3.9.95 \(\int \frac {1}{(-b+a^3 x^2) \sqrt [3]{-b x^2+a^3 x^3}} \, dx\)

Optimal. Leaf size=68 \[ \frac {\text {RootSum}\left [\text {$\#$1}^6-2 \text {$\#$1}^3 a^3+a^6-a^3 b\& ,\frac {\log \left (\sqrt [3]{a^3 x^3-b x^2}-\text {$\#$1} x\right )-\log (x)}{\text {$\#$1}}\& \right ]}{2 b} \]

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Rubi [B]  time = 0.38, antiderivative size = 618, normalized size of antiderivative = 9.09, number of steps used = 5, number of rules used = 3, integrand size = 32, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.094, Rules used = {2056, 912, 91} \begin {gather*} -\frac {x^{2/3} \sqrt [3]{a^3 x-b} \log \left (\sqrt {b}-a^{3/2} x\right )}{4 \sqrt {a} b \sqrt [3]{a^{3/2}-\sqrt {b}} \sqrt [3]{a^3 x^3-b x^2}}-\frac {x^{2/3} \sqrt [3]{a^3 x-b} \log \left (a^{3/2} x+\sqrt {b}\right )}{4 \sqrt {a} b \sqrt [3]{a^{3/2}+\sqrt {b}} \sqrt [3]{a^3 x^3-b x^2}}+\frac {3 x^{2/3} \sqrt [3]{a^3 x-b} \log \left (\frac {\sqrt [3]{a^3 x-b}}{\sqrt {a} \sqrt [3]{a^{3/2}-\sqrt {b}}}-\sqrt [3]{x}\right )}{4 \sqrt {a} b \sqrt [3]{a^{3/2}-\sqrt {b}} \sqrt [3]{a^3 x^3-b x^2}}+\frac {3 x^{2/3} \sqrt [3]{a^3 x-b} \log \left (\frac {\sqrt [3]{a^3 x-b}}{\sqrt {a} \sqrt [3]{a^{3/2}+\sqrt {b}}}-\sqrt [3]{x}\right )}{4 \sqrt {a} b \sqrt [3]{a^{3/2}+\sqrt {b}} \sqrt [3]{a^3 x^3-b x^2}}+\frac {\sqrt {3} x^{2/3} \sqrt [3]{a^3 x-b} \tan ^{-1}\left (\frac {2 \sqrt [3]{a^3 x-b}}{\sqrt {3} \sqrt {a} \sqrt [3]{x} \sqrt [3]{a^{3/2}-\sqrt {b}}}+\frac {1}{\sqrt {3}}\right )}{2 \sqrt {a} b \sqrt [3]{a^{3/2}-\sqrt {b}} \sqrt [3]{a^3 x^3-b x^2}}+\frac {\sqrt {3} x^{2/3} \sqrt [3]{a^3 x-b} \tan ^{-1}\left (\frac {2 \sqrt [3]{a^3 x-b}}{\sqrt {3} \sqrt {a} \sqrt [3]{x} \sqrt [3]{a^{3/2}+\sqrt {b}}}+\frac {1}{\sqrt {3}}\right )}{2 \sqrt {a} b \sqrt [3]{a^{3/2}+\sqrt {b}} \sqrt [3]{a^3 x^3-b x^2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[1/((-b + a^3*x^2)*(-(b*x^2) + a^3*x^3)^(1/3)),x]

[Out]

