Optimal. Leaf size=391 \[ -\frac{\sqrt{c} e \left (a^2 d^2-16 a b c d+16 b^2 c^2\right ) \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}} E\left (\tan ^{-1}\left (\frac{\sqrt{d} x}{\sqrt{c}}\right )|1-\frac{b c}{a d}\right )}{5 b d^{7/2} \sqrt{\frac{c \left (a+b x^2\right )}{a \left (c+d x^2\right )}}}-\frac{e x \left (-\frac{a^2 d}{b}+16 a c-\frac{16 b c^2}{d}\right ) \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}}}{5 d^2}+\frac{c^{3/2} e (8 b c-7 a d) \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}} F\left (\tan ^{-1}\left (\frac{\sqrt{d} x}{\sqrt{c}}\right )|1-\frac{b c}{a d}\right )}{5 d^{7/2} \sqrt{\frac{c \left (a+b x^2\right )}{a \left (c+d x^2\right )}}}+\frac{6 b e x^3 \left (c+d x^2\right ) \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}}}{5 d^2}-\frac{e x \left (c+d x^2\right ) (8 b c-7 a d) \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}}}{5 d^3}-\frac{e x^3 \left (a+b x^2\right ) \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}}}{d} \]
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Rubi [A] time = 0.678075, antiderivative size = 391, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 8, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.308, Rules used = {6719, 467, 581, 582, 531, 418, 492, 411} \[ -\frac{\sqrt{c} e \left (a^2 d^2-16 a b c d+16 b^2 c^2\right ) \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}} E\left (\tan ^{-1}\left (\frac{\sqrt{d} x}{\sqrt{c}}\right )|1-\frac{b c}{a d}\right )}{5 b d^{7/2} \sqrt{\frac{c \left (a+b x^2\right )}{a \left (c+d x^2\right )}}}-\frac{e x \left (-\frac{a^2 d}{b}+16 a c-\frac{16 b c^2}{d}\right ) \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}}}{5 d^2}+\frac{c^{3/2} e (8 b c-7 a d) \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}} F\left (\tan ^{-1}\left (\frac{\sqrt{d} x}{\sqrt{c}}\right )|1-\frac{b c}{a d}\right )}{5 d^{7/2} \sqrt{\frac{c \left (a+b x^2\right )}{a \left (c+d x^2\right )}}}+\frac{6 b e x^3 \left (c+d x^2\right ) \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}}}{5 d^2}-\frac{e x \left (c+d x^2\right ) (8 b c-7 a d) \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}}}{5 d^3}-\frac{e x^3 \left (a+b x^2\right ) \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}}}{d} \]
Antiderivative was successfully verified.
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Rule 6719
Rule 467
Rule 581
Rule 582
Rule 531
Rule 418
Rule 492
Rule 411
Rubi steps
\begin{align*} \int x^4 \left (\frac{e \left (a+b x^2\right )}{c+d x^2}\right )^{3/2} \, dx &=\frac{\left (e \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}} \sqrt{c+d x^2}\right ) \int \frac{x^4 \left (a+b x^2\right )^{3/2}}{\left (c+d x^2\right )^{3/2}} \, dx}{\sqrt{a+b x^2}}\\ &=-\frac{e x^3 \left (a+b x^2\right ) \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}}}{d}+\frac{\left (e \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}} \sqrt{c+d x^2}\right ) \int \frac{x^2 \sqrt{a+b x^2} \left (3 a+6 b x^2\right )}{\sqrt{c+d x^2}} \, dx}{d \sqrt{a+b x^2}}\\ &=-\frac{e x^3 \left (a+b x^2\right ) \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}}}{d}+\frac{6 b e x^3 \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}} \left (c+d x^2\right )}{5 d^2}+\frac{\left (e \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}} \sqrt{c+d x^2}\right ) \int \frac{x^2 \left (-3 a (6 b c-5 a d)-3 b (8 b c-7 a d) x^2\right )}{\sqrt{a+b x^2} \sqrt{c+d x^2}} \, dx}{5 d^2 \sqrt{a+b x^2}}\\ &=-\frac{e x^3 \left (a+b x^2\right ) \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}}}{d}-\frac{(8 b c-7 a d) e x \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}} \left (c+d x^2\right )}{5 d^3}+\frac{6 b e x^3 \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}} \left (c+d x^2\right )}{5 d^2}-\frac{\left (e \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}} \sqrt{c+d x^2}\right ) \int \frac{-3 a b c (8 b c-7 a d)-3 b \left (16 b^2 c^2-16 a b c d+a^2 d^2\right ) x^2}{\sqrt{a+b x^2} \sqrt{c+d