,x,a+b x\right )}{8 b}\\ &=\frac{3 (a+b x) \left (1+(a+b x)^2\right )^{3/2} \sinh ^{-1}(a+b x)}{32 b}-\frac{9 (a+b x)^2 \sinh ^{-1}(a+b x)^2}{16 b}-\frac{3 \left (1+(a+b x)^2\right )^2 \sinh ^{-1}(a+b x)^2}{16 b}+\frac{3 (a+b x) \sqrt{1+(a+b x)^2} \sinh ^{-1}(a+b x)^3}{8 b}+\frac{(a+b x) \left (1+(a+b x)^2\right )^{3/2} \sinh ^{-1}(a+b x)^3}{4 b}+\frac{3 \sinh ^{-1}(a+b x)^4}{32 b}-\frac{3 \operatorname{Subst}\left (\int x \left (1+x^2\right ) \, dx,x,a+b x\right )}{32 b}+\frac{9 \operatorname{Subst}\left (\int \sqrt{1+x^2} \sinh ^{-1}(x) \, dx,x,a+b x\right )}{32 b}+\frac{9 \operatorname{Subst}\left (\int \frac{x^2 \sinh ^{-1}(x)}{\sqrt{1+x^2}} \, dx,x,a+b x\right )}{8 b}\\ &=\frac{45 (a+b x) \sqrt{1+(a+b x)^2} \sinh ^{-1}(a+b x)}{64 b}+\frac{3 (a+b x) \left (1+(a+b x)^2\right )^{3/2} \sinh ^{-1}(a+b x)}{32 b}-\frac{9 (a+b x)^2 \sinh ^{-1}(a+b x)^2}{16 b}-\frac{3 \left (1+(a+b x)^2\right )^2 \sinh ^{-1}(a+b x)^2}{16 b}+\frac{3 (a+b x) \sqrt{1+(a+b x)^2} \sinh ^{-1}(a+b x)^3}{8 b}+\frac{(a+b x) \left (1+(a+b x)^2\right )^{3/2} \sinh ^{-1}(a+b x)^3}{4 b}+\frac{3 \sinh ^{-1}(a+b x)^4}{32 b}-\frac{3 \operatorname{Subst}\left (\int \left (x+x^3\right ) \, dx,x,a+b x\right )}{32 b}-\frac{9 \operatorname{Subst}(\int x \, dx,x,a+b x)}{64 b}+\frac{9 \operatorname{Subst}\left (\int \frac{\sinh ^{-1}(x)}{\sqrt{1+x^2}} \, dx,x,a+b x\right )}{64 b}-\frac{9 \operatorname{Subst}(\int x \, dx,x,a+b x)}{16 b}-\frac{9 \operatorname{Subst}\left (\int \frac{\sinh ^{-1}(x)}{\sqrt{1+x^2}} \, dx,x,a+b x\right )}{16 b}\\ &=-\frac{51 (a+b x)^2}{128 b}-\frac{3 (a+b x)^4}{128 b}+\frac{45 (a+b x) \sqrt{1+(a+b x)^2} \sinh ^{-1}(a+b x)}{64 b}+\frac{3 (a+b x) \left (1+(a+b x)^2\right )^{3/2} \sinh ^{-1}(a+b x)}{32 b}-\frac{27 \sinh ^{-1}(a+b x)^2}{128 b}-\frac{9 (a+b x)^2 \sinh ^{-1}(a+b x)^2}{16 b}-\frac{3 \left (1+(a+b x)^2\right )^2 \sinh ^{-1}(a+b x)^2}{16 b}+\frac{3 (a+b x) \sqrt{1+(a+b x)^2} \sinh ^{-1}(a+b x)^3}{8 b}+\frac{(a+b x) \left (1+(a+b x)^2\right )^{3/2} \sinh ^{-1}(a+b x)^3}{4 b}+\frac{3 \sinh ^{-1}(a+b x)^4}{32 b}\\ \end{align*}

