3.31.96 \(\int \frac {1}{\sqrt [3]{(-a+x) (-b+x)^2} (a-b d+(-1+d) x)} \, dx\)

Optimal. Leaf size=543 \[ \frac {\left (\sqrt [3]{d}-i \sqrt {3} \sqrt [3]{d}\right ) \log \left (\sqrt [3]{-1} (b-x) (b d-a d)^{2/3}-\sqrt [3]{d} (a-b)^{2/3} \sqrt [3]{x \left (2 a b+b^2\right )-a b^2+x^2 (-a-2 b)+x^3}\right )}{2 \sqrt [3]{a-b} (-(d (a-b)))^{2/3}}+\frac {\sqrt {-3-3 i \sqrt {3}} \sqrt [3]{d} \tan ^{-1}\left (\frac {\sqrt {3} \sqrt [3]{d} (a-b)^{2/3} \sqrt [3]{x \left (2 a b+b^2\right )-a b^2+x^2 (-a-2 b)+x^3}}{\sqrt [3]{d} (a-b)^{2/3} \sqrt [3]{x \left (2 a b+b^2\right )-a b^2+x^2 (-a-2 b)+x^3}-2 \sqrt [3]{-1} x (b d-a d)^{2/3}+2 \sqrt [3]{-1} b (b d-a d)^{2/3}}\right )}{\sqrt {2} \sqrt [3]{a-b} (-(d (a-b)))^{2/3}}+\frac {i \left (\sqrt {3} \sqrt [3]{d}+i \sqrt [3]{d}\right ) \log \left (-d^{2/3} (a-b)^{4/3} \left (x \left (2 a b+b^2\right )-a b^2+x^2 (-a-2 b)+x^3\right )^{2/3}+\sqrt [3]{-1} \sqrt [3]{d} (a-b)^{2/3} (x-b) (b d-a d)^{2/3} \sqrt [3]{x \left (2 a b+b^2\right )-a b^2+x^2 (-a-2 b)+x^3}+(-1)^{2/3} d \sqrt [3]{b d-a d} \left (a b^2-2 a b x+a x^2-b^3+2 b^2 x-b x^2\right )\right )}{4 \sqrt [3]{a-b} (-(d (a-b)))^{2/3}} \]

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Rubi [A]  time = 0.67, antiderivative size = 377, normalized size of antiderivative = 0.69, number of steps used = 3, number of rules used = 3, integrand size = 31, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.097, Rules used = {2081, 2077, 91} \begin {gather*} \frac {\left ((a-b)^2 (b-x)\right )^{2/3} \sqrt [3]{(a-b)^2 (x-a)} \log (a-b d+(d-1) x)}{2 \sqrt [3]{d} (a-b)^3 \sqrt [3]{-a b^2+x^2 (-a-2 b)+b x (2 a+b)+x^3}}-\frac {3 \left ((a-b)^2 (b-x)\right )^{2/3} \sqrt [3]{(a-b)^2 (x-a)} \log \left (-\frac {\sqrt [3]{\frac {2}{3}} \sqrt [3]{(a-b)^2 (x-a)}}{\sqrt [3]{d}}-\sqrt [3]{\frac {2}{3}} \sqrt [3]{(a-b)^2 (b-x)}\right )}{2 \sqrt [3]{d} (a-b)^3 \sqrt [3]{-a b^2+x^2 (-a-2 b)+b x (2 a+b)+x^3}}-\frac {\sqrt {3} \left ((a-b)^2 (b-x)\right )^{2/3} \sqrt [3]{(a-b)^2 (x-a)} \tan ^{-1}\left (\frac {1}{\sqrt {3}}-\frac {2 \sqrt [3]{(a-b)^2 (x-a)}}{\sqrt {3} \sqrt [3]{d} \sqrt [3]{(a-b)^2 (b-x)}}\right )}{\sqrt [3]{d} (a-b)^3 \sqrt [3]{-a b^2+x^2 (-a-2 b)+b x (2 a+b)+x^3}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[1/(((-a + x)*(-b + x)^2)^(1/3)*(a - b*d + (-1 + d)*x)),x]

[Out]

