Optimal. Leaf size=60 \[ -\frac {2 x}{3}-\frac {\sin (x)}{9 (1+\cos (x))^2}+\frac {8 \sin (x)}{9 (1+\cos (x))}-\frac {\log (\sin (x)) \sin (x)}{3 (1+\cos (x))^2}+\frac {2 \log (\sin (x)) \sin (x)}{3 (1+\cos (x))} \]
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Rubi [A]
time = 0.09, antiderivative size = 60, normalized size of antiderivative = 1.00, number of steps
used = 6, number of rules used = 7, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.583, Rules used = {2829, 2727,
2634, 12, 3047, 3098, 2814} \begin {gather*} -\frac {2 x}{3}+\frac {8 \sin (x)}{9 (\cos (x)+1)}-\frac {\sin (x)}{9 (\cos (x)+1)^2}+\frac {2 \sin (x) \log (\sin (x))}{3 (\cos (x)+1)}-\frac {\sin (x) \log (\sin (x))}{3 (\cos (x)+1)^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 12
Rule 2634
Rule 2727
Rule 2814
Rule 2829
Rule 3047
Rule 3098
Rubi steps
\begin {align*} \int \frac {\cos (x) \log (\sin (x))}{(1+\cos (x))^2} \, dx &=-\frac {\log (\sin (x)) \sin (x)}{3 (1+\cos (x))^2}+\frac {2 \log (\sin (x)) \sin (x)}{3 (1+\cos (x))}-\int \frac {\cos (x) (1+2 \cos (x))}{3 (1+\cos (x))^2} \, dx\\ &=-\frac {\log (\sin (x)) \sin (x)}{3 (1+\cos (x))^2}+\frac {2 \log (\sin (x)) \sin (x)}{3 (1+\cos (x))}-\frac {1}{3} \int \frac {\cos (x) (1+2 \cos (x))}{(1+\cos (x))^2} \, dx\\ &=-\frac {\log (\sin (x)) \sin (x)}{3 (1+\cos (x))^2}+\frac {2 \log (\sin (x)) \sin (x)}{3 (1+\cos (x))}-\frac {1}{3} \int \frac {\cos (x)+2 \cos ^2(x)}{(1+\cos (x))^2} \, dx\\ &=-\frac {\sin (x)}{9 (1+\cos (x))^2}-\frac {\log (\sin (x)) \sin (x)}{3 (1+\cos (x))^2}+\frac {2 \log (\sin (x)) \sin (x)}{3 (1+\cos (x))}+\frac {1}{9} \int \frac {2-6 \cos (x)}{1+\cos (x)} \, dx\\ &=-\frac {2 x}{3}-\frac {\sin (x)}{9 (1+\cos (x))^2}-\frac {\log (\sin (x)) \sin (x)}{3 (1+\cos (x))^2}+\frac {2 \log (\sin (x)) \sin (x)}{3 (1+\cos (x))}+\frac {8}{9} \int \frac {1}{1+\cos (x)} \, dx\\ &=-\frac {2 x}{3}-\frac {\sin (x)}{9 (1+\cos (x))^2}+\frac {8 \sin (x)}{9 (1+\cos (x))}-\frac {\log (\sin (x)) \sin (x)}{3 (1+\cos (x))^2}+\frac {2 \log (\sin (x)) \sin (x)}{3 (1+\cos (x))}\\ \end {align*}
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Mathematica [A]
time = 0.10, size = 56, normalized size = 0.93 \begin {gather*} -\frac {1}{18} \sec ^3\left (\frac {x}{2}\right ) \left (9 x \cos \left (\frac {x}{2}\right )+3 x \cos \left (\frac {3 x}{2}\right )-(7+3 \log (\sin (x))+\cos (x) (8+6 \log (\sin (x)))) \sin \left (\frac {x}{2}\right )\right ) \end {gather*}
Antiderivative was successfully verified.
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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(105\) vs.
