Optimal. Leaf size=108 \[ -\frac{3 \left (a^2+b^2\right ) (b \cos (c+d x)-a \sin (c+d x)) (a \cos (c+d x)+b \sin (c+d x))}{8 d}+\frac{3}{8} x \left (a^2+b^2\right )^2-\frac{(b \cos (c+d x)-a \sin (c+d x)) (a \cos (c+d x)+b \sin (c+d x))^3}{4 d} \]
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Rubi [A] time = 0.0444016, antiderivative size = 108, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.105, Rules used = {3073, 8} \[ -\frac{3 \left (a^2+b^2\right ) (b \cos (c+d x)-a \sin (c+d x)) (a \cos (c+d x)+b \sin (c+d x))}{8 d}+\frac{3}{8} x \left (a^2+b^2\right )^2-\frac{(b \cos (c+d x)-a \sin (c+d x)) (a \cos (c+d x)+b \sin (c+d x))^3}{4 d} \]
Antiderivative was successfully verified.
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Rule 3073
Rule 8
Rubi steps
\begin{align*} \int (a \cos (c+d x)+b \sin (c+d x))^4 \, dx &=-\frac{(b \cos (c+d x)-a \sin (c+d x)) (a \cos (c+d x)+b \sin (c+d x))^3}{4 d}+\frac{1}{4} \left (3 \left (a^2+b^2\right )\right ) \int (a \cos (c+d x)+b \sin (c+d x))^2 \, dx\\ &=-\frac{3 \left (a^2+b^2\right ) (b \cos (c+d x)-a \sin (c+d x)) (a \cos (c+d x)+b \sin (c+d x))}{8 d}-\frac{(b \cos (c+d x)-a \sin (c+d x)) (a \cos (c+d x)+b \sin (c+d x))^3}{4 d}+\frac{1}{8} \left (3 \left (a^2+b^2\right )^2\right ) \int 1 \, dx\\ &=\frac{3}{8} \left (a^2+b^2\right )^2 x-\frac{3 \left (a^2+b^2\right ) (b \cos (c+d x)-a \sin (c+d x)) (a \cos (c+d x)+b \sin (c+d x))}{8 d}-\frac{(b \cos (c+d x)-a \sin (c+d x)) (a \cos (c+d x)+b \sin (c+d x))^3}{4 d}\\ \end{align*}
Mathematica [A] time = 0.317601, size = 107, normalized size = 0.99 \[ \frac{12 \left (a^2+b^2\right )^2 (c+d x)+8 \left (a^4-b^4\right ) \sin (2 (c+d x))+\left (-6 a^2 b^2+a^4+b^4\right ) \sin (4 (c+d x))-16 a b \left (a^2+b^2\right ) \cos (2 (c+d x))-4 a b \left (a^2-b^2\right ) \cos (4 (c+d x))}{32 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.085, size = 153, normalized size = 1.4 \begin{align*}{\frac{1}{d} \left ({b}^{4} \left ( -{\frac{\cos \left ( dx+c \right ) }{4} \left ( \left ( \sin \left ( dx+c \right ) \right ) ^{3}+{\frac{3\,\sin \left ( dx+c \right ) }{2}} \right ) }+{\frac{3\,dx}{8}}+{\frac{3\,c}{8}} \right ) +a{b}^{3} \left ( \sin \left ( dx+c \right ) \right ) ^{4}+6\,{a}^{2}{b}^{2} \left ( -1/4\,\sin \left ( dx+c \right ) \left ( \cos \left ( dx+c \right ) \right ) ^{3}+1/8\,\sin \left ( dx+c \right ) \cos \left ( dx+c \right ) +1/8\,dx+c/8 \right ) - \left ( \cos \left ( dx+c \right ) \right ) ^{4}{a}^{3}b+{a}^{4} \left ({\frac{\sin \left ( dx+c \right ) }{4} \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{3}+{\frac{3\,\cos \left ( dx+c \right ) }{2}} \right ) }+{\frac{3\,dx}{8}}+{\frac{3\,c}{8}} \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.01215, size = 184, normalized size = 1.7 \begin{align*} -\frac{a^{3} b \cos \left (d x + c\right )^{4}}{d} + \frac{a b^{3} \sin \left (d x + c\right )^{4}}{d} + \frac{{\left (12 \, d x + 12 \, c + \sin \left (4 \, d x + 4 \, c\right ) + 8 \, \sin \left (2 \, d x + 