Mathematica [A]  time = 0.228042, size = 266, normalized size = 1.13 \[ -\frac{3 \left (6 a^2+17\right ) b^2 x^2-16 \sqrt{a^2+2 a b x+b^2 x^2+1} \left (6 a^2 b x+2 a^3+6 a b^2 x^2+5 a+2 b^3 x^3+5 b x\right ) \sinh ^{-1}(a+b x)^3+3 \left (8 a^2 \left (6 b^2 x^2+5\right )+32 a^3 b x+8 a^4+16 a b x \left (2 b^2 x^2+5\right )+8 b^4 x^4+40 b^2 x^2+17\right ) \sinh ^{-1}(a+b x)^2-6 \sqrt{a^2+2 a b x+b^2 x^2+1} \left (6 a^2 b x+2 a^3+6 a b^2 x^2+17 a+2 b^3 x^3+17 b x\right ) \sinh ^{-1}(a+b x)+6 a \left (2 a^2+17\right ) b x+12 a b^3 x^3-12 \sinh ^{-1}(a+b x)^4+3 b^4 x^4}{128 b} \]

Antiderivative was successfully verified.

[In]

Integrate[(1 + a^2 + 2*a*b*x + b^2*x^2)^(3/2)*ArcSinh[a + b*x]^3,x]

[Out]

-(6*a*(17 + 2*a^2)*b*x + 3*(17 + 6*a^2)*b^2*x^2 + 12*a*b^3*x^3 + 3*b^4*x^4 - 6*Sqrt[1 + a^2 + 2*a*b*x + b^2*x^
2]*(17*a + 2*a^3 + 17*b*x + 6*a^2*b*x + 6*a*b^2*x^2 + 2*b^3*x^3)*ArcSinh[a + b*x] + 3*(17 + 8*a^4 + 32*a^3*b*x
+ 40*b^2*x^2 + 8*b^4*x^4 + 16*a*b*x*(5 + 2*b^2*x^2) + 8*a^2*(5 + 6*b^2*x^2))*ArcSinh[a + b*x]^2 - 16*Sqrt[1 +
a^2 + 2*a*b*x + b^2*x^2]*(5*a + 2*a^3 + 5*b*x + 6*a^2*b*x + 6*a*b^2*x^2 + 2*b^3*x^3)*ArcSinh[a + b*x]^3 - 12*
ArcSinh[a + b*x]^4)/(128*b)

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Maple [B]  time = 0.066, size = 592, normalized size = 2.5 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b^2*x^2+2*a*b*x+a^2+1)^(3/2)*arcsinh(b*x+a)^3,x)

[Out]

1/128*(-48-51*a^2+96*arcsinh(b*x+a)^3*(b^2*x^2+2*a*b*x+a^2+1)^(1/2)*x*a^2*b+80*arcsinh(b*x+a)^3*(b^2*x^2+2*a*b
*x+a^2+1)^(1/2)*a+102*arcsinh(b*x+a)*(b^2*x^2+2*a*b*x+a^2+1)^(1/2)*a+80*arcsinh(b*x+a)^3*(b^2*x^2+2*a*b*x+a^2+
1)^(1/2)*x*b-240*arcsinh(b*x+a)^2*x*a*b+102*arcsinh(b*x+a)*(b^2*x^2+2*a*b*x+a^2+1)^(1/2)*x*b-12*x^3*a*b^3-102*
x*a*b-120*arcsinh(b*x+a)^2*x^2*b^2-3*a^4+12*arcsinh(b*x+a)^4-51*arcsinh(b*x+a)^2+36*arcsinh(b*x+a)*(b^2*x^2+2*
a*b*x+a^2+1)^(1/2)*x^2*a*b^2+36*arcsinh(b*x+a)*(b^2*x^2+2*a*b*x+a^2+1)^(1/2)*x*a^2*b+96*arcsinh(b*x+a)^3*(b^2*
x^2+2*a*b*x+a^2+1)^(1/2)*x^2*a*b^2+12*arcsinh(b*x+a)*(b^2*x^2+2*a*b*x+a^2+1)^(1/2)*a^3+32*arcsinh(b*x+a)^3*(b^
2*x^2+2*a*b*x+a^2+1)^(1/2)*a^3-24*arcsinh(b*x+a)^2*x^4*b^4-18*x^2*a^2*b^2-12*x*a^3*b+32*arcsinh(b*x+a)^3*(b^2*
x^2+2*a*b*x+a^2+1)^(1/2)*x^3*b^3+12*arcsinh(b*x+a)*(b^2*x^2+2*a*b*x+a^2+1)^(1/2)*x^3*b^3-96*arcsinh(b*x+a)^2*x
^3*a*b^3-144*arcsinh(b*x+a)^2*x^2*a^2*b^2-96*arcsinh(b*x+a)^2*x*a^3*b-51*b^2*x^2-120*arcsinh(b*x+a)^2*a^2-24*a
rcsinh(b*x+a)^2*a^4-3*x^4*b^4)/b

