Optimal. Leaf size=44 \[ \frac {x}{16 \left (1+x^2\right )^2}+\frac {3 x}{32 \left (1+x^2\right )}+\frac {3}{32} \tan ^{-1}(x)-\frac {\tan ^{-1}(x)}{4 \left (1+x^2\right )^2} \]
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Rubi [A]
time = 0.02, antiderivative size = 44, normalized size of antiderivative = 1.00, number of steps
used = 4, number of rules used = 3, integrand size = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.273, Rules used = {5050, 205, 209}
\begin {gather*} -\frac {\text {ArcTan}(x)}{4 \left (x^2+1\right )^2}+\frac {3 \text {ArcTan}(x)}{32}+\frac {3 x}{32 \left (x^2+1\right )}+\frac {x}{16 \left (x^2+1\right )^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 205
Rule 209
Rule 5050
Rubi steps
\begin {align*} \int \frac {x \tan ^{-1}(x)}{\left (1+x^2\right )^3} \, dx &=-\frac {\tan ^{-1}(x)}{4 \left (1+x^2\right )^2}+\frac {1}{4} \int \frac {1}{\left (1+x^2\right )^3} \, dx\\ &=\frac {x}{16 \left (1+x^2\right )^2}-\frac {\tan ^{-1}(x)}{4 \left (1+x^2\right )^2}+\frac {3}{16} \int \frac {1}{\left (1+x^2\right )^2} \, dx\\ &=\frac {x}{16 \left (1+x^2\right )^2}+\frac {3 x}{32 \left (1+x^2\right )}-\frac {\tan ^{-1}(x)}{4 \left (1+x^2\right )^2}+\frac {3}{32} \int \frac {1}{1+x^2} \, dx\\ &=\frac {x}{16 \left (1+x^2\right )^2}+\frac {3 x}{32 \left (1+x^2\right )}+\frac {3}{32} \tan ^{-1}(x)-\frac {\tan ^{-1}(x)}{4 \left (1+x^2\right )^2}\\ \end {align*}
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Mathematica [A]
time = 0.01, size = 36, normalized size = 0.82 \begin {gather*} \frac {x \left (5+3 x^2\right )+\left (-5+6 x^2+3 x^4\right ) \tan ^{-1}(x)}{32 \left (1+x^2\right )^2} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.09, size = 37, normalized size = 0.84
method | result | size |
default | \(\frac {x}{16 \left (x^{2}+1\right )^{2}}+\frac {3 x}{32 \left (x^{2}+1\right )}+\frac {3 \arctan \left (x \right )}{32}-\frac {\arctan \left (x \right )}{4 \left (x^{2}+1\right )^{2}}\) | \(37\) |
risch | \(\frac {i \ln \left (i x +1\right )}{8 \left (x^{2}+1\right )^{2}}-\frac {i \left (8 \ln \left (-i x +1\right )+3 \ln \left (x -i\right ) x^{4}+6 x^{2} \ln \left (x -i\right )+3 \ln \left (x -i\right )-3 \ln \left (x +i\right ) x^{4}-6 \ln \left (x +i\right ) x^{2}-3 \ln \left (x +i\right )+6 i x^{3}+10 i x \right )}{64 \left (x +i\right )^{2} \left (x -i\right )^{2}}\) | \(108\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 1.02, size = 39, normalized size = 0.89 \begin {gather*} \frac {3 \, x^{3} + 5 \, x}{32 \, {\left (x^{4} + 2 \, x^{2} + 1\right )}} - \frac {\arctan \left (x\right )}{4 \, {\left (x^{2} + 1\right )}^{2}} + \frac {3}{32} \, \arctan \left (x\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.52, size = 38, normalized size = 0.86 \begin {gather*} \frac {3 \, x^{3} + {\left (3 \, x^{4} + 6 \, x^{2} - 5\right )} \arctan \left (x\right ) + 5 \, x}{32 \, {\left (x^{4} + 2 \, x^{2} + 1\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [B] Leaf count of result is larger than twice the leaf count of optimal. 88 vs.
\(2 (37) = 74\).
time = 0.33, size = 88, normalized size = 2.00 \begin {gather*} \frac {3 x^{4} \operatorname {atan}{\left (x \right )}}{32 x^{4} + 64 x^{2} + 32} + \frac {3 x^{3}}{32 x^{4} + 64 x^{2} + 32} + \frac {6 x^{2} \operatorname {atan}{\left (x \right )}}{32 x^{4} + 64 x^{2} + 32} + \frac {5 x}{32 x^{4} + 64 x^{2} + 32} - \frac {5 \operatorname {atan}{\left (x \right )}}{32 x^{4} + 64 x^{2} + 32} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.68, size = 34, normalized size = 0.77 \begin {gather*} \frac {3 \, x^{3} + 5 \, x}{32 \, {\left (x^{2} + 1\right )}^{2}} - \frac {\arctan \left (x\right )}{4 \, {\left (x^{2} + 1\right )}^{2}} + \frac {3}{32} \, \arctan \left (x\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.32, size = 26, normalized size = 0.59 \begin {gather*} \frac {3\,\mathrm {atan}\left (x\right )}{32}+\frac {\frac {5\,x}{32}-\frac {\mathrm {atan}\left (x\right )}{4}+\frac {3\,x^3}{32}}{{\left (x^2+1\right )}^2} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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