3.3.83 \(\int \frac {\sqrt {-c-d x^2}}{\sqrt {a+b x^2}} \, dx\) [283]

Optimal. Leaf size=214 \[ -\frac {d x \sqrt {a+b x^2}}{b \sqrt {-c-d x^2}}+\frac {\sqrt {c} \sqrt {d} \sqrt {a+b x^2} E\left (\tan ^{-1}\left (\frac {\sqrt {d} x}{\sqrt {c}}\right )|1-\frac {b c}{a d}\right )}{b \sqrt {-c-d x^2} \sqrt {\frac {c \left (a+b x^2\right )}{a \left (c+d x^2\right )}}}-\frac {c^{3/2} \sqrt {a+b x^2} F\left (\tan ^{-1}\left (\frac {\sqrt {d} x}{\sqrt {c}}\right )|1-\frac {b c}{a d}\right )}{a \sqrt {d} \sqrt {-c-d x^2} \sqrt {\frac {c \left (a+b x^2\right )}{a \left (c+d x^2\right )}}} \]

[Out]

-d*x*(b*x^2+a)^(1/2)/b/(-d*x^2-c)^(1/2)-c^(3/2)*(1/(1+d*x^2/c))^(1/2)*(1+d*x^2/c)^(1/2)*EllipticF(x*d^(1/2)/c^
(1/2)/(1+d*x^2/c)^(1/2),(1-b*c/a/d)^(1/2))*(b*x^2+a)^(1/2)/a/d^(1/2)/(-d*x^2-c)^(1/2)/(c*(b*x^2+a)/a/(d*x^2+c)
)^(1/2)+(1/(1+d*x^2/c))^(1/2)*(1+d*x^2/c)^(1/2)*EllipticE(x*d^(1/2)/c^(1/2)/(1+d*x^2/c)^(1/2),(1-b*c/a/d)^(1/2
))*c^(1/2)*d^(1/2)*(b*x^2+a)^(1/2)/b/(-d*x^2-c)^(1/2)/(c*(b*x^2+a)/a/(d*x^2+c))^(1/2)

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Rubi [A]
time = 0.07, antiderivative size = 214, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {433, 429, 506, 422} \begin {gather*} -\frac {c^{3/2} \sqrt {a+b x^2} F\left (\text {ArcTan}\left (\frac {\sqrt {d} x}{\sqrt {c}}\right )|1-\frac {b c}{a d}\right )}{a \sqrt {d} \sqrt {-c-d x^2} \sqrt {\frac {c \left (a+b x^2\right )}{a \left (c+d x^2\right )}}}+\frac {\sqrt {c} \sqrt {d} \sqrt {a+b x^2} E\left (\text {ArcTan}\left (\frac {\sqrt {d} x}{\sqrt {c}}\right )|1-\frac {b c}{a d}\right )}{b \sqrt {-c-d x^2} \sqrt {\frac {c \left (a+b x^2\right )}{a \left (c+d x^2\right )}}}-\frac {d x \sqrt {a+b x^2}}{b \sqrt {-c-d x^2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[Sqrt[-c - d*x^2]/Sqrt[a + b*x^2],x]

[Out]

-((d*x*Sqrt[a + b*x^2])/(b*Sqrt[-c - d*x^2])) + (Sqrt[c]*Sqrt[d]*Sqrt[a + b*x^2]*EllipticE[ArcTan[(Sqrt[d]*x)/
Sqrt[c]], 1 - (b*c)/(a*d)])/(b*Sqrt[-c - d*x^2]*Sqrt[(c*(a + b*x^2))/(a*(c + d*x^2))]) - (c^(3/2)*Sqrt[a + b*x
^2]*EllipticF[ArcTan[(Sqrt[d]*x)/Sqrt[c]], 1 - (b*c)/(a*d)])/(a*Sqrt[d]*Sqrt[-c - d*x^2]*Sqrt[(c*(a + b*x^2))/
(a*(c + d*x^2))])

Rule 422

Int[Sqrt[(a_) + (b_.)*(x_)^2]/((c_) + (d_.)*(x_)^2)^(3/2), x_Symbol] :> Simp[(Sqrt[a + b*x^2]/(c*Rt[d/c, 2]*Sq
rt[c + d*x^2]*Sqrt[c*((a + b*x^2)/(a*(c + d*x^2)))]))*EllipticE[ArcTan[Rt[d/c, 2]*x], 1 - b*(c/(a*d))], x] /;
FreeQ[{a, b, c, d}, x] && PosQ[b/a] && PosQ[d/c]

