3.29.95 \(\int \frac {(a-5 b+4 x) (-a^3+3 a^2 x-3 a x^2+x^3)}{((-a+x) (-b+x))^{2/3} (b-a^5 d-(1-5 a^4 d) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5)} \, dx\)

Optimal. Leaf size=317 \[ \frac {\sqrt {3} \tan ^{-1}\left (\frac {\sqrt {3} a^2 \sqrt [3]{d}-2 \sqrt {3} a \sqrt [3]{d} x+\sqrt {3} \sqrt [3]{d} x^2}{a^2 \sqrt [3]{d}+2 \sqrt [3]{x (-a-b)+a b+x^2}-2 a \sqrt [3]{d} x+\sqrt [3]{d} x^2}\right )}{d^{2/3}}+\frac {\log \left (a^3 \sqrt [3]{d}-2 a^2 \sqrt [3]{d} x-a \sqrt [3]{x (-a-b)+a b+x^2}+a \sqrt [3]{d} x^2\right )}{d^{2/3}}-\frac {\log \left (a^6 d^{2/3}-4 a^5 d^{2/3} x+6 a^4 d^{2/3} x^2-4 a^3 d^{2/3} x^3+a^2 \left (x (-a-b)+a b+x^2\right )^{2/3}+a^2 d^{2/3} x^4+\sqrt [3]{x (-a-b)+a b+x^2} \left (a^4 \sqrt [3]{d}-2 a^3 \sqrt [3]{d} x+a^2 \sqrt [3]{d} x^2\right )\right )}{2 d^{2/3}} \]

________________________________________________________________________________________

Rubi [F]  time = 8.67, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {(a-5 b+4 x) \left (-a^3+3 a^2 x-3 a x^2+x^3\right )}{((-a+x) (-b+x))^{2/3} \left (b-a^5 d-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Int[((a - 5*b + 4*x)*(-a^3 + 3*a^2*x - 3*a*x^2 + x^3))/(((-a + x)*(-b + x))^(2/3)*(b - a^5*d - (1 - 5*a^4*d)*x
 - 10*a^3*d*x^2 + 10*a^2*d*x^3 - 5*a*d*x^4 + d*x^5)),x]

[Out]

(-3*(a - 5*b)*(-a + x)^(2/3)*(-b + x)^(2/3)*Defer[Subst][Defer[Int][x^9/((a - b + x^3)^(2/3)*(a*(1 - b/a) + x^
3 - d*x^15)), x], x, (-a + x)^(1/3)])/((a - x)*(b - x))^(2/3) + (12*a*(-a + x)^(2/3)*(-b + x)^(2/3)*Defer[Subs
t][Defer[Int][x^9/((a - b + x^3)^(2/3)*(-(a*(1 - b/a)) - x^3 + d*x^15)), x], x, (-a + x)^(1/3)])/((a - x)*(b -
 x))^(2/3) + (12*(-a + x)^(2/3)*(-b + x)^(2/3)*Defer[Subst][Defer[Int][x^12/((a - b + x^3)^(2/3)*(-(a*(1 - b/a
)) - x^3 + d*x^15)), x], x, (-a + x)^(1/3)])/((a - x)*(b - x))^(2/3)

