3.3.36 \(\int \frac {1}{\sqrt {2-4 x^2} \sqrt {1+x^2}} \, dx\) [236]

Optimal. Leaf size=16 \[ \frac {1}{2} F\left (\sin ^{-1}\left (\sqrt {2} x\right )|-\frac {1}{2}\right ) \]

[Out]

1/2*EllipticF(x*2^(1/2),1/2*I*2^(1/2))

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Rubi [A]
time = 0.00, antiderivative size = 16, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.048, Rules used = {430} \begin {gather*} \frac {1}{2} F\left (\text {ArcSin}\left (\sqrt {2} x\right )|-\frac {1}{2}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Int[1/(Sqrt[2 - 4*x^2]*Sqrt[1 + x^2]),x]

[Out]

EllipticF[ArcSin[Sqrt[2]*x], -1/2]/2

Rule 430

Int[1/(Sqrt[(a_) + (b_.)*(x_)^2]*Sqrt[(c_) + (d_.)*(x_)^2]), x_Symbol] :> Simp[(1/(Sqrt[a]*Sqrt[c]*Rt[-d/c, 2]
))*EllipticF[ArcSin[Rt[-d/c, 2]*x], b*(c/(a*d))], x] /; FreeQ[{a, b, c, d}, x] && NegQ[d/c] && GtQ[c, 0] && Gt
Q[a, 0] &&  !(NegQ[b/a] && SimplerSqrtQ[-b/a, -d/c])

Rubi steps

\begin {align*} \int \frac {1}{\sqrt {2-4 x^2} \sqrt {1+x^2}} \, dx &=\frac {1}{2} F\left (\sin ^{-1}\left (\sqrt {2} x\right )|-\frac {1}{2}\right )\\ \end {align*}

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Mathematica [A]
time = 0.05, size = 16, normalized size = 1.00 \begin {gather*} \frac {1}{2} F\left (\sin ^{-1}\left (\sqrt {2} x\right )|-\frac {1}{2}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[1/(Sqrt[2 - 4*x^2]*Sqrt[1 + x^2]),x]

[Out]

EllipticF[ArcSin[Sqrt[2]*x], -1/2]/2

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Maple [A]
time = 0.10, size = 15, normalized size = 0.94

method	result	size
default	\(\frac {\EllipticF \left (x \sqrt {2}, \frac {i \sqrt {2}}{2}\right )}{2}\)	\(15\)
elliptic	\(\frac {\sqrt {-\left (2 x^{2}-1\right ) \left (x^{2}+1\right )}\, \sqrt {2}\, \EllipticF \left (x \sqrt {2}, \frac {i \sqrt {2}}{2}\right )}{2 \sqrt {-4 x^{4}-2 x^{2}+2}}\)	\(48\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(-4*x^2+2)^(1/2)/(x^2+1)^(1/2),x,method=_RETURNVERBOSE)

[Out]

1/2*EllipticF(x*2^(1/2),1/2*I*2^(1/2))

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-4*x^2+2)^(1/2)/(x^2+1)^(1/2),x, algorithm="maxima")

[Out]

integrate(1/(sqrt(x^2 + 1)*sqrt(-4*x^2 + 2)), x)

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Fricas [A]
time = 0.27, size = 9, normalized size = 0.56 \begin {gather*} \frac {1}{2} \, {\rm ellipticF}\left (\sqrt {2} x, -\frac {1}{2}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-4*x^2+2)^(1/2)/(x^2+1)^(1/2),x, algorithm="fricas")

[Out]

1/2*ellipticF(sqrt(2)*x, -1/2)

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Sympy [A]
time = 2.09, size = 41, normalized size = 2.56 \begin {gather*} \frac {\sqrt {2} \left (\begin {cases} \frac {\sqrt {2} F\left (\operatorname {asin}{\left (\sqrt {2} x \right )}\middle | - \frac {1}{2}\right )}{2} & \text {for}\: x > - \frac {\sqrt {2}}{2} \wedge x < \frac {\sqrt {2}}{2} \end {cases}\right )}{2} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-4*x**2+2)**(1/2)/(x**2+1)**(1/2),x)

[Out]

sqrt(2)*Piecewise((sqrt(2)*elliptic_f(asin(sqrt(2)*x), -1/2)/2, (x > -sqrt(2)/2) & (x < sqrt(2)/2)))/2

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-4*x^2+2)^(1/2)/(x^2+1)^(1/2),x, algorithm="giac")

[Out]

integrate(1/(sqrt(x^2 + 1)*sqrt(-4*x^2 + 2)), x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.06 \begin {gather*} \int \frac {1}{\sqrt {x^2+1}\,\sqrt {2-4\,x^2}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/((x^2 + 1)^(1/2)*(2 - 4*x^2)^(1/2)),x)

[Out]

int(1/((x^2 + 1)^(1/2)*(2 - 4*x^2)^(1/2)), x)

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