Optimal. Leaf size=237 \[ -\frac{f^2 \left (4 a e^2-b^2 f^2\right ) \left (2 d e-b f^2\right )^2}{16 e^4 \left (2 e \left (f \sqrt{a+\frac{x \left (b f^2+e^2 x\right )}{f^2}}+e x\right )+b f^2\right )}+\frac{f^2 \left (4 a e^2-b^2 f^2\right ) \left (2 d e-b f^2\right ) \log \left (2 e \left (f \sqrt{a+\frac{x \left (b f^2+e^2 x\right )}{f^2}}+e x\right )+b f^2\right )}{8 e^4}+\frac{f^2 \left (4 a e^2-b^2 f^2\right ) \left (f \sqrt{a+b x+\frac{e^2 x^2}{f^2}}+e x\right )}{8 e^3}+\frac{\left (f \sqrt{a+b x+\frac{e^2 x^2}{f^2}}+d+e x\right )^3}{6 e} \]
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Rubi [A] time = 0.239352, antiderivative size = 237, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.071, Rules used = {2116, 893} \[ -\frac{f^2 \left (4 a e^2-b^2 f^2\right ) \left (2 d e-b f^2\right )^2}{16 e^4 \left (2 e \left (f \sqrt{a+\frac{x \left (b f^2+e^2 x\right )}{f^2}}+e x\right )+b f^2\right )}+\frac{f^2 \left (4 a e^2-b^2 f^2\right ) \left (2 d e-b f^2\right ) \log \left (2 e \left (f \sqrt{a+\frac{x \left (b f^2+e^2 x\right )}{f^2}}+e x\right )+b f^2\right )}{8 e^4}+\frac{f^2 \left (4 a e^2-b^2 f^2\right ) \left (f \sqrt{a+b x+\frac{e^2 x^2}{f^2}}+e x\right )}{8 e^3}+\frac{\left (f \sqrt{a+b x+\frac{e^2 x^2}{f^2}}+d+e x\right )^3}{6 e} \]
Antiderivative was successfully verified.
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Rule 2116
Rule 893
Rubi steps
\begin{align*} \int \left (d+e x+f \sqrt{a+b x+\frac{e^2 x^2}{f^2}}\right )^2 \, dx &=2 \operatorname{Subst}\left (\int \frac{x^2 \left (d^2 e-(b d-a e) f^2-\left (2 d e-b f^2\right ) x+e x^2\right )}{\left (-2 d e+b f^2+2 e x\right )^2} \, dx,x,d+e x+f \sqrt{a+b x+\frac{e^2 x^2}{f^2}}\right )\\ &=2 \operatorname{Subst}\left (\int \left (\frac{4 a e^2 f^2-b^2 f^4}{16 e^3}+\frac{x^2}{4 e}+\frac{\left (4 a e^2-b^2 f^2\right ) \left (2 d e f-b f^3\right )^2}{16 e^3 \left (2 d e-b f^2-2 e x\right )^2}-\frac{f^2 \left (2 d e-b f^2\right ) \left (4 a e^2-b^2 f^2\right )}{8 e^3 \left (2 d e-b f^2-2 e x\right )}\right ) \, dx,x,d+e x+f \sqrt{a+b x+\frac{e^2 x^2}{f^2}}\right )\\ &=\frac{f^2 \left (4 a e^2-b^2 f^2\right ) \left (e x+f \sqrt{a+b x+\frac{e^2 x^2}{f^2}}\right )}{8 e^3}+\frac{\left (d+e x+f \sqrt{a+b x+\frac{e^2 x^2}{f^2}}\right )^3}{6 e}-\frac{f^2 \left (2 d e-b f^2\right )^2 \left (4 a e^2-b^2 f^2\right )}{16 e^4 \left (b f^2+2 e \left (e x+f \sqrt{a+\frac{x \left (b f^2+e^2 x\right )}{f^2}}\right )\right )}+\frac{f^2 \left (2 d e-b f^2\right ) \left (4 a e^2-b^2 f^2\right ) \log \left (b f^2+2 e \left (e x+f \sqrt{a+\frac{x \left (b f^2+e^2 x\right )}{f^2}}\right )\right )}{8 e^4}\\ \end{align*}
Mathematica [A] time = 0.33063, size = 213, normalized size = 0.9 \[ \frac{\frac{3 \left (b^2 f^2-4 a e^2\right ) \left (b f^3-2 d e f\right )^2}{2 e \left (f \sqrt{a+x \left (b+\frac{e^2 x}{f^2}\right )}+e x\right )+b f^2}+6 f^2 \left (b^2 f^2-4 a e^2\right ) \left (b f^2-2 d e\right ) \log \left (-2 e \left (f \sqrt{a+x \left (b+\frac{e^2 x}{f^2}\right )}+e x\right )-b f^2\right )+6 e f^2 \left (4 a e^2-b^2 f^2\right ) \left (f \sqrt{a+x \left (b+\frac{e^2 x}{f^2}\right )}+e x\right )+8 e^3 \left (f \sqrt{a+x \left (b+\frac{e^2 x}{f^2}\right )}+d+e x\right )^3}{48 e^4} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.005, size = 409, normalized size = 1.7 \begin{align*}{f}^{2}ax+{\frac{{f}^{2}{x}^{2}b}{2}}+{\frac{2\,{e}^{2}{x}^{3}}{3}}+{\frac{2\,{f}^{3}}{3\,e} \left ( a+bx+{\frac{{e}^{2}{x}^{2}}{{f}^{2}}} \right ) ^{{\frac{3}{2}}}}-{\frac{b{f}^{3}x}{2\,e}\sqrt{a+bx+{\frac{{e}^{2}{x}^{2}}{{f}^{2}}}}}-{\frac{{b}^{2}{f}^{5}}{4\,{e}^{3}}\sqrt{a+bx+{\frac{{e}^{2}{x}^{2}}{{f}^{2}}}}}-{\frac{b{f}^{3}a}{2\,e}\ln \left ({ \left ({\frac{b}{2}}+{\frac{{e}^{2}x}{{f}^{2}}} \right ){\frac{1}{\sqrt{{\frac{{e}^{2}}{{f}^{2}}}}}}}+\sqrt{a+bx+{\frac{{e}^{2}{x}^{2}}{{f}^{2}}}} \right ){\frac{1}{\sqrt{{\frac{{e}^{2}}{{f}^{2}}}}}}}+{\frac{{b}^{3}{f}^{5}}{8\,{e}^{3}}\ln \left ({ \left ({\frac{b}{2}}+{\frac{{e}^{2}x}{{f}^{2}}} \right ){\frac{1}{\sqrt{{\frac{{e}^{2}}{{f}^{2}}}}}}}+\sqrt{a+bx+{\frac{{e}^{2}{x}^{2}}{{f}^{2}}}} \right ){\frac{1}{\sqrt{{\frac{{e}^{2}}{{f}^{2}}}}}}}+fd\sqrt{a+bx+{\frac{{e}^{2}{x}^{2}}{{f}^{2}}}}x+{\frac{d{f}^{3}b}{2\,{e}^{2}}\sqrt{a+bx+{\frac{{e}^{2}{x}^{2}}{{f}^{2}}}}}+{dfa\ln \left ({ \left ({\frac{b}{2}}+{\frac{{e}^{2}x}{{f}^{2}}} \right ){\frac{1}{\sqrt{{\frac{{e}^{2}}{{f}^{2}}}}}}}+\sqrt{a+bx+{\frac{{e}^{2}{x}^{2}}{{f}^{2}}}} \right ){\frac{1}{\sqrt{{\frac{{e}^{2}}{{f}^{2}}}}}}}-{\frac{d{f}^{3}{b}^{2}}{4\,{e}^{2}}\ln \left ({ \left ({\frac{b}{2}}+{\frac{{e}^{2}x}{{f}^{2}}} \right ){\frac{1}{\sqrt{{\frac{{e}^{2}}{{f}^{2}}}}}}}+\sqrt{a+bx+{\frac{{e}^{2}{x}^{2}}{{f}^{2}}}} \right ){\frac{1}{\sqrt{{\frac{{e}^{2}}{{f}^{2}}}}}}}+e{x}^{2}d+x{d}^{2}+{\frac{{d}^{3}}{3\,e}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.51377, size = 460, normalized size = 1.94 \begin{align*} \frac{16 \, e^{6} x^{3} + 12 \,{\left (b e^{4} f^{2} + 2 \, d e^{5}\right )} x^{2} + 24 \,{\left (a e^{4} f^{2} + d^{2} e^{4}\right )} x - 3 \,{\left (b^{3} f^{6} + 8 \, a d e^{3} f^{2} - 2 \,{\left (b^{2} d e + 2 \, a b e^{2}\right )} f^{4}\right )} \log \left (-b f^{2} - 2 \, e^{2} x + 2 \, e f \sqrt{\frac{b f^{2} x + e^{2} x^{2} + a f^{2}}{f^{2}}}\right ) - 2 \,{\left (3 \, b^{2} e f^{5} - 8 \, e^{5} f x^{2} - 2 \,{\left (3 \, b d e^{2} + 4 \, a e^{3}\right )} f^{3} - 2 \,{\left (b e^{3} f^{3} + 6 \, d e^{4} f\right )} x\right )} \sqrt{\frac{b f^{2} x + e^{2} x^{2} + a f^{2}}{f^{2}}}}{24 \, e^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (d + e x + f \sqrt{a + b x + \frac{e^{2} x^{2}}{f^{2}}}\right )^{2}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.1727, size = 302, normalized size = 1.27 \begin{align*} \frac{1}{2} \, b f^{2} x^{2} + a f^{2} x + \frac{2}{3} \, x^{3} e^{2} + d x^{2} e + d^{2} x - \frac{1}{8} \,{\left (b^{3} f^{5}{\left | f \right |} - 2 \, b^{2} d f^{3}{\left | f \right |} e - 4 \, a b f^{3}{\left | f \right |} e^{2} + 8 \, a d f{\left | f \right |} e^{3}\right )} e^{\left (-4\right )} \log \left ({\left | -b f^{2} - 2 \,{\left (x e - \sqrt{b f^{2} x + a f^{2} + x^{2} e^{2}}\right )} e \right |}\right ) + \frac{1}{12} \, \sqrt{b f^{2} x + a f^{2} + x^{2} e^{2}}{\left (2 \,{\left (\frac{4 \, x{\left | f \right |} e}{f} + \frac{{\left (b f^{3}{\left | f \right |} e^{3} + 6 \, d f{\left | f \right |} e^{4}\right )} e^{\left (-4\right )}}{f^{2}}\right )} x - \frac{{\left (3 \, b^{2} f^{5}{\left | f \right |} e - 6 \, b d f^{3}{\left | f \right |} e^{2} - 8 \, a f^{3}{\left | f \right |} e^{3}\right )} e^{\left (-4\right )}}{f^{2}}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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