3.4.9 \(\int \frac {(-1+x^3)^{2/3} (2+x^3)}{x^9} \, dx\)

Optimal. Leaf size=28 \[ \frac {\left (x^3-1\right )^{2/3} \left (7 x^6-2 x^3-5\right )}{20 x^8} \]

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Rubi [A]  time = 0.01, antiderivative size = 33, normalized size of antiderivative = 1.18, number of steps used = 2, number of rules used = 2, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {453, 264} \begin {gather*} \frac {\left (x^3-1\right )^{5/3}}{4 x^8}+\frac {7 \left (x^3-1\right )^{5/3}}{20 x^5} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[((-1 + x^3)^(2/3)*(2 + x^3))/x^9,x]

[Out]

(-1 + x^3)^(5/3)/(4*x^8) + (7*(-1 + x^3)^(5/3))/(20*x^5)

Rule 264

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[((c*x)^(m + 1)*(a + b*x^n)^(p + 1))/(a
*c*(m + 1)), x] /; FreeQ[{a, b, c, m, n, p}, x] && EqQ[(m + 1)/n + p + 1, 0] && NeQ[m, -1]

Rule 453

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_)), x_Symbol] :> Simp[(c*(e*x)^(m
+ 1)*(a + b*x^n)^(p + 1))/(a*e*(m + 1)), x] + Dist[(a*d*(m + 1) - b*c*(m + n*(p + 1) + 1))/(a*e^n*(m + 1)), In
t[(e*x)^(m + n)*(a + b*x^n)^p, x], x] /; FreeQ[{a, b, c, d, e, p}, x] && NeQ[b*c - a*d, 0] && (IntegerQ[n] ||
GtQ[e, 0]) && ((GtQ[n, 0] && LtQ[m, -1]) || (LtQ[n, 0] && GtQ[m + n, -1])) &&  !ILtQ[p, -1]

Rubi steps

\begin {align*} \int \frac {\left (-1+x^3\right )^{2/3} \left (2+x^3\right )}{x^9} \, dx &=\frac {\left (-1+x^3\right )^{5/3}}{4 x^8}+\frac {7}{4} \int \frac {\left (-1+x^3\right )^{2/3}}{x^6} \, dx\\ &=\frac {\left (-1+x^3\right )^{5/3}}{4 x^8}+\frac {7 \left (-1+x^3\right )^{5/3}}{20 x^5}\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 23, normalized size = 0.82 \begin {gather*} \frac {\left (x^3-1\right )^{5/3} \left (7 x^3+5\right )}{20 x^8} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[((-1 + x^3)^(2/3)*(2 + x^3))/x^9,x]

[Out]

((-1 + x^3)^(5/3)*(5 + 7*x^3))/(20*x^8)

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IntegrateAlgebraic [A]  time = 0.09, size = 28, normalized size = 1.00 \begin {gather*} \frac {\left (-1+x^3\right )^{2/3} \left (-5-2 x^3+7 x^6\right )}{20 x^8} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[((-1 + x^3)^(2/3)*(2 + x^3))/x^9,x]

[Out]

((-1 + x^3)^(2/3)*(-5 - 2*x^3 + 7*x^6))/(20*x^8)

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fricas [A]  time = 0.47, size = 24, normalized size = 0.86 \begin {gather*} \frac {{\left (7 \, x^{6} - 2 \, x^{3} - 5\right )} {\left (x^{3} - 1\right )}^{\frac {2}{3}}}{20 \, x^{8}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((x^3-1)^(2/3)*(x^3+2)/x^9,x, algorithm="fricas")

[Out]

1/20*(7*x^6 - 2*x^3 - 5)*(x^3 - 1)^(2/3)/x^8

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {{\left (x^{3} + 2\right )} {\left (x^{3} - 1\right )}^{\frac {2}{3}}}{x^{9}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((x^3-1)^(2/3)*(x^3+2)/x^9,x, algorithm="giac")

[Out]

integrate((x^3 + 2)*(x^3 - 1)^(2/3)/x^9, x)