-((Sqrt[3]*((a - b)^2*(b - x))^(2/3)*((a - b)^2*(-a + x))^(1/3)*ArcTan[1/Sqrt[3] - (2*((a - b)^2*(-a + x))^(1/
3))/(Sqrt[3]*d^(1/3)*((a - b)^2*(b - x))^(1/3))])/((a - b)^3*d^(1/3)*(-(a*b^2) + b*(2*a + b)*x + (-a - 2*b)*x^
2 + x^3)^(1/3))) + (((a - b)^2*(b - x))^(2/3)*((a - b)^2*(-a + x))^(1/3)*Log[a - b*d + (-1 + d)*x])/(2*(a - b)
^3*d^(1/3)*(-(a*b^2) + b*(2*a + b)*x + (-a - 2*b)*x^2 + x^3)^(1/3)) - (3*((a - b)^2*(b - x))^(2/3)*((a - b)^2*
(-a + x))^(1/3)*Log[-((2/3)^(1/3)*((a - b)^2*(b - x))^(1/3)) - ((2/3)^(1/3)*((a - b)^2*(-a + x))^(1/3))/d^(1/3
)])/(2*(a - b)^3*d^(1/3)*(-(a*b^2) + b*(2*a + b)*x + (-a - 2*b)*x^2 + x^3)^(1/3))

Rule 91

Int[1/(((a_.) + (b_.)*(x_))^(1/3)*((c_.) + (d_.)*(x_))^(2/3)*((e_.) + (f_.)*(x_))), x_Symbol] :> With[{q = Rt[
(d*e - c*f)/(b*e - a*f), 3]}, -Simp[(Sqrt[3]*q*ArcTan[1/Sqrt[3] + (2*q*(a + b*x)^(1/3))/(Sqrt[3]*(c + d*x)^(1/
3))])/(d*e - c*f), x] + (Simp[(q*Log[e + f*x])/(2*(d*e - c*f)), x] - Simp[(3*q*Log[q*(a + b*x)^(1/3) - (c + d*
x)^(1/3)])/(2*(d*e - c*f)), x])] /; FreeQ[{a, b, c, d, e, f}, x]

Rule 2077

Int[((e_.) + (f_.)*(x_))^(m_.)*((a_) + (b_.)*(x_) + (d_.)*(x_)^3)^(p_), x_Symbol] :> Dist[(a + b*x + d*x^3)^p/
((3*a - b*x)^p*(3*a + 2*b*x)^(2*p)), Int[(e + f*x)^m*(3*a - b*x)^p*(3*a + 2*b*x)^(2*p), x], x] /; FreeQ[{a, b,
d, e, f, m, p}, x] && EqQ[4*b^3 + 27*a^2*d, 0] &&  !IntegerQ[p]

Rule 2081

Int[(P3_)^(p_.)*((e_.) + (f_.)*(x_))^(m_.), x_Symbol] :> With[{a = Coeff[P3, x, 0], b = Coeff[P3, x, 1], c = C
oeff[P3, x, 2], d = Coeff[P3, x, 3]}, Subst[Int[((3*d*e - c*f)/(3*d) + f*x)^m*Simp[(2*c^3 - 9*b*c*d + 27*a*d^2
)/(27*d^2) - ((c^2 - 3*b*d)*x)/(3*d) + d*x^3, x]^p, x], x, x + c/(3*d)] /; NeQ[c, 0]] /; FreeQ[{e, f, m, p}, x
] && PolyQ[P3, x, 3]

