This lecture was on finding the inverse Z transform using contour integration with the trick of using \(z\rightarrow \frac{1}{p}\) for left sided signals to make it easier to do. We send most of the time looking at this. This is a little confusing lecture for me, and need more studying, but it looks like this will not be on exams. Most likely if we have to find inverse Z transform, then use partial fractions or long division. So for now, I will not spend to much time on this unless I think it will be on the exam.
Solution to HW 2 was given.