Rubi steps

\begin {align*} \int \frac {(a-5 b+4 x) \left (-a^3+3 a^2 x-3 a x^2+x^3\right )}{((-a+x) (-b+x))^{2/3} \left (b-a^5 d-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )} \, dx &=\frac {\left ((-a+x)^{2/3} (-b+x)^{2/3}\right ) \int \frac {(a-5 b+4 x) \left (-a^3+3 a^2 x-3 a x^2+x^3\right )}{(-a+x)^{2/3} (-b+x)^{2/3} \left (b-a^5 d-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )} \, dx}{((-a+x) (-b+x))^{2/3}}\\ &=\frac {\left ((-a+x)^{2/3} (-b+x)^{2/3}\right ) \int \frac {\sqrt [3]{-a+x} (a-5 b+4 x) \left (a^2-2 a x+x^2\right )}{(-b+x)^{2/3} \left (b-a^5 d-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )} \, dx}{((-a+x) (-b+x))^{2/3}}\\ &=\frac {\left ((-a+x)^{2/3} (-b+x)^{2/3}\right ) \int \frac {(-a+x)^{7/3} (a-5 b+4 x)}{(-b+x)^{2/3} \left (b-a^5 d-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )} \, dx}{((-a+x) (-b+x))^{2/3}}\\ &=\frac {\left ((-a+x)^{2/3} (-b+x)^{2/3}\right ) \int \frac {(-a+x)^{7/3} (a-5 b+4 x)}{(-b+x)^{2/3} \left (b \left (1-\frac {a^5 d}{b}\right )-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )} \, dx}{((-a+x) (-b+x))^{2/3}}\\ &=\frac {\left ((-a+x)^{2/3} (-b+x)^{2/3}\right ) \int \left (\frac {5 \left (1-\frac {a}{5 b}\right ) b (-a+x)^{7/3}}{(-b+x)^{2/3} \left (-b \left (1-\frac {a^5 d}{b}\right )+\left (1-5 a^4 d\right ) x+10 a^3 d x^2-10 a^2 d x^3+5 a d x^4-d x^5\right )}+\frac {4 x (-a+x)^{7/3}}{(-b+x)^{2/3} \left (b \left (1-\frac {a^5 d}{b}\right )-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )}\right ) \, dx}{((-a+x) (-b+x))^{2/3}}\\ &=\frac {\left (4 (-a+x)^{2/3} (-b+x)^{2/3}\right ) \int \frac {x (-a+x)^{7/3}}{(-b+x)^{2/3} \left (b \left (1-\frac {a^5 d}{b}\right )-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )} \, dx}{((-a+x) (-b+x))^{2/3}}+\frac {\left ((-a+5 b) (-a+x)^{2/3} (-b+x)^{2/3}\right ) \int \frac {(-a+x)^{7/3}}{(-b+x)^{2/3} \left (-b \left (1-\frac {a^5 d}{b}\right )+\left (1-5 a^4 d\right ) x+10 a^3 d x^2-10 a^2 d x^3+5 a d x^4-d x^5\right )} \, dx}{((-a+x) (-b+x))^{2/3}}\\ &=\frac {\left (12 (-a+x)^{2/3} (-b+x)^{2/3}\right ) \operatorname {Subst}\left (\int \frac {x^9 \left (a+x^3\right )}{\left (a-b+x^3\right )^{2/3} \left (-a+b-x^3+d x^{15}\right )} \, dx,x,\sqrt [3]{-a+x}\right )}{((-a+x) (-b+x))^{2/3}}+\frac {\left (3 (-a+5 b) (-a+x)^{2/3} (-b+x)^{2/3}\right ) \operatorname {Subst}\left (\int \frac {x^9}{\left (a-b+x^3\right )^{2/3} \left (a-b+x^3-d x^{15}\right )} \, dx,x,\sqrt [3]{-a+x}\right )}{((-a+x) (-b+x))^{2/3}}\\ &=\frac {\left (12 (-a+x)^{2/3} (-b+x)^{2/3}\right ) \operatorname {Subst}\left (\int \frac {x^9 \left (-a-x^3\right )}{\left (a-b+x^3\right )^{2/3} \left (a \left (1-\frac {b}{a}\right )+x^3-d x^{15}\right )} \, dx,x,\sqrt [3]{-a+x}\right )}{((-a+x) (-b+x))^{2/3}}+\frac {\left (3 (-a+5 b) (-a+x)^{2/3} (-b+x)^{2/3}\right ) \operatorname {Subst}\left (\int \frac {x^9}{\left (a-b+x^3\right )^{2/3} \left (a \left (1-\frac {b}{a}\right )+x^3-d x^{15}\right )} \, dx,x,\sqrt [3]{-a+x}\right )}{((-a+x) (-b+x))^{2/3}}\\ &=\frac {\left (12 (-a+x)^{2/3} (-b+x)^{2/3}\right ) \operatorname {Subst}\left (\int \left (\frac {a x^9}{\left (a-b+x^3\right )^{2/3} \left (-a \left (1-\frac {b}{a}\right )-x^3+d x^{15}\right )}+\frac {x^{12}}{\left (a-b+x^3\right )^{2/3} \left (-a \left (1-\frac {b}{a}\right )-x^3+d x^{15}\right )}\right ) \, dx,x,\sqrt [3]{-a+x}\right )}{((-a+x) (-b+x))^{2/3}}+\frac {\left (3 (-a+5 b) (-a+x)^{2/3} (-b+x)^{2/3}\right ) \operatorname {Subst}\left (\int \frac {x^9}{\left (a-b+x^3\right )^{2/3} \left (a \left (1-\frac {b}{a}\right )+x^3-d x^{15}\right )} \, dx,x,\sqrt [3]{-a+x}\right )}{((-a+x) (-b+x))^{2/3}}\\ &=\frac {\left (12 (-a+x)^{2/3} (-b+x)^{2/3}\right ) \operatorname {Subst}\left (\int \frac {x^{12}}{\left (a-b+x^3\right )^{2/3} \left (-a \left (1-\frac {b}{a}\right )-x^3+d x^{15}\right )} \, dx,x,\sqrt [3]{-a+x}\right )}{((-a+x) (-b+x))^{2/3}}+\frac {\left (12 a (-a+x)^{2/3} (-b+x)^{2/3}\right ) \operatorname {Subst}\left (\int \frac {x^9}{\left (a-b+x^3\right )^{2/3} \left (-a \left (1-\frac {b}{a}\right )-x^3+d x^{15}\right )} \, dx,x,\sqrt [3]{-a+x}\right )}{((-a+x) (-b+x))^{2/3}}+\frac {\left (3 (-a+5 b) (-a+x)^{2/3} (-b+x)^{2/3}\right ) \operatorname {Subst}\left (\int \frac {x^9}{\left (a-b+x^3\right )^{2/3} \left (a \left (1-\frac {b}{a}\right )+x^3-d x^{15}\right )} \, dx,x,\sqrt [3]{-a+x}\right )}{((-a+x) (-b+x))^{2/3}}\\ \end {align*}