x^2}} \, dx}{15 b d^3 \sqrt{a+b x^2}}\\ &=-\frac{e x^3 \left (a+b x^2\right ) \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}}}{d}-\frac{(8 b c-7 a d) e x \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}} \left (c+d x^2\right )}{5 d^3}+\frac{6 b e x^3 \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}} \left (c+d x^2\right )}{5 d^2}+\frac{\left (a c (8 b c-7 a d) e \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}} \sqrt{c+d x^2}\right ) \int \frac{1}{\sqrt{a+b x^2} \sqrt{c+d x^2}} \, dx}{5 d^3 \sqrt{a+b x^2}}+\frac{\left (\left (16 b^2 c^2-16 a b c d+a^2 d^2\right ) e \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}} \sqrt{c+d x^2}\right ) \int \frac{x^2}{\sqrt{a+b x^2} \sqrt{c+d x^2}} \, dx}{5 d^3 \sqrt{a+b x^2}}\\ &=\frac{\left (16 b^2 c^2-16 a b c d+a^2 d^2\right ) e x \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}}}{5 b d^3}-\frac{e x^3 \left (a+b x^2\right ) \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}}}{d}-\frac{(8 b c-7 a d) e x \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}} \left (c+d x^2\right )}{5 d^3}+\frac{6 b e x^3 \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}} \left (c+d x^2\right )}{5 d^2}+\frac{c^{3/2} (8 b c-7 a d) e \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}} F\left (\tan ^{-1}\left (\frac{\sqrt{d} x}{\sqrt{c}}\right )|1-\frac{b c}{a d}\right )}{5 d^{7/2} \sqrt{\frac{c \left (a+b x^2\right )}{a \left (c+d x^2\right )}}}-\frac{\left (c \left (16 b^2 c^2-16 a b c d+a^2 d^2\right ) e \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}} \sqrt{c+d x^2}\right ) \int \frac{\sqrt{a+b x^2}}{\left (c+d x^2\right )^{3/2}} \, dx}{5 b d^3 \sqrt{a+b x^2}}\\ &=\frac{\left (16 b^2 c^2-16 a b c d+a^2 d^2\right ) e x \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}}}{5 b d^3}-\frac{e x^3 \left (a+b x^2\right ) \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}}}{d}-\frac{(8 b c-7 a d) e x \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}} \left (c+d x^2\right )}{5 d^3}+\frac{6 b e x^3 \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}} \left (c+d x^2\right )}{5 d^2}-\frac{\sqrt{c} \left (16 b^2 c^2-16 a b c d+a^2 d^2\right ) e \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}} E\left (\tan ^{-1}\left (\frac{\sqrt{d} x}{\sqrt{c}}\right )|1-\frac{b c}{a d}\right )}{5 b d^{7/2} \sqrt{\frac{c \left (a+b x^2\right )}{a \left (c+d x^2\right )}}}+\frac{c^{3/2} (8 b c-7 a d) e \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}} F\left (\tan ^{-1}\left (\frac{\sqrt{d} x}{\sqrt{c}}\right )|1-\frac{b c}{a d}\right )}{5 d^{7/2} \sqrt{\frac{c \left (a+b x^2\right )}{a \left (c+d x^2\right )}}}\\ \end{align*}
Mathematica [C] time = 0.520487, size = 290, normalized size = 0.74 \[ \frac{e \sqrt{\frac{e \left (a+b x^2\right )}{c+d x^2}} \left (d x \sqrt{\frac{b}{a}} \left (a^2 d \left (7 c+2 d x^2\right )+a b \left (-8 c^2+5 c d x^2+3 d^2 x^4\right )+b^2 x^2 \left (-8 c^2-2 c d x^2+d^2 x^4\right )\right )+8 i c \sqrt{\frac{b x^2}{a}+1} \sqrt{\frac{d x^2}{c}+1} \left (a^2 d^2-3 a b c d+2 b^2 c^2\right ) F\left (i \sinh ^{-1}\left (\sqrt{\frac{b}{a}} x\right )|\frac{a d}{b c}\right )-i c \sqrt{\frac{b x^2}{a}+1} \sqrt{\frac{d x^2}{c}+1} \left (a^2 d^2-16 a b c d+16 b^2 c^2\right ) E\left (i \sinh ^{-1}\left (\sqrt{\frac{b}{a}} x\right )|\frac{a d}{b c}\right )\right )}{5 d^4 \sqrt{\frac{b}{a}} \left (a+b x^2\right )} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.032, size = 933, normalized size = 2.4 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (\frac{{\left (b x^{2} + a\right )} e}{d x^{2} + c}\right )^{\frac{3}{2}} x^{4}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (b e x^{6} + a e x^{4}\right )} \sqrt{\frac{b e x^{2} + a e}{d x^{2} + c}}}{d x^{2} + c}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (\frac{{\left (b x^{2} + a\right )} e}{d x^{2} + c}\right )^{\frac{3}{2}} x^{4}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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