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maple [A]  time = 0.08, size = 25, normalized size = 0.89

method	result	size
trager	\(\frac {\left (x^{3}-1\right )^{\frac {2}{3}} \left (7 x^{6}-2 x^{3}-5\right )}{20 x^{8}}\)	\(25\)
gosper	\(\frac {\left (-1+x \right ) \left (x^{2}+x +1\right ) \left (7 x^{3}+5\right ) \left (x^{3}-1\right )^{\frac {2}{3}}}{20 x^{8}}\)	\(29\)
risch	\(\frac {7 x^{9}-9 x^{6}-3 x^{3}+5}{20 x^{8} \left (x^{3}-1\right )^{\frac {1}{3}}}\)	\(30\)
meijerg	\(-\frac {\mathrm {signum}\left (x^{3}-1\right )^{\frac {2}{3}} \left (-x^{3}+1\right )^{\frac {5}{3}}}{5 \left (-\mathrm {signum}\left (x^{3}-1\right )\right )^{\frac {2}{3}} x^{5}}-\frac {\mathrm {signum}\left (x^{3}-1\right )^{\frac {2}{3}} \left (-\frac {3}{5} x^{6}-\frac {2}{5} x^{3}+1\right ) \left (-x^{3}+1\right )^{\frac {2}{3}}}{4 \left (-\mathrm {signum}\left (x^{3}-1\right )\right )^{\frac {2}{3}} x^{8}}\)	\(78\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((x^3-1)^(2/3)*(x^3+2)/x^9,x,method=_RETURNVERBOSE)

[Out]

1/20*(x^3-1)^(2/3)*(7*x^6-2*x^3-5)/x^8

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maxima [A]  time = 0.32, size = 25, normalized size = 0.89 \begin {gather*} \frac {3 \, {\left (x^{3} - 1\right )}^{\frac {5}{3}}}{5 \, x^{5}} - \frac {{\left (x^{3} - 1\right )}^{\frac {8}{3}}}{4 \, x^{8}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((x^3-1)^(2/3)*(x^3+2)/x^9,x, algorithm="maxima")

[Out]

3/5*(x^3 - 1)^(5/3)/x^5 - 1/4*(x^3 - 1)^(8/3)/x^8

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mupad [B]  time = 0.29, size = 24, normalized size = 0.86 \begin {gather*} -\frac {{\left (x^3-1\right )}^{2/3}\,\left (-7\,x^6+2\,x^3+5\right )}{20\,x^8} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((x^3 - 1)^(2/3)*(x^3 + 2))/x^9,x)

[Out]

-((x^3 - 1)^(2/3)*(2*x^3 - 7*x^6 + 5))/(20*x^8)

