Optimal. Leaf size=112 \[ \frac {5 \sin ^{-1}\left (2 \sqrt {\frac {2}{7}} \sin (x)\right )}{4 \sqrt {2}}+\frac {3}{4} \sin ^{-1}\left (\frac {2 \sin (x)}{\sqrt {3}}\right )-\frac {3}{4} \tan ^{-1}\left (\frac {\sin (x)}{\sqrt {-1+4 \cos ^2(x)}}\right )-\frac {3}{4} \tan ^{-1}\left (\frac {\sin (x)}{\sqrt {-1+8 \cos ^2(x)}}\right )-\frac {1}{2} \sqrt {-1+4 \cos ^2(x)} \sin (x)-\frac {1}{2} \sqrt {-1+8 \cos ^2(x)} \sin (x) \]
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Rubi [A]
time = 0.60, antiderivative size = 112, normalized size of antiderivative = 1.00, number of steps
used = 27, number of rules used = 6, integrand size = 39, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {6874, 399,
222, 385, 210, 201} \begin {gather*} \frac {5 \text {ArcSin}\left (2 \sqrt {\frac {2}{7}} \sin (x)\right )}{4 \sqrt {2}}+\frac {3}{4} \text {ArcSin}\left (\frac {2 \sin (x)}{\sqrt {3}}\right )-\frac {3}{4} \text {ArcTan}\left (\frac {\sin (x)}{\sqrt {7-8 \sin ^2(x)}}\right )-\frac {3}{4} \text {ArcTan}\left (\frac {\sin (x)}{\sqrt {3-4 \sin ^2(x)}}\right )-\frac {1}{2} \sin (x) \sqrt {7-8 \sin ^2(x)}-\frac {1}{2} \sin (x) \sqrt {3-4 \sin ^2(x)} \end {gather*}
Antiderivative was successfully verified.
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Rule 201
Rule 210
Rule 222
Rule 385
Rule 399
Rule 6874
Rubi steps
\begin {align*} \int \frac {\cos (3 x)}{-\sqrt {-1+8 \cos ^2(x)}+\sqrt {3 \cos ^2(x)-\sin ^2(x)}} \, dx &=\text {Subst}\left (\int \frac {-1+4 x^2}{\sqrt {7-8 x^2}-\sqrt {3-4 x^2}} \, dx,x,\sin (x)\right )\\ &=\text {Subst}\left (\int \left (-\frac {1}{\sqrt {7-8 x^2}-\sqrt {3-4 x^2}}+\frac {4 x^2}{\sqrt {7-8 x^2}-\sqrt {3-4 x^2}}\right ) \, dx,x,\sin (x)\right )\\ &=4 \text {Subst}\left (\int \frac {x^2}{\sqrt {7-8 x^2}-\sqrt {3-4 x^2}} \, dx,x,\sin (x)\right )-\text {Subst}\left (\int \frac {1}{\sqrt {7-8 x^2}-\sqrt {3-4 x^2}} \, dx,x,\sin (x)\right )\\ &=4 \text {Subst}\left (\int \left (-\frac {1}{4} \sqrt {7-8 x^2}-\frac {1}{4} \sqrt {3-4 x^2}-\frac {\sqrt {7-8 x^2}}{4 \left (-1+x^2\right )}-\frac {\sqrt {3-4 x^2}}{4 \left (-1+x^2\right )}\right ) \, dx,x,\sin (x)\right )-\text {Subst}\left (\int \left (-\frac {\sqrt {7-8 x^2}}{4 \left (-1+x^2\right )}-\frac {\sqrt {3-4 x^2}}{4 \left (-1+x^2\right )}\right ) \, dx,x,\sin (x)\right )\\ &=\frac {1}{4} \text {Subst}\left (\int \frac {\sqrt {7-8 x^2}}{-1+x^2} \, dx,x,\sin (x)\right )+\frac {1}{4} \text {Subst}\left (\int \frac {\sqrt {3-4 x^2}}{-1+x^2} \, dx,x,\sin (x)\right )-\text {Subst}\left (\int \sqrt {7-8 x^2} \, dx,x,\sin (x)\right )-\text {Subst}\left (\int \sqrt {3-4 x^2} \, dx,x,\sin (x)\right )-\text {Subst}\left (\int \frac {\sqrt {7-8 x^2}}{-1+x^2} \, dx,x,\sin (x)\right )-\text {Subst}\left (\int \frac {\sqrt {3-4 x^2}}{-1+x^2} \, dx,x,\sin (x)\right )\\ &=-\frac {1}{2} \sin (x) \sqrt {7-8 \sin ^2(x)}-\frac {1}{2} \sin (x) \sqrt {3-4 \sin ^2(x)}-\frac {1}{4} \text {Subst}\left (\int \frac {1}{\sqrt {7-8 x^2} \left (-1+x^2\right )} \, dx,x,\sin (x)\right )-\frac {1}{4} \text {Subst}\left (\int \frac {1}{\sqrt {3-4 x^2} \left (-1+x^2\right )} \, dx,x,\sin (x)\right )-\frac {3}{2} \text {Subst}\left (\int \frac {1}{\sqrt {3-4 x^2}} \, dx,x,\sin (x)\right )-2 \text {Subst}\left (\int \frac {1}{\sqrt {7-8 x^2}} \, dx,x,\sin (x)\right )-\frac {7}{2} \text {Subst}\left (\int \frac {1}{\sqrt {7-8 x^2}} \, dx,x,\sin (x)\right )+4 \text {Subst}\left (\int \frac {1}{\sqrt {3-4 x^2}} \, dx,x,\sin (x)\right )+8 \text {Subst}\left (\int \frac {1}{\sqrt {7-8 x^2}} \, dx,x,\sin (x)\right )-\text {Subst}\left (\int \frac {1}{\sqrt {3-4 x^2}} \, dx,x,\sin (x)\right )+\text {Subst}\left (\int \frac {1}{\sqrt {7-8 x^2} \left (-1+x^2\right )} \, dx,x,\sin (x)\right )+\text {Subst}\left (\int \frac {1}{\sqrt {3-4 x^2} \left (-1+x^2\right )} \, dx,x,\sin (x)\right )\\ &=-\frac {11 \sin ^{-1}\left (2 \sqrt {\frac {2}{7}} \sin (x)\right )}{4 \sqrt {2}}+2 \sqrt {2} \sin ^{-1}\left (2 \sqrt {\frac {2}{7}} \sin (x)\right )+\frac {3}{4} \sin ^{-1}\left (\frac {2 \sin (x)}{\sqrt {3}}\right )-\frac {1}{2} \sin (x) \sqrt {7-8 \sin ^2(x)}-\frac {1}{2} \sin (x) \sqrt {3-4 \sin ^2(x)}-\frac {1}{4} \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,\frac {\sin (x)}{\sqrt {7-8 \sin ^2(x)}}\right )-\frac {1}{4} \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,\frac {\sin (x)}{\sqrt {3-4 \sin ^2(x)}}\right )+\text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,\frac {\sin (x)}{\sqrt {7-8 \sin ^2(x)}}\right )+\text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,\frac {\sin (x)}{\sqrt {3-4 \sin ^2(x)}}\right )\\ &=-\frac {11 \sin ^{-1}\left (2 \sqrt {\frac {2}{7}} \sin (x)\right )}{4 \sqrt {2}}+2 \sqrt {2} \sin ^{-1}\left (2 \sqrt {\frac {2}{7}} \sin (x)\right )+\frac {3}{4} \sin ^{-1}\left (\frac {2 \sin (x)}{\sqrt {3}}\right )-\frac {3}{4} \tan ^{-1}\left (\frac {\sin (x)}{\sqrt {7-8 \sin ^2(x)}}\right )-\frac {3}{4} \tan ^{-1}\left (\frac {\sin (x)}{\sqrt {3-4 \sin ^2(x)}}\right )-\frac {1}{2} \sin (x) \sqrt {7-8 \sin ^2(x)}-\frac {1}{2} \sin (x) \sqrt {3-4 \sin ^2(x)}\\ \end {align*}
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Mathematica [C] Result contains complex when optimal does not.
