Problem: Given a matrix A, check to see if it is Hermite.
A Matrix is Hermite if it is the same as the conjugate of its transpose. One way to check is to take the diﬀerence and check that all values in the resulting diﬀerence matrix are zero.
To account for numerical values, the check is done using machine epsilon.
Matlab clear all; i=sqrt(1); mat=[1 13*i 0; 1+3*i 0 6*i; 0 6*i 1]; mat2=conj(transpose(mat)); diff = matmat2

diff = 0 0 0 0 0 0 0 0 0

r=abs(diff)<eps('double')

r = 1 1 1 1 1 1 1 1 1

all(r(:))

1 
Maple mat := Matrix([[1,13*I,0], [1+3*I,0,6*I],[0,6*I,1]]); mat2:= LinearAlgebra:HermitianTranspose(mat); LinearAlgebra:Equal(mat,mat2)

true 