Optimal. Leaf size=34 \[ -\frac {1}{4 \left (1+x^2\right )}-\frac {x \tan ^{-1}(x)}{2 \left (1+x^2\right )}+\frac {1}{4} \tan ^{-1}(x)^2 \]
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Rubi [A]
time = 0.03, antiderivative size = 34, normalized size of antiderivative = 1.00, number of steps
used = 2, number of rules used = 2, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {5054, 5004}
\begin {gather*} -\frac {x \text {ArcTan}(x)}{2 \left (x^2+1\right )}+\frac {\text {ArcTan}(x)^2}{4}-\frac {1}{4 \left (x^2+1\right )} \end {gather*}
Antiderivative was successfully verified.
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Rule 5004
Rule 5054
Rubi steps
\begin {align*} \int \frac {x^2 \tan ^{-1}(x)}{\left (1+x^2\right )^2} \, dx &=-\frac {1}{4 \left (1+x^2\right )}-\frac {x \tan ^{-1}(x)}{2 \left (1+x^2\right )}+\frac {1}{2} \int \frac {\tan ^{-1}(x)}{1+x^2} \, dx\\ &=-\frac {1}{4 \left (1+x^2\right )}-\frac {x \tan ^{-1}(x)}{2 \left (1+x^2\right )}+\frac {1}{4} \tan ^{-1}(x)^2\\ \end {align*}
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Mathematica [A]
time = 0.01, size = 28, normalized size = 0.82 \begin {gather*} \frac {-1-2 x \tan ^{-1}(x)+\left (1+x^2\right ) \tan ^{-1}(x)^2}{4 \left (1+x^2\right )} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.11, size = 29, normalized size = 0.85
method | result | size |
default | \(-\frac {1}{4 \left (x^{2}+1\right )}-\frac {x \arctan \left (x \right )}{2 \left (x^{2}+1\right )}+\frac {\arctan \left (x \right )^{2}}{4}\) | \(29\) |
risch | \(-\frac {\ln \left (i x +1\right )^{2}}{16}+\frac {\left (x^{2} \ln \left (-i x +1\right )+\ln \left (-i x +1\right )+2 i x \right ) \ln \left (i x +1\right )}{8 x^{2}+8}-\frac {x^{2} \ln \left (-i x +1\right )^{2}+\ln \left (-i x +1\right )^{2}+4 i x \ln \left (-i x +1\right )+4}{16 \left (x +i\right ) \left (x -i\right )}\) | \(101\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 1.56, size = 40, normalized size = 1.18 \begin {gather*} -\frac {1}{2} \, {\left (\frac {x}{x^{2} + 1} - \arctan \left (x\right )\right )} \arctan \left (x\right ) - \frac {{\left (x^{2} + 1\right )} \arctan \left (x\right )^{2} + 1}{4 \, {\left (x^{2} + 1\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.66, size = 26, normalized size = 0.76 \begin {gather*} \frac {{\left (x^{2} + 1\right )} \arctan \left (x\right )^{2} - 2 \, x \arctan \left (x\right ) - 1}{4 \, {\left (x^{2} + 1\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: RecursionError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.06, size = 23, normalized size = 0.68 \begin {gather*} \frac {{\mathrm {atan}\left (x\right )}^2}{4}-\frac {\frac {x\,\mathrm {atan}\left (x\right )}{2}+\frac {1}{4}}{x^2+1} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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