Optimal. Leaf size=303 \[ \frac{f^2 \left (4 a e^2-b^2 f^2\right ) \left (f \sqrt{a+b x+\frac{e^2 x^2}{f^2}}+d+e x\right )^2}{16 e^3}+\frac{f^2 \left (4 a e^2-b^2 f^2\right ) \left (2 d e-b f^2\right ) \left (f \sqrt{a+b x+\frac{e^2 x^2}{f^2}}+e x\right )}{8 e^4}-\frac{f^2 \left (4 a e^2-b^2 f^2\right ) \left (2 d e-b f^2\right )^3}{32 e^5 \left (2 e \left (f \sqrt{a+\frac{x \left (b f^2+e^2 x\right )}{f^2}}+e x\right )+b f^2\right )}+\frac{3 f^2 \left (4 a e^2-b^2 f^2\right ) \left (2 d e-b f^2\right )^2 \log \left (2 e \left (f \sqrt{a+\frac{x \left (b f^2+e^2 x\right )}{f^2}}+e x\right )+b f^2\right )}{32 e^5}+\frac{\left (f \sqrt{a+b x+\frac{e^2 x^2}{f^2}}+d+e x\right )^4}{8 e} \]
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Rubi [A] time = 0.384399, antiderivative size = 303, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.071, Rules used = {2116, 893} \[ \frac{f^2 \left (4 a e^2-b^2 f^2\right ) \left (f \sqrt{a+b x+\frac{e^2 x^2}{f^2}}+d+e x\right )^2}{16 e^3}+\frac{f^2 \left (4 a e^2-b^2 f^2\right ) \left (2 d e-b f^2\right ) \left (f \sqrt{a+b x+\frac{e^2 x^2}{f^2}}+e x\right )}{8 e^4}-\frac{f^2 \left (4 a e^2-b^2 f^2\right ) \left (2 d e-b f^2\right )^3}{32 e^5 \left (2 e \left (f \sqrt{a+\frac{x \left (b f^2+e^2 x\right )}{f^2}}+e x\right )+b f^2\right )}+\frac{3 f^2 \left (4 a e^2-b^2 f^2\right ) \left (2 d e-b f^2\right )^2 \log \left (2 e \left (f \sqrt{a+\frac{x \left (b f^2+e^2 x\right )}{f^2}}+e x\right )+b f^2\right )}{32 e^5}+\frac{\left (f \sqrt{a+b x+\frac{e^2 x^2}{f^2}}+d+e x\right )^4}{8 e} \]
Antiderivative was successfully verified.
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Rule 2116
Rule 893
Rubi steps
\begin{align*} \int \left (d+e x+f \sqrt{a+b x+\frac{e^2 x^2}{f^2}}\right )^3 \, dx &=2 \operatorname{Subst}\left (\int \frac{x^3 \left (d^2 e-(b d-a e) f^2-\left (2 d e-b f^2\right ) x+e x^2\right )}{\left (-2 d e+b f^2+2 e x\right )^2} \, dx,x,d+e x+f \sqrt{a+b x+\frac{e^2 x^2}{f^2}}\right )\\ &=2 \operatorname{Subst}\left (\int \left (\frac{f^2 \left (2 d e-b f^2\right ) \left (4 a e^2-b^2 f^2\right )}{16 e^4}+\frac{f^2 \left (4 a e^2-b^2 f^2\right ) x}{16 e^3}+\frac{x^3}{4 e}+\frac{f^2 \left (2 d e-b f^2\right )^3 \left (4 a e^2-b^2 f^2\right )}{32 e^4 \left (2 d e-b f^2-2 e x\right )^2}-\frac{3 \left (4 a e^2-b^2 f^2\right ) \left (2 d e f-b f^3\right )^2}{32 e^4 \left (2 d e-b f^2-2 e x\right )}\right ) \, dx,x,d+e x+f \sqrt{a+b x+\frac{e^2 x^2}{f^2}}\right )\\ &=\frac{f^2 \left (2 d e-b f^2\right ) \left (4 a e^2-b^2 f^2\right ) \left (e x+f \sqrt{a+b x+\frac{e^2 x^2}{f^2}}\right )}{8 e^4}+\frac{f^2 \left (4 a e^2-b^2 f^2\right ) \left (d+e x+f \sqrt{a+b x+\frac{e^2 x^2}{f^2}}\right )^2}{16 e^3}+\frac{\left (d+e x+f \sqrt{a+b x+\frac{e^2 x^2}{f^2}}\right )^4}{8 e}-\frac{f^2 \left (2 d e-b f^2\right )^3 \left (4 a e^2-b^2 f^2\right )}{32 e^5 \left (b f^2+2 e \left (e x+f \sqrt{a+\frac{x \left (b f^2+e^2 x\right )}{f^2}}\right )\right )}+\frac{3 f^2 \left (2 d e-b f^2\right )^2 \left (4 a e^2-b^2 f^2\right ) \log \left (b f^2+2 e \left (e x+f \sqrt{a+\frac{x \left (b f^2+e^2 x\right )}{f^2}}\right )\right )}{32 e^5}\\ \end{align*}