(Sqrt[3]*x^(2/3)*(-b + a^3*x)^(1/3)*ArcTan[1/Sqrt[3] + (2*(-b + a^3*x)^(1/3))/(Sqrt[3]*Sqrt[a]*(a^(3/2) - Sqrt
[b])^(1/3)*x^(1/3))])/(2*Sqrt[a]*(a^(3/2) - Sqrt[b])^(1/3)*b*(-(b*x^2) + a^3*x^3)^(1/3)) + (Sqrt[3]*x^(2/3)*(-
b + a^3*x)^(1/3)*ArcTan[1/Sqrt[3] + (2*(-b + a^3*x)^(1/3))/(Sqrt[3]*Sqrt[a]*(a^(3/2) + Sqrt[b])^(1/3)*x^(1/3))
])/(2*Sqrt[a]*(a^(3/2) + Sqrt[b])^(1/3)*b*(-(b*x^2) + a^3*x^3)^(1/3)) - (x^(2/3)*(-b + a^3*x)^(1/3)*Log[Sqrt[b
] - a^(3/2)*x])/(4*Sqrt[a]*(a^(3/2) - Sqrt[b])^(1/3)*b*(-(b*x^2) + a^3*x^3)^(1/3)) - (x^(2/3)*(-b + a^3*x)^(1/
3)*Log[Sqrt[b] + a^(3/2)*x])/(4*Sqrt[a]*(a^(3/2) + Sqrt[b])^(1/3)*b*(-(b*x^2) + a^3*x^3)^(1/3)) + (3*x^(2/3)*(
-b + a^3*x)^(1/3)*Log[-x^(1/3) + (-b + a^3*x)^(1/3)/(Sqrt[a]*(a^(3/2) - Sqrt[b])^(1/3))])/(4*Sqrt[a]*(a^(3/2)
- Sqrt[b])^(1/3)*b*(-(b*x^2) + a^3*x^3)^(1/3)) + (3*x^(2/3)*(-b + a^3*x)^(1/3)*Log[-x^(1/3) + (-b + a^3*x)^(1/
3)/(Sqrt[a]*(a^(3/2) + Sqrt[b])^(1/3))])/(4*Sqrt[a]*(a^(3/2) + Sqrt[b])^(1/3)*b*(-(b*x^2) + a^3*x^3)^(1/3))

Rule 91

Int[1/(((a_.) + (b_.)*(x_))^(1/3)*((c_.) + (d_.)*(x_))^(2/3)*((e_.) + (f_.)*(x_))), x_Symbol] :> With[{q = Rt[
(d*e - c*f)/(b*e - a*f), 3]}, -Simp[(Sqrt[3]*q*ArcTan[1/Sqrt[3] + (2*q*(a + b*x)^(1/3))/(Sqrt[3]*(c + d*x)^(1/
3))])/(d*e - c*f), x] + (Simp[(q*Log[e + f*x])/(2*(d*e - c*f)), x] - Simp[(3*q*Log[q*(a + b*x)^(1/3) - (c + d*
x)^(1/3)])/(2*(d*e - c*f)), x])] /; FreeQ[{a, b, c, d, e, f}, x]

Rule 912

Int[(((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))^(n_))/((a_) + (c_.)*(x_)^2), x_Symbol] :> Int[ExpandIntegr
and[(d + e*x)^m*(f + g*x)^n, 1/(a + c*x^2), x], x] /; FreeQ[{a, c, d, e, f, g, m, n}, x] && NeQ[c*d^2 + a*e^2,
0] &&  !IntegerQ[m] &&  !IntegerQ[n]

Rule 2056

Int[(u_.)*(P_)^(p_.), x_Symbol] :> With[{m = MinimumMonomialExponent[P, x]}, Dist[P^FracPart[p]/(x^(m*FracPart
[p])*Distrib[1/x^m, P]^FracPart[p]), Int[u*x^(m*p)*Distrib[1/x^m, P]^p, x], x]] /; FreeQ[p, x] &&  !IntegerQ[p
] && SumQ[P] && EveryQ[BinomialQ[#1, x] & , P] &&  !PolyQ[P, x, 2]

