3.9.24 \(\int \sqrt {a x+\sqrt {b^2+a^2 x^2}} \, dx\)

Optimal. Leaf size=62 \[ \frac {\left (\sqrt {a^2 x^2+b^2}+a x\right )^{3/2}}{3 a}-\frac {b^2}{a \sqrt {\sqrt {a^2 x^2+b^2}+a x}} \]

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Rubi [A]  time = 0.03, antiderivative size = 62, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.087, Rules used = {2117, 14} \begin {gather*} \frac {\left (\sqrt {a^2 x^2+b^2}+a x\right )^{3/2}}{3 a}-\frac {b^2}{a \sqrt {\sqrt {a^2 x^2+b^2}+a x}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[Sqrt[a*x + Sqrt[b^2 + a^2*x^2]],x]

[Out]

-(b^2/(a*Sqrt[a*x + Sqrt[b^2 + a^2*x^2]])) + (a*x + Sqrt[b^2 + a^2*x^2])^(3/2)/(3*a)

Rule 14

Int[(u_)*((c_.)*(x_))^(m_.), x_Symbol] :> Int[ExpandIntegrand[(c*x)^m*u, x], x] /; FreeQ[{c, m}, x] && SumQ[u]
&&  !LinearQ[u, x] &&  !MatchQ[u, (a_) + (b_.)*(v_) /; FreeQ[{a, b}, x] && InverseFunctionQ[v]]

Rule 2117

Int[((g_.) + (h_.)*((d_.) + (e_.)*(x_) + (f_.)*Sqrt[(a_) + (c_.)*(x_)^2])^(n_))^(p_.), x_Symbol] :> Dist[1/(2*
e), Subst[Int[((g + h*x^n)^p*(d^2 + a*f^2 - 2*d*x + x^2))/(d - x)^2, x], x, d + e*x + f*Sqrt[a + c*x^2]], x] /
; FreeQ[{a, c, d, e, f, g, h, n}, x] && EqQ[e^2 - c*f^2, 0] && IntegerQ[p]

Rubi steps

\begin {align*} \int \sqrt {a x+\sqrt {b^2+a^2 x^2}} \, dx &=\frac {\operatorname {Subst}\left (\int \frac {b^2+x^2}{x^{3/2}} \, dx,x,a x+\sqrt {b^2+a^2 x^2}\right )}{2 a}\\ &=\frac {\operatorname {Subst}\left (\int \left (\frac {b^2}{x^{3/2}}+\sqrt {x}\right ) \, dx,x,a x+\sqrt {b^2+a^2 x^2}\right )}{2 a}\\ &=-\frac {b^2}{a \sqrt {a x+\sqrt {b^2+a^2 x^2}}}+\frac {\left (a x+\sqrt {b^2+a^2 x^2}\right )^{3/2}}{3 a}\\ \end {align*}

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Mathematica [A]  time = 0.03, size = 59, normalized size = 0.95 \begin {gather*} \frac {2 a x \left (\sqrt {a^2 x^2+b^2}+a x\right )-2 b^2}{3 a \sqrt {\sqrt {a^2 x^2+b^2}+a x}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[Sqrt[a*x + Sqrt[b^2 + a^2*x^2]],x]

[Out]

(-2*b^2 + 2*a*x*(a*x + Sqrt[b^2 + a^2*x^2]))/(3*a*Sqrt[a*x + Sqrt[b^2 + a^2*x^2]])

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IntegrateAlgebraic [A]  time = 0.08, size = 62, normalized size = 1.00 \begin {gather*} -\frac {b^2}{a \sqrt {a x+\sqrt {b^2+a^2 x^2}}}+\frac {\left (a x+\sqrt {b^2+a^2 x^2}\right )^{3/2}}{3 a} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[Sqrt[a*x + Sqrt[b^2 + a^2*x^2]],x]

[Out]

-(b^2/(a*Sqrt[a*x + Sqrt[b^2 + a^2*x^2]])) + (a*x + Sqrt[b^2 + a^2*x^2])^(3/2)/(3*a)

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fricas [A]  time = 0.45, size = 44, normalized size = 0.71 \begin {gather*} \frac {2 \, {\left (2 \, a x - \sqrt {a^{2} x^{2} + b^{2}}\right )} \sqrt {a x + \sqrt {a^{2} x^{2} + b^{2}}}}{3 \, a} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+(a^2*x^2+b^2)^(1/2))^(1/2),x, algorithm="fricas")

[Out]

2/3*(2*a*x - sqrt(a^2*x^2 + b^2))*sqrt(a*x + sqrt(a^2*x^2 + b^2))/a

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \sqrt {a x + \sqrt {a^{2} x^{2} + b^{2}}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+(a^2*x^2+b^2)^(1/2))^(1/2),x, algorithm="giac")

[Out]

integrate(sqrt(a*x + sqrt(a^2*x^2 + b^2)), x)

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maple [F]  time = 180.00, size = 0, normalized size = 0.00 \[\int \sqrt {a x +\sqrt {a^{2} x^{2}+b^{2}}}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a*x+(a^2*x^2+b^2)^(1/2))^(1/2),x)

[Out]

int((a*x+(a^2*x^2+b^2)^(1/2))^(1/2),x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \sqrt {a x + \sqrt {a^{2} x^{2} + b^{2}}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+(a^2*x^2+b^2)^(1/2))^(1/2),x, algorithm="maxima")

[Out]

integrate(sqrt(a*x + sqrt(a^2*x^2 + b^2)), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.02 \begin {gather*} \int \sqrt {a\,x+\sqrt {a^2\,x^2+b^2}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a*x + (b^2 + a^2*x^2)^(1/2))^(1/2),x)

[Out]

int((a*x + (b^2 + a^2*x^2)^(1/2))^(1/2), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \sqrt {a x + \sqrt {a^{2} x^{2} + b^{2}}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+(a**2*x**2+b**2)**(1/2))**(1/2),x)

[Out]

Integral(sqrt(a*x + sqrt(a**2*x**2 + b**2)), x)

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