3.4.11 \(\int \frac {1}{x^6 \sqrt [3]{x+x^3}} \, dx\)

Optimal. Leaf size=28 \[ -\frac {3 \left (x^3+x\right )^{2/3} \left (9 x^4-6 x^2+5\right )}{80 x^6} \]

________________________________________________________________________________________

Rubi [A]  time = 0.06, antiderivative size = 49, normalized size of antiderivative = 1.75, number of steps used = 3, number of rules used = 2, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {2016, 2014} \begin {gather*} -\frac {3 \left (x^3+x\right )^{2/3}}{16 x^6}+\frac {9 \left (x^3+x\right )^{2/3}}{40 x^4}-\frac {27 \left (x^3+x\right )^{2/3}}{80 x^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[1/(x^6*(x + x^3)^(1/3)),x]

[Out]

(-3*(x + x^3)^(2/3))/(16*x^6) + (9*(x + x^3)^(2/3))/(40*x^4) - (27*(x + x^3)^(2/3))/(80*x^2)

Rule 2014

Int[((c_.)*(x_))^(m_.)*((a_.)*(x_)^(j_.) + (b_.)*(x_)^(n_.))^(p_), x_Symbol] :> -Simp[(c^(j - 1)*(c*x)^(m - j
+ 1)*(a*x^j + b*x^n)^(p + 1))/(a*(n - j)*(p + 1)), x] /; FreeQ[{a, b, c, j, m, n, p}, x] &&  !IntegerQ[p] && N
eQ[n, j] && EqQ[m + n*p + n - j + 1, 0] && (IntegerQ[j] || GtQ[c, 0])

Rule 2016

Int[((c_.)*(x_))^(m_.)*((a_.)*(x_)^(j_.) + (b_.)*(x_)^(n_.))^(p_), x_Symbol] :> Simp[(c^(j - 1)*(c*x)^(m - j +
 1)*(a*x^j + b*x^n)^(p + 1))/(a*(m + j*p + 1)), x] - Dist[(b*(m + n*p + n - j + 1))/(a*c^(n - j)*(m + j*p + 1)
), Int[(c*x)^(m + n - j)*(a*x^j + b*x^n)^p, x], x] /; FreeQ[{a, b, c, j, m, n, p}, x] &&  !IntegerQ[p] && NeQ[
n, j] && ILtQ[Simplify[(m + n*p + n - j + 1)/(n - j)], 0] && NeQ[m + j*p + 1, 0] && (IntegersQ[j, n] || GtQ[c,
 0])

Rubi steps

\begin {align*} \int \frac {1}{x^6 \sqrt [3]{x+x^3}} \, dx &=-\frac {3 \left (x+x^3\right )^{2/3}}{16 x^6}-\frac {3}{4} \int \frac {1}{x^4 \sqrt [3]{x+x^3}} \, dx\\ &=-\frac {3 \left (x+x^3\right )^{2/3}}{16 x^6}+\frac {9 \left (x+x^3\right )^{2/3}}{40 x^4}+\frac {9}{20} \int \frac {1}{x^2 \sqrt [3]{x+x^3}} \, dx\\ &=-\frac {3 \left (x+x^3\right )^{2/3}}{16 x^6}+\frac {9 \left (x+x^3\right )^{2/3}}{40 x^4}-\frac {27 \left (x+x^3\right )^{2/3}}{80 x^2}\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]  time = 0.02, size = 28, normalized size = 1.00 \begin {gather*} -\frac {3 \left (x^3+x\right )^{2/3} \left (9 x^4-6 x^2+5\right )}{80 x^6} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[1/(x^6*(x + x^3)^(1/3)),x]

[Out]

(-3*(x + x^3)^(2/3)*(5 - 6*x^2 + 9*x^4))/(80*x^6)

________________________________________________________________________________________

IntegrateAlgebraic [A]  time = 0.21, size = 28, normalized size = 1.00 \begin {gather*} -\frac {3 \left (x+x^3\right )^{2/3} \left (5-6 x^2+9 x^4\right )}{80 x^6} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[1/(x^6*(x + x^3)^(1/3)),x]