________________________________________________________________________________________

Mathematica [F]  time = 1.28, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {(a-5 b+4 x) \left (-a^3+3 a^2 x-3 a x^2+x^3\right )}{((-a+x) (-b+x))^{2/3} \left (b-a^5 d-\left (1-5 a^4 d\right ) x-10 a^3 d x^2+10 a^2 d x^3-5 a d x^4+d x^5\right )} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Integrate[((a - 5*b + 4*x)*(-a^3 + 3*a^2*x - 3*a*x^2 + x^3))/(((-a + x)*(-b + x))^(2/3)*(b - a^5*d - (1 - 5*a^
4*d)*x - 10*a^3*d*x^2 + 10*a^2*d*x^3 - 5*a*d*x^4 + d*x^5)),x]

[Out]

Integrate[((a - 5*b + 4*x)*(-a^3 + 3*a^2*x - 3*a*x^2 + x^3))/(((-a + x)*(-b + x))^(2/3)*(b - a^5*d - (1 - 5*a^
4*d)*x - 10*a^3*d*x^2 + 10*a^2*d*x^3 - 5*a*d*x^4 + d*x^5)), x]

________________________________________________________________________________________

IntegrateAlgebraic [A]  time = 5.34, size = 317, normalized size = 1.00 \begin {gather*} \frac {\sqrt {3} \tan ^{-1}\left (\frac {\sqrt {3} a^2 \sqrt [3]{d}-2 \sqrt {3} a \sqrt [3]{d} x+\sqrt {3} \sqrt [3]{d} x^2}{a^2 \sqrt [3]{d}-2 a \sqrt [3]{d} x+\sqrt [3]{d} x^2+2 \sqrt [3]{a b+(-a-b) x+x^2}}\right )}{d^{2/3}}+\frac {\log \left (a^3 \sqrt [3]{d}-2 a^2 \sqrt [3]{d} x+a \sqrt [3]{d} x^2-a \sqrt [3]{a b+(-a-b) x+x^2}\right )}{d^{2/3}}-\frac {\log \left (a^6 d^{2/3}-4 a^5 d^{2/3} x+6 a^4 d^{2/3} x^2-4 a^3 d^{2/3} x^3+a^2 d^{2/3} x^4+a^2 \left (a b+(-a-b) x+x^2\right )^{2/3}+\sqrt [3]{a b+(-a-b) x+x^2} \left (a^4 \sqrt [3]{d}-2 a^3 \sqrt [3]{d} x+a^2 \sqrt [3]{d} x^2\right )\right )}{2 d^{2/3}} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[((a - 5*b + 4*x)*(-a^3 + 3*a^2*x - 3*a*x^2 + x^3))/(((-a + x)*(-b + x))^(2/3)*(b - a^5*d -
(1 - 5*a^4*d)*x - 10*a^3*d*x^2 + 10*a^2*d*x^3 - 5*a*d*x^4 + d*x^5)),x]