2 \, c\right )\right )} a^{4}}{32 \, d} + \frac{3 \,{\left (4 \, d x + 4 \, c - \sin \left (4 \, d x + 4 \, c\right )\right )} a^{2} b^{2}}{16 \, d} + \frac{{\left (12 \, d x + 12 \, c + \sin \left (4 \, d x + 4 \, c\right ) - 8 \, \sin \left (2 \, d x + 2 \, c\right )\right )} b^{4}}{32 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.49203, size = 273, normalized size = 2.53 \begin{align*} -\frac{16 \, a b^{3} \cos \left (d x + c\right )^{2} + 8 \,{\left (a^{3} b - a b^{3}\right )} \cos \left (d x + c\right )^{4} - 3 \,{\left (a^{4} + 2 \, a^{2} b^{2} + b^{4}\right )} d x -{\left (2 \,{\left (a^{4} - 6 \, a^{2} b^{2} + b^{4}\right )} \cos \left (d x + c\right )^{3} +{\left (3 \, a^{4} + 6 \, a^{2} b^{2} - 5 \, b^{4}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{8 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 1.74196, size = 406, normalized size = 3.76 \begin{align*} \begin{cases} \frac{3 a^{4} x \sin ^{4}{\left (c + d x \right )}}{8} + \frac{3 a^{4} x \sin ^{2}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{4} + \frac{3 a^{4} x \cos ^{4}{\left (c + d x \right )}}{8} + \frac{3 a^{4} \sin ^{3}{\left (c + d x \right )} \cos{\left (c + d x \right )}}{8 d} + \frac{5 a^{4} \sin{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{8 d} - \frac{a^{3} b \cos ^{4}{\left (c + d x \right )}}{d} + \frac{3 a^{2} b^{2} x \sin ^{4}{\left (c + d x \right )}}{4} + \frac{3 a^{2} b^{2} x \sin ^{2}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{2} + \frac{3 a^{2} b^{2} x \cos ^{4}{\left (c + d x \right )}}{4} + \frac{3 a^{2} b^{2} \sin ^{3}{\left (c + d x \right )} \cos{\left (c + d x \right )}}{4 d} - \frac{3 a^{2} b^{2} \sin{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{4 d} - \frac{2 a b^{3} \sin ^{2}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{d} - \frac{a b^{3} \cos ^{4}{\left (c + d x \right )}}{d} + \frac{3 b^{4} x \sin ^{4}{\left (c + d x \right )}}{8} + \frac{3 b^{4} x \sin ^{2}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{4} + \frac{3 b^{4} x \cos ^{4}{\left (c + d x \right )}}{8} - \frac{5 b^{4} \sin ^{3}{\left (c + d x \right )} \cos{\left (c + d x \right )}}{8 d} - \frac{3 b^{4} \sin{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{8 d} & \text{for}\: d \neq 0 \\x \left (a \cos{\left (c \right )} + b \sin{\left (c \right )}\right )^{4} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.13133, size = 165, normalized size = 1.53 \begin{align*} \frac{3}{8} \,{\left (a^{4} + 2 \, a^{2} b^{2} + b^{4}\right )} x - \frac{{\left (a^{3} b - a b^{3}\right )} \cos \left (4 \, d x + 4 \, c\right )}{8 \, d} - \frac{{\left (a^{3} b + a b^{3}\right )} \cos \left (2 \, d x + 2 \, c\right )}{2 \, d} + \frac{{\left (a^{4} - 6 \, a^{2} b^{2} + b^{4}\right )} \sin \left (4 \, d x + 4 \, c\right )}{32 \, d} + \frac{{\left (a^{4} - b^{4}\right )} \sin \left (2 \, d x + 2 \, c\right )}{4 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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