\(2(50)=100\).
time = 0.28, size = 106, normalized size = 1.77
method | result | size |
default | \(\frac {6 \left (\cos ^{3}\left (x \right )\right ) \ln \left (2\right )+6 \left (\cos ^{3}\left (x \right )\right ) \ln \left (\frac {\sin \left (x \right )}{2}\right )-12 \left (\cos ^{2}\left (x \right )\right ) \sin \left (x \right ) \arctan \left (\frac {\cos \left (x \right )-1}{\sin \left (x \right )}\right )+8 \left (\cos ^{3}\left (x \right )\right )-9 \left (\cos ^{2}\left (x \right )\right ) \ln \left (2\right )-9 \left (\cos ^{2}\left (x \right )\right ) \ln \left (\frac {\sin \left (x \right )}{2}\right )-9 \left (\cos ^{2}\left (x \right )\right )+12 \arctan \left (\frac {\cos \left (x \right )-1}{\sin \left (x \right )}\right ) \sin \left (x \right )-6 \cos \left (x \right )+3 \ln \left (2\right )+3 \ln \left (\frac {\sin \left (x \right )}{2}\right )+7}{9 \sin \left (x \right )^{3}}\) | \(106\) |
risch | \(-\frac {2 i \left (3 \,{\mathrm e}^{2 i x}+3 \,{\mathrm e}^{i x}+2\right ) \ln \left ({\mathrm e}^{i x}\right )}{3 \left (1+{\mathrm e}^{i x}\right )^{3}}+\frac {6 \pi -12 x +9 \pi \,{\mathrm e}^{2 i x}-9 \pi \mathrm {csgn}\left (i \sin \left (x \right )\right )^{2} {\mathrm e}^{2 i x}-6 \pi \,\mathrm {csgn}\left (i \left ({\mathrm e}^{2 i x}-1\right )\right ) \mathrm {csgn}\left (\sin \left (x \right )\right )^{2}-9 \pi \mathrm {csgn}\left (\sin \left (x \right )\right )^{3} {\mathrm e}^{2 i x}+9 \pi \mathrm {csgn}\left (i \sin \left (x \right )\right )^{3} {\mathrm e}^{2 i x}-9 \,{\mathrm e}^{i x} \pi \mathrm {csgn}\left (i \sin \left (x \right )\right )^{2}-6 i \ln \left ({\mathrm e}^{2 i x}-1\right ) {\mathrm e}^{3 i x}-18 i \ln \left (2\right ) {\mathrm e}^{2 i x}-6 \pi \mathrm {csgn}\left (\sin \left (x \right )\right )^{3}+18 i {\mathrm e}^{2 i x}+6 \pi \mathrm {csgn}\left (i \sin \left (x \right )\right )^{3}-12 i \ln \left (2\right )+6 i \ln \left ({\mathrm e}^{2 i x}-1\right )+9 \,{\mathrm e}^{i x} \pi +30 i {\mathrm e}^{i x}+9 \,{\mathrm e}^{i x} \pi \,\mathrm {csgn}\left (\sin \left (x \right )\right ) \mathrm {csgn}\left (i \sin \left (x \right )\right )^{2}-9 \,{\mathrm e}^{i x} \pi \,\mathrm {csgn}\left (i {\mathrm e}^{-i x}\right ) \mathrm {csgn}\left (\sin \left (x \right )\right )^{2}+16 i-36 x \,{\mathrm e}^{2 i x}-9 \,{\mathrm e}^{i x} \pi \,\mathrm {csgn}\left (\sin \left (x \right )\right ) \mathrm {csgn}\left (i \sin \left (x \right )\right )-9 \pi \,\mathrm {csgn}\left (i \left ({\mathrm e}^{2 i x}-1\right )\right ) \mathrm {csgn}\left (\sin \left (x \right )\right )^{2} {\mathrm e}^{2 i x}-9 \pi \,\mathrm {csgn}\left (i {\mathrm e}^{-i x}\right ) \mathrm {csgn}\left (\sin \left (x \right )\right )^{2} {\mathrm e}^{2 i x}+9 \pi \,\mathrm {csgn}\left (\sin \left (x \right )\right ) \mathrm {csgn}\left (i \sin \left (x \right )\right )^{2} {\mathrm e}^{2 i x}-9 \pi \,\mathrm {csgn}\left (i \left ({\mathrm e}^{2 i x}-1\right )\right ) \mathrm {csgn}\left (\sin \left (x \right )\right )^{2} {\mathrm e}^{i x}-6 \,\mathrm {csgn}\left (\sin \left (x \right )\right ) \mathrm {csgn}\left (i {\mathrm e}^{-i x}\right ) \mathrm {csgn}\left (i \left ({\mathrm e}^{2 i x}-1\right )\right ) \pi -9 \pi \,\mathrm {csgn}\left (\sin \left (x \right )\right ) \mathrm {csgn}\left (i \sin \left (x \right )\right ) {\mathrm e}^{2 i x}+6 \mathrm {csgn}\left (i \sin \left (x \right )\right )^{2} \mathrm {csgn}\left (\sin \left (x \right )\right ) \pi -6 \mathrm {csgn}\left (\sin \left (x \right )\right )^{2} \mathrm {csgn}\left (i {\mathrm e}^{-i x}\right ) \pi -6 \,\mathrm {csgn}\left (i \sin \left (x \right )\right ) \mathrm {csgn}\left (\sin \left (x \right )\right ) \pi -18 i {\mathrm e}^{i x} \ln \left (2\right )-9 \,{\mathrm e}^{i x} \pi \mathrm {csgn}\left (\sin \left (x \right )\right )^{3}+9 \,{\mathrm e}^{i x} \pi \mathrm {csgn}\left (i \sin \left (x \right )\right )^{3}-12 x \,{\mathrm e}^{3 i x}-36 x \,{\mathrm e}^{i x}-6 \mathrm {csgn}\left (i \sin \left (x \right )\right )^{2} \pi -9 \pi \,\mathrm {csgn}\left (i \left ({\mathrm e}^{2 i x}-1\right )\right ) \mathrm {csgn}\left (i {\mathrm e}^{-i x}\right ) \mathrm {csgn}\left (\sin \left (x \right )\right ) {\mathrm e}^{2 i x}-9 \pi \,\mathrm {csgn}\left (i \left ({\mathrm e}^{2 i x}-1\right )\right ) \mathrm {csgn}\left (i {\mathrm e}^{-i x}\right ) \mathrm {csgn}\left (\sin \left (x \right )\right ) {\mathrm e}^{i x}}{9 \left (1+{\mathrm e}^{i x}\right )^{3}}\) | \(598\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 2.28, size = 86, normalized size = 1.43 \begin {gather*} \frac {1}{6} \, {\left (\frac {3 \, \sin \left (x\right )}{\cos \left (x\right ) + 1} - \frac {\sin \left (x\right )^{3}}{{\left (\cos \left (x\right ) + 1\right )}^{3}}\right )} \log \left (\frac {2 \, \sin \left (x\right )}{{\left (\frac {\sin \left (x\right )^{2}}{{\left (\cos \left (x\right ) + 1\right )}^{2}} + 1\right )} {\left (\cos \left (x\right ) + 1\right )}}\right ) + \frac {5 \, \sin \left (x\right )}{6 \, {\left (\cos \left (x\right ) + 1\right )}} - \frac {\sin \left (x\right )^{3}}{18 \, {\left (\cos \left (x\right ) + 1\right )}^{3}} - \frac {4}{3} \, \arctan \left (\frac {\sin \left (x\right )}{\cos \left (x\right ) + 1}\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.52, size = 53, normalized size = 0.88 \begin {gather*} -\frac {6 \, x \cos \left (x\right )^{2} - 3 \, {\left (2 \, \cos \left (x\right ) + 1\right )} \log \left (\sin \left (x\right )\right ) \sin \left (x\right ) + 12 \, x \cos \left (x\right ) - {\left (8 \, \cos \left (x\right ) + 7\right )} \sin \left (x\right ) + 6 \, x}{9 \, {\left (\cos \left (x\right )^{2} + 2 \, \cos \left (x\right ) + 1\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 3.07, size = 88, normalized size = 1.47 \begin {gather*} - \frac {2 x}{3} - \frac {\log {\left (\frac {\tan {\left (\frac {x}{2} \right )}}{\tan ^{2}{\left (\frac {x}{2} \right )} + 1} \right )} \tan ^{3}{\left (\frac {x}{2} \right )}}{6} + \frac {\log {\left (\frac {\tan {\left (\frac {x}{2} \right )}}{\tan ^{2}{\left (\frac {x}{2} \right )} + 1} \right )} \tan {\left (\frac {x}{2} \right )}}{2} - \frac {\log {\left (2 \right )} \tan ^{3}{\left (\frac {x}{2} \right )}}{6} - \frac {\tan ^{3}{\left (\frac {x}{2} \right )}}{18} + \frac {\log {\left (2 \right )} \tan {\left (\frac {x}{2} \right )}}{2} + \frac {5 \tan {\left (\frac {x}{2} \right )}}{6} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.79, size = 36, normalized size = 0.60 \begin {gather*} -\frac {1}{18} \, \tan \left (\frac {1}{2} \, x\right )^{3} - \frac {1}{6} \, {\left (\tan \left (\frac {1}{2} \, x\right )^{3} - 3 \, \tan \left (\frac {1}{2} \, x\right )\right )} \log \left (\sin \left (x\right )\right ) - \frac {2}{3} \, x + \frac {5}{6} \, \tan \left (\frac {1}{2} \, x\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.79, size = 164, normalized size = 2.73 \begin {gather*} \frac {\frac {4\,\sin \left (2\,x\right )}{9}-\frac {\ln \left (-2\,{\sin \left (x\right )}^2+\sin \left (2\,x\right )\,1{}\mathrm {i}\right )\,7{}\mathrm {i}}{3}-\frac {14\,x}{3}+\frac {\ln \left (\sin \left (x\right )\right )\,7{}\mathrm {i}}{3}+\frac {7\,\sin \left (x\right )}{9}+\frac {\sin \left (2\,x\right )\,\ln \left (\sin \left (x\right )\right )}{3}-\frac {{\sin \left (x\right )}^2\,8{}\mathrm {i}}{9}+{\sin \left (\frac {x}{2}\right )}^2\,\left (\frac {16\,x}{3}+\frac {\ln \left (-2\,{\sin \left (x\right )}^2+\sin \left (2\,x\right )\,1{}\mathrm {i}\right )\,8{}\mathrm {i}}{3}-\frac {\ln \left (\sin \left (x\right )\right )\,8{}\mathrm {i}}{3}-\frac {32}{9}{}\mathrm {i}\right )+\frac {\ln \left (-2\,{\sin \left (x\right )}^2+\sin \left (2\,x\right )\,1{}\mathrm {i}\right )\,\left (2\,{\sin \left (x\right )}^2-1\right )\,1{}\mathrm {i}}{3}+\frac {\ln \left (\sin \left (x\right )\right )\,\sin \left (x\right )}{3}-\frac {\ln \left (\sin \left (x\right )\right )\,\left (2\,{\sin \left (x\right )}^2-1\right )\,1{}\mathrm {i}}{3}+\frac {2\,x\,\left (2\,{\sin \left (x\right )}^2-1\right )}{3}+\frac {32}{9}{}\mathrm {i}}{{\left (2\,{\sin \left (\frac {x}{2}\right )}^2-2\right )}^2} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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