∫ (1+x3)√ ____ −1+x6 ________________________

Optimal. Leaf size=50 \[ \frac {\sqrt {x^6-1}}{3}+\frac {2}{3} \log \left (\sqrt {x^6-1}+x^3\right )+\frac {2}{3} \tan ^{-1}\left (\sqrt {x^6-1}+x^3\right ) \]

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Rubi [F] time = 0.53, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {\left (1+x^3\right ) \sqrt {-1+x^6}}{x \left (-1+x^3\right )} \, dx \end {gather*}

-1/3*Sqrt[-1 + x^6] + ArcTan[Sqrt[-1 + x^6]]/3 + (2*Defer[Int][Sqrt[-1 + x^6]/(-1 + x), x])/3 + (4*Defer[Int][

Sqrt[-1 + x^6]/(1 - I*Sqrt[3] + 2*x), x])/3 + (4*Defer[Int][Sqrt[-1 + x^6]/(1 + I*Sqrt[3] + 2*x), x])/3

\begin {align*} \int \frac {\left (1+x^3\right ) \sqrt {-1+x^6}}{x \left (-1+x^3\right )} \, dx &=\int \left (\frac {2 \sqrt {-1+x^6}}{3 (-1+x)}-\frac {\sqrt {-1+x^6}}{x}+\frac {2 (1+2 x) \sqrt {-1+x^6}}{3 \left (1+x+x^2\right )}\right ) \, dx\\ &=\frac {2}{3} \int \frac {\sqrt {-1+x^6}}{-1+x} \, dx+\frac {2}{3} \int \frac {(1+2 x) \sqrt {-1+x^6}}{1+x+x^2} \, dx-\int \frac {\sqrt {-1+x^6}}{x} \, dx\\ &=-\left (\frac {1}{6} \operatorname {Subst}\left (\int \frac {\sqrt {-1+x}}{x} \, dx,x,x^6\right )\right )+\frac {2}{3} \int \frac {\sqrt {-1+x^6}}{-1+x} \, dx+\frac {2}{3} \int \left (\frac {2 \sqrt {-1+x^6}}{1-i \sqrt {3}+2 x}+\frac {2 \sqrt {-1+x^6}}{1+i \sqrt {3}+2 x}\right ) \, dx\\ &=-\frac {1}{3} \sqrt {-1+x^6}+\frac {1}{6} \operatorname {Subst}\left (\int \frac {1}{\sqrt {-1+x} x} \, dx,x,x^6\right )+\frac {2}{3} \int \frac {\sqrt {-1+x^6}}{-1+x} \, dx+\frac {4}{3} \int \frac {\sqrt {-1+x^6}}{1-i \sqrt {3}+2 x} \, dx+\frac {4}{3} \int \frac {\sqrt {-1+x^6}}{1+i \sqrt {3}+2 x} \, dx\\ &=-\frac {1}{3} \sqrt {-1+x^6}+\frac {1}{3} \operatorname {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\sqrt {-1+x^6}\right )+\frac {2}{3} \int \frac {\sqrt {-1+x^6}}{-1+x} \, dx+\frac {4}{3} \int \frac {\sqrt {-1+x^6}}{1-i \sqrt {3}+2 x} \, dx+\frac {4}{3} \int \frac {\sqrt {-1+x^6}}{1+i \sqrt {3}+2 x} \, dx\\ &=-\frac {1}{3} \sqrt {-1+x^6}+\frac {1}{3} \tan ^{-1}\left (\sqrt {-1+x^6}\right )+\frac {2}{3} \int \frac {\sqrt {-1+x^6}}{-1+x} \, dx+\frac {4}{3} \int \frac {\sqrt {-1+x^6}}{1-i \sqrt {3}+2 x} \, dx+\frac {4}{3} \int \frac {\sqrt {-1+x^6}}{1+i \sqrt {3}+2 x} \, dx\\ \end {align*}

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Mathematica [A] time = 0.13, size = 55, normalized size = 1.10 \begin {gather*} \frac {1}{3} \left (\tan ^{-1}\left (\sqrt {x^6-1}\right )+\frac {x^6+2 \sqrt {x^6-1} \log \left (\sqrt {x^6-1}+x^3\right )-1}{\sqrt {x^6-1}}\right ) \end {gather*}