Rubi steps

\begin {align*} \int \frac {1}{\sqrt [3]{(-a+x) (-b+x)^2} (a-b d+(-1+d) x)} \, dx &=\operatorname {Subst}\left (\int \frac {1}{\left (\frac {1}{3} (-((-a-2 b) (-1+d))+3 (a-b d))+(-1+d) x\right ) \sqrt [3]{-\frac {2}{27} (a-b)^3-\frac {1}{3} (a-b)^2 x+x^3}} \, dx,x,\frac {1}{3} (-a-2 b)+x\right )\\ &=\frac {\left (2^{2/3} \sqrt [3]{-(a-b)^2 (a-x)} \left ((a-b)^2 (b-x)\right )^{2/3}\right ) \operatorname {Subst}\left (\int \frac {1}{\left (-\frac {2}{9} (a-b)^3-\frac {2}{3} (a-b)^2 x\right )^{2/3} \sqrt [3]{-\frac {2}{9} (a-b)^3+\frac {1}{3} (a-b)^2 x} \left (\frac {1}{3} (-((-a-2 b) (-1+d))+3 (a-b d))+(-1+d) x\right )} \, dx,x,\frac {1}{3} (-a-2 b)+x\right )}{3 \sqrt [3]{-a b^2+b (2 a+b) x-(a+2 b) x^2+x^3}}\\ &=-\frac {\sqrt {3} \sqrt [3]{-(a-b)^2 (a-x)} \left ((a-b)^2 (b-x)\right )^{2/3} \tan ^{-1}\left (\frac {1}{\sqrt {3}}-\frac {2 \sqrt [3]{-(a-b)^2 (a-x)}}{\sqrt {3} \sqrt [3]{d} \sqrt [3]{(a-b)^2 (b-x)}}\right )}{(a-b)^3 \sqrt [3]{d} \sqrt [3]{-a b^2+b (2 a+b) x-(a+2 b) x^2+x^3}}-\frac {3 \sqrt [3]{-(a-b)^2 (a-x)} \left ((a-b)^2 (b-x)\right )^{2/3} \log \left (\sqrt [3]{-(a-b)^2 (a-x)}+\sqrt [3]{d} \sqrt [3]{(a-b)^2 (b-x)}\right )}{2 (a-b)^3 \sqrt [3]{d} \sqrt [3]{-a b^2+b (2 a+b) x-(a+2 b) x^2+x^3}}+\frac {\sqrt [3]{-(a-b)^2 (a-x)} \left ((a-b)^2 (b-x)\right )^{2/3} \log (a-b d-(1-d) x)}{2 (a-b)^3 \sqrt [3]{d} \sqrt [3]{-a b^2+b (2 a+b) x-(a+2 b) x^2+x^3}}\\ \end {align*}

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Mathematica [C]  time = 0.04, size = 53, normalized size = 0.10 \begin {gather*} \frac {3 (x-b) \, _2F_1\left (\frac {1}{3},1;\frac {4}{3};\frac {d (b-x)}{a-x}\right )}{(a-b) \sqrt [3]{(x-a) (b-x)^2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[1/(((-a + x)*(-b + x)^2)^(1/3)*(a - b*d + (-1 + d)*x)),x]

[Out]

(3*(-b + x)*Hypergeometric2F1[1/3, 1, 4/3, (d*(b - x))/(a - x)])/((a - b)*((b - x)^2*(-a + x))^(1/3))

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IntegrateAlgebraic [A]  time = 7.72, size = 703, normalized size = 1.29 \begin {gather*} \frac {\sqrt {-3-3 i \sqrt {3}} \sqrt [3]{d} \tan ^{-1}\left (\frac {\sqrt {3} (a-b)^{2/3} \sqrt [3]{d} \sqrt [3]{-a b^2+\left (2 a b+b^2\right ) x+(-a-2 b) x^2+x^3}}{b (-a d+b d)^{2/3}+i \sqrt {3} b (-a d+b d)^{2/3}+\left (-(-a d+b d)^{2/3}-i \sqrt {3} (-a d+b d)^{2/3}\right ) x+(a-b)^{2/3} \sqrt [3]{d} \sqrt [3]{-a b^2+\left (2 a b+b^2\right ) x+(-a-2 b) x^2+x^3}}\right )}{\sqrt {2} \sqrt [3]{a-b} (-((a-b) d))^{2/3}}+\frac {\left (\sqrt [3]{d}-i \sqrt {3} \sqrt [3]{d}\right ) \log \left ((-a d+b d)^{2/3} \left (-b+\sqrt {3} (-i b+i x)+x\right )+2 (a-b)^{2/3} \sqrt [3]{d} \sqrt [3]{-a b^2+\left (2 a b+b^2\right ) x+(-a-2 b) x^2+x^3}\right )}{2 \sqrt [3]{a-b} (-((a-b) d))^{2/3}}+\frac {i \left (i \sqrt [3]{d}+\sqrt {3} \sqrt [3]{d}\right ) \log \left (2 (a-b)^{4/3} d^{2/3} \left (-a b^2+\left (2 a b+b^2\right ) x+(-a-2 b) x^2+x^3\right )^{2/3}+\sqrt [3]{-a d+b d} \left (d \left (a b^2-b^3-2 a b x+2 b^2 x+a x^2-b x^2\right )+\sqrt {3} d \left (-i a b^2+i b^3+2 i a b x-2 i b^2 x-i a x^2+i b x^2\right )\right )+(-a d+b d)^{2/3} \left ((a-b)^{2/3} \sqrt [3]{d} (b-x) \sqrt [3]{-a b^2+\left (2 a b+b^2\right ) x+(-a-2 b) x^2+x^3}+\sqrt {3} (a-b)^{2/3} \sqrt [3]{d} (i b-i x) \sqrt [3]{-a b^2+\left (2 a b+b^2\right ) x+(-a-2 b) x^2+x^3}\right )\right )}{4 \sqrt [3]{a-b} (-((a-b) d))^{2/3}} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[1/(((-a + x)*(-b + x)^2)^(1/3)*(a - b*d + (-1 + d)*x)),x]

