Optimal. Leaf size=133 \[ \frac {\sqrt {3} \tan ^{-1}\left (\frac {1+\frac {2 \sqrt [3]{a^3+b^3 \tan ^2(x)}}{\sqrt [3]{a^3-b^3}}}{\sqrt {3}}\right )}{2 \sqrt [3]{a^3-b^3}}+\frac {\log (\cos (x))}{2 \sqrt [3]{a^3-b^3}}+\frac {3 \log \left (\sqrt [3]{a^3-b^3}-\sqrt [3]{a^3+b^3 \tan ^2(x)}\right )}{4 \sqrt [3]{a^3-b^3}} \]
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Rubi [A]
time = 0.10, antiderivative size = 133, normalized size of antiderivative = 1.00, number of steps
used = 6, number of rules used = 6, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.316, Rules used = {3751, 455, 57,
631, 210, 31} \begin {gather*} \frac {\sqrt {3} \text {ArcTan}\left (\frac {\frac {2 \sqrt [3]{a^3+b^3 \tan ^2(x)}}{\sqrt [3]{a^3-b^3}}+1}{\sqrt {3}}\right )}{2 \sqrt [3]{a^3-b^3}}+\frac {3 \log \left (\sqrt [3]{a^3-b^3}-\sqrt [3]{a^3+b^3 \tan ^2(x)}\right )}{4 \sqrt [3]{a^3-b^3}}+\frac {\log (\cos (x))}{2 \sqrt [3]{a^3-b^3}} \end {gather*}
Antiderivative was successfully verified.
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Rule 31
Rule 57
Rule 210
Rule 455
Rule 631
Rule 3751
Rubi steps
\begin {align*} \int \frac {\tan (x)}{\sqrt [3]{a^3+b^3 \tan ^2(x)}} \, dx &=\text {Subst}\left (\int \frac {x}{\left (1+x^2\right ) \sqrt [3]{a^3+b^3 x^2}} \, dx,x,\tan (x)\right )\\ &=\frac {1}{2} \text {Subst}\left (\int \frac {1}{(1+x) \sqrt [3]{a^3+b^3 x}} \, dx,x,\tan ^2(x)\right )\\ &=\frac {\log (\cos (x))}{2 \sqrt [3]{a^3-b^3}}+\frac {3}{4} \text {Subst}\left (\int \frac {1}{\left (a^3-b^3\right )^{2/3}+\sqrt [3]{a^3-b^3} x+x^2} \, dx,x,\sqrt [3]{a^3+b^3 \tan ^2(x)}\right )-\frac {3 \text {Subst}\left (\int \frac {1}{\sqrt [3]{a^3-b^3}-x} \, dx,x,\sqrt [3]{a^3+b^3 \tan ^2(x)}\right )}{4 \sqrt [3]{a^3-b^3}}\\ &=\frac {\log (\cos (x))}{2 \sqrt [3]{a^3-b^3}}+\frac {3 \log \left (\sqrt [3]{a^3-b^3}-\sqrt [3]{a^3+b^3 \tan ^2(x)}\right )}{4 \sqrt [3]{a^3-b^3}}-\frac {3 \text {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,1+\frac {2 \sqrt [3]{a^3+b^3 \tan ^2(x)}}{\sqrt [3]{a^3-b^3}}\right )}{2 \sqrt [3]{a^3-b^3}}\\ &=\frac {\sqrt {3} \tan ^{-1}\left (\frac {1+\frac {2 \sqrt [3]{a^3+b^3 \tan ^2(x)}}{\sqrt [3]{a^3-b^3}}}{\sqrt {3}}\right )}{2 \sqrt [3]{a^3-b^3}}+\frac {\log (\cos (x))}{2 \sqrt [3]{a^3-b^3}}+\frac {3 \log \left (\sqrt [3]{a^3-b^3}-\sqrt [3]{a^3+b^3 \tan ^2(x)}\right )}{4 \sqrt [3]{a^3-b^3}}\\ \end {align*}
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Mathematica [A]