Integrate[((1 + x^3)*Sqrt[-1 + x^6])/(x*(-1 + x^3)),x]

(ArcTan[Sqrt[-1 + x^6]] + (-1 + x^6 + 2*Sqrt[-1 + x^6]*Log[x^3 + Sqrt[-1 + x^6]])/Sqrt[-1 + x^6])/3

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IntegrateAlgebraic [A] time = 0.15, size = 54, normalized size = 1.08 \begin {gather*} \frac {1}{3} \sqrt {-1+x^6}-\frac {2}{3} \tan ^{-1}\left (x^3-\sqrt {-1+x^6}\right )-\frac {2}{3} \log \left (-x^3+\sqrt {-1+x^6}\right ) \end {gather*}

IntegrateAlgebraic[((1 + x^3)*Sqrt[-1 + x^6])/(x*(-1 + x^3)),x]

Sqrt[-1 + x^6]/3 - (2*ArcTan[x^3 - Sqrt[-1 + x^6]])/3 - (2*Log[-x^3 + Sqrt[-1 + x^6]])/3

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fricas [A] time = 0.67, size = 42, normalized size = 0.84 \begin {gather*} \frac {1}{3} \, \sqrt {x^{6} - 1} + \frac {2}{3} \, \arctan \left (-x^{3} + \sqrt {x^{6} - 1}\right ) - \frac {2}{3} \, \log \left (-x^{3} + \sqrt {x^{6} - 1}\right ) \end {gather*}

integrate((x^3+1)*(x^6-1)^(1/2)/x/(x^3-1),x, algorithm="fricas")

1/3*sqrt(x^6 - 1) + 2/3*arctan(-x^3 + sqrt(x^6 - 1)) - 2/3*log(-x^3 + sqrt(x^6 - 1))

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giac [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\sqrt {x^{6} - 1} {\left (x^{3} + 1\right )}}{{\left (x^{3} - 1\right )} x}\,{d x} \end {gather*}

integrate((x^3+1)*(x^6-1)^(1/2)/x/(x^3-1),x, algorithm="giac")

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method	result	size

trager	\(\frac {\sqrt {x^{6}-1}}{3}+\frac {2 \ln \left (x^{3}+\sqrt {x^{6}-1}\right )}{3}+\frac {\RootOf \left (\textit {\_Z}^{2}+1\right ) \ln \left (\frac {\RootOf \left (\textit {\_Z}^{2}+1\right )+\sqrt {x^{6}-1}}{x^{3}}\right )}{3}\)	\(52\)

int((x^3+1)*(x^6-1)^(1/2)/x/(x^3-1),x,method=_RETURNVERBOSE)

1/3*(x^6-1)^(1/2)+2/3*ln(x^3+(x^6-1)^(1/2))+1/3*RootOf(_Z^2+1)*ln((RootOf(_Z^2+1)+(x^6-1)^(1/2))/x^3)

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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\sqrt {x^{6} - 1} {\left (x^{3} + 1\right )}}{{\left (x^{3} - 1\right )} x}\,{d x} \end {gather*}

integrate((x^3+1)*(x^6-1)^(1/2)/x/(x^3-1),x, algorithm="maxima")

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mupad [F] time = 0.00, size = -1, normalized size = -0.02 \begin {gather*} \int \frac {\left (x^3+1\right )\,\sqrt {x^6-1}}{x\,\left (x^3-1\right )} \,d x \end {gather*}

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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\sqrt {\left (x - 1\right ) \left (x + 1\right ) \left (x^{2} - x + 1\right ) \left (x^{2} + x + 1\right )} \left (x + 1\right ) \left (x^{2} - x + 1\right )}{x \left (x - 1\right ) \left (x^{2} + x + 1\right )}\, dx \end {gather*}

Integral(sqrt((x - 1)*(x + 1)*(x**2 - x + 1)*(x**2 + x + 1))*(x + 1)*(x**2 - x + 1)/(x*(x - 1)*(x**2 + x + 1))

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3.7.38 \(\int \frac {(1+x^3) \sqrt {-1+x^6}}{x (-1+x^3)} \, dx\)