3.7.15 \(\int \frac {1}{x^3 \log ^4(x)} \, dx\) [615]

Optimal. Leaf size=43 \[ -\frac {4}{3} \text {Ei}(-2 \log (x))-\frac {1}{3 x^2 \log ^3(x)}+\frac {1}{3 x^2 \log ^2(x)}-\frac {2}{3 x^2 \log (x)} \]

[Out]

-4/3*Ei(-2*ln(x))-1/3/x^2/ln(x)^3+1/3/x^2/ln(x)^2-2/3/x^2/ln(x)

________________________________________________________________________________________

Rubi [A]
time = 0.05, antiderivative size = 43, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 3, integrand size = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.375, Rules used = {2343, 2346, 2209} \begin {gather*} -\frac {4}{3} \text {ExpIntegralEi}(-2 \log (x))-\frac {1}{3 x^2 \log ^3(x)}+\frac {1}{3 x^2 \log ^2(x)}-\frac {2}{3 x^2 \log (x)} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[1/(x^3*Log[x]^4),x]

[Out]

(-4*ExpIntegralEi[-2*Log[x]])/3 - 1/(3*x^2*Log[x]^3) + 1/(3*x^2*Log[x]^2) - 2/(3*x^2*Log[x])

Rule 2209

Int[(F_)^((g_.)*((e_.) + (f_.)*(x_)))/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[(F^(g*(e - c*(f/d)))/d)*ExpInteg
ralEi[f*g*(c + d*x)*(Log[F]/d)], x] /; FreeQ[{F, c, d, e, f, g}, x] &&  !TrueQ[$UseGamma]

Rule 2343

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_)*((d_.)*(x_))^(m_.), x_Symbol] :> Simp[(d*x)^(m + 1)*((a + b*Log
[c*x^n])^(p + 1)/(b*d*n*(p + 1))), x] - Dist[(m + 1)/(b*n*(p + 1)), Int[(d*x)^m*(a + b*Log[c*x^n])^(p + 1), x]
, x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[m, -1] && LtQ[p, -1]

Rule 2346

Int[((a_.) + Log[(c_.)*(x_)]*(b_.))^(p_)*(x_)^(m_.), x_Symbol] :> Dist[1/c^(m + 1), Subst[Int[E^((m + 1)*x)*(a
+ b*x)^p, x], x, Log[c*x]], x] /; FreeQ[{a, b, c, p}, x] && IntegerQ[m]

Rubi steps

\begin {align*} \int \frac {1}{x^3 \log ^4(x)} \, dx &=-\frac {1}{3 x^2 \log ^3(x)}-\frac {2}{3} \int \frac {1}{x^3 \log ^3(x)} \, dx\\ &=-\frac {1}{3 x^2 \log ^3(x)}+\frac {1}{3 x^2 \log ^2(x)}+\frac {2}{3} \int \frac {1}{x^3 \log ^2(x)} \, dx\\ &=-\frac {1}{3 x^2 \log ^3(x)}+\frac {1}{3 x^2 \log ^2(x)}-\frac {2}{3 x^2 \log (x)}-\frac {4}{3} \int \frac {1}{x^3 \log (x)} \, dx\\ &=-\frac {1}{3 x^2 \log ^3(x)}+\frac {1}{3 x^2 \log ^2(x)}-\frac {2}{3 x^2 \log (x)}-\frac {4}{3} \text {Subst}\left (\int \frac {e^{-2 x}}{x} \, dx,x,\log (x)\right )\\ &=-\frac {4}{3} \text {Ei}(-2 \log (x))-\frac {1}{3 x^2 \log ^3(x)}+\frac {1}{3 x^2 \log ^2(x)}-\frac {2}{3 x^2 \log (x)}\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]
time = 0.02, size = 43, normalized size = 1.00 \begin {gather*} -\frac {4}{3} \text {Ei}(-2 \log (x))-\frac {1}{3 x^2 \log ^3(x)}+\frac {1}{3 x^2 \log ^2(x)}-\frac {2}{3 x^2 \log (x)} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[1/(x^3*Log[x]^4),x]

[Out]

(-4*ExpIntegralEi[-2*Log[x]])/3 - 1/(3*x^2*Log[x]^3) + 1/(3*x^2*Log[x]^2) - 2/(3*x^2*Log[x])

________________________________________________________________________________________

Maple [A]
time = 0.01, size = 37, normalized size = 0.86

method	result	size
risch	\(-\frac {2 \ln \left (x \right )^{2}-\ln \left (x \right )+1}{3 x^{2} \ln \left (x \right )^{3}}+\frac {4 \expIntegral \left (1, 2 \ln \left (x \right )\right )}{3}\)	\(31\)
default	\(-\frac {1}{3 x^{2} \ln \left (x \right )^{3}}+\frac {1}{3 x^{2} \ln \left (x \right )^{2}}-\frac {2}{3 x^{2} \ln \left (x \right )}+\frac {4 \expIntegral \left (1, 2 \ln \left (x \right )\right )}{3}\)	\(37\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/x^3/ln(x)^4,x,method=_RETURNVERBOSE)

[Out]

-1/3/x^2/ln(x)^3+1/3/x^2/ln(x)^2-2/3/x^2/ln(x)+4/3*Ei(1,2*ln(x))

________________________________________________________________________________________

Maxima [A]
time = 1.49, size = 8, normalized size = 0.19 \begin {gather*} -8 \, \Gamma \left (-3, 2 \, \log \left (x\right )\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^3/log(x)^4,x, algorithm="maxima")

[Out]

-8*gamma(-3, 2*log(x))

________________________________________________________________________________________

Fricas [A]
time = 0.79, size = 34, normalized size = 0.79 \begin {gather*} -\frac {4 \, x^{2} \log \left (x\right )^{3} \operatorname {log\_integral}\left (\frac {1}{x^{2}}\right ) + 2 \, \log \left (x\right )^{2} - \log \left (x\right ) + 1}{3 \, x^{2} \log \left (x\right )^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^3/log(x)^4,x, algorithm="fricas")

[Out]

-1/3*(4*x^2*log(x)^3*log_integral(x^(-2)) + 2*log(x)^2 - log(x) + 1)/(x^2*log(x)^3)

________________________________________________________________________________________

Sympy [A]
time = 0.34, size = 32, normalized size = 0.74 \begin {gather*} - \frac {4 \operatorname {Ei}{\left (- 2 \log {\left (x \right )} \right )}}{3} + \frac {- 2 \log {\left (x \right )}^{2} + \log {\left (x \right )} - 1}{3 x^{2} \log {\left (x \right )}^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x**3/ln(x)**4,x)

[Out]

-4*Ei(-2*log(x))/3 + (-2*log(x)**2 + log(x) - 1)/(3*x**2*log(x)**3)

________________________________________________________________________________________

Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^3/log(x)^4,x, algorithm="giac")

[Out]

integrate(1/(x^3*log(x)^4), x)

________________________________________________________________________________________

Mupad [B]
time = 0.28, size = 29, normalized size = 0.67 \begin {gather*} -\frac {4\,\mathrm {ei}\left (-2\,\ln \left (x\right )\right )}{3}-\frac {\frac {2\,{\ln \left (x\right )}^2}{3}-\frac {\ln \left (x\right )}{3}+\frac {1}{3}}{x^2\,{\ln \left (x\right )}^3} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x^3*log(x)^4),x)

[Out]

- (4*ei(-2*log(x)))/3 - ((2*log(x)^2)/3 - log(x)/3 + 1/3)/(x^2*log(x)^3)

________________________________________________________________________________________