3.5.73 \(\int \frac {(\frac {2+x^2}{x^2})^{7/9}}{(2+x^2)^{3/2}} \, dx\) [473]

Optimal. Leaf size=25 \[ -\frac {9 \left (1+\frac {2}{x^2}\right )^{7/9} x}{10 \sqrt {2+x^2}} \]

[Out]

-9/10*(1+2/x^2)^(7/9)*x/(x^2+2)^(1/2)

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Rubi [A]
time = 0.04, antiderivative size = 25, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.130, Rules used = {2016, 446, 270} \begin {gather*} -\frac {9 \left (\frac {2}{x^2}+1\right )^{7/9} x}{10 \sqrt {x^2+2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[((2 + x^2)/x^2)^(7/9)/(2 + x^2)^(3/2),x]

[Out]

(-9*(1 + 2/x^2)^(7/9)*x)/(10*Sqrt[2 + x^2])

Rule 270

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(c*x)^(m + 1)*((a + b*x^n)^(p + 1)/(a*
c*(m + 1))), x] /; FreeQ[{a, b, c, m, n, p}, x] && EqQ[(m + 1)/n + p + 1, 0] && NeQ[m, -1]

Rule 446

Int[((c_) + (d_.)*(x_)^(mn_.))^(q_)*((a_) + (b_.)*(x_)^(n_.))^(p_), x_Symbol] :> Dist[x^(n*FracPart[q])*((c +
d/x^n)^FracPart[q]/(d + c*x^n)^FracPart[q]), Int[(a + b*x^n)^p*((d + c*x^n)^q/x^(n*q)), x], x] /; FreeQ[{a, b,
c, d, n, p, q}, x] && EqQ[mn, -n] &&  !IntegerQ[q] &&  !IntegerQ[p]

Rule 2016

Int[(u_)^(q_.)*(v_)^(p_.), x_Symbol] :> Int[ExpandToSum[u, x]^q*ExpandToSum[v, x]^p, x] /; FreeQ[{p, q}, x] &&
BinomialQ[u, x] && BinomialQ[v, x] &&  !(BinomialMatchQ[u, x] && BinomialMatchQ[v, x])

Rubi steps

\begin {align*} \int \frac {\left (\frac {2+x^2}{x^2}\right )^{7/9}}{\left (2+x^2\right )^{3/2}} \, dx &=\int \frac {\left (1+\frac {2}{x^2}\right )^{7/9}}{\left (2+x^2\right )^{3/2}} \, dx\\ &=\frac {\left (\left (1+\frac {2}{x^2}\right )^{7/9} x^{14/9}\right ) \int \frac {1}{x^{14/9} \left (2+x^2\right )^{13/18}} \, dx}{\left (2+x^2\right )^{7/9}}\\ &=-\frac {9 \left (1+\frac {2}{x^2}\right )^{7/9} x}{10 \sqrt {2+x^2}}\\ \end {align*}

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Mathematica [A]
time = 6.55, size = 25, normalized size = 1.00 \begin {gather*} -\frac {9 \left (1+\frac {2}{x^2}\right )^{7/9} x}{10 \sqrt {2+x^2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[((2 + x^2)/x^2)^(7/9)/(2 + x^2)^(3/2),x]

[Out]

(-9*(1 + 2/x^2)^(7/9)*x)/(10*Sqrt[2 + x^2])

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Maple [A]
time = 0.11, size = 22, normalized size = 0.88

method	result	size
gosper	\(-\frac {9 x \left (\frac {x^{2}+2}{x^{2}}\right )^{\frac {7}{9}}}{10 \sqrt {x^{2}+2}}\)	\(22\)
risch	\(-\frac {9 x \left (\frac {x^{2}+2}{x^{2}}\right )^{\frac {7}{9}}}{10 \sqrt {x^{2}+2}}\)	\(22\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((x^2+2)/x^2)^(7/9)/(x^2+2)^(3/2),x,method=_RETURNVERBOSE)

[Out]

-9/10*x/(x^2+2)^(1/2)*((x^2+2)/x^2)^(7/9)

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((x^2+2)/x^2)^(7/9)/(x^2+2)^(3/2),x, algorithm="maxima")

[Out]

integrate(((x^2 + 2)/x^2)^(7/9)/(x^2 + 2)^(3/2), x)

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Fricas [A]
time = 0.87, size = 21, normalized size = 0.84 \begin {gather*} -\frac {9 \, x \left (\frac {x^{2} + 2}{x^{2}}\right )^{\frac {7}{9}}}{10 \, \sqrt {x^{2} + 2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((x^2+2)/x^2)^(7/9)/(x^2+2)^(3/2),x, algorithm="fricas")

[Out]

-9/10*x*((x^2 + 2)/x^2)^(7/9)/sqrt(x^2 + 2)

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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((x**2+2)/x**2)**(7/9)/(x**2+2)**(3/2),x)

[Out]

Timed out

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((x^2+2)/x^2)^(7/9)/(x^2+2)^(3/2),x, algorithm="giac")

[Out]

integrate(((x^2 + 2)/x^2)^(7/9)/(x^2 + 2)^(3/2), x)

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Mupad [B]
time = 0.45, size = 15, normalized size = 0.60 \begin {gather*} -\frac {9\,x\,{\left (x^2+2\right )}^{5/18}\,{\left (\frac {1}{x^2}\right )}^{7/9}}{10} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((x^2 + 2)/x^2)^(7/9)/(x^2 + 2)^(3/2),x)

[Out]

-(9*x*(x^2 + 2)^(5/18)*(1/x^2)^(7/9))/10

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