Optimal. Leaf size=186 \[ -\frac{5 a b^2 \sqrt{1-(a+b x)^2}}{24 \left (1-a^2\right )^2 x^2}-\frac{\left (11 a^2+4\right ) b^3 \sqrt{1-(a+b x)^2}}{24 \left (1-a^2\right )^3 x}-\frac{a \left (2 a^2+3\right ) b^4 \tanh ^{-1}\left (\frac{1-a (a+b x)}{\sqrt{1-a^2} \sqrt{1-(a+b x)^2}}\right )}{8 \left (1-a^2\right )^{7/2}}-\frac{b \sqrt{1-(a+b x)^2}}{12 \left (1-a^2\right ) x^3}-\frac{\sin ^{-1}(a+b x)}{4 x^4} \]
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Rubi [A] time = 0.274316, antiderivative size = 186, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 7, integrand size = 10, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.7, Rules used = {4805, 4743, 745, 835, 807, 725, 206} \[ -\frac{5 a b^2 \sqrt{1-(a+b x)^2}}{24 \left (1-a^2\right )^2 x^2}-\frac{\left (11 a^2+4\right ) b^3 \sqrt{1-(a+b x)^2}}{24 \left (1-a^2\right )^3 x}-\frac{a \left (2 a^2+3\right ) b^4 \tanh ^{-1}\left (\frac{1-a (a+b x)}{\sqrt{1-a^2} \sqrt{1-(a+b x)^2}}\right )}{8 \left (1-a^2\right )^{7/2}}-\frac{b \sqrt{1-(a+b x)^2}}{12 \left (1-a^2\right ) x^3}-\frac{\sin ^{-1}(a+b x)}{4 x^4} \]
Antiderivative was successfully verified.
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Rule 4805
Rule 4743
Rule 745
Rule 835
Rule 807
Rule 725
Rule 206
Rubi steps
\begin{align*} \int \frac{\sin ^{-1}(a+b x)}{x^5} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{\sin ^{-1}(x)}{\left (-\frac{a}{b}+\frac{x}{b}\right )^5} \, dx,x,a+b x\right )}{b}\\ &=-\frac{\sin ^{-1}(a+b x)}{4 x^4}+\frac{1}{4} \operatorname{Subst}\left (\int \frac{1}{\left (-\frac{a}{b}+\frac{x}{b}\right )^4 \sqrt{1-x^2}} \, dx,x,a+b x\right )\\ &=-\frac{b \sqrt{1-(a+b x)^2}}{12 \left (1-a^2\right ) x^3}-\frac{\sin ^{-1}(a+b x)}{4 x^4}+\frac{b^2 \operatorname{Subst}\left (\int \frac{\frac{3 a}{b}+\frac{2 x}{b}}{\left (-\frac{a}{b}+\frac{x}{b}\right )^3 \sqrt{1-x^2}} \, dx,x,a+b x\right )}{12 \left (1-a^2\right )}\\ &=-\frac{b \sqrt{1-(a+b x)^2}}{12 \left (1-a^2\right ) x^3}-\frac{5 a b^2 \sqrt{1-(a+b x)^2}}{24 \left (1-a^2\right )^2 x^2}-\frac{\sin ^{-1}(a+b x)}{4 x^4}-\frac{b^4 \operatorname{Subst}\left (\int \frac{-\frac{2 \left (2+3 a^2\right )}{b^2}-\frac{5 a x}{b^2}}{\left (-\frac{a}{b}+\frac{x}{b}\right )^2 \sqrt{1-x^2}} \, dx,x,a+b x\right )}{24 \left (1-a^2\right )^2}\\ &=-\frac{b \sqrt{1-(a+b x)^2}}{12 \left (1-a^2\right ) x^3}-\frac{5 a b^2 \sqrt{1-(a+b x)^2}}{24 \left (1-a^2\right )^2 x^2}-\frac{\left (4+11 a^2\right ) b^3 \sqrt{1-(a+b x)^2}}{24 \left (1-a^2\right )^3 x}-\frac{\sin ^{-1}(a+b x)}{4 x^4}+\frac{\left (a \left (3+2 a^2\right ) b^3\right ) \operatorname{Subst}\left (\int \frac{1}{\left (-\frac{a}{b}+\frac{x}{b}\right ) \sqrt{1-x^2}} \, dx,x,a+b x\right )}{8 \left (1-a^2\right )^3}\\ &=-\frac{b \sqrt{1-(a+b x)^2}}{12 \left (1-a^2\right ) x^3}-\frac{5 a b^2 \sqrt{1-(a+b x)^2}}{24 \left (1-a^2\right )^2 x^2}-\frac{\left (4+11 a^2\right ) b^3 \sqrt{1-(a+b x)^2}}{24 \left (1-a^2\right )^3 x}-\frac{\sin ^{-1}(a+b x)}{4 x^4}-\frac{\left (a \left (3+2 a^2\right ) b^3\right ) \operatorname{Subst}\left (\int \frac{1}{\frac{1}{b^2}-\frac{a^2}{b^2}-x^2} \, dx,x,\frac{\frac{1}{b}-\frac{a (a+b x)}{b}}{\sqrt{1-(a+b x)^2}}\right )}{8 \left (1-a^2\right )^3}\\ &=-\frac{b \sqrt{1-(a+b x)^2}}{12 \left (1-a^2\right ) x^3}-\frac{5 a b^2 \sqrt{1-(a+b x)^2}}{24 \left (1-a^2\right )^2 x^2}-\frac{\left (4+11 a^2\right ) b^3 \sqrt{1-(a+b x)^2}}{24 \left (1-a^2\right )^3 x}-\frac{\sin ^{-1}(a+b x)}{4 x^4}-\frac{a \left (3+2 a^2\right ) b^4 \tanh ^{-1}\left (\frac{1-a (a+b x)}{\sqrt{1-a^2} \sqrt{1-(a+b x)^2}}\right )}{8 \left (1-a^2\right )^{7/2}}\\ \end{align*}
Mathematica [A] time = 0.225893, size = 194, normalized size = 1.04 \[ \frac{1}{8} \left (\frac{b \sqrt{-a^2-2 a b x-b^2 x^2+1} \left (a^2 \left (11 b^2 x^2-4\right )-5 a^3 b x+2 a^4+5 a b x+4 b^2 x^2+2\right )}{3 \left (a^2-1\right )^3 x^3}-\frac{a \left (2 a^2+3\right ) b^4 \log \left (\sqrt{1-a^2} \sqrt{-a^2-2 a b x-b^2 x^2+1}-a^2-a b x+1\right )}{\left (1-a^2\right )^{7/2}}+\frac{a \left (2 a^2+3\right ) b^4 \log (x)}{\left (1-a^2\right )^{7/2}}-\frac{2 \sin ^{-1}(a+b x)}{x^4}\right ) \]
Antiderivative was successfully verified.
