Optimal. Leaf size=58 \[ \frac{(b \cos (c+d x)-a \sin (c+d x))^3}{3 d}-\frac{\left (a^2+b^2\right ) (b \cos (c+d x)-a \sin (c+d x))}{d} \]
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Rubi [A] time = 0.0236529, antiderivative size = 58, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 1, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.053, Rules used = {3072} \[ \frac{(b \cos (c+d x)-a \sin (c+d x))^3}{3 d}-\frac{\left (a^2+b^2\right ) (b \cos (c+d x)-a \sin (c+d x))}{d} \]
Antiderivative was successfully verified.
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Rule 3072
Rubi steps
\begin{align*} \int (a \cos (c+d x)+b \sin (c+d x))^3 \, dx &=-\frac{\operatorname{Subst}\left (\int \left (a^2+b^2-x^2\right ) \, dx,x,b \cos (c+d x)-a \sin (c+d x)\right )}{d}\\ &=-\frac{\left (a^2+b^2\right ) (b \cos (c+d x)-a \sin (c+d x))}{d}+\frac{(b \cos (c+d x)-a \sin (c+d x))^3}{3 d}\\ \end{align*}
Mathematica [A] time = 0.336525, size = 81, normalized size = 1.4 \[ \frac{-9 b \left (a^2+b^2\right ) \cos (c+d x)+\left (b^3-3 a^2 b\right ) \cos (3 (c+d x))+2 a \sin (c+d x) \left (\left (a^2-3 b^2\right ) \cos (2 (c+d x))+5 a^2+3 b^2\right )}{12 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.055, size = 75, normalized size = 1.3 \begin{align*}{\frac{1}{d} \left ( -{\frac{{b}^{3} \left ( 2+ \left ( \sin \left ( dx+c \right ) \right ) ^{2} \right ) \cos \left ( dx+c \right ) }{3}}+a{b}^{2} \left ( \sin \left ( dx+c \right ) \right ) ^{3}-{a}^{2}b \left ( \cos \left ( dx+c \right ) \right ) ^{3}+{\frac{{a}^{3} \left ( 2+ \left ( \cos \left ( dx+c \right ) \right ) ^{2} \right ) \sin \left ( dx+c \right ) }{3}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.988474, size = 113, normalized size = 1.95 \begin{align*} -\frac{a^{2} b \cos \left (d x + c\right )^{3}}{d} + \frac{a b^{2} \sin \left (d x + c\right )^{3}}{d} - \frac{{\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} a^{3}}{3 \, d} + \frac{{\left (\cos \left (d x + c\right )^{3} - 3 \, \cos \left (d x + c\right )\right )} b^{3}}{3 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.63253, size = 173, normalized size = 2.98 \begin{align*} -\frac{3 \, b^{3} \cos \left (d x + c\right ) +{\left (3 \, a^{2} b - b^{3}\right )} \cos \left (d x + c\right )^{3} -{\left (2 \, a^{3} + 3 \, a b^{2} +{\left (a^{3} - 3 \, a b^{2}\right )} \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )}{3 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 0.722125, size = 117, normalized size = 2.02 \begin{align*} \begin{cases} \frac{2 a^{3} \sin ^{3}{\left (c + d x \right )}}{3 d} + \frac{a^{3} \sin{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{d} - \frac{a^{2} b \cos ^{3}{\left (c + d x \right )}}{d} + \frac{a b^{2} \sin ^{3}{\left (c + d x \right )}}{d} - \frac{b^{3} \sin ^{2}{\left (c + d x \right )} \cos{\left (c + d x \right )}}{d} - \frac{2 b^{3} \cos ^{3}{\left (c + d x \right )}}{3 d} & \text{for}\: d \neq 0 \\x \left (a \cos{\left (c \right )} + b \sin{\left (c \right )}\right )^{3} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.13192, size = 123, normalized size = 2.12 \begin{align*} -\frac{{\left (3 \, a^{2} b - b^{3}\right )} \cos \left (3 \, d x + 3 \, c\right )}{12 \, d} - \frac{3 \,{\left (a^{2} b + b^{3}\right )} \cos \left (d x + c\right )}{4 \, d} + \frac{{\left (a^{3} - 3 \, a b^{2}\right )} \sin \left (3 \, d x + 3 \, c\right )}{12 \, d} + \frac{3 \,{\left (a^{3} + a b^{2}\right )} \sin \left (d x + c\right )}{4 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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