3.7.14 \(\int x^{14} \sqrt {-1+x^6} \, dx\)

Optimal. Leaf size=48 \[ \frac {1}{144} \sqrt {x^6-1} \left (8 x^{15}-2 x^9-3 x^3\right )-\frac {1}{48} \log \left (\sqrt {x^6-1}+x^3\right ) \]

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Rubi [A]  time = 0.03, antiderivative size = 67, normalized size of antiderivative = 1.40, number of steps used = 6, number of rules used = 5, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.385, Rules used = {275, 279, 321, 217, 206} \begin {gather*} \frac {1}{18} \sqrt {x^6-1} x^{15}-\frac {1}{72} \sqrt {x^6-1} x^9-\frac {1}{48} \sqrt {x^6-1} x^3-\frac {1}{48} \tanh ^{-1}\left (\frac {x^3}{\sqrt {x^6-1}}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^14*Sqrt[-1 + x^6],x]

[Out]

-1/48*(x^3*Sqrt[-1 + x^6]) - (x^9*Sqrt[-1 + x^6])/72 + (x^15*Sqrt[-1 + x^6])/18 - ArcTanh[x^3/Sqrt[-1 + x^6]]/
48

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 217

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Subst[Int[1/(1 - b*x^2), x], x, x/Sqrt[a + b*x^2]] /; FreeQ[{a,
b}, x] &&  !GtQ[a, 0]

Rule 275

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = GCD[m + 1, n]}, Dist[1/k, Subst[Int[x^((m
+ 1)/k - 1)*(a + b*x^(n/k))^p, x], x, x^k], x] /; k != 1] /; FreeQ[{a, b, p}, x] && IGtQ[n, 0] && IntegerQ[m]

Rule 279

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[((c*x)^(m + 1)*(a + b*x^n)^p)/(c*(m +
n*p + 1)), x] + Dist[(a*n*p)/(m + n*p + 1), Int[(c*x)^m*(a + b*x^n)^(p - 1), x], x] /; FreeQ[{a, b, c, m}, x]
&& IGtQ[n, 0] && GtQ[p, 0] && NeQ[m + n*p + 1, 0] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 321

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(c^(n - 1)*(c*x)^(m - n + 1)*(a + b*x^n
)^(p + 1))/(b*(m + n*p + 1)), x] - Dist[(a*c^n*(m - n + 1))/(b*(m + n*p + 1)), Int[(c*x)^(m - n)*(a + b*x^n)^p
, x], x] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0] && GtQ[m, n - 1] && NeQ[m + n*p + 1, 0] && IntBinomialQ[a, b,
c, n, m, p, x]

Rubi steps

\begin {align*} \int x^{14} \sqrt {-1+x^6} \, dx &=\frac {1}{3} \operatorname {Subst}\left (\int x^4 \sqrt {-1+x^2} \, dx,x,x^3\right )\\ &=\frac {1}{18} x^{15} \sqrt {-1+x^6}-\frac {1}{18} \operatorname {Subst}\left (\int \frac {x^4}{\sqrt {-1+x^2}} \, dx,x,x^3\right )\\ &=-\frac {1}{72} x^9 \sqrt {-1+x^6}+\frac {1}{18} x^{15} \sqrt {-1+x^6}-\frac {1}{24} \operatorname {Subst}\left (\int \frac {x^2}{\sqrt {-1+x^2}} \, dx,x,x^3\right )\\ &=-\frac {1}{48} x^3 \sqrt {-1+x^6}-\frac {1}{72} x^9 \sqrt {-1+x^6}+\frac {1}{18} x^{15} \sqrt {-1+x^6}-\frac {1}{48} \operatorname {Subst}\left (\int \frac {1}{\sqrt {-1+x^2}} \, dx,x,x^3\right )\\ &=-\frac {1}{48} x^3 \sqrt {-1+x^6}-\frac {1}{72} x^9 \sqrt {-1+x^6}+\frac {1}{18} x^{15} \sqrt {-1+x^6}-\frac {1}{48} \operatorname {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\frac {x^3}{\sqrt {-1+x^6}}\right )\\ &=-\frac {1}{48} x^3 \sqrt {-1+x^6}-\frac {1}{72} x^9 \sqrt {-1+x^6}+\frac {1}{18} x^{15} \sqrt {-1+x^6}-\frac {1}{48} \tanh ^{-1}\left (\frac {x^3}{\sqrt {-1+x^6}}\right )\\ \end {align*}

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Mathematica [A]  time = 0.03, size = 56, normalized size = 1.17 \begin {gather*} \frac {\left (x^6-1\right ) \left (3 \sin ^{-1}\left (x^3\right )+\sqrt {1-x^6} \left (8 x^{12}-2 x^6-3\right ) x^3\right )}{144 \sqrt {-\left (x^6-1\right )^2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^14*Sqrt[-1 + x^6],x]

[Out]

((-1 + x^6)*(x^3*Sqrt[1 - x^6]*(-3 - 2*x^6 + 8*x^12) + 3*ArcSin[x^3]))/(144*Sqrt[-(-1 + x^6)^2])

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IntegrateAlgebraic [A]  time = 0.13, size = 48, normalized size = 1.00 \begin {gather*} \frac {1}{144} \sqrt {-1+x^6} \left (-3 x^3-2 x^9+8 x^{15}\right )-\frac {1}{48} \log \left (x^3+\sqrt {-1+x^6}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[x^14*Sqrt[-1 + x^6],x]

[Out]