[Out]

(Sqrt[3]*ArcTan[(Sqrt[3]*a^2*d^(1/3) - 2*Sqrt[3]*a*d^(1/3)*x + Sqrt[3]*d^(1/3)*x^2)/(a^2*d^(1/3) - 2*a*d^(1/3)
*x + d^(1/3)*x^2 + 2*(a*b + (-a - b)*x + x^2)^(1/3))])/d^(2/3) + Log[a^3*d^(1/3) - 2*a^2*d^(1/3)*x + a*d^(1/3)
*x^2 - a*(a*b + (-a - b)*x + x^2)^(1/3)]/d^(2/3) - Log[a^6*d^(2/3) - 4*a^5*d^(2/3)*x + 6*a^4*d^(2/3)*x^2 - 4*a
^3*d^(2/3)*x^3 + a^2*d^(2/3)*x^4 + a^2*(a*b + (-a - b)*x + x^2)^(2/3) + (a*b + (-a - b)*x + x^2)^(1/3)*(a^4*d^
(1/3) - 2*a^3*d^(1/3)*x + a^2*d^(1/3)*x^2)]/(2*d^(2/3))

________________________________________________________________________________________

fricas [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a-5*b+4*x)*(-a^3+3*a^2*x-3*a*x^2+x^3)/((-a+x)*(-b+x))^(2/3)/(b-a^5*d-(-5*a^4*d+1)*x-10*a^3*d*x^2+10
*a^2*d*x^3-5*a*d*x^4+d*x^5),x, algorithm="fricas")

[Out]

Timed out

________________________________________________________________________________________

giac [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {{\left (a^{3} - 3 \, a^{2} x + 3 \, a x^{2} - x^{3}\right )} {\left (a - 5 \, b + 4 \, x\right )}}{{\left (a^{5} d + 10 \, a^{3} d x^{2} - 10 \, a^{2} d x^{3} + 5 \, a d x^{4} - d x^{5} - {\left (5 \, a^{4} d - 1\right )} x - b\right )} \left ({\left (a - x\right )} {\left (b - x\right )}\right )^{\frac {2}{3}}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a-5*b+4*x)*(-a^3+3*a^2*x-3*a*x^2+x^3)/((-a+x)*(-b+x))^(2/3)/(b-a^5*d-(-5*a^4*d+1)*x-10*a^3*d*x^2+10
*a^2*d*x^3-5*a*d*x^4+d*x^5),x, algorithm="giac")

[Out]

integrate((a^3 - 3*a^2*x + 3*a*x^2 - x^3)*(a - 5*b + 4*x)/((a^5*d + 10*a^3*d*x^2 - 10*a^2*d*x^3 + 5*a*d*x^4 -
d*x^5 - (5*a^4*d - 1)*x - b)*((a - x)*(b - x))^(2/3)), x)

________________________________________________________________________________________

maple [F]  time = 0.13, size = 0, normalized size = 0.00 \[\int \frac {\left (a -5 b +4 x \right ) \left (-a^{3}+3 a^{2} x -3 a \,x^{2}+x^{3}\right )}{\left (\left (-a +x \right ) \left (-b +x \right )\right )^{\frac {2}{3}} \left (b -a^{5} d -\left (-5 a^{4} d +1\right ) x -10 a^{3} d \,x^{2}+10 a^{2} d \,x^{3}-5 a d \,x^{4}+d \,x^{5}\right )}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a-5*b+4*x)*(-a^3+3*a^2*x-3*a*x^2+x^3)/((-a+x)*(-b+x))^(2/3)/(b-a^5*d-(-5*a^4*d+1)*x-10*a^3*d*x^2+10*a^2*d
*x^3-5*a*d*x^4+d*x^5),x)