[Out]

(Sqrt[-3 - (3*I)*Sqrt[3]]*d^(1/3)*ArcTan[(Sqrt[3]*(a - b)^(2/3)*d^(1/3)*(-(a*b^2) + (2*a*b + b^2)*x + (-a - 2*
b)*x^2 + x^3)^(1/3))/(b*(-(a*d) + b*d)^(2/3) + I*Sqrt[3]*b*(-(a*d) + b*d)^(2/3) + (-(-(a*d) + b*d)^(2/3) - I*S
qrt[3]*(-(a*d) + b*d)^(2/3))*x + (a - b)^(2/3)*d^(1/3)*(-(a*b^2) + (2*a*b + b^2)*x + (-a - 2*b)*x^2 + x^3)^(1/
3))])/(Sqrt[2]*(a - b)^(1/3)*(-((a - b)*d))^(2/3)) + ((d^(1/3) - I*Sqrt[3]*d^(1/3))*Log[(-(a*d) + b*d)^(2/3)*(
-b + Sqrt[3]*((-I)*b + I*x) + x) + 2*(a - b)^(2/3)*d^(1/3)*(-(a*b^2) + (2*a*b + b^2)*x + (-a - 2*b)*x^2 + x^3)
^(1/3)])/(2*(a - b)^(1/3)*(-((a - b)*d))^(2/3)) + ((I/4)*(I*d^(1/3) + Sqrt[3]*d^(1/3))*Log[2*(a - b)^(4/3)*d^(
2/3)*(-(a*b^2) + (2*a*b + b^2)*x + (-a - 2*b)*x^2 + x^3)^(2/3) + (-(a*d) + b*d)^(1/3)*(d*(a*b^2 - b^3 - 2*a*b*
x + 2*b^2*x + a*x^2 - b*x^2) + Sqrt[3]*d*((-I)*a*b^2 + I*b^3 + (2*I)*a*b*x - (2*I)*b^2*x - I*a*x^2 + I*b*x^2))
+ (-(a*d) + b*d)^(2/3)*((a - b)^(2/3)*d^(1/3)*(b - x)*(-(a*b^2) + (2*a*b + b^2)*x + (-a - 2*b)*x^2 + x^3)^(1/
3) + Sqrt[3]*(a - b)^(2/3)*d^(1/3)*(I*b - I*x)*(-(a*b^2) + (2*a*b + b^2)*x + (-a - 2*b)*x^2 + x^3)^(1/3))])/((
a - b)^(1/3)*(-((a - b)*d))^(2/3))