Rubi steps

\begin {align*} \int \frac {1}{\left (-b+a^3 x^2\right ) \sqrt [3]{-b x^2+a^3 x^3}} \, dx &=\frac {\left (x^{2/3} \sqrt [3]{-b+a^3 x}\right ) \int \frac {1}{x^{2/3} \sqrt [3]{-b+a^3 x} \left (-b+a^3 x^2\right )} \, dx}{\sqrt [3]{-b x^2+a^3 x^3}}\\ &=\frac {\left (x^{2/3} \sqrt [3]{-b+a^3 x}\right ) \int \left (-\frac {1}{2 \sqrt {b} x^{2/3} \left (\sqrt {b}-a^{3/2} x\right ) \sqrt [3]{-b+a^3 x}}-\frac {1}{2 \sqrt {b} x^{2/3} \left (\sqrt {b}+a^{3/2} x\right ) \sqrt [3]{-b+a^3 x}}\right ) \, dx}{\sqrt [3]{-b x^2+a^3 x^3}}\\ &=-\frac {\left (x^{2/3} \sqrt [3]{-b+a^3 x}\right ) \int \frac {1}{x^{2/3} \left (\sqrt {b}-a^{3/2} x\right ) \sqrt [3]{-b+a^3 x}} \, dx}{2 \sqrt {b} \sqrt [3]{-b x^2+a^3 x^3}}-\frac {\left (x^{2/3} \sqrt [3]{-b+a^3 x}\right ) \int \frac {1}{x^{2/3} \left (\sqrt {b}+a^{3/2} x\right ) \sqrt [3]{-b+a^3 x}} \, dx}{2 \sqrt {b} \sqrt [3]{-b x^2+a^3 x^3}}\\ &=\frac {\sqrt {3} x^{2/3} \sqrt [3]{-b+a^3 x} \tan ^{-1}\left (\frac {1}{\sqrt {3}}+\frac {2 \sqrt [3]{-b+a^3 x}}{\sqrt {3} \sqrt {a} \sqrt [3]{a^{3/2}-\sqrt {b}} \sqrt [3]{x}}\right )}{2 \sqrt {a} \sqrt [3]{a^{3/2}-\sqrt {b}} b \sqrt [3]{-b x^2+a^3 x^3}}+\frac {\sqrt {3} x^{2/3} \sqrt [3]{-b+a^3 x} \tan ^{-1}\left (\frac {1}{\sqrt {3}}+\frac {2 \sqrt [3]{-b+a^3 x}}{\sqrt {3} \sqrt {a} \sqrt [3]{a^{3/2}+\sqrt {b}} \sqrt [3]{x}}\right )}{2 \sqrt {a} \sqrt [3]{a^{3/2}+\sqrt {b}} b \sqrt [3]{-b x^2+a^3 x^3}}-\frac {x^{2/3} \sqrt [3]{-b+a^3 x} \log \left (\sqrt {b}-a^{3/2} x\right )}{4 \sqrt {a} \sqrt [3]{a^{3/2}-\sqrt {b}} b \sqrt [3]{-b x^2+a^3 x^3}}-\frac {x^{2/3} \sqrt [3]{-b+a^3 x} \log \left (\sqrt {b}+a^{3/2} x\right )}{4 \sqrt {a} \sqrt [3]{a^{3/2}+\sqrt {b}} b \sqrt [3]{-b x^2+a^3 x^3}}+\frac {3 x^{2/3} \sqrt [3]{-b+a^3 x} \log \left (-\sqrt [3]{x}+\frac {\sqrt [3]{-b+a^3 x}}{\sqrt {a} \sqrt [3]{a^{3/2}-\sqrt {b}}}\right )}{4 \sqrt {a} \sqrt [3]{a^{3/2}-\sqrt {b}} b \sqrt [3]{-b x^2+a^3 x^3}}+\frac {3 x^{2/3} \sqrt [3]{-b+a^3 x} \log \left (-\sqrt [3]{x}+\frac {\sqrt [3]{-b+a^3 x}}{\sqrt {a} \sqrt [3]{a^{3/2}+\sqrt {b}}}\right )}{4 \sqrt {a} \sqrt [3]{a^{3/2}+\sqrt {b}} b \sqrt [3]{-b x^2+a^3 x^3}}\\ \end {align*}

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Mathematica [A]  time = 0.03, size = 102, normalized size = 1.50 \begin {gather*} -\frac {3 x \left (\, _2F_1\left (\frac {1}{3},1;\frac {4}{3};\frac {a^{3/2} \left (a^{3/2}-\sqrt {b}\right ) x}{a^3 x-b}\right )+\, _2F_1\left (\frac {1}{3},1;\frac {4}{3};\frac {a^{3/2} \left (a^{3/2}+\sqrt {b}\right ) x}{a^3 x-b}\right )\right )}{2 b \sqrt [3]{x^2 \left (a^3 x-b\right )}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[1/((-b + a^3*x^2)*(-(b*x^2) + a^3*x^3)^(1/3)),x]

[Out]

(-3*x*(Hypergeometric2F1[1/3, 1, 4/3, (a^(3/2)*(a^(3/2) - Sqrt[b])*x)/(-b + a^3*x)] + Hypergeometric2F1[1/3, 1
, 4/3, (a^(3/2)*(a^(3/2) + Sqrt[b])*x)/(-b + a^3*x)]))/(2*b*(x^2*(-b + a^3*x))^(1/3))

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IntegrateAlgebraic [A]  time = 0.00, size = 68, normalized size = 1.00 \begin {gather*} \frac {\text {RootSum}\left [a^6-a^3 b-2 a^3 \text {$\#$1}^3+\text {$\#$1}^6\&,\frac {-\log (x)+\log \left (\sqrt [3]{-b x^2+a^3 x^3}-x \text {$\#$1}\right )}{\text {$\#$1}}\&\right ]}{2 b} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[1/((-b + a^3*x^2)*(-(b*x^2) + a^3*x^3)^(1/3)),x]

[Out]