[Out]

int((a-5*b+4*x)*(-a^3+3*a^2*x-3*a*x^2+x^3)/((-a+x)*(-b+x))^(2/3)/(b-a^5*d-(-5*a^4*d+1)*x-10*a^3*d*x^2+10*a^2*d
*x^3-5*a*d*x^4+d*x^5),x)

________________________________________________________________________________________

maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {{\left (a^{3} - 3 \, a^{2} x + 3 \, a x^{2} - x^{3}\right )} {\left (a - 5 \, b + 4 \, x\right )}}{{\left (a^{5} d + 10 \, a^{3} d x^{2} - 10 \, a^{2} d x^{3} + 5 \, a d x^{4} - d x^{5} - {\left (5 \, a^{4} d - 1\right )} x - b\right )} \left ({\left (a - x\right )} {\left (b - x\right )}\right )^{\frac {2}{3}}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a-5*b+4*x)*(-a^3+3*a^2*x-3*a*x^2+x^3)/((-a+x)*(-b+x))^(2/3)/(b-a^5*d-(-5*a^4*d+1)*x-10*a^3*d*x^2+10
*a^2*d*x^3-5*a*d*x^4+d*x^5),x, algorithm="maxima")

[Out]

integrate((a^3 - 3*a^2*x + 3*a*x^2 - x^3)*(a - 5*b + 4*x)/((a^5*d + 10*a^3*d*x^2 - 10*a^2*d*x^3 + 5*a*d*x^4 -
d*x^5 - (5*a^4*d - 1)*x - b)*((a - x)*(b - x))^(2/3)), x)

________________________________________________________________________________________

mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int -\frac {\left (a-5\,b+4\,x\right )\,\left (a^3-3\,a^2\,x+3\,a\,x^2-x^3\right )}{{\left (\left (a-x\right )\,\left (b-x\right )\right )}^{2/3}\,\left (b-a^5\,d+d\,x^5+x\,\left (5\,a^4\,d-1\right )+10\,a^2\,d\,x^3-10\,a^3\,d\,x^2-5\,a\,d\,x^4\right )} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(-((a - 5*b + 4*x)*(3*a*x^2 - 3*a^2*x + a^3 - x^3))/(((a - x)*(b - x))^(2/3)*(b - a^5*d + d*x^5 + x*(5*a^4*
d - 1) + 10*a^2*d*x^3 - 10*a^3*d*x^2 - 5*a*d*x^4)),x)

[Out]

int(-((a - 5*b + 4*x)*(3*a*x^2 - 3*a^2*x + a^3 - x^3))/(((a - x)*(b - x))^(2/3)*(b - a^5*d + d*x^5 + x*(5*a^4*
d - 1) + 10*a^2*d*x^3 - 10*a^3*d*x^2 - 5*a*d*x^4)), x)

________________________________________________________________________________________

sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (- a + x\right )^{3} \left (a - 5 b + 4 x\right )}{\left (\left (- a + x\right ) \left (- b + x\right )\right )^{\frac {2}{3}} \left (- a^{5} d + 5 a^{4} d x - 10 a^{3} d x^{2} + 10 a^{2} d x^{3} - 5 a d x^{4} + b + d x^{5} - x\right )}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a-5*b+4*x)*(-a**3+3*a**2*x-3*a*x**2+x**3)/((-a+x)*(-b+x))**(2/3)/(b-a**5*d-(-5*a**4*d+1)*x-10*a**3*
d*x**2+10*a**2*d*x**3-5*a*d*x**4+d*x**5),x)

[Out]

Integral((-a + x)**3*(a - 5*b + 4*x)/(((-a + x)*(-b + x))**(2/3)*(-a**5*d + 5*a**4*d*x - 10*a**3*d*x**2 + 10*a
**2*d*x**3 - 5*a*d*x**4 + b + d*x**5 - x)), x)

________________________________________________________________________________________