time = 0.21, size = 131, normalized size = 1.17 \begin {gather*} \frac {1}{8} \left (-6 \tan ^{-1}\left (\frac {\sin (x)}{\sqrt {1+2 \cos (2 x)}}\right )-6 \tan ^{-1}\left (\frac {\sin (x)}{\sqrt {3+4 \cos (2 x)}}\right )-6 i \log \left (\sqrt {1+2 \cos (2 x)}+2 i \sin (x)\right )-5 i \sqrt {2} \log \left (\sqrt {3+4 \cos (2 x)}+2 i \sqrt {2} \sin (x)\right )-4 \sqrt {1+2 \cos (2 x)} \sin (x)-4 \sqrt {3+4 \cos (2 x)} \sin (x)\right ) \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 180.00, size = 0, normalized size = 0.00 \[\int \frac {\cos \left (3 x \right )}{-\sqrt {-1+8 \left (\cos ^{2}\left (x \right )\right )}+\sqrt {3 \left (\cos ^{2}\left (x \right )\right )-\left (\sin ^{2}\left (x \right )\right )}}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 195 vs.
\(2 (84) = 168\).
time = 1.46, size = 195, normalized size = 1.74 \begin {gather*} -\frac {5}{32} \, \sqrt {2} \arctan \left (\frac {{\left (512 \, \sqrt {2} \cos \left (x\right )^{4} - 576 \, \sqrt {2} \cos \left (x\right )^{2} + 113 \, \sqrt {2}\right )} \sqrt {8 \, \cos \left (x\right )^{2} - 1}}{16 \, {\left (128 \, \cos \left (x\right )^{4} - 88 \, \cos \left (x\right )^{2} + 9\right )} \sin \left (x\right )}\right ) - \frac {1}{2} \, \sqrt {8 \, \cos \left (x\right )^{2} - 1} \sin \left (x\right ) - \frac {1}{2} \, \sqrt {4 \, \cos \left (x\right )^{2} - 1} \sin \left (x\right ) + \frac {3}{8} \, \arctan \left (\frac {4 \, {\left (8 \, \cos \left (x\right )^{2} - 5\right )} \sqrt {4 \, \cos \left (x\right )^{2} - 1} \sin \left (x\right ) - 9 \, \cos \left (x\right ) \sin \left (x\right )}{64 \, \cos \left (x\right )^{4} - 71 \, \cos \left (x\right )^{2} + 16}\right ) + \frac {3}{8} \, \arctan \left (\frac {\sin \left (x\right )}{\cos \left (x\right )}\right ) + \frac {3}{8} \, \arctan \left (\frac {9 \, \cos \left (x\right )^{2} - 2}{2 \, \sqrt {8 \, \cos \left (x\right )^{2} - 1} \sin \left (x\right )}\right ) + \frac {3}{4} \, \arctan \left (\frac {\sqrt {4 \, \cos \left (x\right )^{2} - 1}}{\sin \left (x\right )}\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\cos {\left (3 x \right )}}{\sqrt {- \sin ^{2}{\left (x \right )} + 3 \cos ^{2}{\left (x \right )}} - \sqrt {8 \cos ^{2}{\left (x \right )} - 1}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} -\int -\frac {\cos \left (3\,x\right )}{\sqrt {3\,{\cos \left (x\right )}^2-{\sin \left (x\right )}^2}-\sqrt {8\,{\cos \left (x\right )}^2-1}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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