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sympy [C]  time = 2.56, size = 420, normalized size = 15.00 \begin {gather*} \begin {cases} \frac {\left (-1 + \frac {1}{x^{3}}\right )^{\frac {2}{3}} e^{- \frac {i \pi }{3}} \Gamma \left (- \frac {5}{3}\right )}{3 \Gamma \left (- \frac {2}{3}\right )} - \frac {\left (-1 + \frac {1}{x^{3}}\right )^{\frac {2}{3}} e^{- \frac {i \pi }{3}} \Gamma \left (- \frac {5}{3}\right )}{3 x^{3} \Gamma \left (- \frac {2}{3}\right )} & \text {for}\: \frac {1}{\left |{x^{3}}\right |} > 1 \\- \frac {\left (1 - \frac {1}{x^{3}}\right )^{\frac {2}{3}} \Gamma \left (- \frac {5}{3}\right )}{3 \Gamma \left (- \frac {2}{3}\right )} + \frac {\left (1 - \frac {1}{x^{3}}\right )^{\frac {2}{3}} \Gamma \left (- \frac {5}{3}\right )}{3 x^{3} \Gamma \left (- \frac {2}{3}\right )} & \text {otherwise} \end {cases} + 2 \left (\begin {cases} \frac {\left (-1 + \frac {1}{x^{3}}\right )^{\frac {2}{3}} e^{\frac {2 i \pi }{3}} \Gamma \left (- \frac {8}{3}\right )}{3 \Gamma \left (- \frac {2}{3}\right )} + \frac {2 \left (-1 + \frac {1}{x^{3}}\right )^{\frac {2}{3}} e^{\frac {2 i \pi }{3}} \Gamma \left (- \frac {8}{3}\right )}{9 x^{3} \Gamma \left (- \frac {2}{3}\right )} - \frac {5 \left (-1 + \frac {1}{x^{3}}\right )^{\frac {2}{3}} e^{\frac {2 i \pi }{3}} \Gamma \left (- \frac {8}{3}\right )}{9 x^{6} \Gamma \left (- \frac {2}{3}\right )} & \text {for}\: \frac {1}{\left |{x^{3}}\right |} > 1 \\\frac {3 x^{6} \left (1 - \frac {1}{x^{3}}\right )^{\frac {2}{3}} \Gamma \left (- \frac {8}{3}\right )}{9 x^{6} \Gamma \left (- \frac {2}{3}\right ) - 9 x^{3} \Gamma \left (- \frac {2}{3}\right )} - \frac {x^{3} \left (1 - \frac {1}{x^{3}}\right )^{\frac {2}{3}} \Gamma \left (- \frac {8}{3}\right )}{9 x^{6} \Gamma \left (- \frac {2}{3}\right ) - 9 x^{3} \Gamma \left (- \frac {2}{3}\right )} + \frac {5 \left (1 - \frac {1}{x^{3}}\right )^{\frac {2}{3}} \Gamma \left (- \frac {8}{3}\right )}{9 x^{9} \Gamma \left (- \frac {2}{3}\right ) - 9 x^{6} \Gamma \left (- \frac {2}{3}\right )} - \frac {7 \left (1 - \frac {1}{x^{3}}\right )^{\frac {2}{3}} \Gamma \left (- \frac {8}{3}\right )}{9 x^{6} \Gamma \left (- \frac {2}{3}\right ) - 9 x^{3} \Gamma \left (- \frac {2}{3}\right )} & \text {otherwise} \end {cases}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((x**3-1)**(2/3)*(x**3+2)/x**9,x)

[Out]

Piecewise(((-1 + x**(-3))**(2/3)*exp(-I*pi/3)*gamma(-5/3)/(3*gamma(-2/3)) - (-1 + x**(-3))**(2/3)*exp(-I*pi/3)
*gamma(-5/3)/(3*x**3*gamma(-2/3)), 1/Abs(x**3) > 1), (-(1 - 1/x**3)**(2/3)*gamma(-5/3)/(3*gamma(-2/3)) + (1 -
1/x**3)**(2/3)*gamma(-5/3)/(3*x**3*gamma(-2/3)), True)) + 2*Piecewise(((-1 + x**(-3))**(2/3)*exp(2*I*pi/3)*gam
ma(-8/3)/(3*gamma(-2/3)) + 2*(-1 + x**(-3))**(2/3)*exp(2*I*pi/3)*gamma(-8/3)/(9*x**3*gamma(-2/3)) - 5*(-1 + x*
*(-3))**(2/3)*exp(2*I*pi/3)*gamma(-8/3)/(9*x**6*gamma(-2/3)), 1/Abs(x**3) > 1), (3*x**6*(1 - 1/x**3)**(2/3)*ga
mma(-8/3)/(9*x**6*gamma(-2/3) - 9*x**3*gamma(-2/3)) - x**3*(1 - 1/x**3)**(2/3)*gamma(-8/3)/(9*x**6*gamma(-2/3)
- 9*x**3*gamma(-2/3)) + 5*(1 - 1/x**3)**(2/3)*gamma(-8/3)/(9*x**9*gamma(-2/3) - 9*x**6*gamma(-2/3)) - 7*(1 -
1/x**3)**(2/3)*gamma(-8/3)/(9*x**6*gamma(-2/3) - 9*x**3*gamma(-2/3)), True))

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