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Maple [A] time = 0.007, size = 309, normalized size = 1.7 \begin{align*} -{\frac{\arcsin \left ( bx+a \right ) }{4\,{x}^{4}}}-{\frac{b}{ \left ( -12\,{a}^{2}+12 \right ){x}^{3}}\sqrt{-{b}^{2}{x}^{2}-2\,xab-{a}^{2}+1}}-{\frac{5\,{b}^{2}a}{24\, \left ( -{a}^{2}+1 \right ) ^{2}{x}^{2}}\sqrt{-{b}^{2}{x}^{2}-2\,xab-{a}^{2}+1}}-{\frac{5\,{b}^{3}{a}^{2}}{8\, \left ( -{a}^{2}+1 \right ) ^{3}x}\sqrt{-{b}^{2}{x}^{2}-2\,xab-{a}^{2}+1}}-{\frac{5\,{b}^{4}{a}^{3}}{8}\ln \left ({\frac{1}{bx} \left ( -2\,{a}^{2}+2-2\,xab+2\,\sqrt{-{a}^{2}+1}\sqrt{-{b}^{2}{x}^{2}-2\,xab-{a}^{2}+1} \right ) } \right ) \left ( -{a}^{2}+1 \right ) ^{-{\frac{7}{2}}}}-{\frac{3\,{b}^{4}a}{8}\ln \left ({\frac{1}{bx} \left ( -2\,{a}^{2}+2-2\,xab+2\,\sqrt{-{a}^{2}+1}\sqrt{-{b}^{2}{x}^{2}-2\,xab-{a}^{2}+1} \right ) } \right ) \left ( -{a}^{2}+1 \right ) ^{-{\frac{5}{2}}}}-{\frac{{b}^{3}}{6\, \left ( -{a}^{2}+1 \right ) ^{2}x}\sqrt{-{b}^{2}{x}^{2}-2\,xab-{a}^{2}+1}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 3.98883, size = 1115, normalized size = 5.99 \begin{align*} \left [-\frac{3 \,{\left (2 \, a^{3} + 3 \, a\right )} \sqrt{-a^{2} + 1} b^{4} x^{4} \log \left (\frac{{\left (2 \, a^{2} - 1\right )} b^{2} x^{2} + 2 \, a^{4} + 4 \,{\left (a^{3} - a\right )} b x - 2 \, \sqrt{-b^{2} x^{2} - 2 \, a b x - a^{2} + 1}{\left (a b x + a^{2} - 1\right )} \sqrt{-a^{2} + 1} - 4 \, a^{2} + 2}{x^{2}}\right ) + 12 \,{\left (a^{8} - 4 \, a^{6} + 6 \, a^{4} - 4 \, a^{2} + 1\right )} \arcsin \left (b x + a\right ) - 2 \,{\left ({\left (11 \, a^{4} - 7 \, a^{2} - 4\right )} b^{3} x^{3} - 5 \,{\left (a^{5} - 2 \, a^{3} + a\right )} b^{2} x^{2} + 2 \,{\left (a^{6} - 3 \, a^{4} + 3 \, a^{2} - 1\right )} b x\right )} \sqrt{-b^{2} x^{2} - 2 \, a b x - a^{2} + 1}}{48 \,{\left (a^{8} - 4 \, a^{6} + 6 \, a^{4} - 4 \, a^{2} + 1\right )} x^{4}}, -\frac{3 \,{\left (2 \, a^{3} + 3 \, a\right )} \sqrt{a^{2} - 1} b^{4} x^{4} \arctan \left (\frac{\sqrt{-b^{2} x^{2} - 2 \, a b x - a^{2} + 1}{\left (a b x + a^{2} - 1\right )} \sqrt{a^{2} - 1}}{{\left (a^{2} - 1\right )} b^{2} x^{2} + a^{4} + 2 \,{\left (a^{3} - a\right )} b x - 2 \, a^{2} + 1}\right ) + 6 \,{\left (a^{8} - 4 \, a^{6} + 6 \, a^{4} - 4 \, a^{2} + 1\right )} \arcsin \left (b x + a\right ) -{\left ({\left (11 \, a^{4} - 7 \, a^{2} - 4\right )} b^{3} x^{3} - 5 \,{\left (a^{5} - 2 \, a^{3} + a\right )} b^{2} x^{2} + 2 \,{\left (a^{6} - 3 \, a^{4} + 3 \, a^{2} - 1\right )} b x\right )} \sqrt{-b^{2} x^{2} - 2 \, a b x - a^{2} + 1}}{24 \,{\left (a^{8} - 4 \, a^{6} + 6 \, a^{4} - 4 \, a^{2} + 1\right )} x^{4}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{asin}{\left (a + b x \right )}}{x^{5}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.28311, size = 1501, normalized size = 8.07 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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