Mathematica [A] time = 0.570442, size = 276, normalized size = 0.91 \[ \frac{2 e^2 f^2 \left (4 a e^2-b^2 f^2\right ) \left (f \sqrt{a+x \left (b+\frac{e^2 x}{f^2}\right )}+d+e x\right )^2+4 e f^2 \left (4 a e^2-b^2 f^2\right ) \left (2 d e-b f^2\right ) \left (f \sqrt{a+x \left (b+\frac{e^2 x}{f^2}\right )}+e x\right )-\frac{f^2 \left (b^2 f^2-4 a e^2\right ) \left (b f^2-2 d e\right )^3}{2 e \left (f \sqrt{a+x \left (b+\frac{e^2 x}{f^2}\right )}+e x\right )+b f^2}-3 \left (b^2 f^2-4 a e^2\right ) \left (b f^3-2 d e f\right )^2 \log \left (-2 e \left (f \sqrt{a+x \left (b+\frac{e^2 x}{f^2}\right )}+e x\right )-b f^2\right )+4 e^4 \left (f \sqrt{a+x \left (b+\frac{e^2 x}{f^2}\right )}+d+e x\right )^4}{32 e^5} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.01, size = 685, normalized size = 2.3 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.8759, size = 717, normalized size = 2.37 \begin{align*} \frac{32 \, e^{8} x^{4} + 32 \,{\left (b e^{6} f^{2} + 2 \, d e^{7}\right )} x^{3} + 48 \,{\left (d^{2} e^{6} +{\left (b d e^{5} + a e^{6}\right )} f^{2}\right )} x^{2} + 32 \,{\left (3 \, a d e^{5} f^{2} + d^{3} e^{5}\right )} x + 3 \,{\left (b^{4} f^{8} - 16 \, a d^{2} e^{4} f^{2} - 4 \,{\left (b^{3} d e + a b^{2} e^{2}\right )} f^{6} + 4 \,{\left (b^{2} d^{2} e^{2} + 4 \, a b d e^{3}\right )} f^{4}\right )} \log \left (-b f^{2} - 2 \, e^{2} x + 2 \, e f \sqrt{\frac{b f^{2} x + e^{2} x^{2} + a f^{2}}{f^{2}}}\right ) + 2 \,{\left (3 \, b^{3} e f^{7} + 16 \, e^{7} f x^{3} - 4 \,{\left (3 \, b^{2} d e^{2} + 2 \, a b e^{3}\right )} f^{5} + 4 \,{\left (3 \, b d^{2} e^{3} + 8 \, a d e^{4}\right )} f^{3} + 8 \,{\left (b e^{5} f^{3} + 4 \, d e^{6} f\right )} x^{2} - 2 \,{\left (b^{2} e^{3} f^{5} - 12 \, d^{2} e^{5} f - 4 \,{\left (b d e^{4} + 2 \, a e^{5}\right )} f^{3}\right )} x\right )} \sqrt{\frac{b f^{2} x + e^{2} x^{2} + a f^{2}}{f^{2}}}}{32 \, e^{5}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (d + e x + f \sqrt{a + b x + \frac{e^{2} x^{2}}{f^{2}}}\right )^{3}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.17376, size = 504, normalized size = 1.66 \begin{align*} b f^{2} x^{3} e + \frac{3}{2} \, b d f^{2} x^{2} + \frac{3}{2} \, a f^{2} x^{2} e + 3 \, a d f^{2} x + x^{4} e^{3} + 2 \, d x^{3} e^{2} + \frac{3}{2} \, d^{2} x^{2} e + d^{3} x + \frac{3}{32} \,{\left (b^{4} f^{7}{\left | f \right |} - 4 \, b^{3} d f^{5}{\left | f \right |} e - 4 \, a b^{2} f^{5}{\left | f \right |} e^{2} + 4 \, b^{2} d^{2} f^{3}{\left | f \right |} e^{2} + 16 \, a b d f^{3}{\left | f \right |} e^{3} - 16 \, a d^{2} f{\left | f \right |} e^{4}\right )} e^{\left (-5\right )} \log \left ({\left | -b f^{2} - 2 \,{\left (x e - \sqrt{b f^{2} x + a f^{2} + x^{2} e^{2}}\right )} e \right |}\right ) + \frac{1}{16} \, \sqrt{b f^{2} x + a f^{2} + x^{2} e^{2}}{\left (2 \,{\left (4 \,{\left (\frac{2 \, x{\left | f \right |} e^{2}}{f} + \frac{{\left (b f^{4}{\left | f \right |} e^{6} + 4 \, d f^{2}{\left | f \right |} e^{7}\right )} e^{\left (-6\right )}}{f^{3}}\right )} x - \frac{{\left (b^{2} f^{6}{\left | f \right |} e^{4} - 4 \, b d f^{4}{\left | f \right |} e^{5} - 8 \, a f^{4}{\left | f \right |} e^{6} - 12 \, d^{2} f^{2}{\left | f \right |} e^{6}\right )} e^{\left (-6\right )}}{f^{3}}\right )} x + \frac{{\left (3 \, b^{3} f^{8}{\left | f \right |} e^{2} - 12 \, b^{2} d f^{6}{\left | f \right |} e^{3} - 8 \, a b f^{6}{\left | f \right |} e^{4} + 12 \, b d^{2} f^{4}{\left | f \right |} e^{4} + 32 \, a d f^{4}{\left | f \right |} e^{5}\right )} e^{\left (-6\right )}}{f^{3}}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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