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Maxima [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b^2*x^2+2*a*b*x+a^2+1)^(3/2)*arcsinh(b*x+a)^3,x, algorithm="maxima")

[Out]

Exception raised: ValueError

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Fricas [A]  time = 2.87411, size = 792, normalized size = 3.37 \begin{align*} -\frac{3 \, b^{4} x^{4} + 12 \, a b^{3} x^{3} + 3 \,{\left (6 \, a^{2} + 17\right )} b^{2} x^{2} - 16 \,{\left (2 \, b^{3} x^{3} + 6 \, a b^{2} x^{2} + 2 \, a^{3} +{\left (6 \, a^{2} + 5\right )} b x + 5 \, a\right )} \sqrt{b^{2} x^{2} + 2 \, a b x + a^{2} + 1} \log \left (b x + a + \sqrt{b^{2} x^{2} + 2 \, a b x + a^{2} + 1}\right )^{3} - 12 \, \log \left (b x + a + \sqrt{b^{2} x^{2} + 2 \, a b x + a^{2} + 1}\right )^{4} + 6 \,{\left (2 \, a^{3} + 17 \, a\right )} b x + 3 \,{\left (8 \, b^{4} x^{4} + 32 \, a b^{3} x^{3} + 8 \,{\left (6 \, a^{2} + 5\right )} b^{2} x^{2} + 8 \, a^{4} + 16 \,{\left (2 \, a^{3} + 5 \, a\right )} b x + 40 \, a^{2} + 17\right )} \log \left (b x + a + \sqrt{b^{2} x^{2} + 2 \, a b x + a^{2} + 1}\right )^{2} - 6 \,{\left (2 \, b^{3} x^{3} + 6 \, a b^{2} x^{2} + 2 \, a^{3} +{\left (6 \, a^{2} + 17\right )} b x + 17 \, a\right )} \sqrt{b^{2} x^{2} + 2 \, a b x + a^{2} + 1} \log \left (b x + a + \sqrt{b^{2} x^{2} + 2 \, a b x + a^{2} + 1}\right )}{128 \, b} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b^2*x^2+2*a*b*x+a^2+1)^(3/2)*arcsinh(b*x+a)^3,x, algorithm="fricas")

[Out]

