3.6.14 \(\int (1+a^{m x})^3 \, dx\) [514]

Optimal. Leaf size=50 \[ x+\frac {3 a^{m x}}{m \log (a)}+\frac {3 a^{2 m x}}{2 m \log (a)}+\frac {a^{3 m x}}{3 m \log (a)} \]

[Out]

x+3*a^(m*x)/m/ln(a)+3/2*a^(2*m*x)/m/ln(a)+1/3*a^(3*m*x)/m/ln(a)

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Rubi [A]
time = 0.01, antiderivative size = 50, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.222, Rules used = {2320, 45} \begin {gather*} \frac {3 a^{m x}}{m \log (a)}+\frac {3 a^{2 m x}}{2 m \log (a)}+\frac {a^{3 m x}}{3 m \log (a)}+x \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(1 + a^(m*x))^3,x]

[Out]

x + (3*a^(m*x))/(m*Log[a]) + (3*a^(2*m*x))/(2*m*Log[a]) + a^(3*m*x)/(3*m*Log[a])

Rule 45

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 2320

Int[u_, x_Symbol] :> With[{v = FunctionOfExponential[u, x]}, Dist[v/D[v, x], Subst[Int[FunctionOfExponentialFu
nction[u, x]/x, x], x, v], x]] /; FunctionOfExponentialQ[u, x] &&  !MatchQ[u, (w_)*((a_.)*(v_)^(n_))^(m_) /; F
reeQ[{a, m, n}, x] && IntegerQ[m*n]] &&  !MatchQ[u, E^((c_.)*((a_.) + (b_.)*x))*(F_)[v_] /; FreeQ[{a, b, c}, x
] && InverseFunctionQ[F[x]]]

Rubi steps

\begin {align*} \int \left (1+a^{m x}\right )^3 \, dx &=\frac {\text {Subst}\left (\int \frac {(1+x)^3}{x} \, dx,x,a^{m x}\right )}{m \log (a)}\\ &=\frac {\text {Subst}\left (\int \left (3+\frac {1}{x}+3 x+x^2\right ) \, dx,x,a^{m x}\right )}{m \log (a)}\\ &=x+\frac {3 a^{m x}}{m \log (a)}+\frac {3 a^{2 m x}}{2 m \log (a)}+\frac {a^{3 m x}}{3 m \log (a)}\\ \end {align*}

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Mathematica [A]
time = 0.02, size = 45, normalized size = 0.90 \begin {gather*} \frac {\frac {a^{m x} \left (18+9 a^{m x}+2 a^{2 m x}\right )}{6 m}+\frac {\log \left (a^{m x}\right )}{m}}{\log (a)} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(1 + a^(m*x))^3,x]

[Out]

((a^(m*x)*(18 + 9*a^(m*x) + 2*a^(2*m*x)))/(6*m) + Log[a^(m*x)]/m)/Log[a]

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Maple [A]
time = 0.02, size = 41, normalized size = 0.82

method	result	size
derivativedivides	\(\frac {\frac {a^{3 m x}}{3}+\frac {3 a^{2 m x}}{2}+3 a^{m x}+\ln \left (a^{m x}\right )}{m \ln \left (a \right )}\)	\(41\)
default	\(\frac {\frac {a^{3 m x}}{3}+\frac {3 a^{2 m x}}{2}+3 a^{m x}+\ln \left (a^{m x}\right )}{m \ln \left (a \right )}\)	\(41\)
risch	\(x +\frac {3 a^{m x}}{m \ln \left (a \right )}+\frac {3 a^{2 m x}}{2 m \ln \left (a \right )}+\frac {a^{3 m x}}{3 m \ln \left (a \right )}\)	\(49\)
norman	\(x +\frac {3 \,{\mathrm e}^{m x \ln \left (a \right )}}{m \ln \left (a \right )}+\frac {3 \,{\mathrm e}^{2 m x \ln \left (a \right )}}{2 m \ln \left (a \right )}+\frac {{\mathrm e}^{3 m x \ln \left (a \right )}}{3 m \ln \left (a \right )}\)	\(52\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1+a^(m*x))^3,x,method=_RETURNVERBOSE)

[Out]

1/m/ln(a)*(1/3*(a^(m*x))^3+3/2*(a^(m*x))^2+3*a^(m*x)+ln(a^(m*x)))

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Maxima [A]
time = 2.84, size = 46, normalized size = 0.92 \begin {gather*} x + \frac {a^{3 \, m x}}{3 \, m \log \left (a\right )} + \frac {3 \, a^{2 \, m x}}{2 \, m \log \left (a\right )} + \frac {3 \, a^{m x}}{m \log \left (a\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1+a^(m*x))^3,x, algorithm="maxima")

[Out]

x + 1/3*a^(3*m*x)/(m*log(a)) + 3/2*a^(2*m*x)/(m*log(a)) + 3*a^(m*x)/(m*log(a))

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Fricas [A]
time = 0.46, size = 39, normalized size = 0.78 \begin {gather*} \frac {6 \, m x \log \left (a\right ) + 2 \, a^{3 \, m x} + 9 \, a^{2 \, m x} + 18 \, a^{m x}}{6 \, m \log \left (a\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1+a^(m*x))^3,x, algorithm="fricas")

[Out]

1/6*(6*m*x*log(a) + 2*a^(3*m*x) + 9*a^(2*m*x) + 18*a^(m*x))/(m*log(a))

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Sympy [A]
time = 0.05, size = 70, normalized size = 1.40 \begin {gather*} x + \begin {cases} \frac {2 a^{3 m x} m^{2} \log {\left (a \right )}^{2} + 9 a^{2 m x} m^{2} \log {\left (a \right )}^{2} + 18 a^{m x} m^{2} \log {\left (a \right )}^{2}}{6 m^{3} \log {\left (a \right )}^{3}} & \text {for}\: m^{3} \log {\left (a \right )}^{3} \neq 0 \\7 x & \text {otherwise} \end {cases} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1+a**(m*x))**3,x)

[Out]

x + Piecewise(((2*a**(3*m*x)*m**2*log(a)**2 + 9*a**(2*m*x)*m**2*log(a)**2 + 18*a**(m*x)*m**2*log(a)**2)/(6*m**
3*log(a)**3), Ne(m**3*log(a)**3, 0)), (7*x, True))

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Giac [A]
time = 1.12, size = 40, normalized size = 0.80 \begin {gather*} \frac {6 \, m x \log \left ({\left | a \right |}\right ) + 2 \, a^{3 \, m x} + 9 \, a^{2 \, m x} + 18 \, a^{m x}}{6 \, m \log \left (a\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1+a^(m*x))^3,x, algorithm="giac")

[Out]

1/6*(6*m*x*log(abs(a)) + 2*a^(3*m*x) + 9*a^(2*m*x) + 18*a^(m*x))/(m*log(a))

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Mupad [B]
time = 0.33, size = 34, normalized size = 0.68 \begin {gather*} x+\frac {3\,a^{m\,x}+\frac {3\,a^{2\,m\,x}}{2}+\frac {a^{3\,m\,x}}{3}}{m\,\ln \left (a\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a^(m*x) + 1)^3,x)

[Out]

x + (3*a^(m*x) + (3*a^(2*m*x))/2 + a^(3*m*x)/3)/(m*log(a))

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