RootSum[a^6 - a^3*b - 2*a^3*#1^3 + #1^6 & , (-Log[x] + Log[(-(b*x^2) + a^3*x^3)^(1/3) - x*#1])/#1 & ]/(2*b)

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fricas [B]  time = 0.53, size = 2040, normalized size = 30.00

result too large to display

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a^3*x^2-b)/(a^3*x^3-b*x^2)^(1/3),x, algorithm="fricas")

[Out]

-sqrt(3)*(((a^3*b^3 - b^4)/sqrt(a^9*b^5 - 2*a^6*b^6 + a^3*b^7) + 1)/(a^3*b^3 - b^4))^(1/3)*arctan(1/3*(2*sqrt(
3)*b*x*(((a^3*b^3 - b^4)/sqrt(a^9*b^5 - 2*a^6*b^6 + a^3*b^7) + 1)/(a^3*b^3 - b^4))^(1/3)*sqrt(((a^3*b^2*x - (a
^6*b^5 - a^3*b^6)*x/sqrt(a^9*b^5 - 2*a^6*b^6 + a^3*b^7))*(a^3*x^3 - b*x^2)^(1/3)*(((a^3*b^3 - b^4)/sqrt(a^9*b^
5 - 2*a^6*b^6 + a^3*b^7) + 1)/(a^3*b^3 - b^4))^(2/3) + (a^3*b*x^2 - (a^6*b^4 - a^3*b^5)*x^2/sqrt(a^9*b^5 - 2*a
^6*b^6 + a^3*b^7))*(((a^3*b^3 - b^4)/sqrt(a^9*b^5 - 2*a^6*b^6 + a^3*b^7) + 1)/(a^3*b^3 - b^4))^(1/3) + (a^3*x^
3 - b*x^2)^(2/3))/x^2) - 2*sqrt(3)*(a^3*x^3 - b*x^2)^(1/3)*b*(((a^3*b^3 - b^4)/sqrt(a^9*b^5 - 2*a^6*b^6 + a^3*
b^7) + 1)/(a^3*b^3 - b^4))^(1/3) - sqrt(3)*x)/x) - sqrt(3)*(-((a^3*b^3 - b^4)/sqrt(a^9*b^5 - 2*a^6*b^6 + a^3*b
^7) - 1)/(a^3*b^3 - b^4))^(1/3)*arctan(1/3*(2*sqrt(3)*b*x*(-((a^3*b^3 - b^4)/sqrt(a^9*b^5 - 2*a^6*b^6 + a^3*b^
7) - 1)/(a^3*b^3 - b^4))^(1/3)*sqrt(((a^3*b^2*x + (a^6*b^5 - a^3*b^6)*x/sqrt(a^9*b^5 - 2*a^6*b^6 + a^3*b^7))*(
a^3*x^3 - b*x^2)^(1/3)*(-((a^3*b^3 - b^4)/sqrt(a^9*b^5 - 2*a^6*b^6 + a^3*b^7) - 1)/(a^3*b^3 - b^4))^(2/3) + (a
^3*b*x^2 + (a^6*b^4 - a^3*b^5)*x^2/sqrt(a^9*b^5 - 2*a^6*b^6 + a^3*b^7))*(-((a^3*b^3 - b^4)/sqrt(a^9*b^5 - 2*a^
6*b^6 + a^3*b^7) - 1)/(a^3*b^3 - b^4))^(1/3) + (a^3*x^3 - b*x^2)^(2/3))/x^2) - 2*sqrt(3)*(a^3*x^3 - b*x^2)^(1/
3)*b*(-((a^3*b^3 - b^4)/sqrt(a^9*b^5 - 2*a^6*b^6 + a^3*b^7) - 1)/(a^3*b^3 - b^4))^(1/3) - sqrt(3)*x)/x) + 1/2*
(((a^3*b^3 - b^4)/sqrt(a^9*b^5 - 2*a^6*b^6 + a^3*b^7) + 1)/(a^3*b^3 - b^4))^(1/3)*log(-((a^3*b^2*x - (a^6*b^5
- a^3*b^6)*x/sqrt(a^9*b^5 - 2*a^6*b^6 + a^3*b^7))*(((a^3*b^3 - b^4)/sqrt(a^9*b^5 - 2*a^6*b^6 + a^3*b^7) + 1)/(
a^3*b^3 - b^4))^(2/3) - (a^3*x^3 - b*x^2)^(1/3))/x) + 1/2*(-((a^3*b^3 - b^4)/sqrt(a^9*b^5 - 2*a^6*b^6 + a^3*b^
7) - 1)/(a^3*b^3 - b^4))^(1/3)*log(-((a^3*b^2*x + (a^6*b^5 - a^3*b^6)*x/sqrt(a^9*b^5 - 2*a^6*b^6 + a^3*b^7))*(
-((a^3*b^3 - b^4)/sqrt(a^9*b^5 - 2*a^6*b^6 + a^3*b^7) - 1)/(a^3*b^3 - b^4))^(2/3) - (a^3*x^3 - b*x^2)^(1/3))/x
) - 1/4*(((a^3*b^3 - b^4)/sqrt(a^9*b^5 - 2*a^6*b^6 + a^3*b^7) + 1)/(a^3*b^3 - b^4))^(1/3)*log(((a^3*b^2*x - (a
^6*b^5 - a^3*b^6)*x/sqrt(a^9*b^5 - 2*a^6*b^6 + a^3*b^7))*(a^3*x^3 - b*x^2)^(1/3)*(((a^3*b^3 - b^4)/sqrt(a^9*b^
5 - 2*a^6*b^6 + a^3*b^7) + 1)/(a^3*b^3 - b^4))^(2/3) + (a^3*b*x^2 - (a^6*b^4 - a^3*b^5)*x^2/sqrt(a^9*b^5 - 2*a
^6*b^6 + a^3*b^7))*(((a^3*b^3 - b^4)/sqrt(a^9*b^5 - 2*a^6*b^6 + a^3*b^7) + 1)/(a^3*b^3 - b^4))^(1/3) + (a^3*x^
3 - b*x^2)^(2/3))/x^2) - 1/4*(-((a^3*b^3 - b^4)/sqrt(a^9*b^5 - 2*a^6*b^6 + a^3*b^7) - 1)/(a^3*b^3 - b^4))^(1/3
)*log(((a^3*b^2*x + (a^6*b^5 - a^3*b^6)*x/sqrt(a^9*b^5 - 2*a^6*b^6 + a^3*b^7))*(a^3*x^3 - b*x^2)^(1/3)*(-((a^3
*b^3 - b^4)/sqrt(a^9*b^5 - 2*a^6*b^6 + a^3*b^7) - 1)/(a^3*b^3 - b^4))^(2/3) + (a^3*b*x^2 + (a^6*b^4 - a^3*b^5)
*x^2/sqrt(a^9*b^5 - 2*a^6*b^6 + a^3*b^7))*(-((a^3*b^3 - b^4)/sqrt(a^9*b^5 - 2*a^6*b^6 + a^3*b^7) - 1)/(a^3*b^3
- b^4))^(1/3) + (a^3*x^3 - b*x^2)^(2/3))/x^2)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{{\left (a^{3} x^{3} - b x^{2}\right )}^{\frac {1}{3}} {\left (a^{3} x^{2} - b\right )}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a^3*x^2-b)/(a^3*x^3-b*x^2)^(1/3),x, algorithm="giac")

