Optimal. Leaf size=355 \[ \frac{a^{3/4} d \left (\sqrt{a}+\sqrt{c} x^2\right ) \sqrt{\frac{a+c x^4}{\left (\sqrt{a}+\sqrt{c} x^2\right )^2}} \left (9 \sqrt{a} e^2+5 \sqrt{c} d^2\right ) F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{15 c^{3/4} \sqrt{a+c x^4}}-\frac{6 a^{5/4} d e^2 \left (\sqrt{a}+\sqrt{c} x^2\right ) \sqrt{\frac{a+c x^4}{\left (\sqrt{a}+\sqrt{c} x^2\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{5 c^{3/4} \sqrt{a+c x^4}}+\frac{1}{15} d x \sqrt{a+c x^4} \left (5 d^2+9 e^2 x^2\right )+\frac{3}{4} d^2 e x^2 \sqrt{a+c x^4}+\frac{3 a d^2 e \tanh ^{-1}\left (\frac{\sqrt{c} x^2}{\sqrt{a+c x^4}}\right )}{4 \sqrt{c}}+\frac{6 a d e^2 x \sqrt{a+c x^4}}{5 \sqrt{c} \left (\sqrt{a}+\sqrt{c} x^2\right )}+\frac{e^3 \left (a+c x^4\right )^{3/2}}{6 c} \]
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Rubi [A] time = 0.232614, antiderivative size = 355, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 10, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.526, Rules used = {1885, 1177, 1198, 220, 1196, 1248, 641, 195, 217, 206} \[ \frac{a^{3/4} d \left (\sqrt{a}+\sqrt{c} x^2\right ) \sqrt{\frac{a+c x^4}{\left (\sqrt{a}+\sqrt{c} x^2\right )^2}} \left (9 \sqrt{a} e^2+5 \sqrt{c} d^2\right ) F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{15 c^{3/4} \sqrt{a+c x^4}}-\frac{6 a^{5/4} d e^2 \left (\sqrt{a}+\sqrt{c} x^2\right ) \sqrt{\frac{a+c x^4}{\left (\sqrt{a}+\sqrt{c} x^2\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{5 c^{3/4} \sqrt{a+c x^4}}+\frac{1}{15} d x \sqrt{a+c x^4} \left (5 d^2+9 e^2 x^2\right )+\frac{3}{4} d^2 e x^2 \sqrt{a+c x^4}+\frac{3 a d^2 e \tanh ^{-1}\left (\frac{\sqrt{c} x^2}{\sqrt{a+c x^4}}\right )}{4 \sqrt{c}}+\frac{6 a d e^2 x \sqrt{a+c x^4}}{5 \sqrt{c} \left (\sqrt{a}+\sqrt{c} x^2\right )}+\frac{e^3 \left (a+c x^4\right )^{3/2}}{6 c} \]
Antiderivative was successfully verified.
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Rule 1885
Rule 1177
Rule 1198
Rule 220
Rule 1196
Rule 1248
Rule 641
Rule 195
Rule 217
Rule 206
Rubi steps
\begin{align*} \int (d+e x)^3 \sqrt{a+c x^4} \, dx &=\int \left (\left (d^3+3 d e^2 x^2\right ) \sqrt{a+c x^4}+x \left (3 d^2 e+e^3 x^2\right ) \sqrt{a+c x^4}\right ) \, dx\\ &=\int \left (d^3+3 d e^2 x^2\right ) \sqrt{a+c x^4} \, dx+\int x \left (3 d^2 e+e^3 x^2\right ) \sqrt{a+c x^4} \, dx\\ &=\frac{1}{15} d x \left (5 d^2+9 e^2 x^2\right ) \sqrt{a+c x^4}+\frac{1}{15} \int \frac{10 a d^3+18 a d e^2 x^2}{\sqrt{a+c x^4}} \, dx+\frac{1}{2} \operatorname{Subst}\left (\int \left (3 d^2 e+e^3 x\right ) \sqrt{a+c x^2} \, dx,x,x^2\right )\\ &=\frac{1}{15} d x \left (5 d^2+9 e^2 x^2\right ) \sqrt{a+c x^4}+\frac{e^3 \left (a+c x^4\right )^{3/2}}{6 c}+\frac{1}{2} \left (3 d^2 e\right ) \operatorname{Subst}\left (\int \sqrt{a+c x^2} \, dx,x,x^2\right )-\frac{\left (6 a^{3/2} d e^2\right ) \int \frac{1-\frac{\sqrt{c} x^2}{\sqrt{a}}}{\sqrt{a+c x^4}} \, dx}{5 \sqrt{c}}+\frac{1}{15} \left (2 a d \left (5 d^2+\frac{9 \sqrt{a} e^2}{\sqrt{c}}\right )\right ) \int \frac{1}{\sqrt{a+c x^4}} \, dx\\ &=\frac{3}{4} d^2 e x^2 \sqrt{a+c x^4}+\frac{6 a d e^2 x \sqrt{a+c x^4}}{5 \sqrt{c} \left (\sqrt{a}+\sqrt{c} x^2\right )}+\frac{1}{15} d x \left (5 d^2+9 e^2 x^2\right ) \sqrt{a+c x^4}+\frac{e^3 \left (a+c x^4\right )^{3/2}}{6 c}-\frac{6 a^{5/4} d e^2 \left (\sqrt{a}+\sqrt{c} x^2\right ) \sqrt{\frac{a+c x^4}{\left (\sqrt{a}+\sqrt{c} x^2\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{5 c^{3/4} \sqrt{a+c x^4}}+\frac{a^{3/4} d \left (5 \sqrt{c} d^2+9 \sqrt{a} e^2\right ) \left (\sqrt{a}+\sqrt{c} x^2\right ) \sqrt{\frac{a+c x^4}{\left (\sqrt{a}+\sqrt{c} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{15 c^{3/4} \sqrt{a+c x^4}}+\frac{1}{4} \left (3 a d^2 e\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{a+c x^2}} \, dx,x,x^2\right )\\ &=\frac{3}{4} d^2 e x^2 \sqrt{a+c x^4}+\frac{6 a d e^2 x \sqrt{a+c x^4}}{5 \sqrt{c} \left (\sqrt{a}+\sqrt{c} x^2\right )}+\frac{1}{15} d x \left (5 d^2+9 e^2 x^2\right ) \sqrt{a+c x^4}+\frac{e^3 \left (a+c x^4\right )^{3/2}}{6 c}-\frac{6 a^{5/4} d e^2 \left (\sqrt{a}+\sqrt{c} x^2\right ) \sqrt{\frac{a+c x^4}{\left (\sqrt{a}+\sqrt{c} x^2\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{5 c^{3/4} \sqrt{a+c x^4}}+\frac{a^{3/4} d \left (5 \sqrt{c} d^2+9 \sqrt{a} e^2\right ) \left (\sqrt{a}+\sqrt{c} x^2\right ) \sqrt{\frac{a+c x^4}{\left (\sqrt{a}+\sqrt{c} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{15 c^{3/4} \sqrt{a+c x^4}}+\frac{1}{4} \left (3 a d^2 e\right ) \operatorname{Subst}\left (\int \frac{1}{1-c x^2} \, dx,x,\frac{x^2}{\sqrt{a+c x^4}}\right )\\ &=\frac{3}{4} d^2 e x^2 \sqrt{a+c x^4}+\frac{6 a d e^2 x \sqrt{a+c x^4}}{5 \sqrt{c} \left (\sqrt{a}+\sqrt{c} x^2\right )}+\frac{1}{15} d x \left (5 d^2+9 e^2 x^2\right ) \sqrt{a+c x^4}+\frac{e^3 \left (a+c x^4\right )^{3/2}}{6 c}+\frac{3 a d^2 e \tanh ^{-1}\left (\frac{\sqrt{c} x^2}{\sqrt{a+c x^4}}\right )}{4 \sqrt{c}}-\frac{6 a^{5/4} d e^2 \left (\sqrt{a}+\sqrt{c} x^2\right ) \sqrt{\frac{a+c x^4}{\left (\sqrt{a}+\sqrt{c} x^2\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{5 c^{3/4} \sqrt{a+c x^4}}+\frac{a^{3/4} d \left (5 \sqrt{c} d^2+9 \sqrt{a} e^2\right ) \left (\sqrt{a}+\sqrt{c} x^2\right ) \sqrt{\frac{a+c x^4}{\left (\sqrt{a}+\sqrt{c} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{15 c^{3/4} \sqrt{a+c x^4}}\\ \end{align*}