time = 0.10, size = 105, normalized size = 0.79 \begin {gather*} \frac {2 \sqrt {3} \tan ^{-1}\left (\frac {1+\frac {2 \sqrt [3]{a^3+b^3 \tan ^2(x)}}{\sqrt [3]{a^3-b^3}}}{\sqrt {3}}\right )+2 \log (\cos (x))+3 \log \left (\sqrt [3]{a^3-b^3}-\sqrt [3]{a^3+b^3 \tan ^2(x)}\right )}{4 \sqrt [3]{a^3-b^3}} \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 0.03, size = 0, normalized size = 0.00 \[\int \frac {\tan \left (x \right )}{\left (a^{3}+b^{3} \left (\tan ^{2}\left (x \right )\right )\right )^{\frac {1}{3}}}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\tan {\left (x \right )}}{\sqrt [3]{a^{3} + b^{3} \tan ^{2}{\left (x \right )}}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.60, size = 186, normalized size = 1.40 \begin {gather*} \frac {3 \, {\left (a^{3} - b^{3}\right )}^{\frac {2}{3}} \arctan \left (\frac {\sqrt {3} {\left (2 \, {\left (b^{3} \tan \left (x\right )^{2} + a^{3}\right )}^{\frac {1}{3}} + {\left (a^{3} - b^{3}\right )}^{\frac {1}{3}}\right )}}{3 \, {\left (a^{3} - b^{3}\right )}^{\frac {1}{3}}}\right )}{2 \, {\left (\sqrt {3} a^{3} - \sqrt {3} b^{3}\right )}} - \frac {\log \left ({\left (b^{3} \tan \left (x\right )^{2} + a^{3}\right )}^{\frac {2}{3}} + {\left (b^{3} \tan \left (x\right )^{2} + a^{3}\right )}^{\frac {1}{3}} {\left (a^{3} - b^{3}\right )}^{\frac {1}{3}} + {\left (a^{3} - b^{3}\right )}^{\frac {2}{3}}\right )}{4 \, {\left (a^{3} - b^{3}\right )}^{\frac {1}{3}}} + \frac {\log \left ({\left | {\left (b^{3} \tan \left (x\right )^{2} + a^{3}\right )}^{\frac {1}{3}} - {\left (a^{3} - b^{3}\right )}^{\frac {1}{3}} \right |}\right )}{2 \, {\left (a^{3} - b^{3}\right )}^{\frac {1}{3}}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 1.45, size = 250, normalized size = 1.88 \begin {gather*} \frac {\ln \left (\frac {9\,{\left (a^3+b^3\,{\mathrm {tan}\left (x\right )}^2\right )}^{1/3}}{4}-\frac {9\,a^3-9\,b^3}{4\,{\left (a-b\right )}^{2/3}\,{\left (a^2+a\,b+b^2\right )}^{2/3}}\right )}{2\,{\left (a-b\right )}^{1/3}\,{\left (a^2+a\,b+b^2\right )}^{1/3}}+\frac {\ln \left (\frac {9\,{\left (a^3+b^3\,{\mathrm {tan}\left (x\right )}^2\right )}^{1/3}}{4}-\frac {{\left (-1+\sqrt {3}\,1{}\mathrm {i}\right )}^2\,\left (9\,a^3-9\,b^3\right )}{16\,{\left (a-b\right )}^{2/3}\,{\left (a^2+a\,b+b^2\right )}^{2/3}}\right )\,\left (-1+\sqrt {3}\,1{}\mathrm {i}\right )}{4\,{\left (a-b\right )}^{1/3}\,{\left (a^2+a\,b+b^2\right )}^{1/3}}-\frac {\ln \left (\frac {9\,{\left (a^3+b^3\,{\mathrm {tan}\left (x\right )}^2\right )}^{1/3}}{4}-\frac {{\left (1+\sqrt {3}\,1{}\mathrm {i}\right )}^2\,\left (9\,a^3-9\,b^3\right )}{16\,{\left (a-b\right )}^{2/3}\,{\left (a^2+a\,b+b^2\right )}^{2/3}}\right )\,\left (1+\sqrt {3}\,1{}\mathrm {i}\right )}{4\,{\left (a-b\right )}^{1/3}\,{\left (a^2+a\,b+b^2\right )}^{1/3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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