[Out]

integrate(1/((a^3*x^3 - b*x^2)^(1/3)*(a^3*x^2 - b)), x)

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maple [F]  time = 0.00, size = 0, normalized size = 0.00 \[\int \frac {1}{\left (a^{3} x^{2}-b \right ) \left (a^{3} x^{3}-b \,x^{2}\right )^{\frac {1}{3}}}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(a^3*x^2-b)/(a^3*x^3-b*x^2)^(1/3),x)

[Out]

int(1/(a^3*x^2-b)/(a^3*x^3-b*x^2)^(1/3),x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{{\left (a^{3} x^{3} - b x^{2}\right )}^{\frac {1}{3}} {\left (a^{3} x^{2} - b\right )}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a^3*x^2-b)/(a^3*x^3-b*x^2)^(1/3),x, algorithm="maxima")

[Out]

integrate(1/((a^3*x^3 - b*x^2)^(1/3)*(a^3*x^2 - b)), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} -\int \frac {1}{\left (b-a^3\,x^2\right )\,{\left (a^3\,x^3-b\,x^2\right )}^{1/3}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(-1/((b - a^3*x^2)*(a^3*x^3 - b*x^2)^(1/3)),x)

[Out]

-int(1/((b - a^3*x^2)*(a^3*x^3 - b*x^2)^(1/3)), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{\sqrt [3]{x^{2} \left (a^{3} x - b\right )} \left (a^{3} x^{2} - b\right )}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a**3*x**2-b)/(a**3*x**3-b*x**2)**(1/3),x)

[Out]

Integral(1/((x**2*(a**3*x - b))**(1/3)*(a**3*x**2 - b)), x)

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