3.19 \(\int \frac{1}{(b \text{csch}(c+d x))^{5/2}} \, dx\)

Optimal. Leaf size=90 \[ \frac{2 \cosh (c+d x)}{5 b d (b \text{csch}(c+d x))^{3/2}}+\frac{6 i E\left (\left .\frac{1}{2} \left (i c+i d x-\frac{\pi }{2}\right )\right |2\right )}{5 b^2 d \sqrt{i \sinh (c+d x)} \sqrt{b \text{csch}(c+d x)}} \]

[Out]

(2*Cosh[c + d*x])/(5*b*d*(b*Csch[c + d*x])^(3/2)) + (((6*I)/5)*EllipticE[(I*c - Pi/2 + I*d*x)/2, 2])/(b^2*d*Sq
rt[b*Csch[c + d*x]]*Sqrt[I*Sinh[c + d*x]])

________________________________________________________________________________________

Rubi [A]  time = 0.0382342, antiderivative size = 90, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 12, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.25, Rules used = {3769, 3771, 2639} \[ \frac{2 \cosh (c+d x)}{5 b d (b \text{csch}(c+d x))^{3/2}}+\frac{6 i E\left (\left .\frac{1}{2} \left (i c+i d x-\frac{\pi }{2}\right )\right |2\right )}{5 b^2 d \sqrt{i \sinh (c+d x)} \sqrt{b \text{csch}(c+d x)}} \]

Antiderivative was successfully verified.

[In]

Int[(b*Csch[c + d*x])^(-5/2),x]

[Out]

(2*Cosh[c + d*x])/(5*b*d*(b*Csch[c + d*x])^(3/2)) + (((6*I)/5)*EllipticE[(I*c - Pi/2 + I*d*x)/2, 2])/(b^2*d*Sq
rt[b*Csch[c + d*x]]*Sqrt[I*Sinh[c + d*x]])

Rule 3769

Int[(csc[(c_.) + (d_.)*(x_)]*(b_.))^(n_), x_Symbol] :> Simp[(Cos[c + d*x]*(b*Csc[c + d*x])^(n + 1))/(b*d*n), x
] + Dist[(n + 1)/(b^2*n), Int[(b*Csc[c + d*x])^(n + 2), x], x] /; FreeQ[{b, c, d}, x] && LtQ[n, -1] && Integer
Q[2*n]

Rule 3771

Int[(csc[(c_.) + (d_.)*(x_)]*(b_.))^(n_), x_Symbol] :> Dist[(b*Csc[c + d*x])^n*Sin[c + d*x]^n, Int[1/Sin[c + d
*x]^n, x], x] /; FreeQ[{b, c, d}, x] && EqQ[n^2, 1/4]

Rule 2639

Int[Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2*EllipticE[(1*(c - Pi/2 + d*x))/2, 2])/d, x] /; FreeQ[{
c, d}, x]

Rubi steps

\begin{align*} \int \frac{1}{(b \text{csch}(c+d x))^{5/2}} \, dx &=\frac{2 \cosh (c+d x)}{5 b d (b \text{csch}(c+d x))^{3/2}}-\frac{3 \int \frac{1}{\sqrt{b \text{csch}(c+d x)}} \, dx}{5 b^2}\\ &=\frac{2 \cosh (c+d x)}{5 b d (b \text{csch}(c+d x))^{3/2}}-\frac{3 \int \sqrt{i \sinh (c+d x)} \, dx}{5 b^2 \sqrt{b \text{csch}(c+d x)} \sqrt{i \sinh (c+d x)}}\\ &=\frac{2 \cosh (c+d x)}{5 b d (b \text{csch}(c+d x))^{3/2}}+\frac{6 i E\left (\left .\frac{1}{2} \left (i c-\frac{\pi }{2}+i d x\right )\right |2\right )}{5 b^2 d \sqrt{b \text{csch}(c+d x)} \sqrt{i \sinh (c+d x)}}\\ \end{align*}

Mathematica [A]  time = 0.13045, size = 68, normalized size = 0.76 \[ \frac{\sinh (2 (c+d x))-\frac{6 i E\left (\left .\frac{1}{4} (-2 i c-2 i d x+\pi )\right |2\right )}{\sqrt{i \sinh (c+d x)}}}{5 b^2 d \sqrt{b \text{csch}(c+d x)}} \]

Antiderivative was successfully verified.

[In]

Integrate[(b*Csch[c + d*x])^(-5/2),x]

[Out]

(((-6*I)*EllipticE[((-2*I)*c + Pi - (2*I)*d*x)/4, 2])/Sqrt[I*Sinh[c + d*x]] + Sinh[2*(c + d*x)])/(5*b^2*d*Sqrt
[b*Csch[c + d*x]])

________________________________________________________________________________________

Maple [F]  time = 0.069, size = 0, normalized size = 0. \begin{align*} \int \left ( b{\rm csch} \left (dx+c\right ) \right ) ^{-{\frac{5}{2}}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(b*csch(d*x+c))^(5/2),x)

[Out]

int(1/(b*csch(d*x+c))^(5/2),x)

________________________________________________________________________________________

Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\left (b \operatorname{csch}\left (d x + c\right )\right )^{\frac{5}{2}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*csch(d*x+c))^(5/2),x, algorithm="maxima")

[Out]

integrate((b*csch(d*x + c))^(-5/2), x)

________________________________________________________________________________________

Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{b \operatorname{csch}\left (d x + c\right )}}{b^{3} \operatorname{csch}\left (d x + c\right )^{3}}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*csch(d*x+c))^(5/2),x, algorithm="fricas")

[Out]

integral(sqrt(b*csch(d*x + c))/(b^3*csch(d*x + c)^3), x)

________________________________________________________________________________________

Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\left (b \operatorname{csch}{\left (c + d x \right )}\right )^{\frac{5}{2}}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*csch(d*x+c))**(5/2),x)

[Out]

Integral((b*csch(c + d*x))**(-5/2), x)

________________________________________________________________________________________

Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\left (b \operatorname{csch}\left (d x + c\right )\right )^{\frac{5}{2}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*csch(d*x+c))^(5/2),x, algorithm="giac")

[Out]

integrate((b*csch(d*x + c))^(-5/2), x)