3.33 \(\int \sqrt [3]{b \sinh (c+d x)} \, dx\)

Optimal. Leaf size=60 \[ \frac{3 \cosh (c+d x) (b \sinh (c+d x))^{4/3} \, _2F_1\left (\frac{1}{2},\frac{2}{3};\frac{5}{3};-\sinh ^2(c+d x)\right )}{4 b d \sqrt{\cosh ^2(c+d x)}} \]

[Out]

(3*Cosh[c + d*x]*Hypergeometric2F1[1/2, 2/3, 5/3, -Sinh[c + d*x]^2]*(b*Sinh[c + d*x])^(4/3))/(4*b*d*Sqrt[Cosh[
c + d*x]^2])

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Rubi [A]  time = 0.0163367, antiderivative size = 60, normalized size of antiderivative = 1., number of steps used = 1, number of rules used = 1, integrand size = 12, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.083, Rules used = {2643} \[ \frac{3 \cosh (c+d x) (b \sinh (c+d x))^{4/3} \, _2F_1\left (\frac{1}{2},\frac{2}{3};\frac{5}{3};-\sinh ^2(c+d x)\right )}{4 b d \sqrt{\cosh ^2(c+d x)}} \]

Antiderivative was successfully verified.

[In]

Int[(b*Sinh[c + d*x])^(1/3),x]

[Out]

(3*Cosh[c + d*x]*Hypergeometric2F1[1/2, 2/3, 5/3, -Sinh[c + d*x]^2]*(b*Sinh[c + d*x])^(4/3))/(4*b*d*Sqrt[Cosh[
c + d*x]^2])

Rule 2643

Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(Cos[c + d*x]*(b*Sin[c + d*x])^(n + 1)*Hypergeomet
ric2F1[1/2, (n + 1)/2, (n + 3)/2, Sin[c + d*x]^2])/(b*d*(n + 1)*Sqrt[Cos[c + d*x]^2]), x] /; FreeQ[{b, c, d, n
}, x] &&  !IntegerQ[2*n]

Rubi steps

\begin{align*} \int \sqrt [3]{b \sinh (c+d x)} \, dx &=\frac{3 \cosh (c+d x) \, _2F_1\left (\frac{1}{2},\frac{2}{3};\frac{5}{3};-\sinh ^2(c+d x)\right ) (b \sinh (c+d x))^{4/3}}{4 b d \sqrt{\cosh ^2(c+d x)}}\\ \end{align*}

Mathematica [A]  time = 0.0342486, size = 57, normalized size = 0.95 \[ \frac{3 \sqrt{\cosh ^2(c+d x)} \tanh (c+d x) \sqrt [3]{b \sinh (c+d x)} \, _2F_1\left (\frac{1}{2},\frac{2}{3};\frac{5}{3};-\sinh ^2(c+d x)\right )}{4 d} \]

Antiderivative was successfully verified.

[In]

Integrate[(b*Sinh[c + d*x])^(1/3),x]

[Out]

(3*Sqrt[Cosh[c + d*x]^2]*Hypergeometric2F1[1/2, 2/3, 5/3, -Sinh[c + d*x]^2]*(b*Sinh[c + d*x])^(1/3)*Tanh[c + d
*x])/(4*d)

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Maple [F]  time = 0.059, size = 0, normalized size = 0. \begin{align*} \int \sqrt [3]{b\sinh \left ( dx+c \right ) }\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*sinh(d*x+c))^(1/3),x)

[Out]

int((b*sinh(d*x+c))^(1/3),x)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (b \sinh \left (d x + c\right )\right )^{\frac{1}{3}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*sinh(d*x+c))^(1/3),x, algorithm="maxima")

[Out]

integrate((b*sinh(d*x + c))^(1/3), x)

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Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\left (b \sinh \left (d x + c\right )\right )^{\frac{1}{3}}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*sinh(d*x+c))^(1/3),x, algorithm="fricas")

[Out]

integral((b*sinh(d*x + c))^(1/3), x)

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt [3]{b \sinh{\left (c + d x \right )}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*sinh(d*x+c))**(1/3),x)

[Out]

Integral((b*sinh(c + d*x))**(1/3), x)

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (b \sinh \left (d x + c\right )\right )^{\frac{1}{3}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*sinh(d*x+c))^(1/3),x, algorithm="giac")

[Out]

integrate((b*sinh(d*x + c))^(1/3), x)