[Out]

(-3*(x + x^3)^(2/3)*(5 - 6*x^2 + 9*x^4))/(80*x^6)

________________________________________________________________________________________

fricas [A]  time = 0.44, size = 24, normalized size = 0.86 \begin {gather*} -\frac {3 \, {\left (9 \, x^{4} - 6 \, x^{2} + 5\right )} {\left (x^{3} + x\right )}^{\frac {2}{3}}}{80 \, x^{6}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^6/(x^3+x)^(1/3),x, algorithm="fricas")

[Out]

-3/80*(9*x^4 - 6*x^2 + 5)*(x^3 + x)^(2/3)/x^6

________________________________________________________________________________________

giac [A]  time = 0.37, size = 28, normalized size = 1.00 \begin {gather*} -\frac {3}{16} \, {\left (\frac {1}{x^{2}} + 1\right )}^{\frac {8}{3}} + \frac {3}{5} \, {\left (\frac {1}{x^{2}} + 1\right )}^{\frac {5}{3}} - \frac {3}{4} \, {\left (\frac {1}{x^{2}} + 1\right )}^{\frac {2}{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^6/(x^3+x)^(1/3),x, algorithm="giac")

[Out]

-3/16*(1/x^2 + 1)^(8/3) + 3/5*(1/x^2 + 1)^(5/3) - 3/4*(1/x^2 + 1)^(2/3)

________________________________________________________________________________________

maple [A]  time = 0.06, size = 25, normalized size = 0.89

method result size
trager \(-\frac {3 \left (x^{3}+x \right )^{\frac {2}{3}} \left (9 x^{4}-6 x^{2}+5\right )}{80 x^{6}}\) \(25\)
meijerg \(-\frac {3 \left (\frac {9}{5} x^{4}-\frac {6}{5} x^{2}+1\right ) \left (x^{2}+1\right )^{\frac {2}{3}}}{16 x^{\frac {16}{3}}}\) \(25\)
gosper \(-\frac {3 \left (x^{2}+1\right ) \left (9 x^{4}-6 x^{2}+5\right )}{80 x^{5} \left (x^{3}+x \right )^{\frac {1}{3}}}\) \(30\)
risch \(-\frac {3 \left (9 x^{6}+3 x^{4}-x^{2}+5\right )}{80 x^{5} \left (\left (x^{2}+1\right ) x \right )^{\frac {1}{3}}}\) \(32\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/x^6/(x^3+x)^(1/3),x,method=_RETURNVERBOSE)

[Out]

-3/80*(x^3+x)^(2/3)*(9*x^4-6*x^2+5)/x^6

________________________________________________________________________________________

maxima [A]  time = 0.71, size = 31, normalized size = 1.11 \begin {gather*} -\frac {3 \, {\left (9 \, x^{7} + 3 \, x^{5} - x^{3} + 5 \, x\right )}}{80 \, {\left (x^{2} + 1\right )}^{\frac {1}{3}} x^{\frac {19}{3}}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^6/(x^3+x)^(1/3),x, algorithm="maxima")

[Out]

-3/80*(9*x^7 + 3*x^5 - x^3 + 5*x)/((x^2 + 1)^(1/3)*x^(19/3))

________________________________________________________________________________________

mupad [B]  time = 0.21, size = 24, normalized size = 0.86 \begin {gather*} -\frac {3\,{\left (x^3+x\right )}^{2/3}\,\left (9\,x^4-6\,x^2+5\right )}{80\,x^6} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x^6*(x + x^3)^(1/3)),x)

[Out]

-(3*(x + x^3)^(2/3)*(9*x^4 - 6*x^2 + 5))/(80*x^6)

________________________________________________________________________________________

sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{x^{6} \sqrt [3]{x \left (x^{2} + 1\right )}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x**6/(x**3+x)**(1/3),x)

[Out]

Integral(1/(x**6*(x*(x**2 + 1))**(1/3)), x)

________________________________________________________________________________________