Optimal. Leaf size=281 \[ \frac{i \sqrt{(a+b x)^2+1} \text{PolyLog}\left (2,-\frac{i \sqrt{1+i (a+b x)}}{\sqrt{1-i (a+b x)}}\right )}{2 b \sqrt{c (a+b x)^2+c}}-\frac{i \sqrt{(a+b x)^2+1} \text{PolyLog}\left (2,\frac{i \sqrt{1+i (a+b x)}}{\sqrt{1-i (a+b x)}}\right )}{2 b \sqrt{c (a+b x)^2+c}}+\frac{\sqrt{c (a+b x)^2+c}}{2 b c}+\frac{(a+b x) \sqrt{c (a+b x)^2+c} \cot ^{-1}(a+b x)}{2 b c}+\frac{i \sqrt{(a+b x)^2+1} \tan ^{-1}\left (\frac{\sqrt{1+i (a+b x)}}{\sqrt{1-i (a+b x)}}\right ) \cot ^{-1}(a+b x)}{b \sqrt{c (a+b x)^2+c}} \]
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Rubi [A] time = 0.3486, antiderivative size = 281, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 40, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.125, Rules used = {5058, 4953, 261, 4891, 4887} \[ \frac{i \sqrt{(a+b x)^2+1} \text{PolyLog}\left (2,-\frac{i \sqrt{1+i (a+b x)}}{\sqrt{1-i (a+b x)}}\right )}{2 b \sqrt{c (a+b x)^2+c}}-\frac{i \sqrt{(a+b x)^2+1} \text{PolyLog}\left (2,\frac{i \sqrt{1+i (a+b x)}}{\sqrt{1-i (a+b x)}}\right )}{2 b \sqrt{c (a+b x)^2+c}}+\frac{\sqrt{c (a+b x)^2+c}}{2 b c}+\frac{(a+b x) \sqrt{c (a+b x)^2+c} \cot ^{-1}(a+b x)}{2 b c}+\frac{i \sqrt{(a+b x)^2+1} \tan ^{-1}\left (\frac{\sqrt{1+i (a+b x)}}{\sqrt{1-i (a+b x)}}\right ) \cot ^{-1}(a+b x)}{b \sqrt{c (a+b x)^2+c}} \]
Antiderivative was successfully verified.
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Rule 5058
Rule 4953
Rule 261
Rule 4891
Rule 4887
Rubi steps
\begin{align*} \int \frac{(a+b x)^2 \cot ^{-1}(a+b x)}{\sqrt{\left (1+a^2\right ) c+2 a b c x+b^2 c x^2}} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{x^2 \cot ^{-1}(x)}{\sqrt{c+c x^2}} \, dx,x,a+b x\right )}{b}\\ &=\frac{(a+b x) \sqrt{c+c (a+b x)^2} \cot ^{-1}(a+b x)}{2 b c}+\frac{\operatorname{Subst}\left (\int \frac{x}{\sqrt{c+c x^2}} \, dx,x,a+b x\right )}{2 b}-\frac{\operatorname{Subst}\left (\int \frac{\cot ^{-1}(x)}{\sqrt{c+c x^2}} \, dx,x,a+b x\right )}{2 b}\\ &=\frac{\sqrt{c+c (a+b x)^2}}{2 b c}+\frac{(a+b x) \sqrt{c+c (a+b x)^2} \cot ^{-1}(a+b x)}{2 b c}-\frac{\sqrt{1+(a+b x)^2} \operatorname{Subst}\left (\int \frac{\cot ^{-1}(x)}{\sqrt{1+x^2}} \, dx,x,a+b x\right )}{2 b \sqrt{c+c (a+b x)^2}}\\ &=\frac{\sqrt{c+c (a+b x)^2}}{2 b c}+\frac{(a+b x) \sqrt{c+c (a+b x)^2} \cot ^{-1}(a+b x)}{2 b c}+\frac{i \sqrt{1+(a+b x)^2} \cot ^{-1}(a+b x) \tan ^{-1}\left (\frac{\sqrt{1+i (a+b x)}}{\sqrt{1-i (a+b x)}}\right )}{b \sqrt{c+c (a+b x)^2}}+\frac{i \sqrt{1+(a+b x)^2} \text{Li}_2\left (-\frac{i \sqrt{1+i (a+b x)}}{\sqrt{1-i (a+b x)}}\right )}{2 b \sqrt{c+c (a+b x)^2}}-\frac{i \sqrt{1+(a+b x)^2} \text{Li}_2\left (\frac{i \sqrt{1+i (a+b x)}}{\sqrt{1-i (a+b x)}}\right )}{2 b \sqrt{c+c (a+b x)^2}}\\ \end{align*}
Mathematica [A] time = 0.900675, size = 207, normalized size = 0.74 \[ -\frac{\sqrt{c \left (a^2+2 a b x+b^2 x^2+1\right )} \left (-4 i \text{PolyLog}\left (2,-e^{i \cot ^{-1}(a+b x)}\right )+4 i \text{PolyLog}\left (2,e^{i \cot ^{-1}(a+b x)}\right )-2 \cot \left (\frac{1}{2} \cot ^{-1}(a+b x)\right )-4 \cot ^{-1}(a+b x) \log \left (1-e^{i \cot ^{-1}(a+b x)}\right )+4 \cot ^{-1}(a+b x) \log \left (1+e^{i \cot ^{-1}(a+b x)}\right )-2 \tan \left (\frac{1}{2} \cot ^{-1}(a+b x)\right )-\cot ^{-1}(a+b x) \csc ^2\left (\frac{1}{2} \cot ^{-1}(a+b x)\right )+\cot ^{-1}(a+b x) \sec ^2\left (\frac{1}{2} \cot ^{-1}(a+b x)\right )\right )}{8 b c (a+b x) \sqrt{\frac{1}{(a+b x)^2}+1}} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 1.1, size = 202, normalized size = 0.7 \begin{align*}{\frac{{\rm arccot} \left (bx+a\right )xb+{\rm arccot} \left (bx+a\right )a+1}{2\,cb}\sqrt{c \left ( -i+a+bx \right ) \left ( i+a+bx \right ) }}-{\frac{{\frac{i}{2}}}{cb} \left ( i{\rm arccot} \left (bx+a\right )\ln \left ( 1-{(i+a+bx){\frac{1}{\sqrt{1+ \left ( bx+a \right ) ^{2}}}}} \right ) -i{\rm arccot} \left (bx+a\right )\ln \left ( 1+{(i+a+bx){\frac{1}{\sqrt{1+ \left ( bx+a \right ) ^{2}}}}} \right ) -{\it polylog} \left ( 2,-{(i+a+bx){\frac{1}{\sqrt{1+ \left ( bx+a \right ) ^{2}}}}} \right ) +{\it polylog} \left ( 2,{(i+a+bx){\frac{1}{\sqrt{1+ \left ( bx+a \right ) ^{2}}}}} \right ) \right ) \sqrt{c \left ( -i+a+bx \right ) \left ( i+a+bx \right ) }{\frac{1}{\sqrt{{b}^{2}{x}^{2}+2\,xab+{a}^{2}+1}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )} \operatorname{arccot}\left (b x + a\right )}{\sqrt{b^{2} c x^{2} + 2 \, a b c x +{\left (a^{2} + 1\right )} c}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b x + a\right )}^{2} \operatorname{arccot}\left (b x + a\right )}{\sqrt{b^{2} c x^{2} + 2 \, a b c x +{\left (a^{2} + 1\right )} c}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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