Mathematica [C] time = 0.13794, size = 186, normalized size = 0.52 \[ \frac{\sqrt{a+c x^4} \left (9 c d^2 e x^2 \sqrt{\frac{c x^4}{a}+1}+9 \sqrt{a} \sqrt{c} d^2 e \sinh ^{-1}\left (\frac{\sqrt{c} x^2}{\sqrt{a}}\right )+12 c d^3 x \, _2F_1\left (-\frac{1}{2},\frac{1}{4};\frac{5}{4};-\frac{c x^4}{a}\right )+12 c d e^2 x^3 \, _2F_1\left (-\frac{1}{2},\frac{3}{4};\frac{7}{4};-\frac{c x^4}{a}\right )+2 c e^3 x^4 \sqrt{\frac{c x^4}{a}+1}+2 a e^3 \sqrt{\frac{c x^4}{a}+1}\right )}{12 c \sqrt{\frac{c x^4}{a}+1}} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.048, size = 334, normalized size = 0.9 \begin{align*}{\frac{{e}^{3}}{6\,c} \left ( c{x}^{4}+a \right ) ^{{\frac{3}{2}}}}+{\frac{3\,d{e}^{2}{x}^{3}}{5}\sqrt{c{x}^{4}+a}}+{{\frac{6\,i}{5}}d{e}^{2}{a}^{{\frac{3}{2}}}\sqrt{1-{i{x}^{2}\sqrt{c}{\frac{1}{\sqrt{a}}}}}\sqrt{1+{i{x}^{2}\sqrt{c}{\frac{1}{\sqrt{a}}}}}{\it EllipticF} \left ( x\sqrt{{i\sqrt{c}{\frac{1}{\sqrt{a}}}}},i \right ){\frac{1}{\sqrt{{i\sqrt{c}{\frac{1}{\sqrt{a}}}}}}}{\frac{1}{\sqrt{c{x}^{4}+a}}}{\frac{1}{\sqrt{c}}}}-{{\frac{6\,i}{5}}d{e}^{2}{a}^{{\frac{3}{2}}}\sqrt{1-{i{x}^{2}\sqrt{c}{\frac{1}{\sqrt{a}}}}}\sqrt{1+{i{x}^{2}\sqrt{c}{\frac{1}{\sqrt{a}}}}}{\it EllipticE} \left ( x\sqrt{{i\sqrt{c}{\frac{1}{\sqrt{a}}}}},i \right ){\frac{1}{\sqrt{{i\sqrt{c}{\frac{1}{\sqrt{a}}}}}}}{\frac{1}{\sqrt{c{x}^{4}+a}}}{\frac{1}{\sqrt{c}}}}+{\frac{3\,e{d}^{2}{x}^{2}}{4}\sqrt{c{x}^{4}+a}}+{\frac{3\,e{d}^{2}a}{4}\ln \left ({x}^{2}\sqrt{c}+\sqrt{c{x}^{4}+a} \right ){\frac{1}{\sqrt{c}}}}+{\frac{{d}^{3}x}{3}\sqrt{c{x}^{4}+a}}+{\frac{2\,a{d}^{3}}{3}\sqrt{1-{i{x}^{2}\sqrt{c}{\frac{1}{\sqrt{a}}}}}\sqrt{1+{i{x}^{2}\sqrt{c}{\frac{1}{\sqrt{a}}}}}{\it EllipticF} \left ( x\sqrt{{i\sqrt{c}{\frac{1}{\sqrt{a}}}}},i \right ){\frac{1}{\sqrt{{i\sqrt{c}{\frac{1}{\sqrt{a}}}}}}}{\frac{1}{\sqrt{c{x}^{4}+a}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{c x^{4} + a}{\left (e x + d\right )}^{3}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (e^{3} x^{3} + 3 \, d e^{2} x^{2} + 3 \, d^{2} e x + d^{3}\right )} \sqrt{c x^{4} + a}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 3.84379, size = 175, normalized size = 0.49 \begin{align*} \frac{\sqrt{a} d^{3} x \Gamma \left (\frac{1}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{1}{2}, \frac{1}{4} \\ \frac{5}{4} \end{matrix}\middle |{\frac{c x^{4} e^{i \pi }}{a}} \right )}}{4 \Gamma \left (\frac{5}{4}\right )} + \frac{3 \sqrt{a} d^{2} e x^{2} \sqrt{1 + \frac{c x^{4}}{a}}}{4} + \frac{3 \sqrt{a} d e^{2} x^{3} \Gamma \left (\frac{3}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{1}{2}, \frac{3}{4} \\ \frac{7}{4} \end{matrix}\middle |{\frac{c x^{4} e^{i \pi }}{a}} \right )}}{4 \Gamma \left (\frac{7}{4}\right )} + \frac{3 a d^{2} e \operatorname{asinh}{\left (\frac{\sqrt{c} x^{2}}{\sqrt{a}} \right )}}{4 \sqrt{c}} + e^{3} \left (\begin{cases} \frac{\sqrt{a} x^{4}}{4} & \text{for}\: c = 0 \\\frac{\left (a + c x^{4}\right )^{\frac{3}{2}}}{6 c} & \text{otherwise} \end{cases}\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{c x^{4} + a}{\left (e x + d\right )}^{3}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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