Optimal. Leaf size=35 \[ \frac {6}{25 (5-6 x)}-\frac {1}{25 x}-\frac {12}{125} \log (5-6 x)+\frac {12 \log (x)}{125} \]
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Rubi [A]
time = 0.01, antiderivative size = 35, normalized size of antiderivative = 1.00, number of steps
used = 2, number of rules used = 1, integrand size = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {46}
\begin {gather*} \frac {6}{25 (5-6 x)}-\frac {1}{25 x}-\frac {12}{125} \log (5-6 x)+\frac {12 \log (x)}{125} \end {gather*}
Antiderivative was successfully verified.
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Rule 46
Rubi steps
\begin {align*} \int \frac {1}{(5-6 x)^2 x^2} \, dx &=\int \left (\frac {1}{25 x^2}+\frac {12}{125 x}+\frac {36}{25 (-5+6 x)^2}-\frac {72}{125 (-5+6 x)}\right ) \, dx\\ &=\frac {6}{25 (5-6 x)}-\frac {1}{25 x}-\frac {12}{125} \log (5-6 x)+\frac {12 \log (x)}{125}\\ \end {align*}
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Mathematica [A]
time = 0.01, size = 31, normalized size = 0.89 \begin {gather*} \frac {1}{125} \left (\frac {30}{5-6 x}-\frac {5}{x}-12 \log (5-6 x)+12 \log (x)\right ) \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.08, size = 28, normalized size = 0.80
method | result | size |
default | \(-\frac {1}{25 x}+\frac {12 \ln \left (x \right )}{125}-\frac {6}{25 \left (-5+6 x \right )}-\frac {12 \ln \left (-5+6 x \right )}{125}\) | \(28\) |
risch | \(\frac {-\frac {12 x}{25}+\frac {1}{5}}{x \left (-5+6 x \right )}+\frac {12 \ln \left (x \right )}{125}-\frac {12 \ln \left (-5+6 x \right )}{125}\) | \(31\) |
norman | \(\frac {\frac {1}{5}-\frac {72 x^{2}}{125}}{x \left (-5+6 x \right )}+\frac {12 \ln \left (x \right )}{125}-\frac {12 \ln \left (-5+6 x \right )}{125}\) | \(32\) |
meijerg | \(-\frac {1}{25 x}+\frac {6}{125}+\frac {12 \ln \left (x \right )}{125}+\frac {12 \ln \left (2\right )}{125}+\frac {12 \ln \left (3\right )}{125}-\frac {12 \ln \left (5\right )}{125}+\frac {12 i \pi }{125}+\frac {108 x}{625 \left (3-\frac {18 x}{5}\right )}-\frac {12 \ln \left (1-\frac {6 x}{5}\right )}{125}\) | \(46\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 1.78, size = 31, normalized size = 0.89 \begin {gather*} -\frac {12 \, x - 5}{25 \, {\left (6 \, x^{2} - 5 \, x\right )}} - \frac {12}{125} \, \log \left (6 \, x - 5\right ) + \frac {12}{125} \, \log \left (x\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.38, size = 48, normalized size = 1.37 \begin {gather*} -\frac {12 \, {\left (6 \, x^{2} - 5 \, x\right )} \log \left (6 \, x - 5\right ) - 12 \, {\left (6 \, x^{2} - 5 \, x\right )} \log \left (x\right ) + 60 \, x - 25}{125 \, {\left (6 \, x^{2} - 5 \, x\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 0.05, size = 29, normalized size = 0.83 \begin {gather*} \frac {5 - 12 x}{150 x^{2} - 125 x} + \frac {12 \log {\left (x \right )}}{125} - \frac {12 \log {\left (x - \frac {5}{6} \right )}}{125} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.52, size = 40, normalized size = 1.14 \begin {gather*} -\frac {6}{25 \, {\left (6 \, x - 5\right )}} + \frac {6}{125 \, {\left (\frac {5}{6 \, x - 5} + 1\right )}} + \frac {12}{125} \, \log \left ({\left | -\frac {5}{6 \, x - 5} - 1 \right |}\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.22, size = 34, normalized size = 0.97 \begin {gather*} \frac {1}{5\,x\,\left (6\,x-5\right )}-\frac {12}{25\,\left (6\,x-5\right )}-\frac {12\,\ln \left (\frac {6\,x-5}{x}\right )}{125} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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