Rule 429

Int[1/(Sqrt[(a_) + (b_.)*(x_)^2]*Sqrt[(c_) + (d_.)*(x_)^2]), x_Symbol] :> Simp[(Sqrt[a + b*x^2]/(a*Rt[d/c, 2]*
Sqrt[c + d*x^2]*Sqrt[c*((a + b*x^2)/(a*(c + d*x^2)))]))*EllipticF[ArcTan[Rt[d/c, 2]*x], 1 - b*(c/(a*d))], x] /
; FreeQ[{a, b, c, d}, x] && PosQ[d/c] && PosQ[b/a] &&  !SimplerSqrtQ[b/a, d/c]

Rule 433

Int[Sqrt[(a_) + (b_.)*(x_)^2]/Sqrt[(c_) + (d_.)*(x_)^2], x_Symbol] :> Dist[a, Int[1/(Sqrt[a + b*x^2]*Sqrt[c +
d*x^2]), x], x] + Dist[b, Int[x^2/(Sqrt[a + b*x^2]*Sqrt[c + d*x^2]), x], x] /; FreeQ[{a, b, c, d}, x] && PosQ[
d/c] && PosQ[b/a]

Rule 506

Int[(x_)^2/(Sqrt[(a_) + (b_.)*(x_)^2]*Sqrt[(c_) + (d_.)*(x_)^2]), x_Symbol] :> Simp[x*(Sqrt[a + b*x^2]/(b*Sqrt
[c + d*x^2])), x] - Dist[c/b, Int[Sqrt[a + b*x^2]/(c + d*x^2)^(3/2), x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b
*c - a*d, 0] && PosQ[b/a] && PosQ[d/c] &&  !SimplerSqrtQ[b/a, d/c]

Rubi steps

\begin {align*} \int \frac {\sqrt {-c-d x^2}}{\sqrt {a+b x^2}} \, dx &=-\left (c \int \frac {1}{\sqrt {a+b x^2} \sqrt {-c-d x^2}} \, dx\right )-d \int \frac {x^2}{\sqrt {a+b x^2} \sqrt {-c-d x^2}} \, dx\\ &=-\frac {d x \sqrt {a+b x^2}}{b \sqrt {-c-d x^2}}-\frac {c^{3/2} \sqrt {a+b x^2} F\left (\tan ^{-1}\left (\frac {\sqrt {d} x}{\sqrt {c}}\right )|1-\frac {b c}{a d}\right )}{a \sqrt {d} \sqrt {-c-d x^2} \sqrt {\frac {c \left (a+b x^2\right )}{a \left (c+d x^2\right )}}}-\frac {(c d) \int \frac {\sqrt {a+b x^2}}{\left (-c-d x^2\right )^{3/2}} \, dx}{b}\\ &=-\frac {d x \sqrt {a+b x^2}}{b \sqrt {-c-d x^2}}+\frac {\sqrt {c} \sqrt {d} \sqrt {a+b x^2} E\left (\tan ^{-1}\left (\frac {\sqrt {d} x}{\sqrt {c}}\right )|1-\frac {b c}{a d}\right )}{b \sqrt {-c-d x^2} \sqrt {\frac {c \left (a+b x^2\right )}{a \left (c+d x^2\right )}}}-\frac {c^{3/2} \sqrt {a+b x^2} F\left (\tan ^{-1}\left (\frac {\sqrt {d} x}{\sqrt {c}}\right )|1-\frac {b c}{a d}\right )}{a \sqrt {d} \sqrt {-c-d x^2} \sqrt {\frac {c \left (a+b x^2\right )}{a \left (c+d x^2\right )}}}\\ \end {align*}

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Mathematica [A]
time = 0.87, size = 89, normalized size = 0.42 \begin {gather*} \frac {\sqrt {\frac {a+b x^2}{a}} \sqrt {-c-d x^2} E\left (\sin ^{-1}\left (\sqrt {-\frac {b}{a}} x\right )|\frac {a d}{b c}\right )}{\sqrt {-\frac {b}{a}} \sqrt {a+b x^2} \sqrt {\frac {c+d x^2}{c}}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[Sqrt[-c - d*x^2]/Sqrt[a + b*x^2],x]

[Out]

