3.3.70 \(\int \frac {1+x^2}{(-1+x^2) \sqrt [4]{-x^3+x^5}} \, dx\)

Optimal. Leaf size=25 \[ -\frac {4 \left (x^5-x^3\right )^{3/4}}{x^2 \left (x^2-1\right )} \]

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Rubi [A]  time = 0.09, antiderivative size = 16, normalized size of antiderivative = 0.64, number of steps used = 2, number of rules used = 2, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {2056, 449} \begin {gather*} -\frac {4 x}{\sqrt [4]{x^5-x^3}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(1 + x^2)/((-1 + x^2)*(-x^3 + x^5)^(1/4)),x]

[Out]

(-4*x)/(-x^3 + x^5)^(1/4)

Rule 449

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_)), x_Symbol] :> Simp[(c*(e*x)^(m
+ 1)*(a + b*x^n)^(p + 1))/(a*e*(m + 1)), x] /; FreeQ[{a, b, c, d, e, m, n, p}, x] && NeQ[b*c - a*d, 0] && EqQ[
a*d*(m + 1) - b*c*(m + n*(p + 1) + 1), 0] && NeQ[m, -1]

Rule 2056

Int[(u_.)*(P_)^(p_.), x_Symbol] :> With[{m = MinimumMonomialExponent[P, x]}, Dist[P^FracPart[p]/(x^(m*FracPart
[p])*Distrib[1/x^m, P]^FracPart[p]), Int[u*x^(m*p)*Distrib[1/x^m, P]^p, x], x]] /; FreeQ[p, x] &&  !IntegerQ[p
] && SumQ[P] && EveryQ[BinomialQ[#1, x] & , P] &&  !PolyQ[P, x, 2]

Rubi steps

\begin {align*} \int \frac {1+x^2}{\left (-1+x^2\right ) \sqrt [4]{-x^3+x^5}} \, dx &=\frac {\left (x^{3/4} \sqrt [4]{-1+x^2}\right ) \int \frac {1+x^2}{x^{3/4} \left (-1+x^2\right )^{5/4}} \, dx}{\sqrt [4]{-x^3+x^5}}\\ &=-\frac {4 x}{\sqrt [4]{-x^3+x^5}}\\ \end {align*}

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Mathematica [A]  time = 0.03, size = 16, normalized size = 0.64 \begin {gather*} -\frac {4 x}{\sqrt [4]{x^3 \left (x^2-1\right )}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(1 + x^2)/((-1 + x^2)*(-x^3 + x^5)^(1/4)),x]

[Out]

(-4*x)/(x^3*(-1 + x^2))^(1/4)

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IntegrateAlgebraic [A]  time = 0.13, size = 25, normalized size = 1.00 \begin {gather*} -\frac {4 \left (-x^3+x^5\right )^{3/4}}{x^2 \left (-1+x^2\right )} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[(1 + x^2)/((-1 + x^2)*(-x^3 + x^5)^(1/4)),x]

[Out]

(-4*(-x^3 + x^5)^(3/4))/(x^2*(-1 + x^2))

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fricas [A]  time = 0.45, size = 24, normalized size = 0.96 \begin {gather*} -\frac {4 \, {\left (x^{5} - x^{3}\right )}^{\frac {3}{4}}}{x^{4} - x^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((x^2+1)/(x^2-1)/(x^5-x^3)^(1/4),x, algorithm="fricas")

[Out]

-4*(x^5 - x^3)^(3/4)/(x^4 - x^2)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x^{2} + 1}{{\left (x^{5} - x^{3}\right )}^{\frac {1}{4}} {\left (x^{2} - 1\right )}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((x^2+1)/(x^2-1)/(x^5-x^3)^(1/4),x, algorithm="giac")

[Out]

integrate((x^2 + 1)/((x^5 - x^3)^(1/4)*(x^2 - 1)), x)

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maple [A]  time = 0.10, size = 15, normalized size = 0.60

method	result	size
gosper	\(-\frac {4 x}{\left (x^{5}-x^{3}\right )^{\frac {1}{4}}}\)	\(15\)
risch	\(-\frac {4 x}{\left (x^{3} \left (x^{2}-1\right )\right )^{\frac {1}{4}}}\)	\(15\)
trager	\(-\frac {4 \left (x^{5}-x^{3}\right )^{\frac {3}{4}}}{x^{2} \left (x^{2}-1\right )}\)	\(24\)
meijerg	\(-\frac {4 \left (-\mathrm {signum}\left (x^{2}-1\right )\right )^{\frac {1}{4}} \hypergeom \left (\left [\frac {1}{8}, \frac {5}{4}\right ], \left [\frac {9}{8}\right ], x^{2}\right ) x^{\frac {1}{4}}}{\mathrm {signum}\left (x^{2}-1\right )^{\frac {1}{4}}}-\frac {4 \left (-\mathrm {signum}\left (x^{2}-1\right )\right )^{\frac {1}{4}} \hypergeom \left (\left [\frac {9}{8}, \frac {5}{4}\right ], \left [\frac {17}{8}\right ], x^{2}\right ) x^{\frac {9}{4}}}{9 \mathrm {signum}\left (x^{2}-1\right )^{\frac {1}{4}}}\)	\(66\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((x^2+1)/(x^2-1)/(x^5-x^3)^(1/4),x,method=_RETURNVERBOSE)

[Out]

-4*x/(x^5-x^3)^(1/4)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x^{2} + 1}{{\left (x^{5} - x^{3}\right )}^{\frac {1}{4}} {\left (x^{2} - 1\right )}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((x^2+1)/(x^2-1)/(x^5-x^3)^(1/4),x, algorithm="maxima")

[Out]

integrate((x^2 + 1)/((x^5 - x^3)^(1/4)*(x^2 - 1)), x)

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mupad [B]  time = 0.19, size = 23, normalized size = 0.92 \begin {gather*} -\frac {4\,{\left (x^5-x^3\right )}^{3/4}}{x^2\,\left (x^2-1\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((x^2 + 1)/((x^2 - 1)*(x^5 - x^3)^(1/4)),x)

[Out]

-(4*(x^5 - x^3)^(3/4))/(x^2*(x^2 - 1))

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x^{2} + 1}{\sqrt [4]{x^{3} \left (x - 1\right ) \left (x + 1\right )} \left (x - 1\right ) \left (x + 1\right )}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((x**2+1)/(x**2-1)/(x**5-x**3)**(1/4),x)

[Out]

Integral((x**2 + 1)/((x**3*(x - 1)*(x + 1))**(1/4)*(x - 1)*(x + 1)), x)

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