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fricas [A]  time = 0.68, size = 662, normalized size = 1.22 \begin {gather*} \left [-\frac {\sqrt {3} d \sqrt {-\frac {1}{d^{\frac {2}{3}}}} \log \left (-\frac {b^{2} d + {\left (d + 2\right )} x^{2} + 2 \, a b + 3 \, {\left (-a b^{2} - {\left (a + 2 \, b\right )} x^{2} + x^{3} + {\left (2 \, a b + b^{2}\right )} x\right )}^{\frac {1}{3}} {\left (b - x\right )} d^{\frac {2}{3}} - 2 \, {\left (b d + a + b\right )} x + \sqrt {3} {\left ({\left (-a b^{2} - {\left (a + 2 \, b\right )} x^{2} + x^{3} + {\left (2 \, a b + b^{2}\right )} x\right )}^{\frac {1}{3}} {\left (b d - d x\right )} - {\left (b^{2} d - 2 \, b d x + d x^{2}\right )} d^{\frac {1}{3}} + 2 \, {\left (-a b^{2} - {\left (a + 2 \, b\right )} x^{2} + x^{3} + {\left (2 \, a b + b^{2}\right )} x\right )}^{\frac {2}{3}} d^{\frac {2}{3}}\right )} \sqrt {-\frac {1}{d^{\frac {2}{3}}}}}{b^{2} d + {\left (d - 1\right )} x^{2} - a b - {\left (2 \, b d - a - b\right )} x}\right ) - d^{\frac {2}{3}} \log \left (-\frac {{\left (-a b^{2} - {\left (a + 2 \, b\right )} x^{2} + x^{3} + {\left (2 \, a b + b^{2}\right )} x\right )}^{\frac {1}{3}} {\left (b - x\right )} d^{\frac {1}{3}} - {\left (b^{2} - 2 \, b x + x^{2}\right )} d^{\frac {2}{3}} - {\left (-a b^{2} - {\left (a + 2 \, b\right )} x^{2} + x^{3} + {\left (2 \, a b + b^{2}\right )} x\right )}^{\frac {2}{3}}}{b^{2} - 2 \, b x + x^{2}}\right ) + 2 \, d^{\frac {2}{3}} \log \left (-\frac {{\left (b - x\right )} d^{\frac {1}{3}} + {\left (-a b^{2} - {\left (a + 2 \, b\right )} x^{2} + x^{3} + {\left (2 \, a b + b^{2}\right )} x\right )}^{\frac {1}{3}}}{b - x}\right )}{2 \, {\left (a - b\right )} d}, -\frac {2 \, \sqrt {3} d^{\frac {2}{3}} \arctan \left (\frac {\sqrt {3} {\left ({\left (b - x\right )} d^{\frac {1}{3}} - 2 \, {\left (-a b^{2} - {\left (a + 2 \, b\right )} x^{2} + x^{3} + {\left (2 \, a b + b^{2}\right )} x\right )}^{\frac {1}{3}}\right )}}{3 \, {\left (b - x\right )} d^{\frac {1}{3}}}\right ) - d^{\frac {2}{3}} \log \left (-\frac {{\left (-a b^{2} - {\left (a + 2 \, b\right )} x^{2} + x^{3} + {\left (2 \, a b + b^{2}\right )} x\right )}^{\frac {1}{3}} {\left (b - x\right )} d^{\frac {1}{3}} - {\left (b^{2} - 2 \, b x + x^{2}\right )} d^{\frac {2}{3}} - {\left (-a b^{2} - {\left (a + 2 \, b\right )} x^{2} + x^{3} + {\left (2 \, a b + b^{2}\right )} x\right )}^{\frac {2}{3}}}{b^{2} - 2 \, b x + x^{2}}\right ) + 2 \, d^{\frac {2}{3}} \log \left (-\frac {{\left (b - x\right )} d^{\frac {1}{3}} + {\left (-a b^{2} - {\left (a + 2 \, b\right )} x^{2} + x^{3} + {\left (2 \, a b + b^{2}\right )} x\right )}^{\frac {1}{3}}}{b - x}\right )}{2 \, {\left (a - b\right )} d}\right ] \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/((-a+x)*(-b+x)^2)^(1/3)/(a-b*d+(-1+d)*x),x, algorithm="fricas")

[Out]