(Sqrt[(a + b*x^2)/a]*Sqrt[-c - d*x^2]*EllipticE[ArcSin[Sqrt[-(b/a)]*x], (a*d)/(b*c)])/(Sqrt[-(b/a)]*Sqrt[a + b
*x^2]*Sqrt[(c + d*x^2)/c])

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Maple [A]
time = 0.08, size = 161, normalized size = 0.75

method	result	size
default	\(\frac {\left (-a d \EllipticF \left (x \sqrt {-\frac {d}{c}}, \sqrt {\frac {b c}{a d}}\right )+c \EllipticF \left (x \sqrt {-\frac {d}{c}}, \sqrt {\frac {b c}{a d}}\right ) b +a d \EllipticE \left (x \sqrt {-\frac {d}{c}}, \sqrt {\frac {b c}{a d}}\right )\right ) \sqrt {-d \,x^{2}-c}\, \sqrt {b \,x^{2}+a}\, \sqrt {\frac {d \,x^{2}+c}{c}}\, \sqrt {\frac {b \,x^{2}+a}{a}}}{\left (b d \,x^{4}+a d \,x^{2}+c \,x^{2} b +a c \right ) \sqrt {-\frac {d}{c}}\, b}\)	\(161\)
elliptic	\(\frac {\sqrt {-\left (b \,x^{2}+a \right ) \left (d \,x^{2}+c \right )}\, \left (-\frac {c \sqrt {1+\frac {d \,x^{2}}{c}}\, \sqrt {1+\frac {b \,x^{2}}{a}}\, \EllipticF \left (x \sqrt {-\frac {d}{c}}, \sqrt {-1-\frac {-a d -b c}{a d}}\right )}{\sqrt {-\frac {d}{c}}\, \sqrt {-b d \,x^{4}-a d \,x^{2}-c \,x^{2} b -a c}}+\frac {d a \sqrt {1+\frac {d \,x^{2}}{c}}\, \sqrt {1+\frac {b \,x^{2}}{a}}\, \left (\EllipticF \left (x \sqrt {-\frac {d}{c}}, \sqrt {-1-\frac {-a d -b c}{a d}}\right )-\EllipticE \left (x \sqrt {-\frac {d}{c}}, \sqrt {-1-\frac {-a d -b c}{a d}}\right )\right )}{\sqrt {-\frac {d}{c}}\, \sqrt {-b d \,x^{4}-a d \,x^{2}-c \,x^{2} b -a c}\, b}\right )}{\sqrt {b \,x^{2}+a}\, \sqrt {-d \,x^{2}-c}}\)	\(270\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((-d*x^2-c)^(1/2)/(b*x^2+a)^(1/2),x,method=_RETURNVERBOSE)

[Out]

(-a*d*EllipticF(x*(-d/c)^(1/2),(b*c/a/d)^(1/2))+c*EllipticF(x*(-d/c)^(1/2),(b*c/a/d)^(1/2))*b+a*d*EllipticE(x*
(-d/c)^(1/2),(b*c/a/d)^(1/2)))*(-d*x^2-c)^(1/2)*(b*x^2+a)^(1/2)*((d*x^2+c)/c)^(1/2)*((b*x^2+a)/a)^(1/2)/(b*d*x
^4+a*d*x^2+b*c*x^2+a*c)/(-d/c)^(1/2)/b

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-d*x^2-c)^(1/2)/(b*x^2+a)^(1/2),x, algorithm="maxima")

[Out]

integrate(sqrt(-d*x^2 - c)/sqrt(b*x^2 + a), x)

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Fricas [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-d*x^2-c)^(1/2)/(b*x^2+a)^(1/2),x, algorithm="fricas")

[Out]

Exception raised: TypeError >> Symbolic function elliptic_ec takes exactly 1 arguments (2 given)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\sqrt {- c - d x^{2}}}{\sqrt {a + b x^{2}}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-d*x**2-c)**(1/2)/(b*x**2+a)**(1/2),x)

[Out]

Integral(sqrt(-c - d*x**2)/sqrt(a + b*x**2), x)

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-d*x^2-c)^(1/2)/(b*x^2+a)^(1/2),x, algorithm="giac")

[Out]

integrate(sqrt(-d*x^2 - c)/sqrt(b*x^2 + a), x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {\sqrt {-d\,x^2-c}}{\sqrt {b\,x^2+a}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((- c - d*x^2)^(1/2)/(a + b*x^2)^(1/2),x)

[Out]

int((- c - d*x^2)^(1/2)/(a + b*x^2)^(1/2), x)

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