-1/128*(3*b^4*x^4 + 12*a*b^3*x^3 + 3*(6*a^2 + 17)*b^2*x^2 - 16*(2*b^3*x^3 + 6*a*b^2*x^2 + 2*a^3 + (6*a^2 + 5)*
b*x + 5*a)*sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1)*log(b*x + a + sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1))^3 - 12*log(b*x +
a + sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1))^4 + 6*(2*a^3 + 17*a)*b*x + 3*(8*b^4*x^4 + 32*a*b^3*x^3 + 8*(6*a^2 + 5)
*b^2*x^2 + 8*a^4 + 16*(2*a^3 + 5*a)*b*x + 40*a^2 + 17)*log(b*x + a + sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1))^2 - 6*
(2*b^3*x^3 + 6*a*b^2*x^2 + 2*a^3 + (6*a^2 + 17)*b*x + 17*a)*sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1)*log(b*x + a + sq
rt(b^2*x^2 + 2*a*b*x + a^2 + 1)))/b

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Sympy [A]  time = 33.7999, size = 694, normalized size = 2.95 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b**2*x**2+2*a*b*x+a**2+1)**(3/2)*asinh(b*x+a)**3,x)

[Out]

Piecewise((-3*a**4*asinh(a + b*x)**2/(16*b) - 3*a**3*x*asinh(a + b*x)**2/4 - 3*a**3*x/32 + a**3*sqrt(a**2 + 2*
a*b*x + b**2*x**2 + 1)*asinh(a + b*x)**3/(4*b) + 3*a**3*sqrt(a**2 + 2*a*b*x + b**2*x**2 + 1)*asinh(a + b*x)/(3
2*b) - 9*a**2*b*x**2*asinh(a + b*x)**2/8 - 9*a**2*b*x**2/64 + 3*a**2*x*sqrt(a**2 + 2*a*b*x + b**2*x**2 + 1)*as
inh(a + b*x)**3/4 + 9*a**2*x*sqrt(a**2 + 2*a*b*x + b**2*x**2 + 1)*asinh(a + b*x)/32 - 15*a**2*asinh(a + b*x)**
2/(16*b) - 3*a*b**2*x**3*asinh(a + b*x)**2/4 - 3*a*b**2*x**3/32 + 3*a*b*x**2*sqrt(a**2 + 2*a*b*x + b**2*x**2 +
1)*asinh(a + b*x)**3/4 + 9*a*b*x**2*sqrt(a**2 + 2*a*b*x + b**2*x**2 + 1)*asinh(a + b*x)/32 - 15*a*x*asinh(a +
b*x)**2/8 - 51*a*x/64 + 5*a*sqrt(a**2 + 2*a*b*x + b**2*x**2 + 1)*asinh(a + b*x)**3/(8*b) + 51*a*sqrt(a**2 + 2
*a*b*x + b**2*x**2 + 1)*asinh(a + b*x)/(64*b) - 3*b**3*x**4*asinh(a + b*x)**2/16 - 3*b**3*x**4/128 + b**2*x**3
*sqrt(a**2 + 2*a*b*x + b**2*x**2 + 1)*asinh(a + b*x)**3/4 + 3*b**2*x**3*sqrt(a**2 + 2*a*b*x + b**2*x**2 + 1)*a
sinh(a + b*x)/32 - 15*b*x**2*asinh(a + b*x)**2/16 - 51*b*x**2/128 + 5*x*sqrt(a**2 + 2*a*b*x + b**2*x**2 + 1)*a
sinh(a + b*x)**3/8 + 51*x*sqrt(a**2 + 2*a*b*x + b**2*x**2 + 1)*asinh(a + b*x)/64 + 3*asinh(a + b*x)**4/(32*b)
- 51*asinh(a + b*x)**2/(128*b), Ne(b, 0)), (x*(a**2 + 1)**(3/2)*asinh(a)**3, True))

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b^{2} x^{2} + 2 \, a b x + a^{2} + 1\right )}^{\frac{3}{2}} \operatorname{arsinh}\left (b x + a\right )^{3}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b^2*x^2+2*a*b*x+a^2+1)^(3/2)*arcsinh(b*x+a)^3,x, algorithm="giac")

[Out]

integrate((b^2*x^2 + 2*a*b*x + a^2 + 1)^(3/2)*arcsinh(b*x + a)^3, x)