[-1/2*(sqrt(3)*d*sqrt(-1/d^(2/3))*log(-(b^2*d + (d + 2)*x^2 + 2*a*b + 3*(-a*b^2 - (a + 2*b)*x^2 + x^3 + (2*a*b
+ b^2)*x)^(1/3)*(b - x)*d^(2/3) - 2*(b*d + a + b)*x + sqrt(3)*((-a*b^2 - (a + 2*b)*x^2 + x^3 + (2*a*b + b^2)*
x)^(1/3)*(b*d - d*x) - (b^2*d - 2*b*d*x + d*x^2)*d^(1/3) + 2*(-a*b^2 - (a + 2*b)*x^2 + x^3 + (2*a*b + b^2)*x)^
(2/3)*d^(2/3))*sqrt(-1/d^(2/3)))/(b^2*d + (d - 1)*x^2 - a*b - (2*b*d - a - b)*x)) - d^(2/3)*log(-((-a*b^2 - (a
+ 2*b)*x^2 + x^3 + (2*a*b + b^2)*x)^(1/3)*(b - x)*d^(1/3) - (b^2 - 2*b*x + x^2)*d^(2/3) - (-a*b^2 - (a + 2*b)
*x^2 + x^3 + (2*a*b + b^2)*x)^(2/3))/(b^2 - 2*b*x + x^2)) + 2*d^(2/3)*log(-((b - x)*d^(1/3) + (-a*b^2 - (a + 2
*b)*x^2 + x^3 + (2*a*b + b^2)*x)^(1/3))/(b - x)))/((a - b)*d), -1/2*(2*sqrt(3)*d^(2/3)*arctan(1/3*sqrt(3)*((b
- x)*d^(1/3) - 2*(-a*b^2 - (a + 2*b)*x^2 + x^3 + (2*a*b + b^2)*x)^(1/3))/((b - x)*d^(1/3))) - d^(2/3)*log(-((-
a*b^2 - (a + 2*b)*x^2 + x^3 + (2*a*b + b^2)*x)^(1/3)*(b - x)*d^(1/3) - (b^2 - 2*b*x + x^2)*d^(2/3) - (-a*b^2 -
(a + 2*b)*x^2 + x^3 + (2*a*b + b^2)*x)^(2/3))/(b^2 - 2*b*x + x^2)) + 2*d^(2/3)*log(-((b - x)*d^(1/3) + (-a*b^
2 - (a + 2*b)*x^2 + x^3 + (2*a*b + b^2)*x)^(1/3))/(b - x)))/((a - b)*d)]

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int -\frac {1}{\left (-{\left (a - x\right )} {\left (b - x\right )}^{2}\right )^{\frac {1}{3}} {\left (b d - {\left (d - 1\right )} x - a\right )}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/((-a+x)*(-b+x)^2)^(1/3)/(a-b*d+(-1+d)*x),x, algorithm="giac")

[Out]

integrate(-1/((-(a - x)*(b - x)^2)^(1/3)*(b*d - (d - 1)*x - a)), x)

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maple [F]  time = 0.01, size = 0, normalized size = 0.00 \[\int \frac {1}{\left (\left (-a +x \right ) \left (-b +x \right )^{2}\right )^{\frac {1}{3}} \left (a -b d +\left (-1+d \right ) x \right )}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/((-a+x)*(-b+x)^2)^(1/3)/(a-b*d+(-1+d)*x),x)

[Out]

int(1/((-a+x)*(-b+x)^2)^(1/3)/(a-b*d+(-1+d)*x),x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} -\int \frac {1}{\left (-{\left (a - x\right )} {\left (b - x\right )}^{2}\right )^{\frac {1}{3}} {\left (b d - {\left (d - 1\right )} x - a\right )}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/((-a+x)*(-b+x)^2)^(1/3)/(a-b*d+(-1+d)*x),x, algorithm="maxima")

[Out]

-integrate(1/((-(a - x)*(b - x)^2)^(1/3)*(b*d - (d - 1)*x - a)), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {1}{{\left (-\left (a-x\right )\,{\left (b-x\right )}^2\right )}^{1/3}\,\left (a-b\,d+x\,\left (d-1\right )\right )} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/((-(a - x)*(b - x)^2)^(1/3)*(a - b*d + x*(d - 1))),x)

[Out]

int(1/((-(a - x)*(b - x)^2)^(1/3)*(a - b*d + x*(d - 1))), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{\sqrt [3]{\left (- a + x\right ) \left (- b + x\right )^{2}} \left (a - b d + d x - x\right )}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/((-a+x)*(-b+x)**2)**(1/3)/(a-b*d+(-1+d)*x),x)

[Out]

Integral(1/(((-a + x)*(-b + x)**2)**(1/3)*(a - b*d + d*x - x)), x)

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