(Sqrt[-1 + x^6]*(-3*x^3 - 2*x^9 + 8*x^15))/144 - Log[x^3 + Sqrt[-1 + x^6]]/48

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fricas [A]  time = 0.46, size = 42, normalized size = 0.88 \begin {gather*} \frac {1}{144} \, {\left (8 \, x^{15} - 2 \, x^{9} - 3 \, x^{3}\right )} \sqrt {x^{6} - 1} + \frac {1}{48} \, \log \left (-x^{3} + \sqrt {x^{6} - 1}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^14*(x^6-1)^(1/2),x, algorithm="fricas")

[Out]

1/144*(8*x^15 - 2*x^9 - 3*x^3)*sqrt(x^6 - 1) + 1/48*log(-x^3 + sqrt(x^6 - 1))

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \sqrt {x^{6} - 1} x^{14}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^14*(x^6-1)^(1/2),x, algorithm="giac")

[Out]

integrate(sqrt(x^6 - 1)*x^14, x)

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maple [A]  time = 0.20, size = 40, normalized size = 0.83

method	result	size
trager	\(\frac {x^{3} \left (8 x^{12}-2 x^{6}-3\right ) \sqrt {x^{6}-1}}{144}-\frac {\ln \left (x^{3}+\sqrt {x^{6}-1}\right )}{48}\)	\(40\)
risch	\(\frac {x^{3} \left (8 x^{12}-2 x^{6}-3\right ) \sqrt {x^{6}-1}}{144}-\frac {\sqrt {-\mathrm {signum}\left (x^{6}-1\right )}\, \arcsin \left (x^{3}\right )}{48 \sqrt {\mathrm {signum}\left (x^{6}-1\right )}}\)	\(50\)
meijerg	\(\frac {i \sqrt {\mathrm {signum}\left (x^{6}-1\right )}\, \left (\frac {i \sqrt {\pi }\, x^{3} \left (-40 x^{12}+10 x^{6}+15\right ) \sqrt {-x^{6}+1}}{60}-\frac {i \sqrt {\pi }\, \arcsin \left (x^{3}\right )}{4}\right )}{12 \sqrt {-\mathrm {signum}\left (x^{6}-1\right )}\, \sqrt {\pi }}\)	\(66\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^14*(x^6-1)^(1/2),x,method=_RETURNVERBOSE)

[Out]

1/144*x^3*(8*x^12-2*x^6-3)*(x^6-1)^(1/2)-1/48*ln(x^3+(x^6-1)^(1/2))

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maxima [B]  time = 0.32, size = 109, normalized size = 2.27 \begin {gather*} -\frac {\frac {3 \, \sqrt {x^{6} - 1}}{x^{3}} + \frac {8 \, {\left (x^{6} - 1\right )}^{\frac {3}{2}}}{x^{9}} - \frac {3 \, {\left (x^{6} - 1\right )}^{\frac {5}{2}}}{x^{15}}}{144 \, {\left (\frac {3 \, {\left (x^{6} - 1\right )}}{x^{6}} - \frac {3 \, {\left (x^{6} - 1\right )}^{2}}{x^{12}} + \frac {{\left (x^{6} - 1\right )}^{3}}{x^{18}} - 1\right )}} - \frac {1}{96} \, \log \left (\frac {\sqrt {x^{6} - 1}}{x^{3}} + 1\right ) + \frac {1}{96} \, \log \left (\frac {\sqrt {x^{6} - 1}}{x^{3}} - 1\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^14*(x^6-1)^(1/2),x, algorithm="maxima")

[Out]

-1/144*(3*sqrt(x^6 - 1)/x^3 + 8*(x^6 - 1)^(3/2)/x^9 - 3*(x^6 - 1)^(5/2)/x^15)/(3*(x^6 - 1)/x^6 - 3*(x^6 - 1)^2
/x^12 + (x^6 - 1)^3/x^18 - 1) - 1/96*log(sqrt(x^6 - 1)/x^3 + 1) + 1/96*log(sqrt(x^6 - 1)/x^3 - 1)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.02 \begin {gather*} \int x^{14}\,\sqrt {x^6-1} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^14*(x^6 - 1)^(1/2),x)

[Out]

int(x^14*(x^6 - 1)^(1/2), x)

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sympy [A]  time = 3.84, size = 136, normalized size = 2.83 \begin {gather*} \begin {cases} \frac {x^{21}}{18 \sqrt {x^{6} - 1}} - \frac {5 x^{15}}{72 \sqrt {x^{6} - 1}} - \frac {x^{9}}{144 \sqrt {x^{6} - 1}} + \frac {x^{3}}{48 \sqrt {x^{6} - 1}} - \frac {\operatorname {acosh}{\left (x^{3} \right )}}{48} & \text {for}\: \left |{x^{6}}\right | > 1 \\- \frac {i x^{21}}{18 \sqrt {1 - x^{6}}} + \frac {5 i x^{15}}{72 \sqrt {1 - x^{6}}} + \frac {i x^{9}}{144 \sqrt {1 - x^{6}}} - \frac {i x^{3}}{48 \sqrt {1 - x^{6}}} + \frac {i \operatorname {asin}{\left (x^{3} \right )}}{48} & \text {otherwise} \end {cases} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**14*(x**6-1)**(1/2),x)

[Out]

Piecewise((x**21/(18*sqrt(x**6 - 1)) - 5*x**15/(72*sqrt(x**6 - 1)) - x**9/(144*sqrt(x**6 - 1)) + x**3/(48*sqrt
(x**6 - 1)) - acosh(x**3)/48, Abs(x**6) > 1), (-I*x**21/(18*sqrt(1 - x**6)) + 5*I*x**15/(72*sqrt(1 - x**6)) +
I*x**9/(144*sqrt(1 - x**6)) - I*x**3/(48*sqrt(1 - x**6)) + I*asin(x**3)/48, True))

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